SQL Calculate daily increment with Date and ID on multiple variables - sql

I have a table with the following structure:
+----------+-----+-------+----------+
| Date | ID | Likes | Comments |
+----------+-----+-------+----------+
| 1/1/2018 | AAA | 70 | 90 |
| 1/2/2018 | AAA | 80 | 110 |
| 1/1/2018 | BBB | 60 | 5 |
| 1/2/2018 | BBB | 90 | 6 |
+----------+-----+-------+----------+
For each day and ID, I need to calculate the incremental value. The desired output should something like this: desired output
+----------+-----+-------+----------+-------------+----------------+
| Date | ID | Likes | Comments | daily_likes | daily_comments |
+----------+-----+-------+----------+-------------+----------------+
| 1/1/2018 | AAA | 70 | 90 | 70 | 90 |
| 1/2/2018 | AAA | 80 | 110 | 10 | 20 |
| 1/1/2018 | BBB | 60 | 5 | 60 | 5 |
| 1/2/2018 | BBB | 90 | 6 | 30 | 1 |
+----------+-----+-------+----------+-------------+----------------+
I have tried this code but it keeps aggregating the daily_likes or daily_comments together.
SELECT
"date",
"created_time",
("likes_count" - LAG("likes_count", 1) OVER (ORDER BY "date")) AS "daily_likes",
("comments_count" - LAG("comments_count", 1) OVER (ORDER BY "date")) AS "daily_comments",
"id",
"likes_count",
"comments_count",
"user_username"
FROM
"blablabla"
GROUP BY
1,
"id",
"likes_count",
"comments_count",
"user_username",
"created_time"
ORDER BY
1 DESC;

The table structure you postet doesn't match the query. And I'm wondering why you group at all, let alone on nearly every column and a literal...
A query, that would produce the desired output you posted from a table like you posted would be:
SELECT "date",
"id",
"likes",
"comments",
"likes"
- lag("likes",
1,
0) OVER (PARTITION BY "id"
ORDER BY "date") "daily_likes",
"comments"
- lag("comments",
1,
0) OVER (PARTITION BY "id"
ORDER BY "date") "daily_comments"
FROM "elbat"
ORDER BY "date",
"id";
SQL Fiddle
There is no need to group at all.
(However note, to show the daily increase, this requires the source table to have data for every day for every user. If you got gaps, you'd need to join all days (in the respective range) for all users to fill them.

Related

SQL to Get Latest Field Value

I'm trying to write an SQL query (SQL Server) that returns the latest value of a field from a history table.
The table structure is basically as below:
ISSUE TABLE:
issueid
10
20
30
CHANGEGROUP TABLE:
changegroupid | issueid | updated |
1 | 10 | 01/01/2020 |
2 | 10 | 02/01/2020 |
3 | 10 | 03/01/2020 |
4 | 20 | 05/01/2020 |
5 | 20 | 06/01/2020 |
6 | 20 | 07/01/2020 |
7 | 30 | 04/01/2020 |
8 | 30 | 05/01/2020 |
9 | 30 | 06/01/2020 |
CHANGEITEM TABLE:
changegroupid | field | newvalue |
1 | ONE | 1 |
1 | TWO | A |
1 | THREE | Z |
2 | ONE | J |
2 | ONE | K |
2 | ONE | L |
3 | THREE | K |
3 | ONE | 2 |
3 | ONE | 1 | <--
4 | ONE | 1A |
5 | ONE | 1B |
6 | ONE | 1C | <--
7 | ONE | 1D |
8 | ONE | 1E |
9 | ONE | 1F | <--
EXPECTED RESULT:
issueid | updated | newvalue
10 | 03/01/2020 | 1
20 | 07/01/2020 | 1C
30 | 06/01/2020 | 1F
So each change to an issue item creates 1 change group record with the date the change was made, which can then contain 1 or more change item records.
Each change item shows the field name that was changed and the new value.
I then need to link those tables together to get each issue, the latest value of the field name called 'ONE', and ideally the date of the latest change.
These tables are from Jira, for those familiar with that table structure.
I've been trying to get this to work for a while now, so far I've got this query:
SELECT issuenum, MIN(created) AS updated FROM
(
SELECT ISSUE.IssueId, UpdGrp.Created as Created, UpdItm.NEWVALUE
FROM ISSUE
JOIN ChangeGroup UpdGrp ON (UpdGrp.IssueID = CR.ID)
JOIN CHANGEITEM UpdItm ON (UpdGrp.ID = UpdItm.groupid)
WHERE UPPER(UpdItm.FIELD) = UPPER('ONE')
) AS dummy
GROUP BY issuenum
ORDER BY issuenum
This returns the first 2 columns I'm looking for but I'm struggling to work out how to return the final column as when I include that in the first line I get an error saying "Column is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause."
I've done a search on here and can't find anything that exactly matches my requirements.
Use window functions:
SELECT i.*
FROM (SELECT i.IssueId, cg.Created as Created, ui.NEWVALUE,
ROW_NUMBER() OVER (PARTITION BY i.IssueId ORDER BY cg.Created DESC) as seqnum
FROM ISSUE i JOIN
ChangeGroup cg
ON cg.IssueID = CR.ID JOIN
CHANGEITEM ci
ON cg.ID = ci.groupid
WHERE UPPER(UpdItm.FIELD) = UPPER('ONE')
) i
WHERE seqnum = 1
ORDER BY issueid;

SQL group column where other column is equal

I'm trying to select some information from a database.
I get a database with columns like:
Ident,Name,Length,Width,Quantity,Planned
Table data is as follow
+-----------+-----------+---------+---------+------------+---------+
| Ident | Name | Length | Width | Quantity | Planned |
+-----------+-----------+---------+---------+------------+---------+
| 12345 | Name1 | 1500 | 1000 | 20 | 5 |
| 23456 | Name1 | 1500 | 1000 | 30 | 13 |
| 34567 | Name1 | 2500 | 1000 | 10 | 2 |
| 45678 | Name1 | 2500 | 1000 | 10 | 4 |
| 56789 | Name1 | 1500 | 1200 | 20 | 3 |
+-----------+-----------+---------+---------+------------+---------+
my desired result, would be to group rows where "Name,Length and Width" are equal, sum the "Quantity" and reduce it by the sum of "Planned"
e.g:
- Name1,1500,1000,32 --- (32 because (20+30)-(5+13))
- Name1,2500,1000,14 --- (14 because (10+10)-(2+4)))
- Name1,1500,1200,17
now I got problems how to group or join these information to get the wished select. may be some you of can help me.. if further information's required, please write it in comment.
You can achieve it by grouping your table and subtract sums of Quantity and Planned.
select
Name
,Length
,Width
,sum(Quantity) - sum(Planned)
from yourTable
group by Name,Length,Width
select
A1.Name,A1.Length,A1.Width,((A1.Quantity + A2.Quantity) -(A1.Planned+A2.Planned))
from `Table` AS A1, `Table` AS A2
where A1.Name = A2.Name and A1.Length = A2.Length and A1.Width = A2.Width
group by (whatever)
So you are comparing these columns form the same table?

SQL: Get an aggregate (SUM) of a calculation of two fields (DATEDIFF) that has conditional logic (CASE WHEN)

I have a dataset that includes a bunch of stay data (at a hotel). Each row contains a start date and an end date, but no duration field. I need to get a sum of the durations.
Sample Data:
| Stay ID | Client ID | Start Date | End Date |
| 1 | 38 | 01/01/2018 | 01/31/2019 |
| 2 | 16 | 01/03/2019 | 01/07/2019 |
| 3 | 27 | 01/10/2019 | 01/12/2019 |
| 4 | 27 | 05/15/2019 | NULL |
| 5 | 38 | 05/17/2019 | NULL |
There are some added complications:
I am using Crystal Reports and this is a SQL Expression, which obeys slightly different rules. Basically, it returns a single scalar value. Here is some more info: http://www.cogniza.com/wordpress/2005/11/07/crystal-reports-using-sql-expression-fields/
Sometimes, the end date field is blank (they haven't booked out yet). If blank, I would like to replace it with the current timestamp.
I only want to count nights that have occurred in the past year. If the start date of a given stay is more than a year ago, I need to adjust it.
I need to get a sum by Client ID
I'm not actually any good at SQL so all I have is guesswork.
The proper syntax for a Crystal Reports SQL Expression is something like this:
(
SELECT (CASE
WHEN StayDateStart < DATEADD(year,-1,CURRENT_TIMESTAMP) THEN DATEDIFF(day,DATEADD(year,-1,CURRENT_TIMESTAMP),ISNULL(StayDateEnd,CURRENT_TIMESTAMP))
ELSE DATEDIFF(day,StayDateStart,ISNULL(StayDateEnd,CURRENT_TIMESTAMP))
END)
)
And that's giving me the correct value for a single row, if I wanted to do this:
| Stay ID | Client ID | Start Date | End Date | Duration |
| 1 | 38 | 01/01/2018 | 01/31/2019 | 210 | // only days since June 4 2018 are counted
| 2 | 16 | 01/03/2019 | 01/07/2019 | 4 |
| 3 | 27 | 01/10/2019 | 01/12/2019 | 2 |
| 4 | 27 | 05/15/2019 | NULL | 21 |
| 5 | 38 | 05/17/2019 | NULL | 19 |
But I want to get the SUM of Duration per client, so I want this:
| Stay ID | Client ID | Start Date | End Date | Duration |
| 1 | 38 | 01/01/2018 | 01/31/2019 | 229 | // 210+19
| 2 | 16 | 01/03/2019 | 01/07/2019 | 4 |
| 3 | 27 | 01/10/2019 | 01/12/2019 | 23 | // 2+21
| 4 | 27 | 05/15/2019 | NULL | 23 |
| 5 | 38 | 05/17/2019 | NULL | 229 |
I've tried to just wrap a SUM() around my CASE but that doesn't work:
(
SELECT SUM(CASE
WHEN StayDateStart < DATEADD(year,-1,CURRENT_TIMESTAMP) THEN DATEDIFF(day,DATEADD(year,-1,CURRENT_TIMESTAMP),ISNULL(StayDateEnd,CURRENT_TIMESTAMP))
ELSE DATEDIFF(day,StayDateStart,ISNULL(StayDateEnd,CURRENT_TIMESTAMP))
END)
)
It gives me an error that the StayDateEnd is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause. But I don't even know what that means, so I'm not sure how to troubleshoot, or where to go from here. And then the next step is to get the SUM by Client ID.
Any help would be greatly appreciated!
Although the explanation and data set are almost impossible to match, I think this is an approximation to what you want.
declare #your_data table (StayId int, ClientId int, StartDate date, EndDate date)
insert into #your_data values
(1,38,'2018-01-01','2019-01-31'),
(2,16,'2019-01-03','2019-01-07'),
(3,27,'2019-01-10','2019-01-12'),
(4,27,'2019-05-15',NULL),
(5,38,'2019-05-17',NULL)
;with data as (
select *,
datediff(day,
case
when datediff(day,StartDate,getdate())>365 then dateadd(year,-1,getdate())
else StartDate
end,
isnull(EndDate,getdate())
) days
from #your_data
)
select *,
sum(days) over (partition by ClientId)
from data
https://rextester.com/HCKOR53440
You need a subquery for sum based on group by client_id and a join between you table the subquery eg:
select Stay_id, client_id, Start_date, End_date, t.sum_duration
from your_table
inner join (
select Client_id,
SUM(CASE
WHEN StayDateStart < DATEADD(year,-1,CURRENT_TIMESTAMP) THEN DATEDIFF(day,DATEADD(year,-1,CURRENT_TIMESTAMP),ISNULL(StayDateEnd,CURRENT_TIMESTAMP))
ELSE DATEDIFF(day,StayDateStart,ISNULL(StayDateEnd,CURRENT_TIMESTAMP))
END) sum_duration
from your_table
group by Client_id
) t on t.Client_id = your_table.client_id

SQL Combine two tables with two parameters

I searched forum for 1h and didn't find nothing similar.
I have this problem: I want to compare two colums ID and DATE if they are the same in both tables i want to put number from table 2 next to it. But if it is not the same i want to fill yearly quota on the date. I am working in Access.
table1
id|date|state_on_date
1|30.12.2013|23
1|31.12.2013|25
1|1.1.2014|35
1|2.1.2014|12
2|30.12.2013|34
2|31.12.2013|65
2|1.1.2014|43
table2
id|date|year_quantity
1|31.12.2013|100
1|31.12.2014|150
2|31.12.2013|200
2|31.12.2014|300
I want to get:
table 3
id|date|state_on_date|year_quantity
1|30.12.2013|23|100
1|31.12.2013|25|100
1|1.1.2014|35|150
1|2.1.2014|12|150
2|30.12.2013|34|200
2|31.12.2013|65|200
2|1.1.2014|43|300
I tried joins and reading forums but didn't find solution.
Are you looking for this?
SELECT id, date, state_on_date,
(
SELECT TOP 1 year_quantity
FROM table2
WHERE id = t.id
AND date >= t.date
ORDER BY date
) AS year_quantity
FROM table1 t
Output:
| ID | DATE | STATE_ON_DATE | YEAR_QUANTITY |
|----|------------|---------------|---------------|
| 1 | 2013-12-30 | 23 | 100 |
| 1 | 2013-12-31 | 25 | 100 |
| 1 | 2014-01-01 | 35 | 150 |
| 1 | 2014-01-02 | 12 | 150 |
| 2 | 2013-12-30 | 34 | 200 |
| 2 | 2013-12-31 | 65 | 200 |
| 2 | 2014-01-01 | 43 | 300 |
Here is SQLFiddle demo It's for SQL Server but should work just fine in MS Accesss.

SQL query to get the same set of results

This should be a simple one, but say I have a table with data like this:
| ID | Date | Value |
| 1 | 01/01/2013 | 40 |
| 2 | 03/01/2013 | 20 |
| 3 | 10/01/2013 | 30 |
| 4 | 14/02/2013 | 60 |
| 5 | 15/03/2013 | 10 |
| 6 | 27/03/2013 | 70 |
| 7 | 01/04/2013 | 60 |
| 8 | 01/06/2013 | 20 |
What I want is the sum of values per week of the year, showing ALL weeks.. (for use in an excel graph)
What my query gives me, is only the weeks that are actually in the database.
With SQL you cannot return rows that don't exist in some table. To get the effect you want you could create a table called WeeksInYear with only one field WeekNumber that is an Int. Populate the table with all the week numbers. Then JOIN that table to this one.
The query would then look something like the following:
SELECT w.WeekNumber, SUM(m.Value)
FROM MyTable as m
RIGHT OUTER JOIN WeeksInYear AS w
ON DATEPART(wk, m.date) = w.WeekNumber
GROUP BY w.WeekNumber
The missing weeks will not have any data in MyTable and show a 0.