How to arrange the columns of an SQL pivot table in ascending order - sql

Question

Can someone help me in arranging the columns in ascending order.
My output of pivot table is like:
Ref role_name offer_id 10000 104000 8000 8400
43132_43282 Call Center 1 1 0 0 6
43132_43282 Others 1 2 0 0 3
Instead I want it to be like:
Ref role_name offer_id 8000 8400 10000 104000
43132_43282 Call Center 1 0 6 1 0
43132_43282 Others 1 0 3 2 0
DECLARE #cols AS NVARCHAR(MAX), -- for pivot
#cols2 AS NVARCHAR(MAX), -- for select
#query AS NVARCHAR(MAX);
SET #cols = STUFF((
SELECT DISTINCT ',' + QUOTENAME(c.[Offer_cover])
FROM #cover2 c
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
-- this is for the SELECT
SET #cols2 = STUFF((
SELECT DISTINCT ',' + 'ISNULL(' + QUOTENAME(c.[Offer_cover]) + ', 0) ' + QUOTENAME(c.[Offer_cover])
FROM #cover2 c
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
SET #query = 'SELECT Ref,role_name,offer_id, ' + #cols2 + ' from
(
select *
from #cover2
) x
pivot
(
SUM(cover_earning_Count)
for [Offer_cover] in (' + #cols + ')
) p'
EXECUTE (#query)

Answer 1

Can you add the GROUP BY, ORDER BY [Offer_cover] in the #cols2 variable selection and remove the DISTINCT.
So the query will be:
SET #cols2 = STUFF((
SELECT ',' + 'ISNULL(' + QUOTENAME(c.[Offer_cover]) + ', 0) ' + QUOTENAME(c.[Offer_cover])
FROM #cover2 c
GROUP BY c.[Offer_cover] -- changes here
ORDER BY c.[Offer_cover] -- changes here
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
it will return the #cols2 in the ascending order, so it will impact in the final result.