Parent count based on pairing of multiple children - sql

Question

In the below example, I'm trying to count the number of drinks I can make based on the availability of ingredients per bar location that I have.
To further clarify, as seen in the below example: based on the figures highlighted in the chart below; I know that I can only make 1 Margarita on 6/30/2018 (in either DC or FL if I ship the supplies to the location).
Sample of data table
Please use the below code to enter the relevant data above:
CREATE TABLE #drinks
(
a_date DATE,
loc NVARCHAR(2),
parent NVARCHAR(20),
line_num INT,
child NVARCHAR(20),
avail_amt INT
);
INSERT INTO #drinks VALUES ('6/26/2018','CA','Long Island','1','Vodka','7');
INSERT INTO #drinks VALUES ('6/27/2018','CA','Long Island','2','Gin','5');
INSERT INTO #drinks VALUES ('6/28/2018','CA','Long Island','3','Rum','26');
INSERT INTO #drinks VALUES ('6/26/2018','DC','Long Island','1','Vodka','15');
INSERT INTO #drinks VALUES ('6/27/2018','DC','Long Island','2','Gin','18');
INSERT INTO #drinks VALUES ('6/28/2018','DC','Long Island','3','Rum','5');
INSERT INTO #drinks VALUES ('6/26/2018','FL','Long Island','1','Vodka','34');
INSERT INTO #drinks VALUES ('6/27/2018','FL','Long Island','2','Gin','14');
INSERT INTO #drinks VALUES ('6/28/2018','FL','Long Island','3','Rum','4');
INSERT INTO #drinks VALUES ('6/30/2018','DC','Margarita','1','Tequila','6');
INSERT INTO #drinks VALUES ('7/1/2018','DC','Margarita','2','Triple Sec','3');
INSERT INTO #drinks VALUES ('6/29/2018','FL','Margarita','1','Tequila','1');
INSERT INTO #drinks VALUES ('6/30/2018','FL','Margarita','2','Triple Sec','0');
INSERT INTO #drinks VALUES ('7/2/2018','CA','Cuba Libre','1','Rum','1');
INSERT INTO #drinks VALUES ('7/8/2018','CA','Cuba Libre','2','Coke','5');
INSERT INTO #drinks VALUES ('7/13/2018','CA','Cuba Libre','3','Lime','14');
INSERT INTO #drinks VALUES ('7/5/2018','DC','Cuba Libre','1','Rum','0');
INSERT INTO #drinks VALUES ('7/19/2018','DC','Cuba Libre','2','Coke','12');
INSERT INTO #drinks VALUES ('7/31/2018','DC','Cuba Libre','3','Lime','9');
INSERT INTO #drinks VALUES ('7/2/2018','FL','Cuba Libre','1','Rum','1');
INSERT INTO #drinks VALUES ('7/19/2018','FL','Cuba Libre','2','Coke','3');
INSERT INTO #drinks VALUES ('7/17/2018','FL','Cuba Libre','3','Lime','2');
INSERT INTO #drinks VALUES ('6/30/2018','DC','Long Island','3','Rum','4');
INSERT INTO #drinks VALUES ('7/7/2018','FL','Cosmopolitan','5','Triple Sec','7');
The expected results are as follows:
Please note, as seen in the expected results, children are interchangeable. For example, on 7/7/2018 Triple Sec arrived for the drink cosmopolitan; however because the child is also rum, it changes the availability of Margaritas for FL.
Also not the update to the DC region for Cuba Libre's on both 06/30 and 06/31.
Please take into consideration that parts are interchangeable and also that each time a new item arrives it makes available any item previously now.
Lastly - It would be awesome if I could add another column that shows kit availability regardless of location based only on availability of the child. For Ex. If there is a child #3 in DC and none in FL they FL can assume that they have enough inventory to make drink based on inventory in another location!

Answer 1

I've created a couple of extra tables to help with writing the query, but these could be generated from the #drinks table if you wanted:
CREATE TABLE #recipes
(
parent NVARCHAR(20),
child NVARCHAR(20)
);
INSERT INTO #recipes VALUES ('Long Island', 'Vodka');
INSERT INTO #recipes VALUES ('Long Island', 'Gin');
INSERT INTO #recipes VALUES ('Long Island', 'Rum');
INSERT INTO #recipes VALUES ('Maragrita', 'Tequila');
INSERT INTO #recipes VALUES ('Maragrita', 'Triple Sec');
INSERT INTO #recipes VALUES ('Cuba Libre', 'Coke');
INSERT INTO #recipes VALUES ('Cuba Libre', 'Rum');
INSERT INTO #recipes VALUES ('Cuba Libre', 'Lime');
INSERT INTO #recipes VALUES ('Cosmopolitan', 'Cranberry Juice');
INSERT INTO #recipes VALUES ('Cosmopolitan', 'Triple Sec');
CREATE TABLE #locations
(
loc NVARCHAR(20)
);
INSERT INTO #locations VALUES ('CA');
INSERT INTO #locations VALUES ('FL');
INSERT INTO #locations VALUES ('DC');
The query then becomes:
DECLARE #StartDateTime DATETIME
DECLARE #EndDateTime DATETIME
SET #StartDateTime = '2018-06-26'
SET #EndDateTime = '2018-07-31';
--First, build a range of dates that the report has to run for
WITH DateRange(a_date) AS
(
SELECT #StartDateTime AS DATE
UNION ALL
SELECT DATEADD(d, 1, a_date)
FROM DateRange
WHERE a_date < #EndDateTime
)
SELECT a_date, parent, loc, avail_amt
FROM (--available_recipes_inventory
SELECT a_date, parent, loc, avail_amt,
LAG(avail_amt, 1, 0) OVER (PARTITION BY loc, parent ORDER BY a_date) AS previous_avail_amt
FROM (--recipes_inventory
SELECT a_date, parent, loc,
--The least amount of the ingredients for a recipe is the most
--amount of drinks we can make for it
MIN(avail_amt) as avail_amt
FROM (--ingredients_inventory
SELECT dr.a_date, r.parent, r.child, l.loc,
--Default ingredients we don't have with a zero amount
ISNULL(d.avail_amt, 0) as avail_amt
FROM DateRange dr CROSS JOIN
#recipes r CROSS JOIN
#locations l OUTER APPLY
(
--Find the total amount available for each
--ingredient at each location for each date
SELECT SUM(d1.avail_amt) as avail_amt
FROM #drinks d1
WHERE d1.a_date <= dr.a_date
AND d1.loc = l.loc
AND d1.child = r.child
) d
) AS ingredients_inventory
GROUP BY a_date, parent, loc
) AS recipes_inventory
--Remove all recipes that we don't have enough ingredients for
WHERE avail_amt > 0
) AS available_recipes_inventory
--Selects the first time a recipe has enough ingredients to be made
WHERE previous_avail_amt = 0
--Selects when the amount of ingredients has changed
OR previous_avail_amt != avail_amt
ORDER BY a_date
--MAXRECURSION needed to generate the date range
OPTION (MAXRECURSION 0)
GO
The innermost SELECT creates a pseudo inventory table (ingredients_inventory) consisting of location, ingredient, date and amount available. When an ingredient is not available at a location for a particular date, then a zero is used.
The next SELECT query out finds how many of each recipe can be made for each location/date (again this may be zero).
The next SELECT query out is an intermediate table necessary to gather how many of each recipe for each location could be made for the previous day (whilst also removing any drinks that could not be made).
And finally, the outermost SELECT query uses the previous day's data to find when the quantity of each particular recipe that can be made has changed.
This query produces slightly different numbers to your table, but I think that's because yours is wrong? Taking Florida for example, an extra Rum comes in on 2nd July, so the number of Long Islands that can be made goes up to 5. And 2 Cuba Libres can be made by the 19th.
Results:
+------------+-------------+-----+-----------+
| a_date | parent | loc | avail_amt |
+------------+-------------+-----+-----------+
| 2018-06-28 | Long Island | DC | 5 |
| 2018-06-28 | Long Island | CA | 5 |
| 2018-06-28 | Long Island | FL | 4 |
| 2018-06-30 | Long Island | DC | 9 |
| 2018-07-01 | Maragrita | DC | 3 |
| 2018-07-02 | Long Island | FL | 5 |
| 2018-07-07 | Maragrita | FL | 1 |
| 2018-07-13 | Cuba Libre | CA | 5 |
| 2018-07-19 | Cuba Libre | FL | 2 |
| 2018-07-31 | Cuba Libre | DC | 9 |
+------------+-------------+-----+-----------+

Answer 2

I think this would give the required result.
Created a function that'll get the inventory.
Create function GetInventoryByDateAndLocation
(#date DATE, #Loc NVARCHAR(2))
RETURNS TABLE
AS
RETURN
(
Select child,avail_amt from
(Select a_date, child,avail_amt,
ROW_NUMBER() over (partition by child order by a_date desc) as ranking
from drinks where loc = #Loc and a_date<=#date)c
where ranking = 1
)
Then the query:
with parentChild as
(Select distinct parent, line_num, child from drinks),
ParentChildNo as
(Select parent, max(line_num) as ChildNo from parentChild group by parent)
,Inventory as
(Select a_date,loc,s.* from drinks d cross apply
GetInventoryByDateAndLocation(d.a_date, d.loc)s)
, Available as
(Select a_date,parent,loc,count(*) as childAvailable,min(avail_amt) as quantity
from Inventory i
join parentChild c
on i.child = c.child
group by parent,loc,a_date)
Select a_date,a.parent,loc,quantity from available a
join ParentChildNo pc
on a.parent = pc.parent and a.childAvailable = pc.ChildNo
where quantity > 0 order by 1
This would give all the drinks which can be made from the inventory. Hope it solves your issue.
These are just my 2 cents. There are better ways of doing this and I hope more people would read this and suggest better.

Answer 3

don't think this is exactly what your looking for... maybe it will help.
SELECT DISTINCT #drinks.loc,#drinks.parent,avail.Avail
FROM #drinks
LEFT OUTER JOIN (
SELECT DISTINCT #drinks.parent, MIN(availnow.maxavailnow / line_num)
OVER(PARTITION BY parent) as Avail
FROM #drinks
LEFT OUTER JOIN (
SELECT #drinks.child,SUM(avail_amt) maxavailnow
FROM #drinks
LEFT OUTER JOIN (SELECT MAX(a_date) date,loc,child FROM #drinks GROUP BY loc,child) maxx ON #drinks.loc = maxx.loc AND #drinks.child = maxx.child AND maxx.date = #drinks.a_date
GROUP BY #drinks.child
) availnow ON #drinks.child = availnow.child
) avail ON avail.parent = #drinks.parent

Answer 4

SELECT ( SELECT MAX(d2.a_date)
FROM #drinks AS d2
WHERE d2.parent = d.parent
AND d2.loc = d.loc) AS a_date
,d.loc
,d.parent
,SUM(d.avail_amt) AS [avail_amt(SUM)]
,COUNT(d.avail_amt) AS [avail_amt(COUNT)]
FROM #drinks AS d
GROUP BY d.loc
,d.parent
ORDER BY a_date