Convert Date to Float looses two days - sql

Good morning
I have an interesting situation:
1 June 2018 = 43252 as Integer
30 May 2018 = 43250 as Integer
I try to convert a date to the first of the respective month (reporting month) with the following code:
DECLARE #InputDate DateTime, #Result Float, #Date DateTime
Set #InputDate = '2018/06/18 23:13:05'
If isDate(#InputDate) = 0
BEGIN
Set #Result = 0
END
ELSE
BEGIN
Set #Date = DATEFROMPARTS(Year(#InputDate), Month(#InputDate), 1)
Set #Result = cast (cast(#Date as datetime) as float)
Select #Date, #Result
END
The result for #Date is '2018-06-01 00:00:00.000' as expected but the result for #Result = 43250 which is 30 May 2018. How does this happen?

Related

SQL returning invalid results when comparing against 2 date ranges

As mentioned in the subject line, SQL is returning results which are not within the specific date range, here is my SQL snipped below:
DECLARE #StartDate DATETIME
,#EndDate DATETIME
SET #StartDate = '2017-03-04 00:50:00.000'
SET #EndDate = '2017-03-05 01:30:00.000
SELECT * FROM table (NOLOCK) WHERE CreatedOn BETWEEN #StartDate AND #EndDate
Partial Results
CreatedOn
2017-03-04 04:59:57.010
2017-03-04 17:39:50.460
2017-03-04 05:28:22.610
2017-03-04 20:54:39.257
2017-03-04 17:33:19.107
Try below query and also check your CreatedOn data type as DATETIME OR
VARCHAR
DECLARE #StartDate DATETIME,#EndDate DATETIME
SET #StartDate = '2017-03-04 00:50:00.000'
SET #EndDate = '2017-03-05 01:30:00.000
SELECT * FROM table (NOLOCK)
WHERE DATEDIFF(DAY,CreatedOn,#StartDate) <= 0 AND
DATEDIFF(DAY,CreatedOn,#EndDate) >= 0
As others said, there is no way you get different results for the given CreatedOn test data. You need to post actual results vs expected results if you still have problem.
Here is the script I tested and it always prints Yes (as the date is in range)
SET NOCOUNT ON
DECLARE #StartDate DATETIME = '2017-03-04 00:50:00.000',
#EndDate DATETIME = '2017-03-05 01:30:00.000'
DECLARE #CreatedOn TABLE
(
id INT IDENTITY,
CreatedOn DATETIME
)
INSERT #CreatedOn (CreatedOn)
VALUES ('2017-03-04 04:59:57.010'),
('2017-03-04 17:39:50.460'),
('2017-03-04 05:28:22.610'),
('2017-03-04 20:54:39.257'),
('2017-03-04 17:33:19.107'),
DECLARE #index INT = (SELECT COUNT(1) FROM #CreatedOn)
DECLARE #testDate DATETIME
WHILE #index >= 1
BEGIN
SELECT
#testDate = CreatedOn
FROM #CreatedOn
WHERE id = #index
IF #testDate BETWEEN #StartDate AND #EndDate
PRINT CAST(#testDate AS VARCHAR) + ' Yes'
ELSE
PRINT CAST(#testDate AS VARCHAR) + ' No'
SET #index = #index - 1
END
However the DateTime values are region dependent. If you are having the CreatedOn variable/field values in YYYYMMDD or YYYY-MM-DD format, they are language independent.
You might only get different results if you are using a different format. For example if you are trying to validate the date range for '04.03.2017 18:00', it will fail as it will be interpreted as March 4th 2017 in English regional settings.
Here is a small test script.
SET LANGUAGE 'German'
DECLARE #testDateRegion DATETIME = '04.03.2017 15:24'
PRINT CAST(#testDateRegion AS VARCHAR)
GO
SET LANGUAGE 'English'
DECLARE #testDateRegion DATETIME = '04.03.2017 15:24'
PRINT CAST(#testDateRegion AS VARCHAR)
and the output is,
Die Spracheneinstellung wurde auf Deutsch geändert.
Mär 4 2017 3:24PM
Changed language setting to us_english.
Apr 3 2017 3:24PM

Conversion failed when converting date and/or time from character string calculate days

I need to calculate the totaldays in this store procedure, but I keep getting the conversion error:
DECLARE #ifIsMarch varchar(6), #addOneDay date, #startDay int,
#disconnectDay int, #startMonth int, #disconnectMonth int, #startYear
int, #disconnectYear int, #totaldays int
SELECT #startDay = DAY('2014-02-28')
SELECT #disconnectDay = DAY('2014-10-31')
SELECT #startMonth = MONTH('2014-02-28')
SELECT #disconnectMonth = MONTH('2014-10-31')
SELECT #startYear = YEAR('2014-02-28')
SELECT #disconnectYear = YEAR('2014-10-31')
print #startDay
print #disconnectDay
print #startMonth
print #disconnectMonth
print #startYear
print #disconnectYear
SELECT #addOneDay = DATEADD(DAY, 1, CONVERT(DATE, '2014-02-28'))
SELECT #ifIsMarch = LEFT(CONVERT(VARCHAR(15), #addOneDay, 110), 5)
print #addOneDay
Print #ifIsMarch
select #totaldays =
CASE
WHEN #ifIsMarch = '03-01' THEN
CASE
WHEN #DisconnectDate = '31' THEN (360*(#disconnectYear - #startYear)) + (30*(#disconnectMonth - #startMonth))
ELSE (360*(#disconnectYear - #startYear)) + (30*(#disconnectMonth - #startMonth)) + (#disconnectDay - 30)
END
END
print #totaldays
when i get conversion error with datetime, i usually change positions of month number with day number and it begins to work
to get difference between two dates i would suggest to use DATEDIFF
declare #startDate datetime = '20140228'
declare #disconnectDate datetime = '20141031'
SELECT datediff(day, #startDate, #disconnectdate)
if you have dates with -
declare #startDate datetime = convert(datetime, '2014-02-28', 21)
declare #disconnectDate datetime = convert(datetime, '2014-10-31', 21)
SELECT datediff(day, #startDate, #disconnectdate)

Calculating due date using business hours and holidays

I need to calculate due date / end date for SLAs. As input values I have the start date and a timespan (in minutes). This calculation needs to take into account business hours, weekends, and holidays.
I've seen a lot of examples where the input is start date and end date, but have been struggling finding anything similar to the above input values.
Is there an elegant solution to this problem? Is there a way to calculate due date without using a loop? I can't think of a way to do the calculation without doing something similar to the following terrible algorithm:
Create a return variable "due date" and set it to input variable
"start date"
Create a control variable "used minutes" and set it to 0
Create a loop with the condition "used minutes" <= "input timespan"
Inside the loop, add a second to the "due date" return variable
Inside the loop, check if the second is within hours of operation
(checking business hours, weekends, and holidays). If so, increment
control variable "used minutes" by 1.
Upon exiting the loop, return variable "due date"
You need a table with valid business hours, with the weekends and holidays excluded (or marked as weekend/holiday so you can skip them.) Each row represents one day and the number of working hours for that day. Then you query the business hours table from your start date to the first (min) date where the sum(hours*60) is greater than your minutes parameter, excluding marked weekend/holiday rows. That gives you your end date.
Here's the day table:
CREATE TABLE [dbo].[tblDay](
[dt] [datetime] NOT NULL,
[dayOfWk] [int] NULL,
[dayOfWkInMo] [int] NULL,
[isWeekend] [bit] NOT NULL,
[holidayID] [int] NULL,
[workingDayCount] [int] NULL,
CONSTRAINT [PK_tblDay] PRIMARY KEY CLUSTERED
(
[dt] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
here's how I populate the table with days:
CREATE PROCEDURE [dbo].[usp_tblDay]
AS
BEGIN
SET NOCOUNT ON;
DECLARE
#Dt datetime ,
#wkInMo int,
#firstDwOfMo int,
#holID int,
#workDayCount int,
#weekday int,
#month int,
#day int,
#isWkEnd bit
set #workDayCount = 0
SET #Dt = CONVERT( datetime, '2008-01-01' )
while #dt < '2020-01-01'
begin
delete from tblDay where dt = #dt
set #weekday = datepart( weekday, #Dt )
set #month = datepart(month,#dt)
set #day = datepart(day,#dt)
if #day = 1 -- 1st of mo
begin
set #wkInMo = 1
set #firstDwOfMo = #weekday
end
if ((#weekday = 7) or (#weekday = 1))
set #isWkEnd = 1
else
set #isWkEnd = 0
if #isWkEnd = 0 and (#month = 1 and #day = 1)
set #holID=1 -- new years on workday
else if #weekday= 6 and (#month = 12 and #day = 31)
set #holID=1 -- holiday on sat, change to fri
else if #weekday= 2 and (#month = 1 and #day = 2)
set #holID=1 -- holiday on sun, change to mon
else if #wkInMo = 3 and #weekday= 2 and #month = 1
set #holID = 2 -- mlk
else if #wkInMo = 3 and #weekday= 2 and #month = 2
set #holID = 3 -- President’s
else if #wkInMo = 4 and #weekday= 2 and #month = 5 and datepart(month,#dt+7) = 6
set #holID = 4 -- memorial on 4th mon, no 5th
else if #wkInMo = 5 and #weekday= 2 and #month = 5
set #holID = 4 -- memorial on 5th mon
else if #isWkEnd = 0 and (#month = 7 and #day = 4)
set #holID=5 -- July 4 on workday
else if #weekday= 6 and (#month = 7 and #day = 3)
set #holID=5 -- holiday on sat, change to fri
else if #weekday= 2 and (#month = 7 and #day = 5)
set #holID=5 -- holiday on sun, change to mon
else if #wkInMo = 1 and #weekday= 2 and #month = 9
set #holID = 6 -- Labor
else if #isWkEnd = 0 and (#month = 11 and #day = 11)
set #holID=7 -- Vets day on workday
else if #weekday= 6 and (#month = 11 and #day = 10)
set #holID=7 -- holiday on sat, change to fri
else if #weekday= 2 and (#month = 11 and #day = 12)
set #holID=7 -- holiday on sun, change to mon
else if #wkInMo = 4 and #weekday= 5 and #month = 11
set #holID = 8 -- thx
else if #holID = 8
set #holID = 9 -- dy after thx
else if #isWkEnd = 0 and (#month = 12 and #day = 25)
set #holID=10 -- xmas day on workday
else if #weekday= 6 and (#month = 12 and #day = 24)
set #holID=10 -- holiday on sat, change to fri
else if #weekday= 2 and (#month = 12 and #day = 26)
set #holID=10 -- holiday on sun, change to mon
else
set #holID = null
insert into tblDay select #dt,#weekday,#wkInMo,#isWkEnd,#holID,#workDayCount
if #isWkEnd=0 and #holID is null
set #workDayCount = #workDayCount + 1
set #dt = #dt + 1
if datepart( weekday, #Dt ) = #firstDwOfMo
set #wkInMo = #wkInMo + 1
end
END
I also have a holiday table, but everyone's holidays are different:
holidayID holiday rule description
1 New Year's Day Jan. 1
2 Martin Luther King Day third Mon. in Jan.
3 Presidents' Day third Mon. in Feb.
4 Memorial Day last Mon. in May
5 Independence Day 4-Jul
6 Labor Day first Mon. in Sept
7 Veterans' Day Nov. 11
8 Thanksgiving fourth Thurs. in Nov.
9 Fri after Thanksgiving Friday after Thanksgiving
10 Christmas Day Dec. 25
HTH
This is the best I could do, still uses a loop but uses date functions instead of incrementing a minutes variable. Hope you like it.
--set up our source data
declare #business_hours table
(
work_day varchar(10),
open_time varchar(8),
close_time varchar(8)
)
insert into #business_hours values ('Monday', '08:30:00', '17:00:00')
insert into #business_hours values ('Tuesday', '08:30:00', '17:00:00')
insert into #business_hours values ('Wednesday', '08:30:00', '17:00:00')
insert into #business_hours values ('Thursday', '08:30:00', '17:00:00')
insert into #business_hours values ('Friday', '08:30:00', '18:00:00')
insert into #business_hours values ('Saturday', '09:00:00', '14:00:00')
declare #holidays table
(
holiday varchar(10)
)
insert into #holidays values ('2015-01-01')
insert into #holidays values ('2015-01-02')
--Im going to assume the SLA of 2 standard business days (0900-1700) = 8*60*2 = 960
declare #start_date datetime = '2014-12-31 16:12:47'
declare #time_span int = 960-- time till due in minutes
declare #true bit = 'true'
declare #false bit = 'false'
declare #due_date datetime --our output
--other variables
declare #date_string varchar(10)
declare #today_closing datetime
declare #is_workday bit = #true
declare #is_holiday bit = #false
--Given our timespan is in minutes, lets also assume we dont care about seconds in start or due dates
set #start_date = DATEADD(ss,datepart(ss,#start_date)*-1,#start_date)
while (#time_span > 0)
begin
set #due_date = DATEADD(MINUTE,#time_span,#start_date)
set #date_string = FORMAT(DATEADD(dd, 0, DATEDIFF(dd, 0, #start_date)),'yyyy-MM-dd')
set #today_closing = (select convert(datetime,#date_string + ' ' + close_time) from #business_hours where work_day = DATENAME(weekday,#start_date))
if exists((select work_day from #business_hours where work_day = DATENAME(weekday,#start_date)))
set #is_workday = #true
else
set #is_workday = #false
if exists(select holiday from #holidays where holiday = #date_string)
set #is_holiday = #true
else
set #is_holiday = #false
if #is_workday = #true and #is_holiday = #false
begin
if #due_date > #today_closing
set #time_span = #time_span - datediff(MINUTE, #start_date, #today_closing)
else
set #time_span = #time_span - datediff(minute, #start_date, #due_date)
end
set #date_string = FORMAT(DATEADD(dd, 1, DATEDIFF(dd, 0, #start_date)),'yyyy-MM-dd')
set #start_date = CONVERT(datetime, #date_string + ' ' + isnull((select open_time from #business_hours where work_day = DATENAME(weekday,convert(datetime,#date_string))),''))
end
select #due_date
Sql to Calculate due date excluding holidays and considering business hour as below :- < note : - It's working correctly Business hour (8-5) Maintain holiday table
CREATE TABLE [dbo].[holiday](
[id] [int] IDENTITY(1,1) NOT NULL,
[region] [nvarchar](10) NULL,
[Hdate] [date] NULL,
)
>
declare #start datetime= getdate()
declare #slamins int =960 --- SLA time in mins
declare #Country varchar(2)='NA'
declare #start_hour int = 8 -- business start hour
declare #end_hour int = 17 -- business end hour
declare #true bit = 'true'
declare #false bit = 'false'
declare #is_workday bit = #true
declare #is_holiday bit = #false
declare #due_date datetime
declare #today_closing datetime
declare #temp int = 0
declare #holidays table (HDate DateTime) -- Table variable to hold holidayes
---- Get country holidays from table based on the country code (Feel free to remove this or modify as per your DB schema)
Insert Into #Holidays (HDate) Select date from HOLIDAY Where region=#Country and Hdate>=DateAdd(dd, DateDiff(dd,0,#start), 0)
--check for weekends
set #start = case(datepart(dw,#start)+##datefirst-1)%7
when 0 then Convert(dateTime,CONVERT(varchar,#start+1,101)+' 08:00:00')
when 6 then Convert(dateTime,CONVERT(varchar,#start+2,101)+' 08:00:00')
else #start end
-- check if start time is before business hour
if datepart(hh, #start) < #start_hour set #start = Convert(dateTime,CONVERT(varchar,#start,101)+' 08:00:00')
-- check if start time is after business hour
if datepart(hh, #start) >= #end_hour set #start = Convert(dateTime,CONVERT(varchar,#start+1,101)+' 08:00:00')
-- loop start
while (#slamins > 0)
begin
-- prepared closing date time based on start date
set #today_closing = Convert(dateTime,CONVERT(varchar,#start,101)+' 17:00:00')
set #due_date = #start
-- calculate number of Minute between start date and closing date
set #temp = DATEDIFF(N, #start , #today_closing);
--check for weekends
if (DATEPART(dw, #start)!=1 AND DATEPART(dw, #start)!=7)
set #is_workday = #true
else
set #is_workday = #false
--check for holidays
if (Select Count(*) From #Holidays Where HDATE=DateAdd(dd, DateDiff(dd,0,#start), 0)) = 0
set #is_holiday =#false
else
set #is_holiday = #true
if #is_workday = #true and #is_holiday = #false
begin
if(#temp < #slamins)
begin
set #slamins = #slamins - #temp
end
else
begin
set #due_date = DATEADD(MINUTE,#slamins,#start)
set #slamins = 0
print #due_date
end
end
set #start = Convert(dateTime,CONVERT(varchar,#start+1,101)+' 08:00:00')
end
select #due_date
Here is an option using a WorkSchedule table, which will contain the business hours that are available to count towards the SLA. To account for weekends and holidays, just do not insert records for these days into the WorkSchedule table.
This solution also uses a "Tally" table aka numbers table in the due date calc. I also included debug output to help you see what is going on, so just comment out or uncomment any debug sections to see less/more info.
I used SQL temp tables in this example so that you can run it without messing up your current database schema, but you should replace with physical tables if you use this solution.
Test Data setups:
CREATE TABLE #WorkSchedule(WorkStart datetime not null primary key, WorkEnd datetime not null);
GO
CREATE TABLE #Tally (N int not null primary key);
GO
--POPULATE TEST DATA
--populate Tally table
insert into #Tally (N)
select top 10000 N = row_number() over(order by o.object_id)
from sys.objects o cross apply sys.objects o2
;
go
--POPULATE WITH DUMMY TEST DATA
INSERT INTO #WorkSchedule(WorkStart, WorkEnd)
SELECT
workStart = dateadd(hour, 8, t.workDate)
, workEnd = dateadd(hour, 17, t.workDate)
FROM (
SELECT top 10000 workDate = dateadd(day, row_number() over(order by o.object_id), '2000-01-01')
FROM sys.objects o cross apply sys.objects o2
) t
--Exclude weekends from work schedule
WHERE datename(weekday, t.workDate) not in ('Saturday','Sunday')
;
GO
Code to calculate Due Date:
SET NOCOUNT ON;
DECLARE #startDate datetime;
DECLARE #SLA_timespan_mins int;
DECLARE #workStartDayOne datetime;
DECLARE #SLA_Adjusted int;
DECLARE #dueDate datetime;
--SET PARAM VALUES HERE FOR TESTING TO ANY DATE/SLA TIMESPAN YOU WANT:
SET #startDate = '2014-01-04 05:00'; --Saturday
SET #SLA_timespan_mins = 10 * 60 ; --10 hrs.
--get the info day 1, since your start date might be after the work start time.
select top 1 #workStartDayOne = s.WorkStart
--increase the SLA timespan mins to account for difference between work start and start time
, #SLA_Adjusted = case when #startDate > s.WorkStart then datediff(minute, s.WorkStart, #startDate) else 0 end + #SLA_timespan_mins
from #WorkSchedule s
where s.WorkEnd > #startDate
and s.WorkStart <> s.WorkEnd
order by s.WorkStart asc
;
--DEBUG info:
select 'Debug Info' as DebugInfo, #startDate AS StartDate, #workStartDayOne as workStartDayOne, #SLA_timespan_mins as SLA_timespan_mins, #SLA_Adjusted as SLA_Adjusted;
--now sum all the non work hours during that period and determine the additional mins that need added.
;with cteWorkMins as
(
SELECT TOP (#SLA_Adjusted)
s.WorkStart, s.WorkEnd
, WorkMinute = dateadd(minute, t.N, cast(s.WorkStart as datetime))
, t.N as MinuteOfWorkDay
, RowNum = row_number() over(order by s.WorkStart, t.N)
FROM #WorkSchedule s
INNER JOIN #Tally t
ON t.N between 1 and datediff(minute, s.WorkStart, s.WorkEnd)
WHERE s.WorkStart >= #workStartDayOne
ORDER BY s.WorkStart, t.N
)
/**/
SELECT #dueDate = m.WorkMinute
FROM cteWorkMins m
WHERE m.RowNum = #SLA_Adjusted
--*/
/**
--DEBUG: this query will show every minute that is accounted for during the Due Date calculation.
SELECT m.*
FROM cteWorkMins m
--WHERE m.RowNum = #SLA_Adjusted
ORDER BY m.WorkMinute
--*/
;
select #dueDate as DueDate;
GO
Test Cleanup:
IF object_id('TEMPDB..#WorkSchedule') IS NOT NULL
DROP TABLE #WorkSchedule;
GO
IF object_id('TEMPDB..#Tally') IS NOT NULL
DROP TABLE #Tally;
GO
as I understood from your question, what you need is as follow
You have given start date and number of minutes added to it, then you need to get the due date
To get the due date, you need to exclude the holidays and the due date should be during business day
here is what you can do
declare #start datetime,
#min int,
#days int
set #start= '28 Dec 2014'
set #min = 2200
-- get the number of days
set #days=datediff(day,#start,dateadd(minute,#min,#start))
-- get the due date
select max(Date)
from
(select row_number() over( order by t.Id)-1 as Id,t.Date
from DateMetadata t
inner join BusinessDays b on Day(t.Date) = b.Day
where t.Date > = #start and not exists(select 1 from Holidays h
where h.Day=Day(t.Date)
and h.Month=Month(t.Date))) as p
where p.Id < #days
Note :that DateMetadata table you will setup it in your database once
the setup for the above code :
create table Holidays(Id int identity(1,1),
Name nvarchar(50),
Day int,
Month int)
create table BusinessDays(Id int identity(1,1),
Name nvarchar(20),
Day int)
-- i am putting some days that are known,
-- it depends on you to define which holidays you want
insert into Holidays (Name,Day,Month) values('Christmas',25,12)
insert into Holidays(Name,Day,Month) values('New Year',31,12)
insert into Holidays(Name,Day,Month) values('Valentine',14,2)
insert into Holidays(Name,Day,Month) values('Mothers day',21,3)
insert into Holidays(Name,Day,Month) values('April fools day',1,4)
-- i am assuming that the business days are from monday till friday and
-- saturday and sunday are off days
insert into BusinessDays(Name,Day) values ('Monday',1)
insert into BusinessDays(Name,Day) values('Tuesday',2)
insert into BusinessDays(Name,Day) values('Wednesday',3)
insert into BusinessDays(Name,Day) values('Thursday',4)
insert into BusinessDays(Name,Day) values('Friday',5)
this table is needed and you will setup it once
-- set up a table that contains all dates from now till 2050 for example
-- and you can change the value of 2050 depending on your needs
-- this table you will setup it once
create table DateMetadata(Id int identity(1,1),
Date datetime)
declare #date datetime
set #date='01 Jan 2014'
while #date < '31 Dec 2050'
begin
insert into DateMetadata(Date) values(#date)
set #date = #date + 1
end
here a working DEMO
if you need any explanation, i am ready
hope it will help you
I created a function to calculate due date from the table, once it's populated as per Beth's and others' approaches (various similar methods for doing this, as you can see -- it only took me about an hour to think about all the UK holidays and populate the table including Easter dates up to 2029 without using these exact guides).
Note that my table contains SLA in business hours (8 hours in a normal day, 5 days in a normal week), your business hours may vary but you can amend this easily, just make sure your business hours are set the same for both the SLA table and the function below.
Code below is T-SQL (written in SSMS v17.8.1)
CREATE FUNCTION [JIRA].[Fn_JIRA_Due_Date] (
#CreatedDate DATETIME, #SLA_Business_Hours INTEGER
) RETURNS DATETIME
AS
-- SELECT [JIRA].[Fn_JIRA_Due_Date]('2019-12-28 08:00:00', 24)
/*
baldmosher™
2019-03-25
* Function returns the DueDate for a JIRA ticket, based on the CreatedDate and the SLA (based on the Issue Type, or the Epic for Tasks) and business hours per date (set in [JIRA].[Ref_JIRA_Business_Hours])
* Called by IUP to store this at the time the ticket is loaded
* Can only consider SLA in Business Hours:
* <24hrs calendar = <8hrs business
* =24hrs calendar = 8hrs business
* >24hrs calendar = 8hrs business * business days
*/
BEGIN
IF #CreatedDate IS NULL OR #SLA_Business_Hours IS NULL RETURN NULL;
DECLARE #SLA_Hours_Remaining SMALLINT = #SLA_Business_Hours;
--SET DATEFIRST 1;
DECLARE #DueDate DATETIME;
DECLARE #BusHrsStart DECIMAL(18,10) = 8 ; -- start of Business Hours (8am)
DECLARE #BusHrsClose DECIMAL(18,10) = 16 ; -- close of Business Hours (4pm)
--DECLARE #WkndStart DECIMAL(18,10) = 6 ; -- start of weekend (Sat)
DECLARE #Hours_Today SMALLINT ; -- # hours left in day to process ticket
-- PRINT 'Created ' + CAST(CAST(#CreatedDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(#CreatedDate AS TIME) AS VARCHAR(8))
--!!!! extend to the next whole hour just to simplify reporting -- need to work on fixing this eventually
SET #CreatedDate = DATEADD(MINUTE,60-DATEPART(MINUTE,#CreatedDate),#CreatedDate)
-- PRINT 'Rounded ' + CAST(CAST(#CreatedDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(#CreatedDate AS TIME) AS VARCHAR(8))
--check if created outside business hours and adjust CreatedDate to start the clock first thing at the next business hours start of day (days are checked next)
IF DATEPART(HOUR,#CreatedDate) < #BusHrsStart
--created before normal hours, adjust #CreatedDate later to #BusHrsStart same day
BEGIN
SET #CreatedDate = DATEADD(HOUR,#BusHrsStart,CAST(CAST(#CreatedDate AS DATE) AS DATETIME))
END
IF DATEPART(HOUR,#CreatedDate) >= #BusHrsClose
--created after normal hours, adjust #CreatedDate to #BusHrsStart next day
BEGIN
SET #CreatedDate = DATEADD(HOUR,#BusHrsStart,CAST(CAST(#CreatedDate+1 AS DATE) AS DATETIME))
--adjust CreatedDate to start the clock the next day with >0 business hours (i.e. extend if it falls on a weekend or holiday)
SET #CreatedDate = CAST(#CreatedDate AS DATE)
StartNextWorkingDay:
IF (SELECT TOP(1) [Business_Hours] FROM [JIRA].[Ref_JIRA_Business_Hours] b WHERE b.[Date] = #CreatedDate ORDER BY [Date]) = 0
BEGIN
SET #CreatedDate = DATEADD(DAY,1,#CreatedDate)
GOTO StartNextWorkingDay
END
--DATEADD(DAY, DATEDIFF(DAY,0,#CreatedDate+7)/7*7,0); -- midnight, Monday next week
SET #CreatedDate = DATEADD(HOUR,#BusHrsStart,#CreatedDate); -- BusHrsStart
END
-- PRINT 'Started ' + CAST(CAST(#CreatedDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(#CreatedDate AS TIME) AS VARCHAR(8))
--third, check the business hours for each date from CreatedDate onwards to determine the relevant DueDate
SET #DueDate = #CreatedDate
-- PRINT 'SLA Hrs ' + CAST(#SLA_Hours_Remaining AS VARCHAR(2))
SET #Hours_Today = #BusHrsStart + (SELECT TOP(1) [Business_Hours] FROM [JIRA].[Ref_JIRA_Business_Hours] b WHERE b.[Date] = CAST(#DueDate AS DATE) ORDER BY [Date]) - DATEPART(HOUR, #CreatedDate)
-- PRINT 'Hrs Today ' + CAST(#Hours_Today AS VARCHAR(2))
DueNextWorkingDay:
IF #SLA_Hours_Remaining > #Hours_Today
BEGIN
-- PRINT 'Due another day'
SET #SLA_Hours_Remaining = #SLA_Hours_Remaining - #Hours_Today --adjust remaining time after today's hours
SET #Hours_Today = (SELECT TOP(1) [Business_Hours] FROM [JIRA].[Ref_JIRA_Business_Hours] b WHERE b.[Date] = CAST(#DueDate AS DATE) ORDER BY [Date])
-- PRINT 'SLA Hrs ' + CAST(#SLA_Hours_Remaining AS VARCHAR(2))
-- PRINT 'Hrs Today ' + CAST(#Hours_Today AS VARCHAR(2))
SET #DueDate = DATEADD(DAY,1,DATEADD(HOUR,#BusHrsStart,CAST(CAST(#DueDate AS DATE) AS DATETIME))) --adjust DueDate to first thing next day
END
IF #SLA_Hours_Remaining <= #Hours_Today
BEGIN
-- PRINT 'Due today'
SET #DueDate = DATEADD(HOUR,#SLA_Hours_Remaining,#DueDate)
END
ELSE
BEGIN
GOTO DueNextWorkingDay
END
-- PRINT 'DueDate ' + CAST(CAST(#DueDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(#DueDate AS TIME) AS VARCHAR(8))
RETURN #DueDate
END
GO
Table for SLAs:
CREATE TABLE [JIRA].[Ref_JIRA_SLAs](
[SLA_SK] [SMALLINT] IDENTITY(1,1) NOT NULL,
[Project] [VARCHAR](20) NULL,
[Issue_Type] [VARCHAR](50) NULL,
[Epic_Name] [VARCHAR](50) NULL,
[SLA_Business_Hours] [SMALLINT] NULL,
[Comments] [VARCHAR](8000) NULL
) ON [PRIMARY] WITH (DATA_COMPRESSION = PAGE)
GO

get DATEDIFF excluding weekends using sql server

I am using this query to get time taken.
SELECT DATEDIFF(dd, ActualStartDate, ActualCompletionDate) AS TimeTaken
FROM TableName
Now I want to exclude weekends and only include Mon-Fri as days counted.
Example query below, here are some details on how I solved it.
Using DATEDIFF(WK, ...) will give us the number of weeks between the 2 dates. SQL Server evaluates this as a difference between week numbers rather than based on the number of days. This is perfect, since we can use this to determine how many weekends passed between the dates.
So we can multiple that value by 2 to get the number of weekend days that occurred and subtract that from the DATEDIFF(dd, ...) to get the number of weekdays.
This doesn't behave 100% correctly when the start or end date falls on Sunday, though. So I added in some case logic at the end of the calculation to handle those instances.
You may also want to consider whether or not the DATEDIFF should be fully inclusive. e.g. Is the difference between 9/10 and 9/11 1 day or 2 days? If the latter, you'll want to add 1 to the final product.
declare #d1 datetime, #d2 datetime
select #d1 = '9/9/2011', #d2 = '9/18/2011'
select datediff(dd, #d1, #d2) - (datediff(wk, #d1, #d2) * 2) -
case when datepart(dw, #d1) = 1 then 1 else 0 end +
case when datepart(dw, #d2) = 1 then 1 else 0 end
I found when i used this there was a problem when d1 fell on saturday. Below is what i used to correct this.
declare #d1 datetime, #d2 datetime
select #d1 = '11/19/2011' , #d2 = '11/28/2011'
select datediff(dd, #d1, #d2) +case when datepart(dw, #d1) = 7 then 1 else 0 end - (datediff(wk, #d1, #d2) * 2) -
case when datepart(dw, #d1) = 1 then 1 else 0 end +
case when datepart(dw, #d2) = 1 then 1 else 0 end
BEGIN
DECLARE #totaldays INT;
DECLARE #weekenddays INT;
SET #totaldays = DATEDIFF(DAY, #startDate, #endDate)
SET #weekenddays = ((DATEDIFF(WEEK, #startDate, #endDate) * 2) + -- get the number of weekend days in between
CASE WHEN DATEPART(WEEKDAY, #startDate) = 1 THEN 1 ELSE 0 END + -- if selection was Sunday, won't add to weekends
CASE WHEN DATEPART(WEEKDAY, #endDate) = 6 THEN 1 ELSE 0 END) -- if selection was Saturday, won't add to weekends
Return (#totaldays - #weekenddays)
END
This is on SQL Server 2014
declare #d1 datetime, #d2 datetime
select #d1 = '4/19/2017', #d2 = '5/7/2017'
DECLARE #Counter int = datediff(DAY,#d1 ,#d2 )
DECLARE #C int = 0
DECLARE #SUM int = 0
WHILE #Counter > 0
begin
SET #SUM = #SUM + IIF(DATENAME(dw,
DATEADD(day,#c,#d1))IN('Sunday','Monday','Tuesday','Wednesday','Thursday')
,1,0)
SET #Counter = #Counter - 1
set #c = #c +1
end
select #Sum
If you hate CASE statements as much as I do, and want to be able to use the solution inline in your queries, just get the difference of days and subtract the count of weekend days and you'll have the desired result:
declare #d1 datetime, #d2 datetime, #days int
select #d1 = '2018/10/01', #d2 = '2018/11/01'
SET #days = DateDiff(dd, #d1, #d2) - DateDiff(ww, #d1, #d2)*2
print #days
(The only caveat--or at least point to keep in mind--is that this calculation is not inclusive of the last date, so you might need to add one day to the end date to achieve an inclusive result)
I just want to share the code I created that might help you.
DECLARE #MyCounter int = 0, #TempDate datetime, #EndDate datetime;
SET #TempDate = DATEADD(d,1,'2017-5-27')
SET #EndDate = '2017-6-3'
WHILE #TempDate <= #EndDate
BEGIN
IF DATENAME(DW,#TempDate) = 'Sunday' OR DATENAME(DW,#TempDate) = 'Saturday'
SET #MyCounter = #MyCounter
ELSE IF #TempDate not in ('2017-1-1', '2017-1-16', '2017-2-20', '2017-5-29', '2017-7-4', '2017-9-4', '2017-10-9', '2017-11-11', '2017-12-25')
SET #MyCounter = #MyCounter + 1
SET #TempDate = DATEADD(d,1,#TempDate)
CONTINUE
END
PRINT #MyCounter
PRINT #TempDate
If you do have a holiday table, you can also use that so that you don't have to list all the holidays in the ELSE IF section of the code. You can also create a function for this code and use the function whenever you need it in your query.
I hope this might help too.
Using https://stackoverflow.com/a/1804095 and JeffFisher30's answer above (https://stackoverflow.com/a/14572370/6147425) and my own need to have fractional days, I wrote this:
DateDiff(second,Start_Time,End_Time)/86400.0
-2*DateDiff(week, Start_Time, End_Time)
-Case When (DatePart(weekday, Start_Time)+##DateFirst)%7 = 1 Then 1 Else 0 End
+Case When (DatePart(weekday, End_Time)+##DateFirst)%7 = 1 Then 1 Else 0 End
Use this function to calculate the number of business days excluding Saturday and Sunday. Also it will exclude start date and it will include end date.
-- Select [dbo].[GetBussinessDays] ('02/18/2021', '03/06/2021') -- 11 days
CREATE or ALTER FUNCTION [dbo].[GetBussinessDays] (
#StartDate DATETIME,
#EndDate DATETIME
)
returns INT AS
BEGIN
DECLARE #tempStartDate DATETIME= #StartDate;
DECLARE #tempEndDate DATETIME = #EndDate;
IF(#tempStartDate IS NULL
OR
#tempEndDate IS NULL)
BEGIN
RETURN NULL;
END
--To avoid negative values reverse the date if StartDate is grater than EndDate
IF(#StartDate > #EndDate)
BEGIN
SET #StartDate = #tempEndDate;
SET #EndDate = #tempStartDate;
END
DECLARE #Counter INT = Datediff(day,#StartDate ,#EndDate);
DECLARE #TempCounter INT = 0;
DECLARE #TotalBusinessDays INT = 0;
WHILE #Counter >= 0
BEGIN
IF(#TempCounter > 0 OR #Counter = 1) -- To ignore first day's calculation
Begin
SET #TotalBusinessDays = #TotalBusinessDays + Iif(Datename(dw, Dateadd(day,#TempCounter,#StartDate)) IN('Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday'),1,0)
END
SET #Counter = #Counter - 1
SET #TempCounter = #TempCounter +1
END
RETURN #TotalBusinessDays;
END
Using #Derek Kromm answer (Current Marked Answer)
I have modified so it IS tolerant of any localisations that may be on the target server.
DECLARE #d1 DATETIME, #d2 DATETIME
SELECT #d1 = '10/01/2022', #d2 = '10/28/2022'
SELECT (datediff(dd, #d1, #EndQuery)+1) - (datediff(wk, #d1, dateadd(dd,1,#d2)) * 2)
- CASE WHEN DateName(WEEKDAY, #d1) = 'Sunday' THEN 1 ELSE 0 END -- This includes for start date edge case
+ CASE WHEN DateName(WEEKDAY, #d2) = 'Saturday' THEN 1 ELSE 0 END -- This includes for end date edge case.
This is with the end date being innclusive.
/*
EXAMPLE:
/MONDAY/
SET DATEFIRST 1
SELECT dbo.FUNC_GETDATEDIFFERENCE_WO_WEEKEND('2019-02-01','2019-02-12')
*/
CREATE FUNCTION FUNC_GETDATEDIFFERENCE_WO_WEEKEND
(
#pdtmaLastLoanPayDate DATETIME,
#pdtmaDisbursedDate DATETIME
)
RETURNS BIGINT
BEGIN
DECLARE
#mintDaysDifference BIGINT
SET #mintDaysDifference = 0
WHILE CONVERT(NCHAR(10),#pdtmaLastLoanPayDate,121) <= CONVERT(NCHAR(10),#pdtmaDisbursedDate,121)
BEGIN
IF DATEPART(WEEKDAY,#pdtmaLastLoanPayDate) NOT IN (6,7)
BEGIN
SET #mintDaysDifference = #mintDaysDifference + 1
END
SET #pdtmaLastLoanPayDate = DATEADD(DAY,1,#pdtmaLastLoanPayDate)
END
RETURN ISNULL(#mintDaysDifference,0)
END

SQL: How to produce next date given month and day

In my table I have a Month(tinyint) and a Day(tinyint) field. I would like to have a function that takes this month and day and produces a datetime for the next date(including year) given this month and day.
So if I had Month = 9, Day = 7 it would produce 9/7/2009.
If I had Month 1, Day 1 it would produce 1/1/2010.
something like this would work. It's variation on your method, but it doesn't use the MM/DD/YYYY literal format, and it won't blowup against bad input (for better or for worse).
declare #month tinyint
declare #day tinyint
set #month = 9
set #day = 1
declare #date datetime
-- this could be inlined if desired
set #date = convert(char(4),year(getdate()))+'0101'
set #date = dateadd(month,#month-1,#date)
set #date = dateadd(day,#day-1,#date)
if #date <= getdate()-1
set #date = dateadd(year,1,#date)
select #date
Alternatively, to create a string in YYYYMMDD format:
set #date =
right('0000'+convert(char(4),year(getdate())),4)
+ right('00'+convert(char(2),#month),2)
+ right('00'+convert(char(2),#day),2)
Another method, which avoids literals all together:
declare #month tinyint
declare #day tinyint
set #month = 6
set #day = 24
declare #date datetime
declare #today datetime
-- get todays date, stripping out the hours and minutes
-- and save the value for later
set #date = floor(convert(float,getdate()))
set #today = #date
-- add the appropriate number of months and days
set #date = dateadd(month,#month-month(#date),#date)
set #date = dateadd(day,#day-day(#date),#date)
-- increment year by 1 if necessary
if #date < #today set #date = dateadd(year,1,#date)
select #date
Here is my sql example so far. I don't really like it though...
DECLARE #month tinyint,
#day tinyint,
#date datetime
SET #month = 1
SET #day = 1
-- SET DATE TO DATE WITH CURRENT YEAR
SET #date = CONVERT(datetime, CONVERT(varchar,#month) + '/' + CONVERT(varchar,#day) + '/' + CONVERT(varchar,YEAR(GETDATE())))
-- IF DATE IS BEFORE TODAY, ADD ANOTHER YEAR
IF (DATEDIFF(DAY, GETDATE(), #date) < 0)
BEGIN
SET #date = DATEADD(YEAR, 1, #date)
END
SELECT #date
Here's a solution with PostgreSQL
your_date_calculated = Year * 10000 + Month * 100 + Day
gives you a date like 20090623.
select cast( cast( your_date_calculated as varchar ) as date ) + 1
Here's my version. The core of it is just two lines, using the DATEADD function, and it doesn't require any conversion to/from strings, floats or anything else:
DECLARE #Month TINYINT
DECLARE #Day TINYINT
SET #Month = 9
SET #Day = 7
DECLARE #Result DATETIME
SET #Result =
DATEADD(month, ((YEAR(GETDATE()) - 1900) * 12) + #Month - 1, #Day - 1)
IF (#Result < GETDATE())
SET #Result = DATEADD(year, 1, #Result)
SELECT #Result