Whenever i tried to convert HEX (12 11 80 64 29 86) to ASCII, it print out unreadable characters.
12 11 80 64 29 86 - > d)
What is this d) and how can i make it readable?
I'm working with a GPS unit and it send me data through TCP.
Here is a full message
$$ ▒▒d)▒▒▒U071121.000,A,2047.6419,N,09702.6721,E,0.11,185,080718,,*0C|1.0|1409|0000|0001,0000,0000,028A|019E00010C819D45|1E|0006F055|08i-
I need unreadable characters before U071121 in HEX as it represent the device ID.
Here is an ascii table with printable and non printable characters: https://theasciicode.com.ar/ascii-printable-characters/capital-letter-v-uppercase-ascii-code-86.html
Here is the hex version: https://www.rapidtables.com/convert/number/hex-to-ascii.html
I suspect that your 3rd and 6th characters are outside the ascii character set.
Note that hex is base 16. 12 in hex is 18 in decimal.
Related
What does the statement "hexadecimal matches cleanly with modulo 8 word sizes, such as 8, 16, 32, and 64 bits" mean?
Since a single hex digit can represent exactly 4 bits of binary data, any word size that's a multiple of 4 can be exactly represented with a fixed number of hex digits.
And every word size that's a multiple of 8 (i.e. the common ones) can be represented with a number of digits that's a multiple of 2:
8 bits can store values from 00 to FF
16 bits can store values from 0000 to FFFF
32 bits can store values from 00000000 to FFFFFFFF
...
All 2-digit hex numbers can be represented in 8 bits and all 8 bit values can be represented in 2 hex digits. If a hex editor displays some value as CA FE BA BE you can easily grasp that it's 4 bytes and thus 32 bits. Getting that information from the decimal 3405707966 is not quite as trivial (no matter how you group the digits: there's no nice "byte boundaries" in that representation).
If you compare this with decimal, the same isn't true. For example, 8 bits can represent values from 0 to 255 (decimal). So you need up to 3 digits in decimal to represent 8-bit values. But there are 3-digit decimal values that you can't represent in 8 bits: 256 (or anything higher than that) doesn't map onto 8 bits. So the mapping isn't perfect for decimal numbers.
I was checking out the difference between char vs varchar2 from google. I came across a word LEADING LENGTH in this link . THERE it was written that
Suppose you store the string ‘ORATABLE’ in a CHAR(20) field and a VARCHAR2(20) field. The CHAR field will use 22 bytes (2 bytes for leading length). The VARCHAR2 field will use 10 bytes only (8 for the string, 2 bytes for leading length).
Q1:How does the char field will use 22 bytes if the string is of 8 characters if (1 byte = 1 char)?
Q2 What is the LEADING LENGTH ? why it does occupy 2 bytes?
The CHAR() datatype pads the string with characters. So, for 'ORATABLE', it looks like:
'ORATABLE '
12345678901234567890
The "leading length" are two bytes at the beginning that specify the length of the string. Two bytes are needed because one byte is not enough. Two bytes allow lengths up to 65,535 units; one byte would only allow lengths up to 255.
The important point both CHAR() and VARCHAR2() use the same internal format, so there is little reason to sue CHAR(). Personally, I would only use it for fixed-length codes, such as ISO country codes or US social security numbers.
I have input comprising five character upper-case English letters e.g ABCDE and I need to convert this into two character unique ASCII output.
e.g. ABCDE and ZZZZZ should both give two different outputs
I have converted from ABCDE into hex which gives me 4142434445, but from this can I get to a two character output value I require?
Example:
INPUT1 = ABCDE
Converted to hex = 4142434445
INPUT2 = 4142434445
OUTPUT = ?? Any 2 ASCII Characters
Other examples of INPUT1 =
BIRAL
BRMAL
KLAAX
So you're starting with a 5-digit base-26 number, and you want to squeeze that into some 2-digit scheme with base n?
All possible 1-5 digit base-26 numbers gives you a number space of 26^5 = 11,881,376.
So you want the minimum n where n^2 >= 11,881,376.
Which gives you 3446.
Now it's up to you to go and find a suitable glyph block somewhere in UTF where you can reliably block-out 3446 separate characters to act as your new base/alphabet. And construct a mapping from your 5-char base-26 ABCDE type number onto your 2-char base-3446 wierd-glyph number. Good luck with that.
There's not enough variety in ASCII to do this, since it's only 128 printable characters. Limiting yourself to 2-chars of ASCII means you can only address a number space of 16384.
I'm trying to build an parser to deserialze into object. Socket will send byte into parser. For the length of field 22 POS Entry Mode will N3 and byte will be always 2 digit. How to get the value for this field ?
You read the ASCII value of this field, and convert it into an integer.
if it says N3 that means they are three digits numeric field, so if the value say 51, you cast it to 051 and send the ASCII equivalent
Field 22 is pos entry mode. It's 3 digit numeric value. If format is BCD then 2 bytes contains 4 digits[ 0 (padded) + 3 digit POS entry mode). If format is ascci then it is 3 byte.
I am faced with the task of sending ISO 8583 Rev 93 messages and am using openiso8583.net. The company that is consuming my messages gave message samples and I am unclear about the following Field attributes:
Special Characters
Alphabetic & Numeric Characters
Alphabetic & Special Characters
Number & Special Characters
Alphabetic, Numeric, & Special Characters
Here is the example:
Signon Reply
0810822000000200000004000000000000000501130427000005F0F00001
NUM |FLDNAME |FIELD DESCRIPTION |LEN |T|FIELD VALUE
-----|--------|-------------------------------|----|-|--------------------------
N/A |MSGTYPE |MESSAGE TYPE |F2 |H|0810`
N/A |BITMAP1 |FIRST BITMAP |B8 |H|8220000002000000`
1 |BITMAP2 |SECOND BITMAP |B8 |H|0400000000000000`
7 |MISDTMDT|TRANSMISSION DATE AND TIME |F5 |H|0501130427`
11 |MISDSTAN|SYSTEM TRACE AUDIT NUMBER |F3 |H|000005`
39 |MISDRSPC|RESPONSE CODE |F2 |C|00` <------?
70 |MISDNMIC|NETWORK MANAGEMENT INFO CODE |F2 |H|0001`
First, take a look at the message bytes:
0810822000000200000004000000000000000501130427000005*F0F0*0001
My question is how the two bytes { 0xF0, 0xF0 } translates to "00". If the company was sending ASCII, I would expect "00" to be { 0x30, 0x30 }. BCD is used for Numeric values but I can't seem to figure out how character values are being encoded.
Here is the description for field 39:
039:
Network Response Code
Attributes:
an 2*
Description:
A field that indicates the result of a previous related request. It will indicate
approval or reason for rejection if not approved. It is also used to indicate to the
device processor whether or not machines that are capable of retaining the customer's
card should do so.
Format:
In transaction replies, the response code must contain one of the following values
with their corresponding meanings. For debit/host-data-capture 0220 / 0420 messages, a
response code of '00' must be returned to indicate the transaction was approved. For
EBT transactions, please refer to section 4.8 EBT Transaction Receipt Requirements.
an2 means Alphabetic & Numeric Characters
Bitmap 1 is 64 bits
Bitmap 2 is 64 bits
Msg Type is 4 bytes
Field 7 is Numeric 4-bit BCD (Packed unsigned) 10, 5 bytes
Field 11 is Numeric 4-bit BCD (Packed unsigned) 6, 3 bytes
Field 39 is an 2, I assume 2 bytes
Field 70 is Numeric 4-bit BCD (Packed unsigned) 3, 2 bytes
Any clues or pointers would be greatly appreciated. Maybe someone knows of some encoding I clearly do not or can give a general explenation of how characters are encoded for ISO 8583 Rev 93. I do realize that each company can have different implementations though.
I hate answering my own questions quickly but...I just found the answer.
EBCDIC
I guess not being a programmer in the days of punch cards slowed me down on this one
0xF0 = '0'