Multiply two (2) columns of a table - sql

Question

Please I need to multiply total no of jobtype and the value of MEAL_Ticket for a particular date
SELECT DISTINCT
DATENAME(dw, Time) + ', ' + CONVERT(VARCHAR(12), Time, 107) AS Date_to_Display,Vale,
(SELECT COUNT(*) FROM CanLog AS c
WHERE c.Time= clog.Time AND jobtype = 'fulltime') AS Fulltime,
(SELECT COUNT(Jobtype) * SUM(Value) FROM CanLog
WHERE Time BETWEEN '2018-02-12' AND '2018-02-14' AND jobtype = 'fulltime' ) AS FulltimeTicket_Value,
(SELECT COUNT(*) FROM CanLog AS c
WHERE c.Time = clog.Time AND jobtype = 'contract') AS Contract,
(SELECT COUNT(*) FROM CanLog AS c
WHERE c.Time = clog.Time AND jobtype = 'casual') AS Casual
FROM
CanLog AS clog
WHERE
Time BETWEEN '2018-02-12' AND '2018-02-14'
GROUP BY
Time, Jobtype
ORDER BY
2 ASC
I got this error
Column 'CanLog.Value' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause
What I want is this output:
Fulltime FulltimeTicket_Value Contract Casual
2018/06/04 1 500(1*500) 6 2
2018/06/05 3 1500(3*500) 0 0
2018/06/06 0 0 (0*500) 3 1
2018/06/07 2 1000(2*500) 1 0
2018/06/08 1 500(1*500) 1 3
2018/06/09 0 0(0*500) 1 4
Please help
EDIT:
Sample table
CREATE TABLE [dbo].[CanLog]
(
[id] [int] IDENTITY(1,1) NOT NULL,
[Firstname] [nvarchar](50) NOT NULL,
[Designation] [nvarchar](50) NOT NULL,
[Jobtype] [nvarchar](50) NOT NULL,
[Employ_No] [nvarchar](50) NOT NULL,
[Receipt_No] [int] NOT NULL,
[Username] [nvarchar](50) NOT NULL,
[Time] [datetime] NOT NULL,
[Value] [int] NULL
) ON [PRIMARY]

Answer 1

Initial query has a lot of warning signs:
GROUP BY does not match SELECT
DISTINCT + GROUP BY
unnecessary subqueries could be replaced with conditional aggregation
positional ORDER BY
I would recommend to avoid column names such as Value/Time
Datename(dw, Time) + ', ' + CONVERT(VARCHAR(12), Time, 107) I would replace it with CAST(Time AS DATE)
Time BETWEEN '2018-02-12' AND '2018-02-14' this kind of comparison may be dangerous (as mentioned by #Gordon)
I believe you want something like:
SELECT
Date_to_Display = CAST(Time AS DATE),
Fulltime = SUM(CASE WHEN jobtype = 'fulltime' THEN 1 ELSE 0 END),
FulltimeTicket_Value = SUM(CASE WHEN jobtype = 'fulltime' THEN 1 ELSE 0 END) *
MAX(CASE WHEN jobtype = 'fulltime' THEN Value ELSE 0 END),
Contract = SUM(CASE WHEN jobtype = 'contract' THEN 1 ELSE 0 END),
Casual = SUM(CASE WHEN jobtype = 'casual' THEN 1 ELSE 0 END)
FROM
CanLog AS clog
WHERE
Time >= '2018-02-12' and time < '2018-02-15'
GROUP BY
CAST(Time AS DATE)
ORDER BY
CAST(Time AS DATE);

Answer 2

In addition to many of the points that Lukasz makes, you should avoid using between on date/time columns. A very good explanation is in Aaron Bertrand's blog What do Between and the Devil Have In Common.
You can also simplify the logic using indicator variables:
select cast(time as date) as Date_to_Display,
sum(is_fulltime) as Fulltime,
sum(value * is_fulltime) as FulltimeTicket_Value,
sum(is_contract) as Contract,
sum(is_casual) as Casual
from CanLog cl cross apply
(values (case when cl.jobtype = 'fulltime' then 1 else 0 end),
(case when cl.jobtype = 'contract' then 1 else 0 end),
(case when cl.jobtype = 'casual' then 1 else 0 end)
) v(is_contract, iscasual)
where Time >= '2018-02-12' and time < '2018-02-15'
group by cast(time as date)
order by cast(time as date);