SQL query with conditions for audit - sql

Question

I want to write a SQL query for several columns with conditions. the table looks like this:
ID Company User
1 Bov LPF
2 Ak LPF
3 Bov LPF
4 Bov ABC
5 Ak ABC
6 ZP ABC
7 REP ABC
8 REP CDE
9 KEK CDE
10 Ak CDE
11 PER CDE
12 Bov BKE
The result must be as followed:
Give me three rows per user (only the users with at least three rows will be in the result).
Company Bov, REP and Ak must return at least two times in the result
It is for an audit so everything must be ordered randomly (order by newid() for example)
Total rows is 9.
Expected result for example:
ID Company User
1 Bov LPF
2 Ak LPF
3 Bov LPF
4 Bov ABC
5 Ak ABC
7 REP ABC
8 REP CDE
10 Ak CDE
11 PER CDE
How should i write the query?
Update:
I was thinking about a query like this, but this doesn't give me the right results:
select *
from
(
select *,row_number() over(partition by user,company order by user, company) as row, ROW_NUMBER() over(order by newid()) as total
from
(
select *
from
(
select *, 0 as Bov, sum(iif(Company= 'Ak',1,0)) over (order by newid()) as Ak
FROM table a
where Company = 'Ak'
) as eu
where eu.Ak <= 2
UNION ALL
select *
from
(
select *, sum(iif(company = 'Bov',1,0)) over (order by newid() ) as Bov, 0 as Ak
FROM table a
where Company = 'Bov'
) as nn
where nn.Bov <= 2
UNION ALL
select *, 0 as Bov, 0 as Ak
FROM table a
where Company not in ('Bov','Ak')
) as z
) as z1
where z1.row <= 3
and z1.total <= 9
Filter <= 2 is for the company that must return at least two times in the result
Filter row <= 3 is for the three rows per user.
Filter total <= 9 is for the total rows that must be 9.
With this query i am not for sure that i have at least two rows for the companies Bov, Ak and REP.

Answer 1

select *
from table
group by id
having count(User) <= 3
order by id
Is this what you need?

Answer 2

You can use this.
DECLARE #MyTable TABLE (ID INT, Company VARCHAR(10), [User] VARCHAR(10))
INSERT INTO #MyTable VALUES
(1 , 'Bov', 'LPF'),
(2 , 'Ak ', 'LPF'),
(3 , 'Bov', 'LPF'),
(4 , 'Bov', 'ABC'),
(5 , 'Ak ', 'ABC'),
(6 , 'ZP ', 'ABC'),
(7 , 'REP', 'ABC'),
(8 , 'REP', 'CDE'),
(9 , 'KEK', 'CDE'),
(10 , 'Ak ', 'CDE'),
(11 , 'PER', 'CDE'),
(12 , 'Bov', 'BKE')
SELECT ID, Company, [User] FROM
( SELECT *
, ROW_NUMBER() OVER (PARTITION BY [User] ORDER BY (CASE WHEN Company IN ('Bov','REP','Ak') THEN 0 ELSE 1 END) ) RN
, COUNT(*) OVER (PARTITION BY [User]) CmpCnt
, COUNT(CASE WHEN Company IN ('Bov','REP','Ak') THEN 1 END) OVER (PARTITION BY [User]) PriCmpCnt
FROM #MyTable
) T
WHERE
T.CmpCnt > 2
and T.PriCmpCnt > 1
and T.RN < 4
order by ID
Result:
ID Company User
----------- ---------- ----------
1 Bov LPF
2 Ak LPF
3 Bov LPF
4 Bov ABC
5 Ak ABC
7 REP ABC
8 REP CDE
10 Ak CDE
11 PER CDE

Answer 3

Here's how I'd approach it; see comments for explanation / let me know if you need anymore info to understand anything...
SQL Fiddle Demo
;with cte as
(
select Id
, Company
, [User]
, Row_Number() over (partition by [User] order by randomOrder) PerUserRowNum
, case
when Company in ('BOV','REP', 'AK') then
case
when Row_Number() over (partition by Company order by randomOrder) <= 2 then 1
else 0
end
else 0
end MustInclude
from (select *, newid() randomOrder from SourceData) x
)
select top 9 --total rows is 9
Id, Company, [User]
from cte
where PerUserRowNum <= 3 --show 3 rows per user
and [User] in ( --only the users with at least three rows will be in the result
select [User]
from cte
where PerUserRowNum = 3
)
order by MustInclude desc, newid() --ensure all the stuff we must include is returned, then make up the rest of the results with whatever