Is it possible to only merge some columns? I have a DataFrame df1 with columns x, y, z, and df2 with columns x, a ,b, c, d, e, f, etc.
I want to merge the two DataFrames on x, but I only want to merge columns df2.a, df2.b - not the entire DataFrame.
The result would be a DataFrame with x, y, z, a, b.
I could merge then delete the unwanted columns, but it seems like there is a better method.
You want to use TWO brackets, so if you are doing a VLOOKUP sort of action:
df = pd.merge(df,df2[['Key_Column','Target_Column']],on='Key_Column', how='left')
This will give you everything in the original df + add that one corresponding column in df2 that you want to join.
You could merge the sub-DataFrame (with just those columns):
df2[list('xab')] # df2 but only with columns x, a, and b
df1.merge(df2[list('xab')])
If you want to drop column(s) from the target data frame, but the column(s) are required for the join, you can do the following:
df1 = df1.merge(df2[['a', 'b', 'key1']], how = 'left',
left_on = 'key2', right_on = 'key1').drop(columns = ['key1'])
The .drop(columns = 'key1') part will prevent 'key1' from being kept in the resulting data frame, despite it being required to join in the first place.
You can use .loc to select the specific columns with all rows and then pull that. An example is below:
pandas.merge(dataframe1, dataframe2.iloc[:, [0:5]], how='left', on='key')
In this example, you are merging dataframe1 and dataframe2. You have chosen to do an outer left join on 'key'. However, for dataframe2 you have specified .iloc which allows you to specific the rows and columns you want in a numerical format. Using :, your selecting all rows, but [0:5] selects the first 5 columns. You could use .loc to specify by name, but if your dealing with long column names, then .iloc may be better.
This is to merge selected columns from two tables.
If table_1 contains t1_a,t1_b,t1_c..,id,..t1_z columns,
and table_2 contains t2_a, t2_b, t2_c..., id,..t2_z columns,
and only t1_a, id, t2_a are required in the final table, then
mergedCSV = table_1[['t1_a','id']].merge(table_2[['t2_a','id']], on = 'id',how = 'left')
# save resulting output file
mergedCSV.to_csv('output.csv',index = False)
Slight extension of the accepted answer for multi-character column names, using inner join by default:
df1 = df1.merge(df2[["Key_Column", "Target_Column1", "Target_Column2"]])
This assumes that Key_Column is the only column both dataframes have in common.
Related
I want to add a new column to a datframe "table" (name: conc) which uses the values in columns (plate, ab) to get the numeric value from the dataframe "concs"
Below is what I mean, with the dataframe "exp" used to show what I expect the data to look like
what is the proper way to do this. Is it using some multiple condition, or do I need to reshape the concs dataframe somehow?
Use DataFrame.melt with left join for new column concs, if no match is created NaNs:
exp = concs.melt('plate', var_name='ab', value_name='concs').merge(table,on=['plate', 'ab'], how='left')
Solution should be simplify - if same columns names 'plate', 'ab' in both DataFrames and need merge by both is possible omit on parameter:
exp = concs.melt('plate', var_name='ab', value_name='concs').merge(table, how='left')
First melt the concs dataframe and then merge with table:
out = concs.melt(id_vars=['plate'],
value_vars=concs.columns.drop('plate').tolist(),
var_name='ab').merge(table, on=['plate', 'ab'
]).rename(columns={'value': 'concs'})
or just make good use of parameters of melt like in jezraels' answer:
out = concs.melt(id_vars=['plate'],
value_name='concs',
var_name='ab').merge(table, on=['plate', 'ab'])
I'm trying to understand how to concat three individual dataframes (i.e df1, df2, df3) into a new dataframe say df4 whereby each individual dataframe has its own column left to right order.
I've tried using concat with axis = 1 to do this, but it appears not possible to automate this with a single action.
Table1_updated = pd.DataFrame(columns=['3P','2PG-3Io','3Io'])
Table1_updated=pd.concat([get_table1_3P,get_table1_2P_max_3Io,get_table1_3Io])
Note that with the exception of get_table1_2P_max_3Io, which has two columns, all other dataframes have one column
For example,
get_table1_3P =
get_table1_2P_max_3Io =
get_table1_3Io =
Ultimately, i would like to see the following:
I believe you need first concat and tthen change order by list of columns names:
Table1_updated=pd.concat([get_table1_3P,get_table1_2P_max_3Io,get_table1_3Io], axis=1)
Table1_updated = Table1_updated[['3P','2PG-3Io','3Io']]
I have a dataframe as
df = pd.DataFrame(np.random.randn(5,4),columns=list('ABCD'))
I can use the following to achieve the traditional calculation like mean(), sum()etc.
df.loc['calc'] = df[['A','D']].iloc[2:4].mean(axis=0)
Now I have two questions
How can I apply a formula (like exp(mean()) or 2.5*mean()/sqrt(max()) to column 'A' and 'D' for rows 2 to 4
How can I append row to the existing df where two values would be mean() of the A and D and two values would be of specific formula result of C and B.
Q1:
You can use .apply() and lambda functions.
df.iloc[2:4,[0,3]].apply(lambda x: np.exp(np.mean(x)))
df.iloc[2:4,[0,3]].apply(lambda x: 2.5*np.mean(x)/np.sqrt(max(x)))
Q2:
You can use dictionaries and combine them and add it as a row.
First one is mean, the second one is some custom function.
ad = dict(df[['A', 'D']].mean())
bc = dict(df[['B', 'C']].apply(lambda x: x.sum()*45))
Combine them:
ad.update(bc)
df = df.append(ad, ignore_index=True)
Say I have n dataframes, df1, df2...dfn.
Finding rows that contain "bad" values in a row in a given dataframe is done by e.g.,
index1 = df1[df1.isin([np.nan, np.inf, -np.inf])]
index2 = df2[df2.isin([np.nan, np.inf, -np.inf])]
Now, droping these bad rows in the bad dataframe is done with:
df1 = df1.replace([np.inf, -np.inf], np.nan).dropna()
df2 = df2.replace([np.inf, -np.inf], np.nan).dropna()
The problem is that any function that expects the two (n) dataframes columns to be of the same length may give an error if there is bad data in one df but not the other.
How do I drop not just the bad row from the offending dataframe, but the same row from a list of dataframes?
So in the two dataframe case, if in df1 date index 2009-10-09 contains a "bad" value, that same row in df2 will be dropped.
[Possible "ugly"? solution?]
I suspect that one way to do it is to merge the two (n) dataframes on date, then apply the cleanup function to drop "bad" values are automatic since the entire row gets dropped? But what happens if a date is missing from one dataframe and not the other? [and they still happen to be the same length?]
Doing your replace
df1 = df1.replace([np.inf, -np.inf], np.nan)
df2 = df2.replace([np.inf, -np.inf], np.nan)
Then, Here we using inner .
newdf=pd.concat([df1,df2],axis=1,keys=[1,2], join='inner').dropna()
And split it back to two dfs , here we using combine_first with dropna of original df
df1,df2=[s[1].loc[:,s[0]].combine_first(x.dropna()) for x,s in zip([df1,df2],newdf.groupby(level=0,axis=1))]
I have a data frame and use some of its columns to group by:
grouped = df.groupby(['col1', 'col2'])
Now I use mean function to get a new data frame object from the above created groupby object:
df_new = grouped.mean()
Now I have two data frames (df and df2) and I would like to merge them using col1 and col2. The problem that I have now is that df2 does no have these columns. After groupby operation col1 and col2 are "shifted" to index. So, to resolve this problem, I try to create these columns:
df2['col1'] = df2['index'][0]
df2['col2'] = df2['index'][1]
But it does not work because 'index' is not recognized as a column of the data frame.
As an alternative Andy Hayden's method, you could use as_index=False to preserve the columns as columns rather than indices:
df2 = df.groupby(['col1', 'col2'], as_index=False).mean()
You can use left_index (or right_index) arguments of merge:
left_index : boolean, default False
Use the index from the left DataFrame as the join key(s).
If it is a MultiIndex, the number of keys in the other DataFrame (either the index
or a number of columns) must match the number of levels
and use right_on to determine which columns it should merge the index with.
So it'll be something like:
pd.merge(df, df_new, left_on=['col1', 'col2'], right_index=True)