I am trying to find all records in a database with an admission date which is older than a certain time frame (in this case, all admission dates older than 4 days old).
I have:
select memberid, admitdate
from membertable
where admitdate < (sysdate-4)
As a result, I'm getting a lot of admission dates which match this, but I'm ALSO getting dates which are from only 2 days ago, so that doesn't match my code. What am I doing wrong?
If it helps, the admit dates have a format of mm/dd/yyyy.
Dates, including sysdate, have a time component. Even if all your admitdate values are at midnight that is still a time, and sysdate is only going to be at midnight if you run your query then.
select sysdate, sysdate-4, trunc(sysdate), trunc(sysdate)-4 from dual;
SYSDATE SYSDATE-4 TRUNC(SYSDATE) TRUNC(SYSDATE)-4
------------------- ------------------- ------------------- -------------------
2018-06-21 16:44:53 2018-06-17 16:44:53 2018-06-21 00:00:00 2018-06-17 00:00:00
If you filter your records on sysdate-4 then that will include any admitdate values up to, in this example, 2018-06-17 16:44:53; so presumably all the records for the 17th if they are actually all midnight.
with membertable (memberid, admitdate) as (
select 1, date '2018-06-15' from dual
union all select 2, date '2018-06-16' from dual
union all select 3, date '2018-06-17' from dual
union all select 4, date '2018-06-18' from dual
union all select 5, date '2018-06-19' from dual
union all select 6, date '2018-06-20' from dual
union all select 7, date '2018-06-21' from dual
)
select memberid, admitdate
from membertable
where admitdate < (sysdate-4);
MEMBERID ADMITDATE
---------- -------------------
1 2018-06-15 00:00:00
2 2018-06-16 00:00:00
3 2018-06-17 00:00:00
If you truncate the value you're comparing against then its time portion will also be treated as midnight, so you'll only match record up to - but not including - that point in time, 2018-06-17 00:00:00:
with membertable (memberid, admitdate) as (
select 1, date '2018-06-15' from dual
union all select 2, date '2018-06-16' from dual
union all select 3, date '2018-06-17' from dual
union all select 4, date '2018-06-18' from dual
union all select 5, date '2018-06-19' from dual
union all select 6, date '2018-06-20' from dual
union all select 7, date '2018-06-21' from dual
)
select memberid, admitdate
from membertable
where admitdate < trunc(sysdate)-4;
MEMBERID ADMITDATE
---------- -------------------
1 2018-06-15 00:00:00
2 2018-06-16 00:00:00
admitdate should be a date. You seem to be suggesting it is a string. You can try:
where to_date(admitdate, 'MM/DD/YYYY') < trunc(sysdate) - 4;
You can then fix the data in the table, so it is stored as a date.
Related
I have a query in Oracle SQL. My query gives three columns: old_data ,new_data and transaction_date. I want to sort this data primarily based on increasing transaction_date and secondly in such a way that new_data of previous row equals old_data of next row. Both new_data and old_date are number fields that can decrease or increase.
If I sort just by transaction_date, some data has the same exact date and time and hence the order will not be accurate as I need new_data of previous row to match old_data of current row. I also cannot use a hierarchical query alone to meet the second sorting condition since transaction_date sorting is the primary sorting condition.
Can anyone suggest a solution?
A sample output will need to look like below:
output_sample
Thanks in advance
You could use a hierarchical query and connect by equal dates as well as the relationship between old- and new-data:
SELECT transaction_date,
new_data,
old_data
FROM table_name
START WITH old_data IS NULL -- You need to define how to pick the first row
CONNECT BY
PRIOR transaction_date = transaction_date
AND PRIOR new_data = old_date
ORDER SIBLINGS BY
transaction_date
Which, for the sample data:
ALTER SESSION SET NLS_DATE_FORMAT = 'YYYY-MM-DD HH24:MI:SS';
CREATE TABLE table_name ( transaction_date, new_data, old_data ) AS
SELECT DATE '2022-01-01', 1, NULL FROM DUAL UNION ALL
SELECT DATE '2022-01-01', 2, 1 FROM DUAL UNION ALL
SELECT DATE '2022-01-01', 3, 2 FROM DUAL UNION ALL
SELECT DATE '2022-01-02', 3, NULL FROM DUAL UNION ALL
SELECT DATE '2022-01-02', 1, 3 FROM DUAL UNION ALL
SELECT DATE '2022-01-02', 2, 1 FROM DUAL UNION ALL
SELECT DATE '2022-01-03', 4, NULL FROM DUAL;
Outputs:
TRANSACTION_DATE
NEW_DATA
OLD_DATA
2022-01-01 00:00:00
1
null
2022-01-01 00:00:00
2
1
2022-01-01 00:00:00
3
2
2022-01-02 00:00:00
3
null
2022-01-02 00:00:00
1
3
2022-01-02 00:00:00
2
1
2022-01-03 00:00:00
4
null
fiddle
Update
Given the updated sample data:
CREATE TABLE table_name ( transaction_date, old_data, new_data ) AS
SELECT DATE '2021-12-20'+INTERVAL '11:25' HOUR TO MINUTE, 0, 115.09903 FROM DUAL UNION ALL
SELECT DATE '2021-12-20'+INTERVAL '11:25' HOUR TO MINUTE, 115.09903, 115.13233 FROM DUAL UNION ALL
SELECT DATE '2021-12-20'+INTERVAL '11:25' HOUR TO MINUTE, 115.13233, 115.16490 FROM DUAL UNION ALL
SELECT DATE '2021-12-20'+INTERVAL '11:25' HOUR TO MINUTE, 115.16490, 115.19678 FROM DUAL UNION ALL
SELECT DATE '2021-12-20'+INTERVAL '11:35' HOUR TO MINUTE, 115.19678, 115.22799 FROM DUAL UNION ALL
SELECT DATE '2021-12-20'+INTERVAL '11:35' HOUR TO MINUTE, 115.22799, 115.25854 FROM DUAL UNION ALL
SELECT DATE '2021-12-20'+INTERVAL '11:35' HOUR TO MINUTE, 115.25854, 115.28846 FROM DUAL UNION ALL
SELECT DATE '2021-12-20'+INTERVAL '11:35' HOUR TO MINUTE, 115.28846, 115.31776 FROM DUAL;
Then, since both old_data and new_data increase with time, you could use:
SELECT *
FROM table_name
ORDER BY old_data;
or:
SELECT *
FROM table_name
ORDER BY new_data;
or, if you want to use the hierarchy then:
SELECT transaction_date,
old_data,
new_data
FROM table_name
START WITH old_data = 0
CONNECT BY
PRIOR transaction_date <= transaction_date
AND PRIOR new_data = old_data
ORDER SIBLINGS BY
transaction_date
Which all output:
TRANSACTION_DATE
OLD_DATA
NEW_DATA
2021-12-20 11:25:00
0
115.09903
2021-12-20 11:25:00
115.09903
115.13233
2021-12-20 11:25:00
115.13233
115.1649
2021-12-20 11:25:00
115.1649
115.19678
2021-12-20 11:35:00
115.19678
115.22799
2021-12-20 11:35:00
115.22799
115.25854
2021-12-20 11:35:00
115.25854
115.28846
2021-12-20 11:35:00
115.28846
115.31776
fiddle
We have following table to query data from,
EMPLOYEE_ABSENCE_TAB
emp_id
absence_id
from_date
to_date
absence_continuation
100
1
01/01/2022
03/01/2022
100
2
01/02/2022
05/02/2022
1
200
3
01/01/2022
07/01/2022
200
4
10/01/2022
14/01/2022
3
200
5
16/01/2022
20/01/2022
4
300
6
01/01/2022
14/01/2022
We need to connect data hierarchically based on the following logic.
Output should be emp_id, absence_days, from_date and to_date.
absence_days : number of absence days = sum(to_date - from_date)
from_date : first from_date where absence_continuation is NULL
to_date : last to_date connect by prior absence_id = absence_continuation
Expected Outcome
emp_id
absence_days
from_date
to_date
100
8
01/01/2022
05/02/2022
200
17
01/01/2022
20/01/2022
300
14
01/01/2022
14/01/2022
I tried hierarchical but could able to come up with working solution. How can this be achieved using hierarchical query in Oracle SQL?
You don't need to consider the hierarchy in the data (assuming that there are no overlaps); you just need to aggregate:
SELECT emp_id,
SUM(to_date - from_date + 1) AS absence_days,
MIN(from_date) AS from_date,
MAX(to_date) AS to_date
FROM EMPLOYEE_ABSENCE_TAB
GROUP BY emp_id
Which, for the sample data:
CREATE TABLE EMPLOYEE_ABSENCE_TAB
(emp_id, absence_id, from_date, to_date, absence_continuation) AS
SELECT 100, 1, DATE '2022-01-01', DATE '2022-01-03', NULL FROM DUAL UNION ALL
SELECT 100, 2, DATE '2022-02-01', DATE '2022-02-05', 1 FROM DUAL UNION ALL
SELECT 200, 3, DATE '2022-01-01', DATE '2022-01-07', NULL FROM DUAL UNION ALL
SELECT 200, 4, DATE '2022-01-10', DATE '2022-01-14', 3 FROM DUAL UNION ALL
SELECT 200, 5, DATE '2022-01-16', DATE '2022-01-20', 4 FROM DUAL UNION ALL
SELECT 300, 6, DATE '2022-01-01', DATE '2022-01-14', NULL FROM DUAL;
Outputs:
EMP_ID
ABSENCE_DAYS
FROM_DATE
TO_DATE
100
8
2022-01-01 00:00:00
2022-02-05 00:00:00
200
17
2022-01-01 00:00:00
2022-01-20 00:00:00
300
14
2022-01-01 00:00:00
2022-01-14 00:00:00
If you did want to consider the hierarchy and get the duration of each absence (and not the total absences per employee) then you can use:
SELECT emp_id,
absence_id,
SUM(to_date - from_date + 1) AS absence_days,
MIN(from_date) AS from_date,
MAX(to_date) AS to_date
FROM (
SELECT emp_id,
CONNECT_BY_ROOT absence_id AS absence_id,
to_date - from_date + 1 AS absence_days,
from_date,
to_date
FROM EMPLOYEE_ABSENCE_TAB
START WITH absence_continuation IS NULL
CONNECT BY PRIOR absence_id = absence_continuation
)
GROUP BY
emp_id,
absence_id
Which outputs the same (with an additional absence_id column for the id of the first part of the absence) for your sample data as you only have a single absence for each employee; if you had more absences then it would aggregate each absence separately.
db<>fiddle here
I have a problem with fetching few exceptions from DB.
Example, table b:
sn
v_num
start_date
end_date
1
001
01-01-2019
31-12-2099
1
002
01-01-2021
31-01-2022
1
003
01-02-2022
31-12-2099
2
001
01-01-2022
31-12-2099
2
002
01-07-2022
31-07-2022
2
003
01-08-2022
31-12-2099
Expected output:
sn
v_num
start_date
end_date
1
003
01-02-2022
31-12-2099
2
001
01-01-2022
31-12-2099
Currently I'm here:
SELECT * FROM table a, table b
WHERE a.sn = b.sn
AND b.v_num = (SELECT max (v_num) FROM b WHERE a.sn = b.sn)
but obviously that is not good because of a few cases like this with sn = 2.
Conclusion, I need to get unique sn record where v_num is max (95% of them in DB) except in case if start_date of max v_num record is > today.
Filter using start_date <= TRUNC(SYSDATE) then use the ROW_NUMBER analytic function:
SELECT *
FROM (
SELECT a.*,
ROW_NUMBER() OVER (PARTITION BY sn ORDER BY v_num DESC) AS rn
FROM "TABLE" a
WHERE start_date <= TRUNC(SYSDATE)
)
WHERE rn = 1;
If the start_date has a time component then you can use start_date < TRUNC(SYSDATE) + INTERVAL '1' DAY to get all the values for today from 00:00:00 to 23:59:59.
If you can have ties for the maximum and want to return all the ties then you can use the RANK analytic function instead of ROW_NUMBER.
Which, for the sample data:
CREATE TABLE "TABLE" (sn, v_num, start_date, end_date) AS
SELECT 1, '001', DATE '2022-01-01', DATE '2099-12-31' FROM DUAL UNION ALL
SELECT 1, '002', DATE '2022-01-01', DATE '2022-01-31' FROM DUAL UNION ALL
SELECT 1, '003', DATE '2022-02-01', DATE '2099-12-31' FROM DUAL UNION ALL
SELECT 2, '001', DATE '2022-01-01', DATE '2099-12-31' FROM DUAL UNION ALL
SELECT 2, '002', DATE '2022-07-01', DATE '2022-07-31' FROM DUAL UNION ALL
SELECT 2, '003', DATE '2022-08-01', DATE '2099-12-31' FROM DUAL;
Outputs:
SN
V_NUM
START_DATE
END_DATE
RN
1
003
2022-02-01 00:00:00
2099-12-31 00:00:00
1
2
001
2022-01-01 00:00:00
2099-12-31 00:00:00
1
db<>fiddle here
Notice the 2017-04-01, 2018-02-01, 2018-07-01, and 2019-01-01 months are missing in the output. I want to show only those months which are missing. Does anyone know how to go about this?
Query:
SELECT TO_DATE("Month", 'mon''yy') as dates FROM sample_sheet
group by dates
order by dates asc;
Output:
2017-01-01
2017-02-01
2017-03-01
2017-05-01
2017-06-01
2017-07-01
2017-08-01
2017-09-01
2017-10-01
2017-11-01
2017-12-01
2018-01-01
2018-03-01
2018-04-01
2018-05-01
2018-06-01
2018-08-01
2018-09-01
2018-10-01
2018-11-01
2018-12-01
2019-02-01
2019-03-01
2019-04-01
I don't know Vertica, so I wrote a working proof of concept in Microsoft SQL Server and tried to convert it to Vertica syntax based on the online documentation.
It should look like this:
with
months as (
select 2017 as date_year, 1 as date_month, to_date('2017-01-01', 'YYYY-MM-DD') as first_date, to_date('2017-01-31', 'yyyy-mm-dd') as last_date
union all
select
year(add_months(first_date, 1)) as date_year,
month(add_months(first_date, 1)) as date_month,
add_months(first_date, 1) as first_date,
last_day(add_months(first_date, 1)) as last_date
from months
where first_date < current_date
),
sample_dates (a_date) as (
select to_date('2017-01-15', 'YYYY-MM-DD') union all
select to_date('2017-01-22', 'YYYY-MM-DD') union all
select to_date('2017-02-01', 'YYYY-MM-DD') union all
select to_date('2017-04-15', 'YYYY-MM-DD') union all
select to_date('2017-06-15', 'YYYY-MM-DD')
)
select *
from sample_dates right join months on sample_dates.a_date between first_date and last_date
where sample_dates.a_date is null
Months is a recursive dynamic table that holds all months since 2017-01, with first and last day of the month. sample_dates is just a list of dates to test the logic - you should replace it with your own table.
Once you build that monthly calendar table all you need to do is check your dates against it using an outer query to see what dates are not between any of those periods between first_date and last_date columns.
You can build a TIMESERIES of all dates between the first input date and the last input date (The highest granularity of a TIMESERIES is the day.), and filter out only the months' first days out of that; then left join that created sequence of firsts of month with your input to find out where the join would fail, checking for NULLS from the input branch of the join:
WITH
-- your input
input(mth1st) AS (
SELECT DATE '2017-01-01'
UNION ALL SELECT DATE '2017-02-01'
UNION ALL SELECT DATE '2017-03-01'
UNION ALL SELECT DATE '2017-05-01'
UNION ALL SELECT DATE '2017-06-01'
UNION ALL SELECT DATE '2017-07-01'
UNION ALL SELECT DATE '2017-08-01'
UNION ALL SELECT DATE '2017-09-01'
UNION ALL SELECT DATE '2017-10-01'
UNION ALL SELECT DATE '2017-11-01'
UNION ALL SELECT DATE '2017-12-01'
UNION ALL SELECT DATE '2018-01-01'
UNION ALL SELECT DATE '2018-03-01'
UNION ALL SELECT DATE '2018-04-01'
UNION ALL SELECT DATE '2018-05-01'
UNION ALL SELECT DATE '2018-06-01'
UNION ALL SELECT DATE '2018-08-01'
UNION ALL SELECT DATE '2018-09-01'
UNION ALL SELECT DATE '2018-10-01'
UNION ALL SELECT DATE '2018-11-01'
UNION ALL SELECT DATE '2018-12-01'
UNION ALL SELECT DATE '2019-02-01'
UNION ALL SELECT DATE '2019-03-01'
UNION ALL SELECT DATE '2019-04-01'
)
,
-- need a series of month's firsts
-- TIMESERIES works for INTERVAL DAY TO SECOND
-- so build that timeseries, and filter out
-- the month's firsts
limits(mth1st) AS (
SELECT MIN(mth1st) FROM input
UNION ALL SELECT MAX(mth1st) FROM input
)
,
alldates AS (
SELECT dt::DATE FROM limits
TIMESERIES dt AS '1 day' OVER(ORDER BY mth1st::TIMESTAMP)
)
,
allfirsts(mth1st) AS (
SELECT dt FROM alldates WHERE DAY(dt)=1
)
SELECT
allfirsts.mth1st
FROM allfirsts
LEFT JOIN input USING(mth1st)
WHERE input.mth1st IS NULL;
-- out mth1st
-- out ------------
-- out 2017-04-01
-- out 2018-02-01
-- out 2018-07-01
-- out 2019-01-01
Let say i have this table
Date Inventory Sold
---------- --------------
14/04/2014 9
15/04/2014 21
16/04/2014 10
17/04/2014 20
18/04/2014 12
19/04/2014 25
20/04/2014 33
--and many more dates
how do i make it to a table like this
Date Range Inventory Sold
-------------- ----------------
xxx-xxx 50
xxx-xxx 44
the Date Range is suppose to be the range by week, eg: 14/04/2014 - 20/04/2014
Group your data by the date truncated to "whole weeks", like for example:
with data as (
select date '2014-04-14' sold_date, 9 inventory_sold from dual
union all
select date '2014-04-15', 21 from dual
union all
select date '2014-04-16', 10 from dual
union all
select date '2014-04-17', 20 from dual
union all
select date '2014-04-18', 12 from dual
union all
select date '2014-04-19', 25 from dual
union all
select date '2014-04-20', 33 from dual
union all
select date '2014-04-21', 1 from dual
)
select trunc(sold_date,'IW') week_start
, sum(inventory_sold)
from data
group by trunc(sold_date,'IW')
order by trunc(sold_date,'IW')
IW is ISO Week, meaning it uses monday-sunday weeks. Trunc(date,'IW') gives the monday of the week.
If you need to display the range, then you can use something like:
with data as (
select date '2014-04-14' sold_date, 9 inventory_sold from dual
union all
select date '2014-04-15', 21 from dual
union all
select date '2014-04-16', 10 from dual
union all
select date '2014-04-17', 20 from dual
union all
select date '2014-04-18', 12 from dual
union all
select date '2014-04-19', 25 from dual
union all
select date '2014-04-20', 33 from dual
union all
select date '2014-04-21', 1 from dual
)
select to_char(trunc(sold_date,'W'),'DD-MM-YY')
||'->'||
to_char(trunc(sold_date,'W')+6,'DD-MM-YY') week
, sum(inventory_sold)
from data
group by trunc(sold_date,'W')
order by trunc(sold_date,'W')
Hope this is useful :-)
Pointing you to:
WHERE
date >= 'selected_date_low'
AND date <= '$selected_date_high'