I can’t find out how to get data from an mplot3d graph. Something similar to the 2D style:
line.get_xdata()
Is it possible?
Line3D
You can get get the original data from the (private) _verts3d attribute
xdata, ydata, zdata = line._verts3d
print(xdata)
Complete example
import matplotlib as mpl
from mpl_toolkits.mplot3d import Axes3D
import numpy as np
import matplotlib.pyplot as plt
mpl.rcParams['legend.fontsize'] = 10
fig = plt.figure()
ax = fig.gca(projection='3d')
# Prepare arrays x, y, z
x = np.arange(5)
y = np.arange(5)*4
z = np.arange(5)*100
line, = ax.plot(x, y, z, label='curve')
fig.canvas.draw()
xdata, ydata, zdata = line._verts3d
print(xdata) # This prints [0 1 2 3 4]
plt.show()
Some explanation: The problem with get_data or get_xdata is that it will return the projected coordinates once the figure is drawn. So while before drawing the figure, line.get_xdata() would indeed return the correct values, after drawing, it would return something like
[ -6.14413090e-02 -3.08824862e-02 -3.33066907e-17 3.12113190e-02 6.27567511e-02]
in the above example, which is the x component of the 3D coordinates projected onto 2D.
There is a pull request to matplotlib, which would allow to get the data via methods get_data_3d. This is still not merged, but might allow the above to be done without using private arguments in a future version of matplotlib.
Poly3DCollection
For a plot_surface plot this looks similar, except that the attribute to look at is the ._vec
surf = ax.plot_surface(X, Y, Z)
xdata, ydata, zdata, _ = surf._vec
print(xdata)
This issue was filed on Github and there is contribution that adds new get_data_3d and set_data_3d methods. Unfortunately, these changes is likely not yet available in distributions. So you might have to continue using private variable line._verts3d.
See more here: https://github.com/matplotlib/matplotlib/issues/8914
Related
I am using the following snippet of code to make a scatterplot using seaborn:
import matplotlib.pyplot as plt
import seaborn as sns
plt.figure(figsize = (15,7))
sns.set()
plt.figure(figsize = (15,7))
sns.scatterplot(data = analysis_df, x = 'nota_percoftotal', y = 'post-pre')
plt.show()
This is the figure that I get:
As you can see, there is a stream of data points lying on the downwards sloping line. My question is, how can I know what these data points are in my dataset? My dataset looks something like this:
uni_const_code nota_percoftotal post-pre
1|9|95 34.337349 -15.637197
1|9|96 43.684211 -52.935894
1|9|97 42.857143 -14.455647
The column uni_const_code is the key in the dataset.
Edit 1: I used mplcursors making the following modifications:
fig, ax = plt.subplots()
x = analysis_df['nota_percoftotal']
y = analysis_df['post-pre']
line, = ax.plot(x, y, "to")
mplcursors.cursor(ax).connect("add", lambda sel: sel.annotation.set_text(labels[sel.target.index]))
plt.show()
But I still don't get what I want. The output is just a scattergram like before, I don't get anything even when I hover/click on the scatter dots.
I'm having issues with redrawing the figure here. I allow the user to specify the units in the time scale (x-axis) and then I recalculate and call this function plots(). I want the plot to simply update, not append another plot to the figure.
def plots():
global vlgaBuffSorted
cntr()
result = collections.defaultdict(list)
for d in vlgaBuffSorted:
result[d['event']].append(d)
result_list = result.values()
f = Figure()
graph1 = f.add_subplot(211)
graph2 = f.add_subplot(212,sharex=graph1)
for item in result_list:
tL = []
vgsL = []
vdsL = []
isubL = []
for dict in item:
tL.append(dict['time'])
vgsL.append(dict['vgs'])
vdsL.append(dict['vds'])
isubL.append(dict['isub'])
graph1.plot(tL,vdsL,'bo',label='a')
graph1.plot(tL,vgsL,'rp',label='b')
graph2.plot(tL,isubL,'b-',label='c')
plotCanvas = FigureCanvasTkAgg(f, pltFrame)
toolbar = NavigationToolbar2TkAgg(plotCanvas, pltFrame)
toolbar.pack(side=BOTTOM)
plotCanvas.get_tk_widget().pack(side=TOP)
You essentially have two options:
Do exactly what you're currently doing, but call graph1.clear() and graph2.clear() before replotting the data. This is the slowest, but most simplest and most robust option.
Instead of replotting, you can just update the data of the plot objects. You'll need to make some changes in your code, but this should be much, much faster than replotting things every time. However, the shape of the data that you're plotting can't change, and if the range of your data is changing, you'll need to manually reset the x and y axis limits.
To give an example of the second option:
import matplotlib.pyplot as plt
import numpy as np
x = np.linspace(0, 6*np.pi, 100)
y = np.sin(x)
# You probably won't need this if you're embedding things in a tkinter plot...
plt.ion()
fig = plt.figure()
ax = fig.add_subplot(111)
line1, = ax.plot(x, y, 'r-') # Returns a tuple of line objects, thus the comma
for phase in np.linspace(0, 10*np.pi, 500):
line1.set_ydata(np.sin(x + phase))
fig.canvas.draw()
fig.canvas.flush_events()
You can also do like the following:
This will draw a 10x1 random matrix data on the plot for 50 cycles of the for loop.
import matplotlib.pyplot as plt
import numpy as np
plt.ion()
for i in range(50):
y = np.random.random([10,1])
plt.plot(y)
plt.draw()
plt.pause(0.0001)
plt.clf()
This worked for me. Repeatedly calls a function updating the graph every time.
import matplotlib.pyplot as plt
import matplotlib.animation as anim
def plot_cont(fun, xmax):
y = []
fig = plt.figure()
ax = fig.add_subplot(1,1,1)
def update(i):
yi = fun()
y.append(yi)
x = range(len(y))
ax.clear()
ax.plot(x, y)
print i, ': ', yi
a = anim.FuncAnimation(fig, update, frames=xmax, repeat=False)
plt.show()
"fun" is a function that returns an integer.
FuncAnimation will repeatedly call "update", it will do that "xmax" times.
This worked for me:
from matplotlib import pyplot as plt
from IPython.display import clear_output
import numpy as np
for i in range(50):
clear_output(wait=True)
y = np.random.random([10,1])
plt.plot(y)
plt.show()
I have released a package called python-drawnow that provides functionality to let a figure update, typically called within a for loop, similar to Matlab's drawnow.
An example usage:
from pylab import figure, plot, ion, linspace, arange, sin, pi
def draw_fig():
# can be arbitrarily complex; just to draw a figure
#figure() # don't call!
plot(t, x)
#show() # don't call!
N = 1e3
figure() # call here instead!
ion() # enable interactivity
t = linspace(0, 2*pi, num=N)
for i in arange(100):
x = sin(2 * pi * i**2 * t / 100.0)
drawnow(draw_fig)
This package works with any matplotlib figure and provides options to wait after each figure update or drop into the debugger.
In case anyone comes across this article looking for what I was looking for, I found examples at
How to visualize scalar 2D data with Matplotlib?
and
http://mri.brechmos.org/2009/07/automatically-update-a-figure-in-a-loop
(on web.archive.org)
then modified them to use imshow with an input stack of frames, instead of generating and using contours on the fly.
Starting with a 3D array of images of shape (nBins, nBins, nBins), called frames.
def animate_frames(frames):
nBins = frames.shape[0]
frame = frames[0]
tempCS1 = plt.imshow(frame, cmap=plt.cm.gray)
for k in range(nBins):
frame = frames[k]
tempCS1 = plt.imshow(frame, cmap=plt.cm.gray)
del tempCS1
fig.canvas.draw()
#time.sleep(1e-2) #unnecessary, but useful
fig.clf()
fig = plt.figure()
ax = fig.add_subplot(111)
win = fig.canvas.manager.window
fig.canvas.manager.window.after(100, animate_frames, frames)
I also found a much simpler way to go about this whole process, albeit less robust:
fig = plt.figure()
for k in range(nBins):
plt.clf()
plt.imshow(frames[k],cmap=plt.cm.gray)
fig.canvas.draw()
time.sleep(1e-6) #unnecessary, but useful
Note that both of these only seem to work with ipython --pylab=tk, a.k.a.backend = TkAgg
Thank you for the help with everything.
All of the above might be true, however for me "online-updating" of figures only works with some backends, specifically wx. You just might try to change to this, e.g. by starting ipython/pylab by ipython --pylab=wx! Good luck!
Based on the other answers, I wrapped the figure's update in a python decorator to separate the plot's update mechanism from the actual plot. This way, it is much easier to update any plot.
def plotlive(func):
plt.ion()
#functools.wraps(func)
def new_func(*args, **kwargs):
# Clear all axes in the current figure.
axes = plt.gcf().get_axes()
for axis in axes:
axis.cla()
# Call func to plot something
result = func(*args, **kwargs)
# Draw the plot
plt.draw()
plt.pause(0.01)
return result
return new_func
Usage example
And then you can use it like any other decorator.
#plotlive
def plot_something_live(ax, x, y):
ax.plot(x, y)
ax.set_ylim([0, 100])
The only constraint is that you have to create the figure before the loop:
fig, ax = plt.subplots()
for i in range(100):
x = np.arange(100)
y = np.full([100], fill_value=i)
plot_something_live(ax, x, y)
I'm trying to get a colorbar for the following minimal example of my code.
g1 = gridspec.GridSpec(1, 1)
f, ((ax0)) = plt.subplots(1, 1)
ax0 = subplot(g1[0])
cmap = matplotlib.cm.get_cmap('viridis')
for i in linspace(0,1,11):
x = [-1,0,1]
y = [i,i,i]
rgba = cmap(i)
im = ax0.plot(x,y,color=rgba)
f.colorbar(im)
I also tried f.colorbar(cmap)
Probably pretty obvious, but I get errors such as
'ListedColormap' object has no attribute 'autoscale_None'
In reality, the value defining i is more complex, but I think this should do the trick. My data is plotted with plot and not with imshow (for which I know how to make the colormap).
The answers so far seem overly complicated. fig.colorbar() expects a ScalarMappable as its first argument. Often ScalarMappables are produced by imshow or contourplots and are readily avaible.
In this case you would need to define your custom ScalarMappable to provide to the colorbar.
import matplotlib.pyplot as plt
import numpy as np
fig, ax = plt.subplots()
cmap = plt.cm.get_cmap('viridis')
for i in np.linspace(0,1,11):
x = [-1,0,1]
y = [i,i,i]
rgba = cmap(i)
im = ax.plot(x,y,color=rgba)
sm = plt.cm.ScalarMappable(cmap=cmap)
sm.set_array([])
fig.colorbar(sm)
plt.show()
You should pass an Image or ContourSet when you call colorbar on a Figure.
You can make an image of the data points by calling plt.imshow with the data. You can start with this:
data = []
for i in np.linspace(0,1,11):
x = [-1,0,1]
y = [i,i,i]
rgba = cmap(i)
ax0.plot(x,y,color=rgba)
data.append([x, y])
image = plt.imshow(data)
figure.colorbar(image)
plt.show()
Reference:
https://matplotlib.org/api/figure_api.html#matplotlib.figure.Figure.colorbar
Oluwafemi Sule's solution almost works, but it plots the matrix into the same figure as the lines. Here a solution that opens a second figure, does the imshow call on that second figure, uses the result to draw the colorbar in the first figure, and then closes the second figure before calling plt.show():
import matplotlib
from matplotlib import pyplot as plt
from matplotlib import gridspec
import numpy as np
cmap = matplotlib.cm.get_cmap('viridis')
g1 = gridspec.GridSpec(1, 1)
f0, ((ax0)) = plt.subplots(1, 1)
f1, ((ax1)) = plt.subplots(1, 1)
for i in np.linspace(0,1,11):
x = [-1,0,1]
y = [i,i,i]
rgba = cmap(i)
ax0.plot(x,y,color=rgba)
data = np.linspace(0,1,100).reshape((10,10))
image = ax1.imshow(data)
f0.colorbar(image)
plt.close(f1)
plt.show()
The result looks like this:
I'm new to matplotlib, so I do not have strong enough command of the language to know if I'm going about this the right way, but I've been searching for the answer for a while now, and I just cannot find anything one way or the other on this.
I know how to use matplotlib's append_axes locator function to append histograms alongside 2D plots, e.g.:
axMain= fig1.add_subplot(111)
cax = plt.contourf(xl,y1,z1)
divider = make_axes_locatable(axMain)
axHisty = divider.append_axes("right", 1.2, pad=0.1, sharey=axMain)
axHisty.plot(x,y)
and I also know how to append a colorbar in a similar manner:
divider = make_axes_locatable(axMain)
ax_cb = divider.new_horizontal(size='5%', pad=0.3)
fig1.add_axes(ax_cb)
fig1.colorbar(cax, cax=ax_cb)
What I am not clear on is how to do both in the same subplot without the two appended figures overlapping. To be clear, I want the histogram to have the same yaxis ticks and height as the axContour, and I want the colorbar to have the same height as axContour. ImageGrid doesn't seem to be quite what I want because I do not want to fix the size of my plot. It would better for me if I could add/remove these figure "embellishments" interactively, but maybe that is not possible...Let me know!
You are already fixing the size of your plot with divider.append_axes("right", 1.2, pad=0.1, sharey=axMain). 1.2 is the size of the new axis. Below is a way of plotting three axes using gridspec.
import matplotlib.pyplot as plt
import numpy as np
import matplotlib.gridspec as grd
from numpy.random import rand
# add axes
fig1 = plt.figure(1)
gs = grd.GridSpec(1, 3, width_ratios=[5,1, 1], wspace=0.3)
axMain = plt.subplot(gs[0])
axHisty = plt.subplot(gs[1])
ax_cb = plt.subplot(gs[2])
# some things to plot
x = [1,2,3,4]
y = [1,2,3,4]
x1 = [1,2,3,4]
y1 = [1,2,3,4]
z1 = rand(4,4)
# make plots
h = axMain.contourf(x1,y1,z1)
axHisty.plot(x,y)
cb = plt.colorbar(h, cax = ax_cb)
plt.show()
I have created a histogram with matplotlib using the pyplot.hist() function. I would like to add a Poison error square root of bin height (sqrt(binheight)) to the bars. How can I do this?
The return tuple of .hist() includes return[2] -> a list of 1 Patch objects. I could only find out that it is possible to add errors to bars created via pyplot.bar().
Indeed you need to use bar. You can use to output of hist and plot it as a bar:
import numpy as np
import pylab as plt
data = np.array(np.random.rand(1000))
y,binEdges = np.histogram(data,bins=10)
bincenters = 0.5*(binEdges[1:]+binEdges[:-1])
menStd = np.sqrt(y)
width = 0.05
plt.bar(bincenters, y, width=width, color='r', yerr=menStd)
plt.show()
Alternative Solution
You can also use a combination of pyplot.errorbar() and drawstyle keyword argument. The code below creates a plot of the histogram using a stepped line plot. There is a marker in the center of each bin and each bin has the requisite Poisson errorbar.
import numpy
import pyplot
x = numpy.random.rand(1000)
y, bin_edges = numpy.histogram(x, bins=10)
bin_centers = 0.5*(bin_edges[1:] + bin_edges[:-1])
pyplot.errorbar(
bin_centers,
y,
yerr = y**0.5,
marker = '.',
drawstyle = 'steps-mid-'
)
pyplot.show()
My personal opinion
When plotting the results of multiple histograms on the the same figure, line plots are easier to distinguish. In addition, they look nicer when plotting with a yscale='log'.