Divide result of 2 queries element wis - sql

Question

I can't find a way to divide the result of my 2 queries.
They look like that :
SELECT periode, cee_ref_no, SUM(somme) AS total FROM V_STAT_NAMUR
WHERE code_ref_no IN (1, 2, 3, 4, 5, 6, 193, 215, 237, 259, 281)
AND periode BETWEEN '201401' AND '201412'
AND cee_ref_no = '961'
GROUP BY periode, cee_ref_no
ORDER BY periode;
AND
SELECT periode, cee_ref_no, SUM(somme) AS total FROM V_STAT_NAMUR
WHERE code_ref_no IN (7, 8, 9, 10, 205, 227, 249, 271, 293)
AND periode BETWEEN '201401' AND '201412'
AND cee_ref_no = '961'
GROUP BY periode, cee_ref_no
ORDER BY periode;
They look pretty similar, and both return something like this :
DATE | CEE_REF_NO | TOTAL
201401 | 961 | 10713
201402 | 961 | 9593
... | 961 | ...
201412 | 961 | 10426
How can I merge these to obtain something like this :
DATE | CEE_REF_NO | TOTAL
201401 | 961 | Total Q1/ Total Q2
201402 | 961 | Total Q1/ Total Q2
... | 961 | ...
201412 | 961 | Total Q1/ Total Q2
Everything I tried returned either only one row, or 12 rows with the same result.
Thanks a lot !

Answer 1

You can try with this:
select q1.periode, q1.cee_ref_no, q1.total as Total1, q2.total as Total2, q1.total/q2.total as Division
from (
SELECT periode, cee_ref_no, SUM(somme) AS total FROM V_STAT_NAMUR
WHERE code_ref_no IN (1, 2, 3, 4, 5, 6, 193, 215, 237, 259, 281)
AND periode BETWEEN '201401' AND '201412'
AND cee_ref_no = '961'
GROUP BY periode, cee_ref_no
) q1
join (
SELECT periode, cee_ref_no, SUM(somme) AS total FROM V_STAT_NAMUR
WHERE code_ref_no IN (7, 8, 9, 10, 205, 227, 249, 271, 293)
AND periode BETWEEN '201401' AND '201412'
AND cee_ref_no = '961'
GROUP BY periode, cee_ref_no
) q2
on q1.Periode=q2.Periode
and q1.cee_ref_no=q2.cee_ref_no
Basicaly you have just to create 2 subselect with your queries and join them by period and cee_ref_no (in case you were going to include more than 1 cee_ref_no, in your example there is just one). Then you will be able to divide the Total from q1 and q2.
Take care about the join, I don't know if your data will have information for all the months in both queries.
PS: Query not tested, written directly on editor.

Answer 2

Use conditional aggregation:
SELECT periode, cee_ref_no,
SUM(CASE WHEN code_ref_no IN (1, 2, 3, 4, 5, 6, 193, 215, 237, 259, 281) THEN somme ELSE 0 END) AS total_1,
SUM(CASE WHEN code_ref_no IN (7, 8, 9, 10, 205, 227, 249, 271, 293) THEN somme ELSE 0 END) AS total_2,
(SUM(CASE WHEN code_ref_no IN (1, 2, 3, 4, 5, 6, 193, 215, 237, 259, 281) THEN somme ELSE 0 END) /
SUM(CASE WHEN code_ref_no IN (7, 8, 9, 10, 205, 227, 249, 271, 293) THEN sommeEND)
) AS ratio
FROM V_STAT_NAMUR
WHERE AND
periode BETWEEN '201401' AND '201412'
GROUP BY periode, cee_ref_no
ORDER BY periode;

Answer 3

Try this
Select periode, cee_ref_no, total1/total2 as Total
From (
SELECT periode, cee_ref_no,
sum(Case when code_ref_no in (1, 2, 3, 4, 5, 6, 193, 215, 237, 259, 281) Then somme else 0 end) as total1,
sum(Case when code_ref_no in (7, 8, 9, 10, 205, 227, 249, 271, 293) Then somme else 0 end) as total2
From my_table
WHERE code_ref_no IN (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 193, 205, 215, 227, 237, 249, 259, 271, 281, 293)
AND periode BETWEEN '201401' AND '201412'
AND cee_ref_no = '961'
GROUP BY periode, cee_ref_no
)
ORDER BY periode;