I have three tabels, each of them has a date column (the date column is an INT field and needs to stay that way). I need a UNION accross all three tables so that I get the list of unique dates in accending order like this:
20040602
20051215
20060628
20100224
20100228
20100422
20100512
20100615
Then I need to add a column to the result of the query where I subtract one from each date and place it one row above as the end date. Basically I need to generate the end date from the start date somehow and this is what I got so far (not working):
With Query1 As (
Select date_one As StartDate
From table_one
Union
Select date_two As StartDate
From table_two
Union
Select date_three e As StartDate
From table_three
Order By Date Asc
)
Select Query1.StartDate - 1 As EndDate
From Query1
Thanks a lot for your help!
Building on your existing union cte, we can use lead() in the outer query to get the start_date of the next record, and withdraw 1 from it.
with q as (
select date_one start_date from table_one
union select date_two from table_two
union select date_three from table_three
)
select
start_date,
dateadd(day, -1, lead(start_date) over(order by start_date)) end_date
from q
order by start_date
If the datatype the original columns are numeric, then you need to do some casting before applying date functions:
with q as (
select cast(cast(date_one as varchar(8)) as date) start_date from table_one
union select cast(cast(date_two as varchar(8)) as date) from table_two
union select cast(cast(date_three as varchar(8)) as date) from table_three
)
select
start_date,
dateadd(day, -1, lead(start_date) over(order by start_date)) end_date
from q
order by start_date
Fields:
Student_ID, Department, Start_Date
ex:
1,A, 2017-01-1
1,B, 2017-07-1
1,C, 2017-12-1
Expected Output:
Student_ID, Department, Start_Date, End_Date
ex:
1,A, 2017-01-1, 2017-07-01
1,B, 2017-07-1,2017-12-01
1,C, 2017-12-1, ...
End_Date is the start Date of the next record for the student ID
Give a row_number based on student_id and order by start_date. And use a join.
Query
with cte as(
select row_number() over(
partition by Student_ID
order by Start_Date asc
) as rn, *
from your_table_name
)
select t1.Student_ID, t1.Department, t1.Start_Date,
t2.Start_Date as end_date
from cte t1
left join cte t2
on t1.rn = t2.rn - 1
and t1.Student_Id = t2.Student_Id;
Find demo here
SELECT student_id,department_id, start_date,
LEAD(start_date, 1) OVER (PARTITION BY student_id ORDER BY start_date) AS "End_Date"
FROM Your_Table
You can use Lead() function as above
I have a table and each record has a date. We can assume that a date range is contiguous if there's not a 3 month break. How can I find the start of the most recent contiguous date range?
For example, imagine if I had this data:
1990-5-1
1990-6-4
1990-10-28
1990-11-14
1990-12-19
1991-1-20
1991-4-30
1991-5-13
I'd like for it to return 1991-4-30 because it's the start of the most recent contiguous range of dates.
I think this does what you're looking for. Using my own table and column names as test data. This is on Oracle.
select * from (
select * from sm_ss_tickets t1 where exists (
select * from sm_ss_tickets t2 where t2.created_date between t1.created_date and t1.created_date+90 and t1.rowid <> t2.rowid
) order by created_date asc
) where rownum = 1;
Maybe something like the following would work:
WITH d1 AS (
SELECT date'1990-05-01' AS dt FROM dual
UNION ALL
SELECT date'1990-06-04' AS dt FROM dual
UNION ALL
SELECT date'1990-10-28' AS dt FROM dual
UNION ALL
SELECT date'1990-11-14' AS dt FROM dual
UNION ALL
SELECT date'1990-12-19' AS dt FROM dual
UNION ALL
SELECT date'1991-01-20' AS dt FROM dual
UNION ALL
SELECT date'1991-04-30' AS dt FROM dual
UNION ALL
SELECT date'1991-05-13' AS dt FROM dual
)
SELECT MAX(dt) FROM (
SELECT dt, LAG(dt) OVER ( ORDER BY dt ) AS prev_dt, LEAD(dt) OVER ( ORDER BY dt ) AS next_dt
FROM d1
) WHERE ( dt > ADD_MONTHS(prev_dt, 3) OR prev_dt IS NULL )
AND dt > ADD_MONTHS(next_dt, -3)
In the above, a date can only be the start of a contiguous sequence if there is no prior date within 3 months (either it is more than three months ago or it doesn't exist at all) and there is also a subsequent date within 3 months.
You can use LAG and LEAD. Find the query below. I think it works fine.
tmp_year is the table I have created. tdate is the column.
The records in the table are
28-JAN-15
27-JAN-15
26-JAN-15
25-JAN-15
12-JUL-14
11-JUL-14
10-JUL-14
09-JUL-14
24-DEC-13
23-DEC-13
22-DEC-13
21-DEC-13
15-SEP-13
07-JUN-13
27-FEB-13
19-NOV-12
11-AUG-12
Please find the query which returns 25th Jan 2015.
select max(d.tdate) from (
select c.tdate,c.next_date,c.date_diff,lag(date_diff) over( order by tdate) prev_diff from (
select b.tdate ,b.next_date,(next_date-tdate) date_diff from
(select a.tdate,lead(a.tdate) over(order by a.tdate) next_date from tmp_year a ) b ) c) d where d.date_diff<90 and d.prev_diff>=90;
I have following table tbl in database and I have dynamic joining date 1-1-2012 and I want this date is between (Fall and spring) or (spring and summer) or (summer and fall).I want query in which i passed only joining date which return semestertime and joining date in Oracle.
Semestertime joiningDate
Fall 10-13-2011
Spring 2-1-2012
Summer 6-11-2012
Fall 10-1-2015
If I understand your question correctly:
SELECT *
FROM your_table
WHERE joiningDate between to_date (your_lower_limit_date_here, 'mm-dd-yyyy')
AND to_date (your_upper_limit_date_here, 'mm-dd-yyyy`);
What about something like that:
select 'BEFORE' term,
t."Semestertime", to_char(t."joiningDate", 'MM-DD-YYYY')
from (
select tbl.*, rownum rn from tbl where tbl."joiningDate" < to_date('1-1-2012','MM-DD-YYYY')
-- ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
-- your reference date
order by tbl."joiningDate" desc) t
where rn = 1
union all
select 'AFTER' term,
t."Semestertime", to_char(t."joiningDate", 'MM-DD-YYYY')
from (
select tbl.*, rownum rn from tbl where tbl."joiningDate" > to_date('1-1-2012','MM-DD-YYYY')
-- ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
-- your reference date
order by tbl."joiningDate" asc) t
where rn = 1
This will return the "term" before and after a given date. You will probably have to adapt such query to your specific needs. But that might be a good starting point.
For example, given your business rules, you might consider using <= instead of <. You you might require to have the result displayer a column instead of rows. Bu all of this shouldn't be too had to change.
As an alternate solution using CTE and sub-queries:
with testdata as (select to_date('1-1-2012','MM-DD-YYYY') refdate from dual)
select v.what, tbl.* from tbl join
(
select 'BEFORE' what, max(t1."joiningDate") d
from tbl t1
where t1."joiningDate" < to_date('1-1-2012','MM-DD-YYYY')
union all
select 'AFTER' what, min(t1."joiningDate") d
from tbl t1
where t1."joiningDate" > to_date('1-1-2012','MM-DD-YYYY')
) v
on tbl."joiningDate" = v.d
See http://sqlfiddle.com/#!4/c7fa5/15 for a live demo comparing those solutions.
I have a table of the sort:
USER | PLAN | START_DATE | END_DATE
1 | A | 20110101 | NULL
1 | B | 20100101 | 20101231
2 | A | 20100101 | 20100505
In a way that if END_DATE is null, means that this user has that plan currently active.
What I want to query is:
(a) the current plan he has active, or (b) the lastest plan he was into. I need only one row returned for each given user.
Now, I managed to do that in using unions and sub queries, but it happens that table is massive and these are not efficient enough.
Would any of you guys have a quicker way to query that?
Thanks,
[EDIT]
Most answers here return a single value. That was my bad. What I meant was to return a single value per user but all users at once. I've adapted the answers I could (and corrected the question) but just making it clear for future reference.
This question is a little hard to answer without further information about the data and the table. When you say in your comment that you have all the indexes that you need, what are these indexes?
Also, are the time periods abutting and non-overlapping? Can you just get the period with the latest START_DATE?
The problem with looking at END_DATE is that a normal B-Tree index doesn't index NULLs. So, a predicate of the form where end_date is nulll is unlikely to use the index. You could use a bitmap index with the column as those type of indexes do index nulls but that might not be ideal because of some of the other drawbacks of bitmap indexes.
For the reasons given above, I would probably use a query similar to the one below:
select user, plan, start_date, end_date
from (
select
user,
plan,
start_date,
end_date,
row_number() over (partition by user order start_date desc) as row_num_1,
row_number() over (partition by user order end_date desc nulls first) as row_num_2
from user_table
where user = :userid
)
where row_num_1 = 1
You could probably use either the row_num_1 or the row_num_2 column here depending on the exact requirements.
OR
select user, plan, start_date, end_date
from (
select
user,
plan,
start_date,
end_date,
from user_table
where user = :userid
order by start_date desc
)
where rownum = 1
The first query should work whether you are trying get all the users back or just one. The second query will only work with one user.
If you can augment the question with more details of the schema (indexes, meaning of the start/end date) you are likely to get better answers.
CREATE TABLE XY
( USERID INTEGER NOT NULL
, PLAN VARCHAR2(8) NOT NULL
, START_DATE DATE NOT NULL
, END_DATE DATE )
TABLESPACE USERS;
INSERT INTO XY ( USERID, PLAN, START_DATE, END_DATE )
VALUES ( 1, 'A', To_Date('22-05-2011 00:00:00', 'DD-MM-YYYY HH24:MI:SS'), To_Date('22-05-2011 00:00:00', 'DD-MM-YYYY HH24:MI:SS') );
INSERT INTO XY ( USERID, PLAN, START_DATE, END_DATE )
VALUES ( 1, 'B', To_Date('01-04-2011 00:00:00', 'DD-MM-YYYY HH24:MI:SS'), NULL );
INSERT INTO XY ( USERID, PLAN, START_DATE, END_DATE )
VALUES ( 2, 'A', To_Date('03-05-2011 00:00:00', 'DD-MM-YYYY HH24:MI:SS'), To_Date('04-05-2011 00:00:00', 'DD-MM-YYYY HH24:MI:SS') );
INSERT INTO XY ( USERID, PLAN, START_DATE, END_DATE )
VALUES ( 2, 'B', To_Date('15-05-2011 00:00:00', 'DD-MM-YYYY HH24:MI:SS'), To_Date('20-05-2011 00:00:00', 'DD-MM-YYYY HH24:MI:SS') );
COMMIT WORK;
SELECT USERID, PLAN, END_DATE, START_DATE
FROM (SELECT USERID,
PLAN,
END_DATE,
START_DATE,
ROW_NUMBER() OVER(PARTITION BY USERID ORDER BY END_DATE DESC) SEQUEN
FROM XY)
WHERE SEQUEN < 2
This may help:
SELECT user,plan,end_date,start_date
FROM ( SELECT users,plans,end_date,start_date, DENSE_RANK() OVER ( PARTITION BY user
ORDER BY end_date DESC) sequen
FROM table_name
)
WHERE sequen <= 2
Have you tried to limit the resultset with rownum?
select plan
from (
select plan
from YourTable
where User = 1
order by
case when end_date is null then '99991231' else end_date end desc
)
where rownum < 2
AFAIK Using CASE and sub queries will cause your query to become very slow. So better to use them with care. How About:
SELECT User, Plan, start_Date, MAX(End_Date) FROM Plans WHERE User NOT IN
(SELECT User FROM Plans WHERE End_Date IS NULL)
GROUP BY Start_Date, Plan, User
UNION
SELECT User,Plan,Start_Date FROM Plans WHERE End_Date IS NULL
I'm not a SQL guru. consider this just as a suggestion.
Hope this helps.
Does this work?
SELECT U.user
,(SELECT Plan FROM t WHERE t.user=u.user AND end_date IS NULL LIMIT 1) AS Current_Plan
,(SELECT Plan FROM t WHERE t.user=u.user AND end_date IS NOT NULL ORDER BY end_date DESC LIMIT 1) AS Last_Plan
FROM
( SELECT DISTINCT USER FROM t ) AS U
If it is slow, please send us the EXPLAIN output for the query.
How about this?
select PLAN
from USER_TABLE
where END_DATE is null or END_DATE = (
select max(END_DATE)
from USER_TABLE
where USER = 1 and END_DATE is not null)
and USER = 1
I suggest the following :
with t as
(select 1 as col_id, 1 as USER_id, 'A' as PLAN , 20110101 as START_DATE, NULL as END_DATE from dual union all
select 2,1,'B', 20100101,20101231 from dual union all
select 3,2,'A', 20100102,20100505 from dual union all
select 4,2,'C', 20100101,20100102 from dual)
--
SELECT user_id, plan
FROM (SELECT user_id,
plan,
MAX(nvl(END_DATE, 99999999)) over(PARTITION BY user_id) max_date,
nvl(END_DATE, 99999999) END_DATE
FROM t)
WHERE max_date = end_date