PDO Access Query - sql

Question

Hi everyone I've some problems with a PDO query in access.
$result1 = $database->prepare('SELECT * FROM tblDestinazioni INNER JOIN tblRagioneSociale ON tblDestinazioni.id_cliente = tblRagioneSociale.id_cliente');
//$result1->execute(array(':nrags' => $rag, ':ndrags' => $nuovadest));
$result1->execute();
in this way it works, but i have to insert two more conditions... so:
$result1 = $database->prepare('SELECT * FROM tblDestinazioni INNER JOIN tblRagioneSociale ON tblDestinazioni.id_cliente = tblRagioneSociale.id_cliente WHERE tblDestinazioni.nome_dest=ndrags AND tblRagioneSociale.nomer=nrags');
$result1->execute(array(':nrags' => $rag, ':ndrags' => $nuovadest));
But it doesn't work (It returns to me a wrong result).
Please help me,
Thanks a lot
tblDestinazioni:
id_destinazioni INT AUTO_INCREMENT(PK)
id_cliente INT(FK)
nome_dest VARCHAR(30)
tblRagioneSociale:
id_cliente INT(PK)
rags VARCHAR(30)
more code:
<?php
$db_username = ''; //username
$db_password = ''; //password
$database_path = "Z:\\2017datiW.mdb";
$database = new PDO("odbc:DRIVER={Microsoft AccessDriver(*.mdb)}; DBQ=$database_path; Uid=$db_username; Pwd=$db_password;");
$rag=$_POST["rag"];
$nuovadest=$_POST["nuovadest"];
$result1 = $database->prepare('SELECT * FROM tblDestinazioni INNER JOIN tblRagioneSociale ON tblDestinazioni.id_cliente = tblRagioneSociale.id_cliente');
$result1->execute(array(':nrags' => $rag, ':ndrags' => $nuovadest));
?>