I have the below Query
SELECT distinct
COUNT(Status) AS [Transactions],
left(DATENAME(mm, Date_Reported), 3) AS Month,
DATENAME(yyyy, Date_Reported) AS Year
FROM [Transactions]
GROUP BY DATENAME(mm, Date_Reported), DATENAME(yyyy,Date_Reported)
ORDER BY Year, Month DESC;
My output is as below:
Transaction | Month | Year
123 | Jan | 2000
1234 | Mar | 2000
12 | Feb | 2000
How can I alter the query so I can get the month and year together like "Jan 2000" and then order it by the date so Jan 2000, Feb 2000 and Mar 2000
Thank you in advance
I think you want :
SELECT COUNT(Status) AS [Transactions], t1.MonthYear
FROM [Transactions] t
CROSS APPLY ( VALUES (CONCAT(DATENAME(mm, Date_Reported),' ',
DATENAME(yyyy, Date_Reported)),
DATEPART(mm, Date_Reported)
)
) t1 (MonthYear, Morder)
GROUP BY t1.MonthYear, t1.Morder
ORDER BY t1.Morder;
Related
I have a SQLite database and sales table is like the following,
| Id | quantity | dateTime |
------------------------------------
| 1 | 10 | 2019-12-25 12:55 |
| 2 | 05 | 2019-12-30 12:55 |
| 3 | 25 | 2020-08-23 12:55 |
| 4 | 25 | 2020-08-24 12:55 |
| 5 | 56 | 2020-08-25 12:55 |
| 6 | 25 | 2020-08-26 12:55 |
| 7 | 12 | 2020-08-27 12:55 |
| 8 | 30 | 2020-08-28 12:55 |
| 9 | 40 | 2020-08-29 12:55 |
I need to get the Current Week data (Mon to Sun) and the Current Year data from (Jan to Dec). So if I pass today date I need to get only the Current Week sales data group by days like the following,
If I pass today date and time (2020-08-28 13:55) the query should give me Current Week data like this,
Day Sold Items (SUM(quantity))
Monday 20
Tuesday 25
Wednesday 10
Thursday 50
Friday 60
Saturday 0 (If the date hasn't come yet I need to get 0)
Sunday 0
And same as the Current Year data when I pass the Current Date,
Month Sold Items (SUM(quantity))
JAN 20
FEB 25
MAR 10
APR 50
MAY 60
JUN 0 (If the month hasn't come yet I need to get 0)
JUL 0
... ...
I tried with multiple queries in SQLite but couldn't get what I need. Here are the queries I tried,
Weekly Data (This one gave me past week data also)
SELECT SUM(quantity) as quantity, strftime('%w', dateTime) as Day
From sales
Group by strftime('%w', dateTime)
Monthly Data
SELECT SUM(quantity) as quantity, strftime('%m', dateTime) as Month
From sales
Group by strftime('%m', dateTime)
So anybody can help me to achieve this? Thanks in advance.
For the totals of the current week you need a CTE that returns the names of the days and the another one that returns the Monday of the current week.
You must cross join these CTEs and left join your table to aggregate:
with
days as (
select 1 nr, 'Monday' day union all
select 2, 'Tuesday' union all
select 3, 'Wednesday' union all
select 4, 'Thursday' union all
select 5, 'Friday' union all
select 6, 'Saturday' union all
select 7, 'Sunday'
),
weekMonday as (
select date(
'now',
case when strftime('%w', 'now') <> '1' then '-7 day' else '0 day' end,
'weekday 1'
) monday
)
select d.day,
coalesce(sum(t.quantity), 0) [Sold Items]
from days d cross join weekMonday wm
left join tablename t
on strftime('%w', t.dateTime) + 0 = d.nr % 7
and date(t.dateTime) between wm.monday and date(wm.monday, '6 day')
group by d.nr, d.day
order by d.nr
For the totals of the current year you need a CTE that returns the month names and then left join the table to aggregate:
with
months as (
select 1 nr, 'JAN' month union all
select 2 nr, 'FEB' union all
select 3 nr, 'MAR' union all
select 4 nr, 'APR' union all
select 5 nr, 'MAY' union all
select 6 nr, 'JUN' union all
select 7 nr, 'JUL' union all
select 8 nr, 'AUG' union all
select 9 nr, 'SEP' union all
select 10 nr, 'OCT' union all
select 11 nr, 'NOV' union all
select 12 nr, 'DEC'
)
select m.month,
coalesce(sum(t.quantity), 0) [Sold Items]
from months m
left join tablename t
on strftime('%m', t.dateTime) + 0 = m.nr
and date(t.dateTime) between date('now','start of year') and date('now','start of year', '1 year', '-1 day')
group by m.nr, m.month
order by m.nr
You can use the below query to get the weekly date, I am assuming that everydate has single entry and hence not grouping otherwise you can add group by.
First we will get the weekly calendar based on the input date (I have taken current date)
and then left join with calendar to get the required sold items info.
WITH seq(n) AS
(
SELECT 0 UNION ALL SELECT n + 1 FROM seq
WHERE n < DATEDIFF(DAY, (SELECT DATEADD(DAY, 2 - DATEPART(WEEKDAY, GETDATE()), CAST(GETDATE() AS DATE)) [Week_Start_Date]), (Select DATEADD(DAY, 8 - DATEPART(WEEKDAY, GETDATE()), CAST(GETDATE() AS DATE)) [Week_End_Date]))
),
CALENDAR(d) AS
(
SELECT DATEADD(DAY, n, (SELECT DATEADD(DAY, 2 - DATEPART(WEEKDAY, GETDATE()), CAST(GETDATE() AS DATE)) [Week_Start_Date])) FROM seq
)
SELECT coalesce(QUANTITY, 0) sold_items ,DATENAME(WEEKDAY, d) week_day FROM CALENDAR a left outer join Table_WEEKDAY b
on (a.d = convert(date, b.dateTime))
ORDER BY d
OPTION (MAXRECURSION 0);
You can try the below - DEMO
select day,coalesce(sum(quantity),0) as quantity
from
(select 0 as day union all select 1 union all select 2 union all select 3 union all select 4
union all select 5 union all select 6) as d
left join sales on cast(strftime('%w', dateTime) as int)=day
group by strftime('%w', dateTime),day
order by day
How can i use SQL and SUM monthly data (quarter view)? I will not use Stored Procedures etc.
Current data:
ID | Sales
201601 | 5
201602 | 15
201603 | 5
201604 | 20
201605 | 8
201606 | 2
...
My ID column is like yyyymm
What I want is:
Quarter | Sales
Q1 | 25
Q2 | 30
....
You can try a query like below
SELECT
LEFT(ID,4) Year,
'Q'+ CAST((CAST(RIGHT(ID,2) AS INT)-1 )/3 +1 AS varchar) Quarter,
SUM(Sales) Sales
FROM
Yourtable
GROUP BY
LEFT(ID,4),
'Q'+ CAST((CAST(RIGHT(ID,2) AS INT) -1 )/3 +1 AS varchar)
order by year
SQL demo link
You can use DATEPART and QUARTER to get the quarter of a DATETIME. You just need to build the DATETIME using DATEFROMPARTS and parsing your ID column.
The CONCAT just adds 'Q' to the period number.
SELECT LEFT(id,4) [Year],
CONCAT('Q',DATEPART(QUARTER, DATEFROMPARTS(LEFT(id,4), RIGHT(id, 2), 1))) [Quarter],
SUM(Sales) [Sales]
FROM yourtable
GROUP BY LEFT(id,4), DATEPART(q, DATEFROMPARTS(LEFT(id,4), RIGHT(id, 2), 1))
ORDER BY [Year], [Quarter]
I have a table with a date column. I wanted to get the count of months and display them in the order of months. Months should be displayed as 'Jan', 'Feb' etc. If I use to_char function, the order by happens on text. I can use extract(month from dt), but that will also display month in number format. This is part of a report and month should be displayed in 'Mon' format only.
SELECT to_char(dt,'Mon'), COUNT(*) FROM tb GROUP BY to_char(dt,'Mon') ORDER BY to_char(dt,'Mon');
to_char | count
---------+-------
Dec | 1
Jan | 1
Jul | 2
select month, total
from (
select
extract(month from dt) as month_number,
to_char(dt,'mon') as month,
count(*) as total
from tb
group by 1, 2
) s
order by month_number
I need to get monthly count of distinct customers based on last three month Sales.
To show the result by adding current month customer count and adding last three month customer to the count as below:
In month of APRIL ,distinct customers count of (APRIL+MARCH+FEBRUARY)
In month of MAY,distinct customers count of (MAY+APRIL+MARCH)
In month of JUNE,distinct customers count of (JUNE+MAY+APRIL)
In month of JULY,distinct customers count of (JULY+JUNE+MAY)
Here what I tried:
SELECT MonNumber = MONTH(h.Invoicedate) ,
YearNumber = YEAR(h.Invoicedate) ,
PartyCount = ( SELECT COUNT(DISTINCT s.CustomerID)
FROM salesdata s
WHERE s.Invoicedate BETWEEN DATEADD(month, -6,
h.Invoicedate)
AND h.Invoicedate
)
FROM salesdata h
GROUP BY MONTH(h.Invoicedate) ,
YEAR(h.Invoicedate)
ORDER BY YEAR(h.Invoicedate) ,
MONTH(h.Invoicedate)
| Year | Month | COUNT |
|-----------|----------|-------------|
| 2014 | Jan | 6 |
| 2014 | Feb | 6 |
| 2014 | Mar | 6 |
| 2014 | Apr | 4 |
| 2014 | May | 6 |
| 2014 | Jun | 6 |
View the table on SQL Fiddle
Here it is.
WITH dt AS (
-- set invoice to BOM to get one row per month
SELECT DISTINCT DATEADD(mm,DATEDIFF(mm,0,InvoiceDate),0) AS InvoiceDate
FROM salesdata
)
SELECT YEAR(dt.InvoiceDate) AS YEAR
, MONTH(dt.InvoiceDate) AS MONTH
, COUNT(DISTINCT CustomerId) AS PARTYCOUNT
FROM salesdata s
INNER JOIN dt
-- Define your window
ON s.InvoiceDate >= DATEADD(MM, -2, dt.InvoiceDate)
AND s.InvoiceDate < DATEADD(MM, 1, dt.InvoiceDate)
GROUP BY YEAR(dt.InvoiceDate)
, MONTH(dt.InvoiceDate)
ORDER BY 1, 2
You need to apply some aggregate function to invoicedate.
This should work: fiddle
SELECT
-- get the first of the current month and substract two months
dateadd(month, -2, DATEADD(day, -day(h.Invoicedate) + 1, h.Invoicedate)) as first_of_month,
PartyCount = ( SELECT COUNT(DISTINCT s.CustomerID)
FROM salesdata s
WHERE s.Invoicedate >= dateadd(month, -2, DATEADD(day, -day(h.Invoicedate) + 1, h.Invoicedate))
AND s.Invoicedate < min(dateadd(month, 1, DATEADD(day, -day(h.Invoicedate) + 1, h.Invoicedate)))
)
FROM salesdata h
group by
dateadd(month, -2, DATEADD(day, -day(h.Invoicedate) + 1, h.Invoicedate))
order by 1
I would prefer to create a table with the month names and date ranges first and then simply use this instead.
I have a table with "date" column. Each row represents a survey.
date
11/19/2013 5:51:41 PM
11/22/2013 1:30:38 PM
11/23/2013 3:09:17 PM
12/2/2014 5:24:17 PM
12/25/2014 11:42:56 AM
1/6/2014 2:24:49 PM
I want to count the number of survey per month cumulatively. As you see from the above table, there are 3 surveys for Nov 2013, 2 surveys for Dec 2013, 1 survey for Jan 2014. The cumulative number of survey per month would be:
month | year | number_of_survey
11 | 2013 | 3
12 | 2013 | 5
1 | 2014 | 6
I have this query which shows correct number of surveys for 2013, and number of survey for 2014 is not cumulative.
with SurveyPerMonth as -- no of Survey per month
(
select datepart(month, s.date) as month,
datepart(year, s.date) as year,
count(*) as no_of_surveys
from myTable s
group by datepart(year, s.date), datepart(month, s.date)
)
select p1.month, p1.year, sum(p2.no_of_surveys) as surveys -- cumulatively
from SurveyPerMonth p1
inner join SurveyPerMonth p2 on p1.month >= p2.month and p1.year>=p2.year **-- the problem is probably comes from this line of code**
group by p1.month, p1.year
order by p1.year, p1.month;
This query returns:
month | year | surveys
11 | 2013 | 3
12 | 2013 | 5
1 | 2014 | 1 // 2014 is not cumulative
How can I calculate cumulative number of surveys per month for 2014 as well?
Something like this ?
SELECT date = create_date INTO #myTable FROM master.sys.objects
;WITH perMonth ( [year], [month], [no_of_surveys])
AS (SELECT DatePart(year, s.date) ,
DatePart(month, s.date),
COUNT(*)
FROM #myTable s
GROUP BY datepart(year, s.date),
datepart(month, s.date))
SELECT [year],
[month],
[no_of_surveys] = ( SELECT SUM([no_of_surveys])
FROM perMonth agg
WHERE (agg.[year] < pm.[year])
OR (agg.[year] = pm.[year] AND agg.[month] <= pm.[month]))
FROM perMonth pm
ORDER BY [year], [month]
Edit: seems I missed the ball with < and >, fixed it and added small example
'--This should work.I have added a new column 'monthyear'
with surveypermonth as -- no of survey per month
(
select datepart(month, s.date) as month,
datepart(year, s.date) as year,
datepart(year, s.date) *100 + datepart(month, s.date) as monthyear,
count(*) as no_of_surveys
from test s
group by datepart(year, s.date), datepart(month, s.date),datepart(year, s.date)*100 + datepart(month, s.date)
)
select a.month,substring(cast(monthyear as varchar(6)),1,4) as year,surveys from
(
select p1.month, p1.monthyear as monthyear, sum(p2.no_of_surveys) as surveys
from surveypermonth p1
inner join surveypermonth p2 on p1.monthyear>=p2.monthyear
group by p1.month, p1.monthyear
--order by p1.monthyear, p1.month
)a