I want to place edge labels on a specified position in my graph. I found that i can manipulate the labels position with text-margin-x and text-margin-y but to calculate the needed margins I need to know the current position of the label. I already tried using source-label and the position of the source node but this means that text-events no longer work.
Is there a way to get/calculate the position of the label on segments edges?
Furthermore to help me align certain labels I need to know how to get/calculate the bounding box of the edge label, is there a way to do this?
Any help is appreciated!
I found that i can use edge.midpoint() to get the location of the label.
For the size of the label I use a workaround where I render everything once to get the labelHeight and labelWidth from rstyle and then I rerender everything correctly.
Related
I want to set the width and height of a mpld3 plot to a specific value (in pixels, so it fits the div it is in). The way I tried it looks like this (javascript):
commands["width"]=plotWidth;
commands["height"]=plotHeight;
mpld3.draw_figure("plotname",commands);
plotWidth and plotHeight the values I want the height and width to be set to.
Now, this actually sets the size of the mpld3-figure object to the values I want, but the plot inside still keeps its old size, so it looks like nothing happened.
So, how do I change the size of the plot itself? So far it looks like whatever I do, the plot does not change.
You can change the shape of an mpld3 plot when creating a figure with the python code plt.figure(figsize=(width,height)) (where width and height are in inches). Here is a notebook demonstrating this.
There has been some interest in making mpld3 figures "responsive", which would be a cooler and more precise way to accomplish your goal, but so far no one has tried making the necessary code changes. Patches welcome!
I don't think this is possible out of the box but wanted to make sure.
We'd like to do the following.
Take any image input and force the output width to be a fixed size. If the width is less than the output width, we'd like to center the image and add horizontal padding to the image but not add vertical padding.
For example
Original image is 700px x 400px
Final output size of 1000px width x 400px. This would include 150px padding left and 150px padding right (no top / bottom padding).
I know that we can upscale the image (scale=both) or set the canvas scale (but that adds top / bottom padding) or we could add padding to the image but none are really what we want.
Thanks for any help
Response to Nathanael
Your comments are exactly correct.
I expected http://z.zr.io/ri/red-leaf.jpg?width=1000&scale=canvas&bgcolor=gray to work exactly as it does
Yes, our problem is that the image heights are not known beforehand, but it's good to know that this works with a known height
I think it would be great if there was a command for scale=padwidth that would work with variable heights. Or a setting for padwidth=true and padheight=false that could be used in conjunction with scale=canvas.
So, let's say that you're given an 800x600px image, and you apply ?width=1000&scale=canvas. You were expecting that this would produce a 1000x600px image, but instead it produced a 1000x750px image, right?
http://z.zr.io/ri/red-leaf.jpg?width=1000&scale=canvas&bgcolor=gray
If you specify the height explicitly, the padding goes away - but you may not know the image height beforehand, correct?
http://z.zr.io/ri/red-leaf.jpg?width=1000&scale=canvas&bgcolor=gray&height=600
What would be the least surprising behavior - maintaining aspect ratio, or only adding the minimum padding required? How would you expect this to behave, or be exposed as a command?
I'm trying to get and set the position of a draggable legend in matplotlib. My application consists of an interactive GUI, which has a redraw/plot function that should perform the follow steps:
save the position of the current legend.
clear the current axes and perform various plotting operations, which may or may add labels to their plots.
build a new draggable legend (ax.legend().draggable()) and restore the old position of the legend.
In between these steps the user is free to drag the legend around, and the goal is to persist the legend position when the plots are redrawn.
My first approach was to use oldpos = legend.get_bbox_to_anchor() and legend.set_bbox_to_anchor(oldpos) in steps 1 and 3. However this causes to move the legend completely off the visible area.
Note that I have to use ax.legend() and cannot use fig.legend(lines, labels), since step 2 is completely decoupled, i.e., I don't know anything about lines and labels in step 3. According to answers to the question How to position and align a matplotlib figure legend? there seems to be a difference between these two possibilities regarding axes or figure coordinates. Obviously my problem calls for figure coordinates, but I haven't fully understood how to convert the bbox to a "bbox in figure coordinates".
The even more severe problem I just realized is that apparently legend.get_bbox_to_anchor() always seems to return the same values irrespective of the drag position. So maybe the anchor can only be (ab-)used to manipulate the position of static legends? Is there another/proper way to save and restore the position of a draggable legend?
By looking at the implementation of Legend I found out that there is an undocumented property _loc, which exactly does what I want. My solution now looks astonishingly simple:
oldLegPos = ax.get_legend()._loc
# perform all plotting operations...
legend = ax.legend().draggable()
legend._loc = oldLegPos
It looks like _loc automatically stores figure coordinates, since I do not have to convert the coordinates in any way (eg. when the plotting operations completely change the axes ranges/coordinates).
I am using core plot to make a line graph for my iPhone app. So far I successfully made the line graph from my xml data.
Furthermore I added a text layer that shows the value (for example 40) once I select the cell
holding the value 40. For this, I use the function:
(CPTLayer *)dataLabelForPlot:(CPTPlot *)plot recordIndex:(NSUInteger)index
So now I want to have a vertical line on the graph to indicate the selected value (the 40). I tried adding CPTBarplot but somehow the bars show only at the beginning of the graph axis.
Is there a function from core plot like the above that will create a line indicator?
I would appreciate if someone can give me some hint how to solve this problem and thank you very much in advance.
You could use a scatter plot for that. There's a point selection demo in the Mac CPTTestApp that draws a crosshair over the selected point. It would be trivial to modify that to only draw the vertical line.
The -numberOfRecordsForPlot: datasource method returns the number of points in the selection indicator (5 for the crosshairs) or zero (0) if there is no current selection. The -numberForPlot:field:recordIndex: method returns the points in the indicator. The points are drawn in this order:
Left
Right
Center (with plot symbol)
Top
Bottom
The -symbolForScatterPlot:recordIndex: method controls the plot symbol in the center. You can eliminate this method if you don't need any symbols on the indicator plot.
I want to get the PlotArea width and height in order to calculate the proportion.
I used ActiveChart.PlotArea.Width to get the width, and then tested the width using Photoshop.
I discovered that the width returned by ActiveChart.PlotArea.Width is wrong.
Image shows what I am talking about:
I have no Idea why...
Please help me to understand why it happens and how to fix it...
Thanks!
PlotArea.Width is returning the width in points not pixels.
http://msdn.microsoft.com/en-us/library/ff198324.aspx
Points are a unit of length. Pixels are variable on a number of factors like monitor, fonts, truefont settings, ect. Here is a SO post about converting pixels to points: Convert Pixels to Points