how to get first day and last day of a quarter for a date?
and also first day and last day of 2 quarters back for a date in Hive or sql
for example for Feb 03 2014 first day and last day of the quarter will be
Jan 01 2014 and Mar 31 2014
and for the same date first and last day of 2 quarters back will be Jul 01 2013 and Sep 31 2013
You can accomplish this in the following way (not too fancy, but there is no direct way). To make it simpler, I just concatenated both output dates
-- before Hive 1.3
select
case
when ceil(month(mydate)/ 3.0) = 1 then concat("Jan 01 ",year(mydate),"|","Mar 31 ",year(mydate))
when ceil(month(mydate)/ 3.0) = 2 then then concat("Apr 01 ",year(mydate),"|","Jun 30 ",year(mydate))
when ceil(month(mydate)/ 3.0) = 3 then then concat("Jul 01 ",year(mydate),"|","Sep 30 ",year(mydate))
when ceil(month(mydate)/ 3.0) = 4 then then concat("Oct 01 ",year(mydate),"|","Dec 31 ",year(mydate))
else
null
end,
ceil(month(mydate)) as quarter
from (
select
from_unixtime(unix_timestamp('Feb 03 2014' , 'MMM dd yyyy')) as mydate
) t;
--Hive 1.3 or higher
select
case
when quarter(mydate) = 1 then concat("Jan 01 ",year(mydate),"|","Mar 31 ",year(mydate))
when quarter(mydate) = 2 then then concat("Apr 01 ",year(mydate),"|","Jun 30 ",year(mydate))
when quarter(mydate) = 3 then then concat("Jul 01 ",year(mydate),"|","Sep 30 ",year(mydate))
when quarter(mydate) = 4 then then concat("Oct 01 ",year(mydate),"|","Dec 31 ",year(mydate))
else
null
end,
ceil(month(mydate)) as quarter
from (
select
from_unixtime(unix_timestamp('Feb 03 2014' , 'MMM dd yyyy')) as mydate
) t;
just replace the hardcoded date for your column in the select in the inner query
Related
Need this table as output
DECLARE #ADate DATETIME
SET #ADate = GETDATE()
SELECT DAY(EOMONTH(#ADate)) AS DaysInMonth
Output: Jan 31 (I got only one month’s output. I need all the months in 2022 and their days)
You can do something like this:
WITH months AS
(
SELECT 1 AS MONTH
UNION ALL
SELECT MONTH + 1
FROM months
WHERE MONTH < 12
)
SELECT CAST(DATENAME(month, CONCAT("2022-" , months.MONTH, "-01")) AS CHAR(3)) AS 'MONTH' , DAY(EOMONTH(CONCAT("2022-" , months.MONTH, "-01"))) as DAY FROM months
Output:
MONTH
DAY
Jan
31
Feb
28
Mar
31
Apr
30
May
31
Jun
30
Jul
31
Aug
31
Sep
30
Oct
31
Nov
30
Dec
31
Create a row generator from 1 to 12 using WITH ,after that is just formating the output
You can view the result here: https://onecompiler.com/sqlserver/3yurzpsnm
I have a table with one row
employee(date)
date
52 week in 2021
23 week in 2022
34 week in 2021
1 week in 2022
52 week in 2022
I tried the below query but it's not working
select date from employee order by date desc
I want to order by in desc for above column. I'm expecting output like below
date
52 week in 2022
23 week in 2022
1 week in 2022
52 week in 2021
34 week in 2021
Extracting year and week part and then performing sort:
SELECT *
FROM tab
ORDER BY RIGHT(date,4) DESC, CAST(LEFT(date,2) AS INT) DESC
I have a table of location which has 'Date column'. I have to find recent date by each group of locationID for e.g. locationID 1 has most recent date '31 May 2022'. After finding recent date from the group of locationID I have to add 14 days in that recent date and store it in NewDate column. and add + 1 in that new date for other row for that group of locationID.
My table is:
id locationID Date NewDate
1 1 31 May 2022
2 1 16 May 2022
3 1 28 Apr 2021
4 2 29 Mar 2022
5 2 22 Feb 2022
6 3 14 Jun 2022
7 3 27 Oct 2021
8 4 01 Feb 2022
9 4 04 May 2022
10 4 14 Jun 2021
11 5 01 Jun 2022
12 5 29 May 2022
13 5 20 Sep 2022
14 5 11 Aug 2022
15 5 03 Aug 2022
Answer should be as below:
For e.g. for locationID = 1
id locationID Date NewDate
1 1 31 May 2022 14 Jun 2022 // Recent Date + 14 Days - 31 May + 14 Days
2 1 16 May 2022 15 Jun 2022 // Recent Date + 15 Days - 31 May + 15 Days
3 1 28 Apr 2021 16 Jun 2022 // Recent Date + 16 Days - 31 May + 16 Days
I have come across few similar post and found recent date like this:
SELECT L.*
FROM Locations L
INNER JOIN
(SELECT locationID, MAX(Date) AS MAXdate
FROM Locations
GROUP BY locationID) groupedL
ON L.locationID = groupedL.locationID
AND L.Date = groupedL.MAXdate
using above code I am able to find recent date per location but how do I add and increment required days and store it to NewDate column ? I am new to MariaDB, please suggest similar post link, any reference documents or blogs. Should I make some function to perform this logic and call the function to store required dates in NewDate column? I am not sure please suggest. Thank you.
RESULT SHOULD LOOK LIKE BELOW:
id locationID Date NewDate
1 1 31 May 2022 14 Jun 2022 // Recent Date for locationid 1 + 14 Days - 31 May + 14 Days
2 1 16 May 2022 15 Jun 2022 // Recent Date for locationid 1 + 15 Days - 31 May + 15 Days
3 1 28 Apr 2021 16 Jun 2022 // Recent Date for locationid 1 + 16 Days - 31 May + 16 Days
4 2 29 Mar 2022 12 APR 2022 // Recent Date for locationid 2 + 14 Days
5 2 22 Feb 2022 13 APR 2022 // Recent Date for locationid 2 + 15 Days
6 3 14 Jun 2022 28 JUN 2022 // Recent Date for locationid 3 + 14 Days
7 3 27 Oct 2021 29 JUN 2022 // Recent Date for locationid 3 + 15 Days
8 4 01 Feb 2022 18 MAY 2022 // Recent Date for locationid 4 + 14 Days
9 4 04 May 2022 19 MAY 2022 // Recent Date for locationid 4 + 15 Days
10 4 14 Jun 2021 20 MAY 2022 // Recent Date for locationid 4 + 16 Days
11 5 01 Jun 2022 04 OCT 2022 // Recent Date for locationid 5 + 14 Days
12 5 29 May 2022 05 OCT 2022 // Recent Date for locationid 5 + 15 Days
13 5 20 Sep 2022 06 OCT 2022 // Recent Date for locationid 5 + 16 Days
14 5 11 Aug 2022 07 OCT 2022 // Recent Date for locationid 5 + 17 Days
15 5 03 Aug 2022 08 OCT 2022 // Recent Date for locationid 5 + 18 Days
You can use a cte:
with cte as (
select l1.*, l2.m, (select sum(l4.id < l1.id and l4.locationid = l1.locationid) from locations l4) inc from locations l1
join (select l3.locationid, max(l3.dt) m from locations l3 group by l3.locationid) l2 on l1.locationid = l2.locationid
)
select c.id, c.locationid, c.dt, c.m + interval 14 + c.inc day from cte c
You could use analytic window functions and update the original table by joining to a sub-query (works for MariaDB):
update t
join (
select Id,
Date_Add(First_Value(date) over(partition by locationId order by date desc),
interval (13 + row_number() over(partition by locationId order by date desc)) day
) NewDate
from t
)nd on t.id = nd.id
set t.Newdate = nd.NewDate;
See DB<>Fiddle example
I have table like below
customer
date
end date
1
jan 1 2021
jan 30 2021
1
jan 2 2021
jan 31 2021
1
jan 3 2021
feb 1 2021
1
jan 27 2021
feb 26 2021
1
feb 3 2021
mar 5 2021
2
jan 2 2021
jan 31 2021
2
jan 10 2021
feb 9 2021
2
feb 10 2021
mar 12 2021
Now, I wanted to update the value in the 'end date' column of a row based on the values in the previous row 'end date' and the current row 'date'.
Say if the date in current row < end date of the previous row, I wanted to update the end date of the current row = (end date of the previous row).
I Wanted to do this repeated for all the rows (grouped by customer).
I want the output as below. Just need it in the select statement instead of a updating/inserting in a table.
Note - in below as the second row(end date) is updated with the value in the first row (jan 30 2021), now the third row value (jan 3 2021) is evaluated against the updated value in the second row (which is jan 30 2021) but not with the second row value before update (jan 31 2021).
customer
date
end date
1
jan 1 2021
jan 30 2021
1
jan 2 2021
jan 30 2021 [updated because current date < previous end date]
1
jan 3 2021
jan 30 2021[updated because current date < previous end date]
1
jan 27 2021
jan 30 2021 [updated because current date < previous end date]
1
feb 3 2021
mar 5 2021
2
jan 2 2021
jan 31 2021
2
jan 10 2021
jan 31 2021[updated because current date < previous end date]
2
feb 10 2021
mar 12 2021
I think I should go this way. I use the datasource twice just to get the way its needed to perform the operation without updating or inserting into the table.
input table:
1|2021-01-01|2021-01-30
1|2021-01-02|2021-01-31
1|2021-01-03|2021-02-01
1|2021-01-27|2021-02-26
1|2021-02-03|2021-03-05
2|2021-01-02|2021-01-31
2|2021-01-10|2021-02-09
2|2021-02-10|2021-03-12
code:
with num_raw_data as (
SELECT row_number() over(partition by customer)as num, customer,date_init,date_end
FROM `project-id.data-set.table`
), analyzed_data as(
select r.num,
r.customer,
r.date_init,
r.date_end,
case when date_init<(select date_end from num_raw_data where num=r.num-1 and customer=r.customer and EXTRACT(month FROM r.date_init)=EXTRACT(month FROM date_init)) then 1 else 0 end validation
from num_raw_data r
)
select customer,
date_init,
case when validation !=0 then (select MIN(date_end) from analyzed_data where validation=0 and customer=ad.customer and date_init<ad.date_end) else date_end end as date_end
from analyzed_data ad
order by customer,num
output:
1|2021-01-01|2021-01-30
1|2021-01-02|2021-01-30
1|2021-01-03|2021-01-30
1|2021-01-27|2021-01-30
1|2021-02-03|2021-03-05
2|2021-01-02|2021-01-31
2|2021-01-10|2021-01-31
2|2021-02-10|2021-03-12
Using column validation from analyzed_data to get to know where I should be looking for changes. I'm not sure if its fast (probably not) but it works for the scenario you bring in your question.
I have a table like this
Date Year Month Day Turn_1 Turn_2 Turn_3
28/08/2014 2014 08 28 Foo Bar Xab
And i would like to "rotate" it in something like this:
Date Year Month Day Turn Source
28/08/2014 2014 08 28 Foo Turn_1
28/08/2014 2014 08 28 Bar Turn_2
28/08/2014 2014 08 28 Xab Turn_3
I need the "Source" column because i need to join this results to another table that say:
Source Interval
Turn_1 08 - 18
Turn_2 11 - 20
Turn_3 18 - 24
For now i have use unpivot to rotate the table, but i dont know how to display the "Source" column (and if it is possible):
select dt_date, df_year, df_month, df_turn
from my_rotatation_table
unpivot( df_turn
for x in(turn_1,
turn_2,
turn_3
))
SOLVED:
select dt_date, df_year, df_month, df_turn, df_source
from my_rotatation_table
unpivot( df_turn
for df_source in(turn_1 as 'Turn_1',
turn_2 as 'Turn_2',
turn_3 as 'Turn_3'
))
Use this query:
with t (Dat, Year, Month, Day, Turn_1, Turn_2, Turn_3) as (
select sysdate, 2014, 08, 28, 'Foo', 'Bar', 'Xab' from dual
)
select dat, year, month, day, turn, source from t
unpivot (
source for turn in (Turn_1, Turn_2, Turn_3)
)
DAT YEAR MONTH DAY TURN SOURCE
----------------------------------------------
08/01/2014 2014 8 28 TURN_1 Foo
08/01/2014 2014 8 28 TURN_2 Bar
08/01/2014 2014 8 28 TURN_3 Xab