Calculate time diffrence in SQL with shifts - sql

Question

i have two table
the first table contains the record of a ticket with start date and end date
start_date | End_Date
21-02-2017 07:52:32 | 22-02-2017 09:56:32
21-02-2017 09:52:32 | 23-02-2017 17:52:32
the second table contains the details of the weekly shift:
shift_day | Start_Time | End_Time
MON 9:00 18:00
TUE 10:00 19:00
WED 9:00 18:00
THU 10:00 19:00
FRI 9:00 18:00
I am looking to get the time difference in the first table which will only include the time as per the second table.

Answer 1

Use a recursive sub-query factoring clause to generate each day within your time ranges and then correlate that with your shifts to restrict the time for each day to be within the shift hours and then aggregate to get the total:
Oracle 18 Setup:
CREATE TABLE times ( start_date, End_Date ) AS
SELECT DATE '2017-02-21' + INTERVAL '07:52:32' HOUR TO SECOND,
DATE '2017-02-22' + INTERVAL '09:56:32' HOUR TO SECOND
FROM DUAL
UNION ALL
SELECT DATE '2017-02-21' + INTERVAL '09:52:32' HOUR TO SECOND,
DATE '2017-02-23' + INTERVAL '17:52:32' HOUR TO SECOND
FROM DUAL;
CREATE TABLE weekly_shifts ( shift_day, Start_Time, End_Time ) AS
SELECT 'MON', INTERVAL '09:00' HOUR TO MINUTE, INTERVAL '18:00' HOUR TO MINUTE FROM DUAL UNION ALL
SELECT 'TUE', INTERVAL '10:00' HOUR TO MINUTE, INTERVAL '19:00' HOUR TO MINUTE FROM DUAL UNION ALL
SELECT 'WED', INTERVAL '09:00' HOUR TO MINUTE, INTERVAL '18:00' HOUR TO MINUTE FROM DUAL UNION ALL
SELECT 'THU', INTERVAL '10:00' HOUR TO MINUTE, INTERVAL '19:00' HOUR TO MINUTE FROM DUAL UNION ALL
SELECT 'FRI', INTERVAL '09:00' HOUR TO MINUTE, INTERVAL '18:00' HOUR TO MINUTE FROM DUAL;
Query 1:
WITH days ( id, start_date, day_start, day_end, end_date ) AS (
SELECT ROWNUM,
start_date,
start_date,
LEAST( TRUNC( start_date ) + INTERVAL '1' DAY, end_date ),
end_date
FROM times
UNION ALL
SELECT id,
start_date,
day_end,
LEAST( day_end + INTERVAL '1' DAY, end_date ),
end_date
FROM days
WHERE day_end < end_date
)
SELECT start_date,
end_date,
SUM( shift_end - shift_start ) AS days_worked_on_shift
FROM (
SELECT ID,
start_date,
end_date,
GREATEST( day_start, TRUNC( day_start ) + start_time ) AS shift_start,
LEAST( day_end, TRUNC( day_start ) + end_time ) AS shift_end
FROM days d
INNER JOIN
weekly_shifts w
ON ( TO_CHAR( d.day_start, 'DY' ) = w.shift_day )
)
GROUP BY id, start_date, end_date;
Result:
START_DATE END_DATE DAYS_WORKED_ON_SHIFT
------------------- ------------------- --------------------
2017-02-21 07:52:32 2017-02-22 09:56:32 0.414259259259259259
2017-02-21 09:52:32 2017-02-23 17:52:32 1.078148148148148148