i am relatively new to SQL and I'm looking to create a query that states how many records were created by those other than a certain "good" group of users (userids). If possible grouped by month as well. Any suggestions? I have some basic logic set out below.
Table is called newcompanies
SELECT COUNT(record_num), userid
FROM Newcompanies
WHERE userID <> (certain group of userIds)
GROUP BY Month
Will i be required to create a second table where the group of "good" userids is held
There are a few ways to do this. Without knowing your exact columns, this will be a rough estimate.
SELECT id,
DATEPART(MONTH, created_date) AS created_month,
COUNT(*)
FROM your_table
WHERE id NOT IN(
--hardcode userID's here
)
GROUP BY
id,
DATEPART(MONTH, created_date)
Or you could have a table with your good id's and then exclude those.
SELECT id,
DATEPART(MONTH, created_date) AS created_month,
COUNT(*)
FROM your_table
WHERE id NOT IN(
SELECT id
from your_good_id_table
)
GROUP BY
id,
DATEPART(MONTH, created_date)
-- if month is not a field in the table you will have to do a function to parse out the month that will depend on the sql database you are using, if it is MS SQL you can do Month(datefield)
SELECT COUNT(record_num), userid, Month
FROM Newcompanies
WHERE userID NOT IN (
Select UserID
from ExcludeTheseUserIDs
)
GROUP BY Month, userid
Related
I have the following query that allows me to aggregate the number of unique sellers/buyers for every single day from the Flipside API:
SELECT
date_trunc('day', block_timestamp) AS date,
COUNT(DISTINCT(seller_address)) AS unique_sellers,
COUNT(DISTINCT(buyer_address)) AS unique_buyers
FROM ethereum.core.ez_nft_sales
GROUP BY date
Now, I've been trying a lot of different things, but I can't for the life of me figure out how it would be possible to get the number of unique active addresses on a given day as I would need to somehow merge the sellers and buyers and then count the unique addresses. I would greatly appreciate any kind of help. Thanks in advance!
This is how I managed to solve the issue by using a separate query for the unique_active and merging them:
WITH
other_values AS (
SELECT
date_trunc('day', block_timestamp) AS date,
COUNT(DISTINCT seller_address) AS unique_sellers,
COUNT(DISTINCT buyer_address) AS unique_buyers
FROM ethereum.core.ez_nft_sales
GROUP BY date
),
unique_addresses AS (
SELECT
date,
COUNT(*) as unique_active
FROM (
SELECT
date_trunc('day', block_timestamp) as date,
seller_address as address
FROM ethereum.core.ez_nft_sales
GROUP BY date, seller_address
UNION
SELECT
date_trunc('day', block_timestamp) as date,
buyer_address as address
FROM ethereum.core.ez_nft_sales
GROUP BY date, buyer_address
)
GROUP BY date
)
SELECT * FROM other_values
LEFT JOIN unique_addresses
ON other_values.date = unique_addresses.date
ORDER BY other_values.date DESC
I need to group different years in my dataset so that I can see the total number of login_log_id each year has(BigQuery)
SELECT login_log_id,
DATE(login_time) as login_date,
EXTRACT(YEAR FROM login_time) as login_year,
TIME(login_time) as login_time,
FROM `steel-time-347714.flex.logs`
GROUP BY login_log_id
I want to make a group by so that I can see total number of login_log_id generated in different years.
My columns are login_log_id, login_time
I am getting following error :-
SELECT list expression references column login_time which is neither grouped nor aggregated at [2:6]
The error is because every column you refer to in the select need to be aggregated or be in the GROUP BY.
If you want the total logins by year, you can do:
SELECT
EXTRACT(YEAR FROM login_time) as login_year,
COUNT(1) as total_logins,
COUNT(DISTINCT login_log_id) as total_unique_logins
FROM `steel-time-347714.flex.logs`
GROUP BY login_year
But if you want the total by login_log_id and year:
SELECT
login_log_id,
EXTRACT(YEAR FROM login_time) as login_year,
COUNT(1) as total_logins
FROM `steel-time-347714.flex.logs`
GROUP BY login_log_id, login_year
This is a sample data file
Data Contains unique IDs with different latitudes and longitudes on multiple timestamps.I would like to select the rows of latest 30 days of coordinates for each unique ID.Please help me on how to run the query .This date is in Hive table
Regards,
Akshay
According to your example above (where no current year dates for id=2,3), you can numbering date for each id (order by date descending) using window function ROW_NUMBER(). Then just get latest 30 values:
--get all values for each id where num<=30 (get last 30 days for each day)
select * from
(
--numbering each date for each id order by descending
select *, row_number()over(partition by ID order by DATE desc)num from Table
)X
where num<=30
If you need to get only unique dates (without consider time) for each id, then can try this query:
select * from
(
--numbering date for each id
select *, row_number()over(partition by ID order by new_date desc)num
from
(
-- move duplicate using distinct
select distinct ID,cast(DATE as date)new_date from Table
)X
)Y
where num<=30
In Oracle this will be:
SELECT * FROM TEST_DATE1
WHERE DATEUPDT > SYSDATE - 30;
select * from MyTable
where
[Date]>=dateadd(d, -30, getdate());
To group by ID and perform aggregation, something like this
select ID,
count(*) row_count,
max(Latitude) max_lat,
max(Longitude) max_long
from MyTable
where
[Date]>=dateadd(d, -30, getdate())
group by ID;
I have a table with the following columns:
Date
Skills,
Customer ID
I want to find out Date(x), Customers, Count of Customers in between Date(x) and Date(x)+6
Can somebody guide me how to make this query, or can I create this function in SQL Server?
If I understand you correctly, you want something like this:
(take care, can be bad syntax, because i "work" only with oracle. But I think that it should work)
select date, customer_id, COUNT(*)
from your_table --add your table
where date between getdate() and DATEADD(day, 6, getdate())
-- between current database system date and +6 day
group by date, customer id
order by COUNT (*) desc -- if you want, you can order your result - ASC||DESC
If you have data on each date, then perhaps this is what you want:
select date, count(*),
sum(count(*)) over (order by date rows between 6 preceding and current row) as week_count
from t
group by date;
having table
id|date|somefield
I need to get count of entries for each day of the year
select EXTRACT (DAY_OF_YEAR FROM date) as day, id from table
works fine
but when I try
select EXTRACT (DAY_OF_YEAR FROM date) as day, count(*) from table
fails
select count(*) from table group by EXTRACT (DAY_OF_YEAR FROM date)
fails as well
You need to add a group by expression. Here is some pseudo code, I will work up a SqlFiddle in a moment.
select EXTRACT (DAY_OF_YEAR FROM date) as day,
count(*)
from table
group by EXTRACT (DAY_OF_YEAR FROM date)
SQLFIDDLE (Using MYSQL) http://sqlfiddle.com/#!2/42c9e/10