The following snippet retrieves all artists (names) from around the world using the dbpedia.org database.
prefix dbo: <http://dbpedia.org/ontology/>
select distinct (str(?name_) as ?name) {
?artist a dbo:Artist ;
rdfs:label ?name_ .
}
What I would like to do next, is extend this snippet so that a) I filter by a certain city and b) present the following optional fields:
name (this works already)
city name
birth date
sub class (e.g. Actor, MusicalArtist etc.)
dbo:birthDate will give you the birth date of the artist.
dbo:birthPlace will give you the birth place of the artist.
rdf:type / dbc:subject will give you all the roles that the artist have. Be careful, this one can be tremendous. Perhaps should you refine your research (Yago, dbc, dbo, wikidata, ...).
Here is an example of artists born in Pinner and their birthDate :
prefix dbo: <http://dbpedia.org/ontology/>
select distinct (str(?name_) as ?name) ?birthPlace ?birthDate {
?artist a dbo:Artist ;
rdfs:label ?name_ .
?artist dbo:birthPlace ?birthPlace .
?artist dbo:birthDate ?birthDate .
filter(?birthPlace = dbr:Pinner)
}
Related
I want to get the information the title of a book with the most authors.
I have used the following query, however I get blank back. If I take them out individually, for example only using title info I will get some type of data, but having the two together I don't.
PREFIX dct: <http://purl.org/dc/terms/>
PREFIX dc: <http://purl.org/dc/elements/1.1/>
SELECT ?creators ?title (count(?book) as ?count)
WHERE
{ ?creators dct:creator ?book .
?title dc:title ?book .
}
group by ?creators ?title order by desc(?count)
new to SPARQL. Trying to figure out why I get different results on these two queries. It's based on this other question, where I'm trying to match properties to a name of a person. For example, I'm curious to know the birthday of J.K. Rowling, without knowing her URI directly. Here's the code from the link above:
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX dbo: <http://dbpedia.org/ontology/>
SELECT DISTINCT *
WHERE
{
?item rdfs:label ?itemLabel .
FILTER ( ?itemLabel = "Car"#en ) .
?item dbo:abstract ?itemDescription .
FILTER (lang(?itemDescription) = 'en')
}
ORDER BY ?itemLabel
compared to the query I'd like with J.K.:
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX dbo: <http://dbpedia.org/ontology/>
SELECT DISTINCT *
WHERE
{
?item rdfs:label ?itemLabel .
FILTER ( ?itemLabel = "J.K. Rowling"#en ) .
?item dbo:abstract ?itemDescription .
FILTER (lang(?itemDescription) = 'en')
}
ORDER BY ?itemLabel
The first one works fine, however, when I replace "Car" with "J.K. Rowling" as in the second, nothing is returned (her URI is return if I remove the dbo:abstract line and the filter line for it). J.K. Rowling does have a dbo:abstract in English. I'm not sure why it works for one and not the other. The only thing I can see that that 'Car' is a 'Thing', while J.K. is a 'person'
I'm new to SPARQL and I'm a bit stuck on a part of an assignment I have. I'm querying dbpedia for all the countries in the European Union which have a total population >= 3000000. For each country I'd like to show their corresponding government type. I would like the final result set to contain 3 columns:
the English label for each country
the English label for each type of government
the total population value
and then sorted descending on the total population.
PREFIX dct: <http://purl.org/dc/terms/>
PREFIX dbo: <http://dbpedia.org/ontology/>
PREFIX dbp: <http://dbpedia.org/property/>
PREFIX dbrc: <http://dbpedia.org/resource/Category:>
SELECT DISTINCT ?country xsd:integer(?populationTotal) ?government_type ?engName ?gov_type
WHERE {
?country dct:subject dbrc:Member_states_of_the_European_Union ;
a dbo:Country ;
rdfs:label ?engName .
OPTIONAL { ?country dbo:governmentType ?government_type . ?government_type rdfs:label ?gov_type . }
OPTIONAL { ?country dbo:populationTotal ?populationTotal . }
FILTER (xsd:integer(?populationTotal) >= 3000000 && langMatches(lang(?engName), "en"))
FILTER (langMatches(lang(?gov_type), "en"))
} ORDER BY DESC(?populationTotal)
I've managed to get dbpedia to return all the info I need, however I'd like to only keep the columns above in bulletpoints and not the country column. I know there should be a way to return that country directly with the label however I'm having troubles getting any closer to a solution...
I am trying to select all people born in a specific country (e.g. Portugal) from DBPedia.
I could use this query:
SELECT DISTINCT ?person
WHERE {
?person dbpedia-owl:birthPlace dbpedia:Portugal.
}
But the problem is that not all people have dbpedia:Portugal as birthPlace. About 30% of people have just a town name as birthPlace, e.g.
dbpedia:Lisbon
I could add all Portugal cities in a FILTER clause but it's a big list.
May be it's possible to infer Portugal from Lisbon in the SPARQL query somehow?
(to not to add all Portugal cities in FILTER to get ALL persons)
If we assume all the cities in a specific country are defined as part of that country in dbpedia, you could have a query that first looks for the people that have dbpedia:Portugal as a country and then cities within dbpedia:Portugal.
SELECT DISTINCT ?person
WHERE {
?person a dbpedia-owl:Person.
Optional{
?person dbpedia-owl:birthPlace ?country.
}
Optional{
?person dbpedia-owl:birthPlace ?place.
?place dbpedia-owl:country ?country
}
filter(?country= dbpedia:Portugal)
}
The query that you have written identifies 1723 distinct URIs, and this finds 2563 URIs.
Artemis' answer works, but it's very verbose for what's a pretty simple query. It can be simplified to:
select distinct ?person where {
?person a dbpedia-owl:Person ;
dbpedia-owl:birthPlace/dbpedia-owl:country? dbpedia:Portugal
}
SPARQL results (2449)
Full results may be achieved by this http://answers.semanticweb.com/questions/22450/sparql-selecting-people-by-country
- 2730 persons
PREFIX dbpedia-owl: <http://dbpedia.org/ontology/>
PREFIX dbpedia: <http://dbpedia.org/resource/>
SELECT ?person
WHERE
{
{?person a <http://dbpedia.org/ontology/Person>;
<http://dbpedia.org/ontology/birthPlace> ?place.
?place <http://dbpedia.org/ontology/country> ?birthCountry.
?birthCountry a <http://dbpedia.org/ontology/Country>.
FILTER (?birthCountry = dbpedia:Portugal).
}
UNION
{ ?person a <http://dbpedia.org/ontology/Person>;
<http://dbpedia.org/ontology/birthPlace> ?birthCountry.
?birthCountry a <http://dbpedia.org/ontology/Country>.
FILTER (?birthCountry = dbpedia:Portugal).
}
}
GROUP BY ?person
ORDER BY ?person
I'm trying to extract entity dictionary contains person name etc. from dbpedia using sparql.
PREFIX owl: <http://dbpedia.org/ontology/>
PREFIX dbpprop: <http://dbpedia.org/property/>
SELECT ?name
WHERE {
?person a owl:Person .
?person dbpprop:name ?name . FILTER(lang(?name) = "en")
}
The query above did succeed, but when I change the language name to fr, there is nothing to fetch.
How can I fetch names in other languages?
Moreover, why can't I filter language using query below?
SELECT ?name
WHERE {
?person a owl:Person .
?person dbpprop:language "English"
?person dbpprop:name ?name .
}
// this query returns nothing
I tried to fetch all languages using
SELECT DISTINCT ?lanName
WHERE {
?person a owl:Person .
?person dbpprop:language ?lanName .
}
and the result set contains English.
You need to filter based on the language of the value of the property. Not every property will have values in different languages, but some properties will. It seems, from your example, that dbpprop:name doesn't have values in every language. You may find more values in other languages if you look on the other language specific DBpediae.
However, for something like a name, you'll probably get multi-language results if you use the rdfs:label property. For instance, to get the names of Barack Obama, Daniel Webster, and Johnny Cash in Russian, you could do:
select ?label {
values ?person { dbpedia:Johnny_Cash dbpedia:Barack_Obama dbpedia:Daniel_Webster }
?person rdfs:label ?label .
filter langMatches(lang(?label),"ru")
}
SPARQL results
As an aside, note the use of langMatches rather than equality for matching language tags. This is usually a better approach, because it will correctly handle the different language tags within a language For example (from the SPARQL specification), you can find both of the French literals:
"Cette Série des Années Soixante-dix"#fr .
"Cette Série des Années Septante"#fr-BE .
with langMatches(lang(?title),"fr"), but only the first one with lang(?title) = "fr".
You are looking for rdfs:label for a name, of course all the names are English, you are looking at the English dbpedia.
PREFIX owl: <http://dbpedia.org/ontology/>
PREFIX dbpprop: <http://dbpedia.org/property/>
SELECT distinct *
WHERE {
?person a owl:Person .
?person rdfs:label ?name .
FILTER(lang(?name) = "fr")
}
Again, for the second one, if you replace the name with the rdfs: label you can have:
PREFIX owl: <http://dbpedia.org/ontology/>
PREFIX dbpprop: <http://dbpedia.org/property/>
SELECT distinct *
WHERE {
?person a owl:Person .
?person rdfs:label ?name .
?person dbpprop:language <http://dbpedia.org/resource/English_language>.
}