Perform ranking depend on category - sql

I Have a table looks like this:
RowNum category Rank4A Rank4B
-------------------------------------------
1 A
2 A
3 B
5 A
6 B
9 B
My requirement is based on the RowNum order, Make two new ranking columns depend on category. Rank4A works like the DENSERANK() by category = A, but if the row is for category B, it derives the latest appeared rank for category A order by RowNum. Rank4B have similar logic, but it orders by RowNum in DESC order. So the result would like this (W means this cell I don't care its value):
RowNum category Rank4A Rank4B
-------------------------------------------
1 A 1 W
2 A 2 W
3 B 2 3
5 A 3 2
6 B W 2
9 B W 1
One more additional requirement is that CROSS APPLY or CURSOR is not allowed due to dataset being large. Any neat solutions?
Edit: Also no CTE (due to MAX 32767 limit)

You can use the following query:
SELECT RowNum, category,
SUM(CASE
WHEN category = 'A' THEN 1
ELSE 0
END) OVER (ORDER BY RowNum) AS Rank4A,
SUM(CASE
WHEN category = 'B' THEN 1
ELSE 0
END) OVER (ORDER BY RowNum DESC) AS Rank4B
FROM mytable
ORDER BY RowNum

Giorgos Betsos' answer is better, please read it first.
Try this out. I believe each CTE is clear enough to show the steps.
IF OBJECT_ID('tempdb..#Data') IS NOT NULL
DROP TABLE #Data
CREATE TABLE #Data (
RowNum INT,
Category CHAR(1))
INSERT INTO #Data (
RowNum,
Category)
VALUES
(1, 'A'),
(2, 'A'),
(3, 'B'),
(5, 'A'),
(6, 'B'),
(9, 'B')
;WITH AscendentDenseRanking AS
(
SELECT
D.RowNum,
D.Category,
AscendentDenseRanking = DENSE_RANK() OVER (ORDER BY D.Rownum ASC)
FROM
#Data AS D
WHERE
D.Category = 'A'
),
LaggedRankingA AS
(
SELECT
D.RowNum,
AscendentDenseRankingA = MAX(A.AscendentDenseRanking)
FROM
#Data AS D
INNER JOIN AscendentDenseRanking AS A ON D.RowNum > A.RowNum
WHERE
D.Category = 'B'
GROUP BY
D.RowNum
),
DescendantDenseRanking AS
(
SELECT
D.RowNum,
D.Category,
DescendantDenseRanking = DENSE_RANK() OVER (ORDER BY D.Rownum DESC)
FROM
#Data AS D
WHERE
D.Category = 'B'
),
LaggedRankingB AS
(
SELECT
D.RowNum,
AscendentDenseRankingB = MAX(A.DescendantDenseRanking)
FROM
#Data AS D
INNER JOIN DescendantDenseRanking AS A ON D.RowNum < A.RowNum
WHERE
D.Category = 'A'
GROUP BY
D.RowNum
)
SELECT
D.RowNum,
D.Category,
Rank4A = ISNULL(RA.AscendentDenseRanking, LA.AscendentDenseRankingA),
Rank4B = ISNULL(RB.DescendantDenseRanking, LB.AscendentDenseRankingB)
FROM
#Data AS D
LEFT JOIN AscendentDenseRanking AS RA ON D.RowNum = RA.RowNum
LEFT JOIN LaggedRankingA AS LA ON D.RowNum = LA.RowNum
LEFT JOIN DescendantDenseRanking AS RB ON D.RowNum = RB.RowNum
LEFT JOIN LaggedRankingB AS LB ON D.RowNum = LB.RowNum
/*
Results:
RowNum Category Rank4A Rank4B
----------- -------- -------------------- --------------------
1 A 1 3
2 A 2 3
3 B 2 3
5 A 3 2
6 B 3 2
9 B 3 1
*/
This isn't a recursive CTE, so the limit 32k doesn't apply.

Related

Reorder the rows of a table according to the numbers of similar cells in a specific column using SQL

I have a table like this:
D
S
2
1
2
3
4
2
4
3
4
5
6
1
in which the code of symptoms(S) of three diseases(D) are shown. I want to rearrange this table (D-S) such that the diseases with more symptoms come up i.e. order it by decreasing the numbers of symptoms as below:
D
S
4
2
4
3
4
5
2
1
2
3
6
1
Can anyone help me to write a SQL code for it in SQL server?
I had tried to do this as the following but this doesn't work:
SELECT *
FROM (
select D, Count(S) cnt
from [D-S]
group by D
) Q
order by Q.cnt desc
select
D,
S
from
D-S
order by
count(*) over(partition by D) desc,
D,
S;
Two easy ways to approach this:
--==== Sample Data
DECLARE #t TABLE (D INT, S INT);
INSERT #t VALUES(2,1),(2,3),(4,2),(4,3),(4,5),(6,1);
--==== Using Window Function
SELECT t.D, t.S
FROM (SELECT t.*, Rnk = COUNT(*) OVER (PARTITION BY t.D) FROM #t AS t) AS t
ORDER BY t.Rnk DESC;
--==== Using standard GROUP BY
SELECT t.*
FROM #t AS t
JOIN
(
SELECT t2.D, Cnt = COUNT(*)
FROM #t AS t2
GROUP BY t2.D
) AS t2 ON t.D = t2.D
ORDER BY t2.Cnt DESC;
Results:
D S
----------- -----------
4 2
4 3
4 5
2 1
2 3
6 1

SQL transpose multiple rows to different columns

I have SQL server data Table, like this:
ID
SYMPTOM1
SYMPTOM2
1
A
B
1
C
D
2
E
F
3
A
C
3
D
E
I'd like to obtain this:
ID
SYMPTOM1
SYMPTOM2
SYMPTOM3
SYMPTOM4
1
A
B
C
D
2
E
F
3
A
C
D
E
That should be an "easy" pivot, but I can't figure it out.
How could a SQL query be written?
*EDIT
Excuse me, I have neglected an important detail. The number of rows in the table is very large, some 500.000 so the IDs are very large.
You could do it as a self join - use row number to have another column that is either 1 or 2 (depending on how many times ID appeared), 1 should always appear, 2 sometimes appears, so left joining those rows with 2 onto those rows with 1 (based on the id) gives you the end result..
WITH x AS(
SELECT
t.ID,
t.SYMPTOM1,
t.SYMPTOM2,
ROW_NUMBER() OVER (PARTITION BY t.ID ORDER BY t.SYMPTOM1) as rn
FROM t
)
SELECT
*
FROM
x x1
LEFT JOIN x x2 ON x1.id = x2.id AND x1.rn = 1 AND x2.rn = 2
You can pivot on a row-number
SELECT
t.ID,
SYMPTOM1 = MAX(CASE WHEN t.rn = 1 THEN t.SYMPTOM1 END),
SYMPTOM2 = MAX(CASE WHEN t.rn = 1 THEN t.SYMPTOM2 END),
SYMPTOM3 = MAX(CASE WHEN t.rn = 2 THEN t.SYMPTOM1 END),
SYMPTOM4 = MAX(CASE WHEN t.rn = 2 THEN t.SYMPTOM2 END)
FROM (
SELECT
t.*,
rn = ROW_NUMBER() OVER (PARTITION BY t.ID ORDER BY (SELECT 1))
FROM YourTable t
) t
GROUP BY t.ID;

sql numbering the partition of Numbers

I have a set of numbers like this
ID
===
1
2
3
1
2
1
1
2
3
4
5
...
I want to select a new row that increase when fetch next 1 like this
ID number
=== ========
1 1
2 1
3 1
1 2
2 2
1 3
1 4
2 4
3 4
4 4
5 4
Any suggestion ?
Assuming that you have a column o which specify the ordering then you can use a self-join like this:
select d1.o, d1.id, count(*)
from data d1
join data d2 on d1.o >= d2.o and d2.id = 1
group by d1.o, d1.id
DBFiddle DEMO
You can solve this with use of cte and window functions, as follows:
DECLARE #t TABLE (ID INT);
INSERT INTO #t VALUES (1),(2),(3),(1),(2),(1),(1),(2),(3),(4),(5);
WITH cte AS(
SELECT ID, ROW_NUMBER() OVER (ORDER BY (SELECT 1)) rn
FROM #t
),
cte1 AS(
SELECT ID, rn, ROW_NUMBER() OVER (ORDER BY rn) rn2
FROM cte
WHERE ID = 1
)
SELECT c.ID, MAX(rn2) OVER (ORDER BY c.rn) rn
FROM cte c
LEFT JOIN cte1 c1 ON c1.rn = c.rn
ORDER BY c.rn

SQL get the closest two rows within duplicate rows

I have following table
ID Name Stage
1 A 1
1 B 2
1 C 3
1 A 4
1 N 5
1 B 6
1 J 7
1 C 8
1 D 9
1 E 10
I need output as below with parameters A and N need to select closest rows where difference between stage is smallest
ID Name Stage
1 A 4
1 N 5
I need to select rows where difference between stage is smallest
This query can make use of an index on (name, stage) efficiently:
WITH cte AS (
SELECT TOP 1
a.id AS a_id, a.name AS a_name, a.stage AS a_stage
, n.id AS n_id, n.name AS n_name, n.stage AS n_stage
FROM tbl a
CROSS APPLY (
SELECT TOP 1 *, stage - a.stage AS diff
FROM tbl
WHERE name = 'N'
AND stage >= a.stage
ORDER BY stage
UNION ALL
SELECT TOP 1 *, a.stage - stage AS diff
FROM tbl
WHERE name = 'N'
AND stage < a.stage
ORDER BY stage DESC
) n
WHERE a.name = 'A'
ORDER BY diff
)
SELECT a_id AS id, a_name AS name, a_stage AS stage FROM cte
UNION ALL
SELECT n_id, n_name, n_stage FROM cte;
SQL Server uses CROSS APPLY in place of standard-SQL LATERAL.
In case of ties (equal difference) the winner is arbitrary, unless you add more ORDER BY expressions as tiebreaker.
dbfiddle here
This solution works, if u know the minimum difference is always 1
SELECT *
FROM myTable as a
CROSS JOIN myTable as b
where a.stage-b.stage=1;
a.ID a.Name a.Stage b.ID b.Name b.Stage
1 A 4 1 N 5
Or simpler if u don't know the minimum
SELECT *
FROM myTable as a
CROSS JOIN myTable as b
where a.stage-b.stage in (SELECT min (a.stage-b.stage)
FROM myTable as a
CROSS JOIN myTable as b)

left join without duplicate values using MIN()

I have a table_1:
id custno
1 1
2 2
3 3
and a table_2:
id custno qty descr
1 1 10 a
2 1 7 b
3 2 4 c
4 3 7 d
5 1 5 e
6 1 5 f
When I run this query to show the minimum order quantities from every customer:
SELECT DISTINCT table_1.custno,table_2.qty,table_2.descr
FROM table_1
LEFT OUTER JOIN table_2
ON table_1.custno = table_2.custno AND qty = (SELECT MIN(qty) FROM table_2
WHERE table_2.custno = table_1.custno )
Then I get this result:
custno qty descr
1 5 e
1 5 f
2 4 c
3 7 d
Customer 1 appears twice each time with the same minimum qty (& a different description) but I only want to see customer 1 appear once. I don't care if that is the record with 'e' as a description or 'f' as a description.
First of all... I'm not sure why you need to include table_1 in the queries to begin with:
select custno, min(qty) as min_qty
from table_2
group by custno;
But just in case there is other information that you need that wasn't included in the question:
select table_1.custno, ifnull(min(qty),0) as min_qty
from table_1
left outer join table_2
on table_1.custno = table_2.custno
group by table_1.custno;
"Generic" SQL way:
SELECT table_1.custno,table_2.qty,table_2.descr
FROM table_1, table_2
WHERE table_2.id = (SELECT TOP 1 id
FROM table_2
WHERE custno = table_1.custno
ORDER BY qty )
SQL 2008 way (probably faster):
SELECT custno, qty, descr
FROM
(SELECT
custno,
qty,
descr,
ROW_NUMBER() OVER (PARTITION BY custno ORDER BY qty) RowNum
FROM table_2
) A
WHERE RowNum = 1
If you use SQL-Server you could use ROW_NUMBER and a CTE:
WITH CTE AS
(
SELECT table_1.custno,table_2.qty,table_2.descr,
RN = ROW_NUMBER() OVER ( PARTITION BY table_1.custno
Order By table_2.qty ASC)
FROM table_1
LEFT OUTER JOIN table_2
ON table_1.custno = table_2.custno
)
SELECT custno, qty,descr
FROM CTE
WHERE RN = 1
Demolink