How can I get the count per hour?
select count_hr_1, count_hr_2, count_hr_3 from db.table where year=2018 and month=01 and day=02 and hour=01 OR hour=02 OR hour=03;
This SQL/Query is probably invalid but I want to get the counts of hour 1,2,3
If you are able to process the resultset as multiple rows instead of one, you could use GROUP BY:
select hour, count(*)
from db.table
where
year = 2018
and month = 1
and day = 2
and hour in (1, 2, 3)
group by hour
select sum(case when hour = 1 then 1 else 0 end) as count_hr_1,
sum(case when hour = 2 then 1 else 0 end) as count_hr_2,
sum(case when hour = 3 then 1 else 0 end) as count_hr_3
from db.table
where year = 2018
and month = 1
and day = 2
and hour in (1,2,3)
Related
I'm trying to get a selection of records where the date field of the record(s) is current date + 7 Days
I was previously doing this in MySQL like so:
SUM(CASE WHEN ( d.next_date + INTERVAL 7 DAY) THEN 1 ELSE 0 END) AS dateCount
But now trying to do this on DB2 it's not working
SUM(case WHEN f.next_date + 7 days then 1 else 0 end) as dateCount
I'm wondering why this would be, but I'm simply trying to get a count of all records where the date is today + 7 days.
What am I doing wrong
Your case expression is lacking a comparison, e.g. when (some_value is compared to other_value) then do_something .... Perhaps an equal?
SUM(case when {date field of the record} = f.next_date + 7 days then 1 else 0 end) as dateCount
Try this:
select sum(case when f.next_date = current date + 7 day then 1 end) as dateCount
from table(values
current date + 1 day
, current date + 7 day
, current date + 7 day
) f(next_date);
First here's a sample table.
enter image description here
Provider_name patient date status length
AF AGUIR00001 07/05/2018 3 30
AF ABBOT00001 07/05/2018 30
BB ADAMS00001 07/05/2018 3 30
BB ACEVE00001 07/06/2018 3 30
I have created a query that lets me count the total number of appointments versus the number of appointments with a certain status(eg checked out). I was able to create it and group it by provider.
select provider_name,
count(patient) total,
sum(case when status = 3 then 1 else 0 end) as Checkedout
from appointment
group by provider_name
Then I moved on to the next phase which was to get the total length of those appointments with checkedout status. I made this query but it does not break down into each provider.
select provider_name,
count(patient) total,
sum(case when status = 3 then 1 else 0 end) as Checkedout,
(select sum(length) from appointment where status = 3
and date between '06/01/2018' and '07/06/2018')
from appointment where date between '06/01/2018' and '07/06/2018'
group by provider_name
I need it so that the last column in the query is segregated per provider_name.
Thank you in advance for helping me out.
Actually, you were on the right way, try this:
select provider_name,
count(patient) total,
sum(case when status = 3 then 1 else 0 end) as Checkedout,
sum(case when status = 3 then length else 0 end) as len_status3
from appointment
where date between '2018-01-06' and '2018-06-07'
group by provider_name;
According to your last comment, you need a WITH ROLLUP modifier for GROUP BY as in the following :
select coalesce(provider_name,'Total') as provider_name,
count(patient) total,
sum(case when status = 3 then 1 else 0 end) as Checkedout,
sum(case when status = 3 then length else 0 end) as len_status3
from appointment
where date between '2018-01-06' and '2018-06-07'
group by provider_name with rollup;
SQL Fiddle Demo
you shoul do as for checkedoutout
select provider_name,
count(patient) total,
sum(case when status = 3 then 1 else 0 end) as Checkedout,
sum( case when status = 3 then length else 0 ) as total_length
from appointment where date between '06/01/2018' and '07/06/2018'
group by provider_name
I got a table of Visitors.
Visitor has the following columns:
Id
StartTime (Date)
Purchased (bool)
Shipped (bool)
For each day within the last 7 days, I want to select 3 counts of the Visitors who have that day as StartTime:
The count of total visitors
The count of total visitors where Purchased = true
The count of total visitors where Shipped = true
Ideally the returned result would be:
Day Total TotalPurchased TotalShipped
1 100 67 42
2 82 61 27
etc...
I am used to .NET Linq so this has proved to be quite a challenge for me.
All I have come up with so far is the following:
SELECT COUNT(*) AS Total
FROM [dbo].[Visitors]
WHERE DAY([StartTime]) = DAY(GETDATE())
It selects the total of the current day just fine, however I feel pretty stuck right now so it'd be nice if someone could point me in the right direction.
For the last 7 days use the query proposed by Stanislav but with this WHERE clause
SELECT DAY([StartTime]) theDay,
COUNT(*) AS Tot,
SUM(CASE WHEN Purchased=true THEN 1 ELSE 0 END) as TotPurch,
SUM(CASE WHEN Shipped=true THEN 1 ELSE 0 END) as TotShip
FROM [dbo].[Visitors]
WHERE [StartTime] BETWEEN GETDATE()-7 AND GETDATE()
GROUP BY DAY([StartTime])
SELECT COUNT(*) AS Total,
SUM(CASE WHEN Purchased=true THEN 1 ELSE 0 END) as TotalPurchased,
SUM(CASE WHEN Shipped=true THEN 1 ELSE 0 END) as TotalShipped
FROM [dbo].[Visitors]
WHERE DAY([StartTime]) = DAY(GETDATE())
and add GROUP BY DAY([StartTime]) as jarlh mentioned
Here's a simple select that will give you the dataset you want
SELECT DATEDIFF(day,StartTime, getdate())+1 as [Day], -- Add 1 to display 1 to 7 instead of 0 to 6
COUNT(*) as Total,
SUM(CASE WHEN Purchased = 1 THEN 1 ELSE 0 END) as TotalPurchased,
SUM(CASE WHEN Shipped = 1 THEN 1 ELSE 0 END) AS TotalShipped
FROM Visitors
WHERE DATEDIFF(day,startTime,GETDATE()) < 6
GROUP BY DATEDIFF(day,startTime,GETDATE())
ORDER BY 1
This query will not take into consideration the time component of the date.
I have a table in this form:
id year type amount
1 2015 in 10
2 2015 out 5
3 2016 in 20
4 2016 out 1
...
The followin query will give me the sum of the amount of type = 'in' grouped by year:
SELECT year, sum(amount)
FROM table
WHERE type = in
GROUP BY year
How am I going to get the following result?
year sum(in) sum(out) "in-out"
2015 10 5 5
2016 20 1 19
sum(in) is the sum of the 'amount' where type='in'.
Use a CASE statement to handle the values of type.
SELECT year,
SUM(CASE WHEN type = 'in' THEN amount ELSE 0 END) AS sum_in,
SUM(CASE WHEN type = 'out' THEN amount ELSE 0 END) AS sum_out,
SUM(CASE WHEN type = 'in' THEN amount ELSE -amount END) AS in_out
FROM table
GROUP BY year;
I do have a table license_Usage where which works like a log of the usage of licenses in a day
ID User license date
1 1 A 22/1/2015
2 1 A 23/1/2015
3 1 B 23/1/2015
4 1 A 24/1/2015
5 2 A 22/2/2015
6 2 A 23/2/2015
7 1 B 23/2/2015
Where I want to Count how many licenses a user used in a month, the result should look like:
User Jan Feb
1 2 1 ...
2 0 2
How can I manage to do that???
You need a PIVOT or cross tab query. e.g.
SELECT [User],
COUNT(CASE WHEN Month = 1 THEN 1 END) AS Jan,
COUNT(CASE WHEN Month = 2 THEN 1 END) AS Feb,
COUNT(CASE WHEN Month = 3 THEN 1 END) AS Mar
/*TODO - Fill in other 9 months using above pattern*/
FROM [license]
CROSS APPLY (SELECT MONTH([date])) AS CA(Month)
WHERE [date] >= '20150101'
AND [date] < '20160101'
AND [license] = 'A'
GROUP BY [User]
SQL Fiddle