I am new to SQL and have had pretty good luck figuring things out thus far but I am missing something in this query:
The question is how to return a distinct count from two columns using another column and the criteria if the value is greater than 0.
I have tried IF and AND operators (My current query returns a 0 not an error, and it works when only using one .shp criteria)
select count (distinct ti.TO_ADDRESS)
from ti
where ti.input_id = 'xxx_029_01z_c_zzzzbab_ecrm.shp'
and ti.input_id = 'xxx_030_01z_c_zzzzbab_ecrm.shp'
and ti.OPENED>0;
Thanks so much!!
I think you want two levels of aggregation:
select count(*)
from (select ti.TO_ADDRESS
from ti
where ti.input_id in ('xxx_029_01z_c_zzzzbab_ecrm.shp', 'xxx_030_01z_c_zzzzbab_ecrm.shp') and
ti.OPENED > 0
group by ti.TO_ADDRESS
having count(distinct ti.input_id) = 2 -- has both of them
) ti;
Related
I do have a problem with a task because my division value is different when I use it alone and when I use it in full code. Let's say I do this code:
SELECT (count(paimta))::numeric / count(distinct paimta) as average
FROM Stud.Egzempliorius;
and finally a number I get is 2.(6)7, but when I use it in full code which is:
SELECT Stud.Egzempliorius.Paimta, COUNT(PAIMTA) as PaimtaKnyga
FROM Stud.Skaitytojas, Stud.Egzempliorius
WHERE Stud.Skaitytojas.Nr=Stud.Egzempliorius.Skaitytojas
GROUP BY Stud.Egzempliorius.Paimta
HAVING count(paimta) > (count(paimta))::numeric / count(distinct paimta);
it's value changes because division is not working anymore and let's say instead of having
HAVING count(paimta) > (count(paimta))::numeric / count(distinct paimta);
my codes turns into
HAVING count(paimta) > (count(paimta))::numeric;
and these values are equal, so I can't get final answer. That's database I use https://klevas.mif.vu.lt/~baronas/dbvs/biblio/show-table.php?table=Stud.Egzempliorius
I was struggling for 10 hours now and finally I've lost my patience... So, my question is what I have to do that this code:
SELECT (count(paimta))::numeric / count(distinct paimta) as average
FROM Stud.Egzempliorius;
value doesn't change in full code?
Picture how it changes Photo
Your solution fails because the two queries operate on a different groups of rows. The first query does a computation over the whole dataset, while the second one groups by paimta.
One option would have been to use window functions, but as far as concerns Postgres does not support count(distinct) as a window function.
I think that the simplest approach is to use a subquery :
select e.paimta, count(paimta) as paimtaknyga
from stud.skaitytojas s
inner join stud.egzempliorius e on s.nr = e.skaitytojas
group by e.paimta
having count(paimta) > (
select (count(paimta))::numeric / count(distinct paimta) from stud.egzempliorius
)
I'm using PostgreSQL 10 and trying to run this query. I started with a CTE which I am referencing as 'query.'
SELECT
ROW_NUMBER()OVER() AS my_new_id,
query.geom AS geom,
query.pop AS pop,
query.name,
query.distance AS dist,
query.amenity_size,
((amenity_size)/(distance)^2) AS attract_score,
SUM((amenity_size)/(distance)^2) AS tot_attract_score,
((amenity_size)/(distance)^2) / SUM((amenity_size)/(distance)^2) as marketshare
INTO table_mktshare
FROM query
WHERE
distance > 0
GROUP BY
query.name,
query.amenity_size,
query.geom,
query.pop,
query.distance
The query runs but the problem lies in the 'markeshare' column. It returns the same answer with or without the SUM operator and returns one, which appears to make both the attract_score and the tot_attract_score the same. Why is the SUM operator read the same as the expression above it?
This is occurring specifically because each combination of columns in the group by clause uniquely identifies one row in the table. I don't know if this is intentional, but more normally, one would expect something like this:
SELECT ROW_NUMBER() OVER() AS my_new_id,
query.geom AS geom, query.pop AS pop, query.name,
SUM((amenity_size)/(distance)^2) AS tot_attract_score,
INTO table_mktshare
FROM query
WHERE distance > 0
GROUP BY query.name, query.geom, query.pop;
This is not your intention, but it does give a flavor of what's expected.
I've got an aggregated query that checks if I have more than one record matching certain conditions.
SELECT RegardingObjectId, COUNT(*) FROM [CRM_MSCRM].[dbo].[AsyncOperationBase] a
where WorkflowActivationId IN ('55D9A3CF-4BB7-E311-B56B-0050569512FE',
'1BF5B3B9-0CAE-E211-AEB5-0050569512FE',
'EB231B79-84A4-E211-97E9-0050569512FE',
'F0DDF5AE-83A3-E211-97E9-0050569512FE',
'9C34F416-F99A-464E-8309-D3B56686FE58')
and StatusCode = 10
group by RegardingObjectId
having COUNT(*) > 1
That's nice, but then there is one field in AsyncOperationBase that will be unique. Say count(*) = 3, well, AsyncOperationBaseId in AsyncOperationBase will have 3 different values since AsyncOperationBase is the table's primary key.
To be honest, I would not even know what terms and expressions to Google to find a solution.
If anyone has a solution and also, is there any words to describe what I'm looking for ? Perhaps BI people are often faced with such a requirement or something...
I could do it with an SSRS report where the report would visually do the grouping then I could expand each grouped row to get the AsyncOperationBaseId value, but simply through SQL, I can't seem to find a way out...
Thanks.
select * from [CRM_MSCRM].[dbo].[AsyncOperationBase]
where RegardingObjectId in
(
SELECT RegardingObjectId
FROM [CRM_MSCRM].[dbo].[AsyncOperationBase] a
where WorkflowActivationId IN
(
'55D9A3CF-4BB7-E311-B56B-0050569512FE',
'1BF5B3B9-0CAE-E211-AEB5-0050569512FE',
'EB231B79-84A4-E211-97E9-0050569512FE',
'F0DDF5AE-83A3-E211-97E9-0050569512FE',
'9C34F416-F99A-464E-8309-D3B56686FE58'
)
and StatusCode = 10
group by RegardingObjectId
having COUNT(*) > 1
)
SELECT firstpartno, nOccurrence, nMale, nFemale, COUNT(nMale) / CAST
((SELECT SUM(nOccurrence) AS Expr1
FROM (SELECT COUNT(dbo.vw_Tally1.nMale) AS nOccurrence
FROM dbo.vw_Split4) AS SumTally) AS decimal) AS nMProportion, COUNT(nFemale) / CAST
((SELECT SUM(nOccurrence) AS Expr1
FROM (SELECT COUNT(dbo.vw_Tally1.nFemale) AS nOccurrence
FROM dbo.vw_Split4 AS vw_Split4_1) AS SumTally_1) AS decimal) AS nFProportion
FROM dbo.vw_Tally1
GROUP BY firstpartno, nOccurrence, nMale, nFemale
If i understood your question here's the solution for you :
SELECT
firstpartno
,nOccurrence
,nMale
,nFemale
,CASE WHEN SUM_nOccurrence.SUM_nOccurrenceMale = 0
THEN 0
ELSE COUNT(nMale)/SUM_nOccurrence.SUM_nOccurrenceMale
END AS nMProportion
,CASE WHEN SUM_nOccurrence.nOccurrenceFemale = 0
THEN 0
ELSE COUNT(nFemale)/SUM_nOccurrence.nOccurrenceFemale
END AS nFProportion
FROM
dbo.vw_Tally1
LEFT JOIN
(SELECT
CAST(SUM(nOccurrenceMale)AS decimal) AS SUM_nOccurrenceMale
,CAST(SUM(nOccurrenceFemale)AS decimal) AS SUM_nOccurrenceFemale
FROM (SELECT
COUNT(dbo.vw_Tally1.nMale) AS nOccurrenceMale
,COUNT(dbo.vw_Tally1.nFemale) AS nOccurrenceFemale
FROM dbo.vw_Split4 ) AS SumTally) SUM_nOccurrence
ON 1=1
GROUP BY
firstpartno
,nOccurrence
,nMale
,nFemale
I hope this will help you
Good Luck :)
The query looks dubious to say the least. You select all records of table vw_Tally1. For each of these records you do the following:
select COUNT(vw_Tally1.nMale) from table vw_Split4. This is COUNT(*) of vw_Split4 when vw_Tally1.nMale is not null, otherwise it is null.
Then you sum this value. Which makes no sense, as the sum of a value is the value itself.
You do the same for nFemale.
At last you group by (firstpartno, nOccurrence, nMale, nFemale) and use the values found so strangly to calculate something. As you don't aggregate the found values, you get a random match per group. I.e. the dbms takes one of the matching records. As nMale and nFemale are grouping columns, the values are constant for all records of the group. So no big problem, but a lot of useless work.
So to speed this up, first think of what you want to select actually. This looks like to become a very simple select statement in the end. We can help you, if you tell us what your tables contain, what result set you are after, what does nMale and nFemale stand for, and what are the primary keys or unique columns of the tables involved.
iam not a big ORACLE - SQL Expert, so i hope someone knows a good way to find the "duplicate" record wich is causing the: single-row subquery returns more than one row error.
This my Statement:
SELECT
CAST(af.SAP_SID AS VARCHAR2(4000)) APP_ID,
(SELECT DR_OPTION
FROM
DR_OPTIONS
WHERE DR_OPTIONS.ID = (
select dr_option from applications where applications.sap_sid = af.sap_sid)) DR_OPTION
FROM
APPLICATIONS_FILER_VIEW af
it works on my test system, so iam "sure" there must be an error inside the available data records, but i have no idea how to find those ..
Try with this query:
select applications.sap_sid, count(dr_option)
from applications
group by applications.sap_sid
having count(dr_option) > 1
This should give you the sap_sid of the duplicated rows
I'd suggest simplifying your query:
SELECT CAST(af.SAP_SID AS VARCHAR2(4000)) APP_ID,
dr.DR_OPTION
FROM APPLICATIONS_FILER_VIEW af
INNER JOIN applications a ON af.sap_sid = a.sap_sid
INNER JOIN DR_OPTIONS dr ON a.dr_option = dr.ID
I would investigate what you get when you run:
select dr_option from applications where applications.sap_sid = af.sap_sid
but you could force only one row to be returned (I see this as being a fudge and would not recommend using it at least add an order by to have some control over the row being returned) with something like:
SELECT
CAST(af.SAP_SID AS VARCHAR2(4000)) APP_ID,
(SELECT DR_OPTION
FROM
DR_OPTIONS
WHERE DR_OPTIONS.ID = (
select dr_option
from applications
where applications.sap_sid = af.sap_sid
and rownumber = 1)
) DR_OPTION
FROM
APPLICATIONS_FILER_VIEW af
(not tested just googled how to limit results in oracle)
If you fix the data issue (as per A.B.Cades comment) then I would recommend converting it to use joins as per weenoid's answer. this would also highlight other data issues that may arise in the future.
IN SHORT: I have never fixed anything in this way.. the real answer is to investigate the multiple rows returned and decide what you want to do maybe:
add more where clauses
order the results and only select top row
actually keep the duplicates as they represent a scenario you have not thought of before