I've been trying to implement the Spatial Pyramid Pooling (https://arxiv.org/abs/1406.4729), but I've been having a problem with the input size.
My input has shape (batch_size, None, n_feature_maps) and I have the following code:
self.y_conv_unstacked = tf.unstack(self.conv_output, axis=0)
self.y_maxpool = []
for tensor in self.y_conv_unstacked:
for size_pool in self.out_pool_size:
self.w_strd = self.w_size = math.ceil(float(tensor.get_shape()[1]) / size_pool)
self.pad_w = int(size_pool * self.w_size - tensor.get_shape()[1])
self.padded_tensor = tf.pad(tensor, tf.constant([[0, 0], [0, 0], [0, self.pad_w], [0, 0]]))
self.max_pool = tf.nn.max_pool(self.padded_tensor, ksize=[1, 1, self.w_size, 1], strides=[1, 1, self.w_strd, 1], padding='SAME')
self.spp_tensor = tf.concat([self.spp_tensor, tf.reshape(self.max_pool, [1, size_pool, self.n_fm1])], axis=1)
self.y_maxpool.append(spp_tensor)
Since the inputs in the batch have different sizes, I am unstacking them and pooling each tensor separately. However when using tensor.get_shape()[1], it returns "?". If I use tensor.get_shape().as_list()[1], it returns None.
I would like to know how I can work around this nondefined size. Is it possible to get the tensor's shape at runtime?
Edit: Using tf.shape, I get a tensor. How can I use this tensor to create the ksize, strides and paddings I need?
I would like to know how I can work around this nondefined size. Is it
possible to get the tensor's shape at runtime?
Use tf.shape() op to get the dynamic shape of a tensor instead of the x.get_shape() which returns the static shape of x.
This is explained in detail here.
In the above code replace tensor.get_shape()[1] with tf.shape(tensor)[1]
Related
The problem is, I have an indices tensor with shape [batch_size, seq_len, k] and every element in this tensor is in range [0, hidden_dim). I want to create a mask tensor with shape [batch_size, seq_len, hidden_dim] where every element indexed by the indices tensor is 1 and other elements are 0. k is smaller than hidden_dim. For example:
indices = [[[0],[1],[2]]] #batch_size=1, seq_len=3, k=1
mask = tf.zeros(shape=(1,3,3)) #batch_size=1, seq_len=3, hidden_dim = 3
How can I get a target mask tensor whose elements indicated by the indices are 1, i.e.:
target_mask = [[[1, 0, 0], [0, 1, 0], [0, 0, 1]]]
This can be accomplished using tf.one_hot, e.g.:
mask = tf.one_hot(indices, depth=hidden_dim, axis=-1) # [batch, seq_len, k, hidden_dim]
I wasn't clear on what you'd like to happen to k. tf.one_hot() will keep the axis as is, i.e. you'll get a delta distribution for each [batch-index, seq-index, k-index] tuple.
Trying to load Tensorflow trained model into Deeplearning4J with following error:
IllegalStateException: Invalid array shape: cannot associate an array with shape [38880] with a placeholder of shape [-1, -1, -1, 3]:shape is wrong rank or does not match on one or more dimensions
var arr: INDArray = Nd4j.create(data) //.reshape(1, -1, -1, 3);
arr = Nd4j.pile(arr, arr)
sd.associateArrayWithVariable(arr, sd.variables.get(0))
Python model was loaded like that:
# Load image using OpenCV and
# expand image dimensions to have shape: [1, None, None, 3]
# i.e. a single-column array, where each item in the column has the pixel RGB value
image = cv2.imread(PATH_TO_IMAGE)
image_expanded = np.expand_dims(image, axis=0)
Please explain any question if you know:
1) What means [1, None, None, 3] in terms of Python arrays
2) What means np.expand_dims(image, axis=0) in Python
3) Deeplearning4J reshape(1, -1, -1, 3);
You're mixing two different concepts here, TF placeholders, and imperative numpy-like reshape.
In your case, model expects 4D input tensor, with shape [-1, -1, -1, 3]. For human it can be translated to [Any, Any, Any, 3]. But you're trying to feed it with tensor with shape [38880], rank 1.
Now to your questions.
1) See above. -1 is treated as "Any".
2) This function adds 1 as dimension. i.e. if you have [38880], expand_dims at axis=0 will make it [1, 38880]
3) Nope, that's wrong. You should not use that as your shape. You have some image there, so you should specify proper dimensions your image has, i.e. [1, 800, 600, 3].
I have to swap tensor's axes using tf.transpose to do the batch matrix multiplication (as the code shown below).
tensor input_a: shape [10000, 10000]
tensor input_b: shape [batch_size, 10000, 10]
tensor output: shape [batch_size, 10000, 10]
# reshape_input_b: shape [10000, batch_size, 10]
transpose_input_b = tf.transpose(input_b, [1, 0, 2])
# transpose_input_b : shape [10000, batch_size * 10]
reshape_input_b = tf.reshape(transpose_input_b , [10000, -1])
# ret: shape [10000, batch_size * 10]
ret = tf.matmul(input_a, reshape_input_b, a_is_sparse = True)
# reshape_ret: [10000, batch_size, 10]
reshape_ret = tf.reshape(ret, [10000, -1, 10])
# output : [batch_size, 10000, 10]
output = tf.transpose(reshape_ret, [1, 0, 2])
However, it seems very slow. I noticed this in the document page of tf.transpose:
In numpy transposes are memory-efficient constant time operations as they simply return a new view of the same data with adjusted strides.
TensorFlow does not support strides, so transpose returns a new tensor with the items permuted.
So, I think it might be the reason why my code run slowly? Is there any way to swap tensor's axes, or do the batch matrix multiplication efficiently?
I am doing the image semantic segmentation job with unet. I am confused with the last layers for pixel classification. The Unet code is like this:
...
reshape = Reshape((n_classes,self.img_rows * self.img_cols))(conv9)
permute = Permute((2,1))(reshape)
activation = Activation('softmax')(permute)
model = Model(input = inputs, output = activation)
return model
...
Can I just reshape without using Permute like this?
reshape = Reshape((self.img_rows * self.img_cols, n_classes))(conv9)
Updated:
I found the training result is not right when when using the directly reshape way:
reshape = Reshape((self.img_rows * self.img_cols, n_classes))(conv9) // the loss is not convergent
My groundtruth is generated like this:
X = []
Y = []
im = cv2.imread(impath)
X.append(im)
seg_labels = np.zeros((height, width, n_classes))
for spath in segpaths:
mask = cv2.imread(spath, 0)
seg_labels[:, :, c] += mask
Y.append(seg_labels.reshape(width*height, n_classes))
Why reshape directly does not work?
You clearly misunderstand the meaning of each operation and the final goal:
final goal: classification for each pixel, i.e. softmax along the semantic class axis
how to achieve this goal in the original code? Let's see the code line by line:
reshape = Reshape((n_classes,self.img_rows * self.img_cols))(conv9) # L1
permute = Permute((2,1))(reshape) # L2
activation = Activation('softmax')(permute) # L3
L1's output dim = n_class-by-n_pixs, (n_pixs=img_rows x img_cols)
L2's output dim = n_pixs-by-n_class
L3's output dim = n_pixs-by-n_class
Note the default softmax activation is applied to the last axis, i.e. the axis that n_class stands for, which is the semantic class axis.
Therefore, this original code fulfills the final goal of semantic segmentation.
Let's revisit the code that you want to change, which is
reshape = Reshape((self.img_rows * self.img_cols, n_classes))(conv9) # L4
L4's output dim = n_pixs-by-n_class
My guess is that you think L4's output dim matches L2's, and thus L4 is a short-cut that is equivalent to executing L1 and L2.
However, matching the shape does not necessarily mean matching the physical meaning of axes. Why? A simple example will explain.
Say you have 2 semantic classes and 3 pixels. To see the difference assume all three pixels belong to the same class.
In other words, a ground truth tensor will look like this
# cls#1 cls#2
[ [0, 1], # pixel #1
[0, 1], # pixel #2
[0, 1], # pixel #3
]
Assume you have a perfect network and generate the exact response for each pixel, but your solution will create a tensor like below
# cls#1 cls#2
[ [0, 0], # pixel #1
[0, 1], # pixel #2
[1, 1], # pixel #3
]
whose shape is the same as the ground truth's, but fails to match the physical meaning of axes.
This further makes the softmax operation meaningless, because it is supposed to apply to the class dimension, but this dimension does not physically exist. As a result, it leads to the following erroneous output after applying softmax,
# cls#1 cls#2
[ [0.5, 0.5], # pixel #1
[0, 1], # pixel #2
[0.5, 0.5], # pixel #3
]
which completely mess up the training even if it is under the ideal assumption.
Therefore, it is a good habit to write down the physical meaning of each axis of a tensor. When you do any tensor reshape operation, ask yourself whether the physical meaning of an axis is changed in your expected way.
For example, if you have a tensor T of shape batch_dim x img_rows x img_cols x feat_dim, you can do many things and not all of them make sense (due to the problematic physical meaning of axes)
(Wrong) reshape it to whatever x feat_dim, because whatever dimension is meaningless in testing where the batch_size might be different.
(Wrong) reshape it to batch_dim x feat_dim x img_rows x img_cols, because the 2nd dimension is NOT the feature dimension and neither for the 3rd and 4th dimension.
(Correct) permute axes (3,1,2), and this will lead you the tensor of shape batch_dim x feat_dim x img_rows x img_cols, while keeping the physical meaning of each axis.
(Correct) reshape it to batch_dim x whatever x feat_dim. This is also valid, because the whatever=img_rows x img_cols is equivalent to the pixel location dimension, and both the meanings of batch_dim and feat_dim are unchanged.
Your code will still be runnable since the shape will be the same, but the result (backprops) will be different since the values of tensors will be different. For example:
arr = np.array([[[1,1,1],[1,1,1]],[[2,2,2],[2,2,2]],[[3,3,3],[3,3,3]],[[4,4,4],[4,4,4]]])
arr.shape
>>>(4, 2, 3)
#do reshape, then premute
reshape_1 = arr.reshape((4, 2*3))
np.swapaxes(reshape_1, 1, 0)
>>>array([[1, 2, 3, 4],
[1, 2, 3, 4],
[1, 2, 3, 4],
[1, 2, 3, 4],
[1, 2, 3, 4],
[1, 2, 3, 4]])
#do reshape directly
reshape_2 = arr.reshape(2*3, 4)
reshape_2
>>>array([[1, 1, 1, 1],
[1, 1, 2, 2],
[2, 2, 2, 2],
[3, 3, 3, 3],
[3, 3, 4, 4],
[4, 4, 4, 4]])
The Reshape and Permute is done to take the softmax at each pixel location. Adding to #meowongac's answer, Reshape preserves the order of the elements. In this case, since the channel dimensions have to be swapped, Reshape followed by Permute is appropriate.
Considering the case of (2,2) image with 3 values at each location,
arr = np.array([[[1,1],[1,1]],[[2,2],[2,2]],[[3,3],[3,3]]])
>>> arr.shape
(3, 2, 2)
>>> arr
array([[[1, 1],
[1, 1]],
[[2, 2],
[2, 2]],
[[3, 3],
[3, 3]]])
>>> arr[:,0,0]
array([1, 2, 3])
The channel values at each location are [1,2,3]. The goal is to swap the channel axis(length 3) to the end.
>>> arr.reshape((2,2,3))[0,0]
array([1, 1, 1]) # incorrect
>>> arr.transpose((1,2,0))[0,0] # similar to what permute does.
array([1, 2, 3]) # correct
More examples at this link: https://discuss.pytorch.org/t/how-to-change-shape-of-a-matrix-without-dispositioning-the-elements/30708
From the accepted answer in this question,
given the following
input and kernel matrices, the output of tf.nn.conv2d is
[[14 6]
[6 12]]
which makes sense. However, when I make the input and kernel matrices have 3-channels each (by repeating each original matrix), and run the same code:
# the previous input
i_grey = np.array([
[4, 3, 1, 0],
[2, 1, 0, 1],
[1, 2, 4, 1],
[3, 1, 0, 2]
])
# copy to 3-dimensions
i_rgb = np.repeat( np.expand_dims(i_grey, axis=0), 3, axis=0 )
# convert to tensor
i_rgb = tf.constant(i_rgb, dtype=tf.float32)
# make kernel depth match input; same process as input
k = np.array([
[1, 0, 1],
[2, 1, 0],
[0, 0, 1]
])
k_rgb = np.repeat( np.expand_dims(k, axis=0), 3, axis=0 )
# convert to tensor
k_rgb = tf.constant(k_rgb, dtype=tf.float32)
here's what my input and kernel matrices look like at this point
# reshape input to format: [batch, in_height, in_width, in_channels]
image_rgb = tf.reshape(i_rgb, [1, 4, 4, 3])
# reshape kernel to format: [filter_height, filter_width, in_channels, out_channels]
kernel_rgb = tf.reshape(k_rgb, [3, 3, 3, 1])
conv_rgb = tf.squeeze( tf.nn.conv2d(image_rgb, kernel_rgb, [1,1,1,1], "VALID") )
with tf.Session() as sess:
conv_result = sess.run(conv_rgb)
print(conv_result)
I get the final output:
[[35. 15.]
[35. 26.]]
But I was expecting the original output*3:
[[42. 18.]
[18. 36.]]
because from my understanding, each channel of the kernel is convolved with each channel of the input, and the resultant matrices are summed to get the final output.
Am I missing something from this process or the tensorflow implementation?
Reshape is a tricky function. It will produce you the shape you want, but can easily ground things together. In cases like yours, one should avoid using reshape by all means.
In that particular case instead, it is better to duplicate the arrays along the new axis. When using [batch, in_height, in_width, in_channels] channels is the last dimension and it should be used in repeat() function. Next code should better reflect the logic behind it:
i_grey = np.expand_dims(i_grey, axis=0) # add batch dim
i_grey = np.expand_dims(i_grey, axis=3) # add channel dim
i_rgb = np.repeat(i_grey, 3, axis=3 ) # duplicate along channels dim
And likewise with filters:
k = np.expand_dims(k, axis=2) # input channels dim
k = np.expand_dims(k, axis=3) # output channels dim
k_rgb = np.repeat(k, 3, axis=2) # duplicate along the input channels dim