I have the date as below
SELECT TO_CHAR(SYSDATE, 'DDD') FROM dual;
result for above query is : 117
I need to convert this 117 to month and day. anyone knows how to perform this in PL SQL
the expected result is 04-27
Change 'DDD' to 'MM-DD'.
Try this:
SELECT TO_CHAR(SYSDATE, 'MM-DD')
FROM dual;
OUTPUT:
04-27
Demo:
http://sqlfiddle.com/#!4/622055/7
EDITED:
DDD shows Number of Days from the first of a year.
For Example:
SELECT TO_CHAR(TO_DATE('2018-01-01','YYYY-MM-DD'), 'DDD')
FROM dual;
gives output 001 since it is the First Day of year 2018.
So to break 117 you need the year.
Then you can use this query.
SELECT TO_CHAR(TO_DATE('2018-01-01','YYYY-MM-DD') + column_name - 1, 'MM-DD')
FROM dual;
Example Query:
SELECT TO_CHAR(TO_DATE('2018-01-01','YYYY-MM-DD') + 117 - 1, 'MM-DD')
FROM dual;
OUTPUT:
04-27
Demo:
http://sqlfiddle.com/#!4/622055/37
If you have "117" and want to convert it to a date, you'll have to use a little bit (but really - just a little bit) of arithmetics. As 'DDD' represents number of days since the 1st of current year, add it to ... well the 1st of current year and apply appropriate format mask to convert it to date. I subtracted "1" as you want to get yesterday.
For example:
SQL> select to_char(sysdate, 'ddd') from dual;
TO_
---
117
SQL> select to_date(trunc(sysdate, 'yyyy') + 117, 'dd.mm.rrrr') - 1 resul
2 from dual;
RESULT
----------
27.04.2018
SQL>
Or, using the format you specified (MM-DD):
SQL> select to_char(trunc(sysdate, 'yyyy') + 117 - 1, 'mm-dd') result
2 from dual;
RESUL
-----
04-27
SQL>
Related
I want No. of days between these 2 dates using Oracle SQL
Dates:
BETWEEN "1/1/2018" AND "6/11/2018"
How to write SQL Query?
between date '2018-01-01' and date '2018-11-06'
where DATE literal looks exactly like that: DATE 'YYYY-MM-DD'
In your example:
double quote's can't be used
even if you used single quotes, that would be a string, not DATE so you'd depend on whether Oracle is capable of converting it (implicitly) to date or not
therefore, always use dates, not strings
[EDIT]
This is how you select the whole calendar between those two dates:
select date '2018-01-01' + level - 1
from dual
connect by level <= date '2018-11-06' - date '2018-01-01' + 1;
As other answers have pointed out you can simply divide two dates, but there is also no need for any additional arithmetic.
The code:
select to_date('6/11/2018', 'DD/MM/YYYY') - to_date('1/1/2018', 'DD/MM/YYYY')
from dual;
The result: 309
you can simple do:
select date1-date2 form dual;
or
select (sysdate-to_date('01-jan-2018'))-(sysdate-to_date('10-jan-2018'))from dual;
Just use
select date'2018-11-06' - date'2018-01-01' + 1 as days_difference
from dual;
DAYS_DIFFERENCE
---------------
310
or
with t( myDate ) as
(
select date'2018-11-06' from dual union all
select date'2018-01-01' from dual
)
select max(myDate) - min(myDate) + 1 as days_difference
from t;
DAYS_DIFFERENCE
---------------
310
How to get the last date of next year in oracle sql?
Last date of next year is one day before the first day of the year after next. So you should be able to get it by adding 24 months to the first day of THIS year, and then subtracting one day. Like this:
select sysdate, add_months(trunc(sysdate, 'y'), 24) - 1 as last_day_next_year from dual;
SYSDATE LAST_DAY_NEXT_YEAR
---------- ------------------
2016-08-04 2017-12-31
1 row selected.
Try this:
select add_months(to_date('31-DEC-' || to_char(current_date, 'YYYY')),12) from dual;
Something like...
Select last_day(add_months(sysdate, 12 + (12- to_number(to_char(sysdate, 'mm'))))) from dual;
I have dates stored like String in database.
The format is 'yyyy-ww' (example: '2015-43').
I need to get the first day of the week.
I tried to convert this string into date but there is no 'ww' option for the function "to_date".
Do you have an idea to perform this convertion?
EDIT
Test results based on the answers -
Thanks for your anwsers, but I have many problems to apply your solutions to my context:
select
TRUNC ( 2015 + ((43 - 1) * 7), 'IW' )
from dual
==> Error : ORA-01722: invalid number
select
TRUNC(to_date('2015','YYYY')+ to_number('01') *7, 'IW')
from dual
==> 2015-02-02 00:00:00
I waited for a date in january
select
trunc(to_date(regexp_substr('2015-01', '\d+',1,2), 'YYYY') + regexp_substr('2015-01', '\d+') * 7, 'IW') dt2
from dual
==> 0039-09-14 00:00:00
select
regexp_substr('2015-01', '\d+',1,2) as res1,
regexp_substr('2015-01', '\d+') * 7 as res2
from dual
==> res1 = 01
==> res2 = 14105
try to use by truncate
with t as (
select '16-2010' dt from dual
)
--
--
select dt,
trunc(to_date(regexp_substr(dt, '\d+',1,2), 'YYYY') + regexp_substr(dt, '\d+') * 7, 'IW') dt2
from t
I have dates stored like String in database.
You should never do that. It is a bad design. you should store date as DATE and not as a string. For all kinds of requirements for date manipulations Oracle provides the required DATE functions and format models. As and when needed, you could extract/display the way you want.
I need to get the first day of the week.
TRUNC (dt, 'IW') returns the Monday on or before the given date.
Anyway, in your case, you have the literal as YYYY-WW format. You could first extract the year and week number and combine them together to get the date using TRUNC.
TRUNC ( year + ((week_number - 1) * 7)
, 'IW
)
So, the above should give you the Monday of the week number passed for that year.
SQL> WITH DATA AS
2 ( SELECT '2015-43' str FROM dual
3 )
4 SELECT TRUNC(to_date(SUBSTR(str, 1, 4),'YYYY')+ to_number(SUBSTR(str, instr(str, '-',1)+1))*7, 'IW')
5 FROM DATA
6 /
TRUNC(TO_
---------
23-NOV-15
SQL>
Similar to Lalit's, however, I think I've corrected the math (his seemed to be off a bit when I tested .. )
with w_data as (
select sysdate + level +200 d from dual connect by level <= 10
),
w_weeks as (
select d, to_char(d,'yyyy-iw') c
from w_data
)
SELECT d, c, trunc(d,'iw'),
TRUNC(
to_date(SUBSTR(c, 1, 4)||'0101','yyyymmdd')-8+to_char(to_date(SUBSTR(c, 1, 4)||'0101','yyyymmdd'),'d')
+to_number(SUBSTR(c, instr(c, '-',1)+1)-1)*7 ,'IW')
FROM w_weeks;
The extra columns help show the dates before, and after.
I would do the following:
WITH d1 AS (
SELECT '2015-43' AS mydate FROM dual
)
SELECT TRUNC(TRUNC(TO_DATE(REGEXP_SUBSTR(mydate, '^\d{4}'), 'YYYY'), 'YEAR') + (COALESCE(TO_NUMBER(REGEXP_SUBSTR(mydate, '\d+$')), 0)-1) * 7, 'IW')
FROM d1
The first thing the above query does is get the first four digits of the string 2015-43 and truncates that to the closest year (if you convert convert 2015 using TO_DATE() it returns a date within the current month; that is SELECT TO_DATE('2015', 'YYYY') FROM dual returns 01-FEB-2015; we need to truncate this value to the YEAR in order to get 01-JAN-2015). I then add the number of weeks minus one times seven and truncate the whole thing by IW. This returns a date of 01-OCT-2015 (see SQL Fiddle here).
According ISO the 4th of January is always in week 1, so your query should look like
Select
TRUNC(TO_DATE(REGEXP_SUBSTR(your_column, '^\d{4}')||'-01-04', 'YYYY-MM-DD')
+ 7*(REGEXP_SUBSTR(your_column, '\d$')-1), 'IW')
from your_table;
However, there is a problem. ISO year used for Week number can be different than actual year. For example, 1st Jan 2008 was in ISO week number 53 of 2007.
I think a proper working solution you get only when you generate ISO weeks from date value.
WITH w AS
(SELECT TO_CHAR(DATE '2010-01-04' + LEVEL * INTERVAL '7' DAY, 'IYYY-IW') AS week_number,
TRUNC(DATE '2010-01-04' + LEVEL * INTERVAL '7' DAY, 'IW') AS first_day
FROM dual
CONNECT BY DATE '2010-01-04' + LEVEL * INTERVAL '7' DAY < SYSDATE)
SELECT your_Column, first_day
FROM w your_table
JOIN w ON week_number = your_Column;
Your date range must bigger than 2010-01-04 and not bigger than current day.
This is what I used:
select
to_date(substr('2017/01',1,4)||'/'||to_char(to_number(substr('2017/01',6,2)*7)-5),'yyyy/ddd') from dual;
I require a query that selects rows where the time is less or equal to 12:00
I had something like this in mind:
SELECT daterow FROM datecolumn WHERE daterow <= TO_DATE('12:00, HH24:MI')
However i get an error:
ORA-01843: not a valid month
How would i go about to get all rows that have a time less than 12:00 mid-day?
Try this,
SELECT daterow FROM datecolumn WHERE daterow <= TO_DATE('12:00', 'HH24:MI');
Try This:
SELECT daterow FROM datecolumn
WHERE TO_DATE(daterow,'HH24:MI') <= TO_DATE('12:00', 'HH24:MI');
In order to select all rows where time portion of the daterow column value is less than or equal to mid-day 12:00 you can use to_char() function to extract hour and minutes and to_number() to convert it to a number for further comparison:
-- sample of data. Just for the sake of demonstration
SQL> with t1(col) as(
2 select sysdate - to_dsinterval('P0DT3H') from dual union all
3 select sysdate - to_dsinterval('P0DT2H') from dual union all
4 select sysdate - to_dsinterval('P0DT1H') from dual union all
5 select sysdate + to_dsinterval('P0DT3H') from dual union all
6 select sysdate + to_dsinterval('-P2DT0H') from dual
7 )
8 select to_char(col, 'dd.mm.yyyy hh24:mi:ss') as res
9 from t1 t
10 where to_number(to_char(col, 'hh24mi')) <= 1200
11 ;
Result:
RES
-------------------
26.08.2013 08:10:59
26.08.2013 09:10:59
26.08.2013 10:10:59
24.08.2013 11:10:59
Sorry, but <= TO_DATE('12:00', 'HH24:MI') does not work. It does not extract the hour and minute from each date and compares it to 12:00. Instead it constructs the date representing high noon on the fisrt of the current month and compares each date to this date.
If you want to extract something from a date, use the extract function.
Attention: When using extract on a date, and want to extract hours, minutes or seconds, you have first to convert the date to a timestamp.
Example:
SELECT
extract(hour FROM cast(A AS TIMESTAMP)) AS h,
extract(MINUTE FROM cast(A AS TIMESTAMP)) AS m
FROM
DEMO
;
You can find a complete example on sqlfiddle. The example also shows that the to_date method doesn't work.
See the results of below queries:
>> SELECT ADD_MONTHS(TO_DATE('30-MAR-11','DD-MON-RR'),-4) FROM DUAL;
30-NOV-10
>> SELECT ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR'),4) FROM DUAL;
31-MAR-11
How can I get '30-MAR-11' when adding 4 months to some date?
Please help.
There is another question here about Oracle and Java
It states that
From the Oracle reference on add_months http://download-west.oracle.com/docs/cd/B19306_01/server.102/b14200/functions004.htm
If date is the last day of the month or if the resulting month has fewer days than the day component of date, then the result is the last day of the resulting month. Otherwise, the result has the same day component as date.
So I guess you have to manually check stating day and ending day to change the behaviour of the function. Or maybe by adding days instead of months. (But I didn't find a add_day function in the ref)
As a workaround, I might possibly use this algorithm:
Calculate the target date TargetDate1 using ADD_MONTHS.
Alternatively calculate the target date TargetDate2 like this:
1) apply ADD_MONTHS to the first of the source date's month;
2) add the difference of days between the source date and the beginning of the same month.
Select the LEAST between the TargetDate1 and TargetDate2.
So in the end, the target date will contain a different day component if the source date's day component is greater than the number of day in the target month. In this case the target date will be the last day of the corresponding month.
I'm not really sure about my knowledge of Oracle's SQL syntax, but basically the implementation might look like this:
SELECT
LEAST(
ADD_MONTHS(SourceDate, Months),
ADD_MONTHS(TRUNC(SourceDate, 'MONTH'), Months)
+ (SourceDate - TRUNC(SourceDate, 'MONTH'))
) AS TargetDate
FROM (
SELECT
TO_DATE('30-NOV-10', 'DD-MON-RR') AS SourceDate,
4 AS Months
FROM DUAL
)
Here is a detailed illustration of how the method works:
SourceDate = '30-NOV-10'
Months = 4
TargetDate1 = ADD_MONTHS('30-NOV-10', 4) = '31-MAR-11' /* unacceptable */
TargetDate2 = ADD_MONTHS('01-NOV-10', 4) + (30 - 1)
= '01-MAR-11' + 29 = '30-MAR-11' /* acceptable */
TargetDate = LEAST('31-MAR-11', '30-MAR-11') = '30-MAR-11'
And here are some more examples to show different cases:
SourceDate | Months | TargetDate1 | TargetDate2 | TargetDate
-----------+--------+-------------+-------------+-----------
29-NOV-10 | 4 | 29-MAR-11 | 29-MAR-11 | 29-MAR-11
30-MAR-11 | -4 | 30-NOV-10 | 30-NOV-10 | 30-NOV-10
31-MAR-11 | -4 | 30-NOV-10 | 01-DEC-10 | 30-NOV-10
30-NOV-10 | 3 | 28-FEB-11 | 02-MAR-11 | 28-FEB-11
You can use interval arithmetic to get the result you want
SQL> select date '2011-03-30' - interval '4' month
2 from dual;
DATE'2011
---------
30-NOV-10
SQL> ed
Wrote file afiedt.buf
1 select date '2010-11-30' + interval '4' month
2* from dual
SQL> /
DATE'2010
---------
30-MAR-11
Be aware, however, that there are pitfalls to interval arithmetic if you're working with days that don't exist in every month
SQL> ed
Wrote file afiedt.buf
1 select date '2011-03-31' + interval '1' month
2* from dual
SQL> /
select date '2011-03-31' + interval '1' month
*
ERROR at line 1:
ORA-01839: date not valid for month specified
How about something like this:
SELECT
LEAST(
ADD_MONTHS(TO_DATE('30-MAR-11','DD-MON-RR'),-4),
ADD_MONTHS(TO_DATE('30-MAR-11','DD-MON-RR')-1,-4)+1
)
FROM
DUAL
;
Result: 30-NOV-10
SELECT
LEAST(
ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR'),4),
ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR')-1,4)+1
)
FROM
DUAL
;
Result: 30-MAR-11
the add_months function returns a date plus n months.
Since 30th November is the last date of the month, adding 4 months will result in a date that's the end of 4 months. This is expected behavior. If the dates are not bound to change, a workaround is to subtract a day after the new date has been returned
SQL> SELECT ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR'),4) -1 from dual;
ADD_MONTH
---------
30-MAR-11
SELECT TO_DATE('30-NOV-10','DD-MON-RR') +
(
ADD_MONTHS(TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM'),4) -
TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM')
) RESULT
FROM DUAL;
This section in paranthesis:
ADD_MONTHS(TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM'),4) - TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM')
gives you number of days between the date you entered and 4 months later. So, adding this number of days to the date you given gives the exact date after 4 months.
Ref: http://www.dba-oracle.com/t_test_data_date_generation_sql.htm
Simple solution:
ADD_MONTHS(date - 1, x) + 1
Here is the trick:
select add_months(to_date('20160228', 'YYYYMMDD')-1, 1)+1 from dual;
Enjoy!
We have come to simpler (in our understanding) solution to this problem - take the least day number from original and add_month result dates, as this:
TRUNC(ADD_MONTHS(input_date,1),'MM') + LEAST(TO_CHAR(input_date, 'DD'), TO_CHAR(ADD_MONTHS(input_date,1), 'DD')) - 1
Some other examples here do not work on every date, below our test results:
WITH DATES as (
SELECT TO_DATE('2020-01-31', 'YYYY-MM-DD HH24:MI:SS') as input_date,
'2020-02-29' as expected_date
FROM dual
UNION ALL
SELECT TO_DATE('2020-02-28', 'YYYY-MM-DD HH24:MI:SS'),
'2020-03-28'
FROM dual
UNION ALL
SELECT TO_DATE('2020-09-30', 'YYYY-MM-DD HH24:MI:SS'),
'2020-10-30'
FROM dual
UNION ALL
SELECT TO_DATE('2020-09-01', 'YYYY-MM-DD HH24:MI:SS'),
'2020-10-01'
FROM dual
UNION ALL
SELECT TO_DATE('2019-01-30', 'YYYY-MM-DD HH24:MI:SS'),
'2019-02-28'
FROM dual
UNION ALL
SELECT TO_DATE('2020-02-29', 'YYYY-MM-DD HH24:MI:SS'),
'2020-03-29'
FROM dual
UNION ALL
SELECT TO_DATE('2020-09-29', 'YYYY-MM-DD HH24:MI:SS'),
'2020-10-29'
FROM dual
UNION ALL
SELECT TO_DATE('2020-03-01', 'YYYY-MM-DD HH24:MI:SS'),
'2020-04-01'
FROM dual
),
methods as (
SELECT
input_date,
expected_date,
ADD_MONTHS(input_date,1) as standard_way,
add_months(input_date-1, 1)+1 as wrong_way,
TO_DATE(LEAST(TO_CHAR(input_date, 'DD'), TO_CHAR(ADD_MONTHS(input_date,1), 'DD')) || '-' || TO_CHAR(ADD_MONTHS(input_date,1), 'MM-YYYY'), 'DD-MM-YYYY') as good_way,
TRUNC(ADD_MONTHS(input_date,1),'MM') + LEAST(TO_CHAR(input_date, 'DD'), TO_CHAR(ADD_MONTHS(input_date,1), 'DD')) - 1 as better_way
FROM
DATES
)
SELECT
input_date,
expected_date,
standard_way,
CASE WHEN TO_CHAR(standard_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as standard_way_ok,
wrong_way,
CASE WHEN TO_CHAR(wrong_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as wrong_way_ok,
good_way,
CASE WHEN TO_CHAR(good_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as good_way_ok,
better_way,
CASE WHEN TO_CHAR(better_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as better_way_ok
FROM
methods
;
CREATE OR REPLACE FUNCTION My_Add_Month(
STARTDATE DATE,
MONTHS_TO_ADD NUMBER
)
RETURN DATE
IS
MY_ADD_MONTH_RESULT DATE;
BEGIN
SELECT ORACLES_ADD_MONTH_RESULT + NET_DAYS_TO_ADJUST INTO MY_ADD_MONTH_RESULT FROM
(
SELECT T.*,CASE WHEN SUBSTRACT_DAYS > ADD_DAYS THEN ADD_DAYS - SUBSTRACT_DAYS ELSE 0 END AS NET_DAYS_TO_ADJUST FROM
(
SELECT T.*,EXTRACT(DAY FROM ORACLES_ADD_MONTH_RESULT) AS SUBSTRACT_DAYS FROM
(
SELECT ADD_MONTHS(STARTDATE,MONTHS_TO_ADD) AS ORACLES_ADD_MONTH_RESULT,EXTRACT(DAY FROM STARTDATE) AS ADD_DAYS FROM DUAL
)T
)T
)T;
RETURN TRUNC(MY_ADD_MONTH_RESULT);
END My_Add_Month;
/
--test & verification of logic & function both
SELECT T.*,ORACLES_ADD_MONTH_RESULT + NET_DAYS_TO_ADJUST AS MY_ADD_MONTH_RESULT,
My_Add_Month(STARTDATE,MONTHS_TO_ADD) MY_ADD_MONTH_FUNCTION_RESULT
FROM
(
SELECT T.*,CASE WHEN SUBSTRACT_DAYS > ADD_DAYS THEN ADD_DAYS - SUBSTRACT_DAYS ELSE 0 END AS NET_DAYS_TO_ADJUST FROM
(
SELECT T.*,EXTRACT(DAY FROM ORACLES_ADD_MONTH_RESULT) AS SUBSTRACT_DAYS FROM
(
SELECT T.*,ADD_MONTHS(STARTDATE,MONTHS_TO_ADD) AS ORACLES_ADD_MONTH_RESULT,EXTRACT(DAY FROM STARTDATE) AS ADD_DAYS FROM
(
SELECT TO_DATE('28/02/2014','DD/MM/YYYY') AS STARTDATE, 1 AS MONTHS_TO_ADD FROM DUAL
)T
)T
)T
)T;
Query-result
STARTDATE 2/28/2014
MONTHS_TO_ADD 1
ORACLES_ADD_MONTH_RESULT 3/31/2014
ADD_DAYS 28
SUBSTRACT_DAYS 31
NET_DAYS_TO_ADJUST -3
MY_ADD_MONTH_RESULT 3/28/2014
MY_ADD_MONTH_FUNCTION_RESULT 3/28/2014