I have a table called requests, and Im looking to count how many requests where the column rideId is not null each day during the last week. I have the following query:
Select count(*), dayname(time) as Day
from request
where time >= (select current_timestamp - interval 7 day) and rideId is not null
group by dayname(time)
order by dayofweek(Day);
How can I make it so it shows me those days where there is no request with rideId and count should be 0
Table is: Request(userId, time, rideId)
Move the not null check into your count, and join to a calendar table to bring in the missing days.
SELECT
t1.dname,
COALESCE(t2.numRides, 0) AS numRides
FROM
(
SELECT 'Monday' AS dname, 2 AS dow UNION ALL
SELECT 'Tuesday', 3 UNION ALL
SELECT 'Wednesday', 4 UNION ALL
SELECT 'Thursday', 5 UNION ALL
SELECT 'Friday', 6 UNION ALL
SELECT 'Saturday', 7 UNION ALL
SELECT 'Sunday', 1
) t1
LEFT JOIN
(
SELECT DAYNAME(time) AS dname, COUNT(rideId) AS numRides
FROM request
WHERE time >= DATE_SUB(CURDATE(),INTERVAL 7 DAY)
GROUP BY DAYNAME(time)
) t2
ON t1.dname = t2.dname
ORDER BY t1.dow;
Select a.day, coalesce(b.cnt, 0) as cnt
from (--select all days here) a
left join
(select dayname(time) as day, count(*) as cnt
from requests
where some_condition
group by day) b
using a.day = b.day
order by day;
Related
Is there a way to improve this query? I see two problems here -
Repetitive code
Hard coded strings
The first CTE calculates count based on 18 months. The second CTE calculates count based on 12 months.
with month_18 as (
select proc_cd, count(*) as month_18 from
(
select distinct patient, proc_cd from
service
where proc_cd = '35'
and month_id >= (select month_id from annual)
and month_id <= '202009' --This month should be 18 months from the month above
and length(patient) > 1
) a
group by proc_cd
),
month_12 as
(
select proc_cd, count(*) as month_12 from
(
select distinct patient_id, proc_cd from
service
where proc_cd = '35'
and month_id >= '201910'
and month_id <= '202009' --This month should be 12 months from the month above
and length(patient) > 1
) a
group by proc_cd
)
select a.*, b.month_12 from
month_18 a
join month_12 b
on a.proc_cd = b.proc_cd
If I understand correctly, you can use conditional aggregation:
select proc_cd,
count(distinct patient) filter (where month_id >= (select month_id from annual) and month_id <= '202009') as month_18,
count(distinct patient) filter (where month_id >= '201910' and month_id <= '202009')
from service
where proc_cd = 35 and
length(patient) > 1
group by proc_cd;
If you have to deal with date arithmetic on the month ids, you can convert to a date, do the arithmetic and convert back to a string:
select to_char(to_date(month_id, 'YYYYMM') - interval '12 month', 'YYYYMM')
from (values ('202009')) v(month_id);
I have a table have 3 columns id, open_time, close_time, the data looks like this:
then I want a SQL to get result like this:
the rule is : if the date equals to open time then New, if the date > open_time and date < close_time then Open, if the date equals close_time then Closed
how can I write the SQL in Oracle?
First build a table on-the-fly containing all dates from the minimum date in the table until today. You need a recursive query for this.
Then build a table on-the-fly for the three statuses.
Now cross join the two to get all combinations. These are the rows you want.
The rest is counting per day and status, which can be achieved with a join and grouping or with one or more subqueries. I'm showing the join:
with days(day) as
(
select min(open_time) as day from opentimes
union all
select day + 1 from days where day < trunc(sysdate)
)
, statuses as
(
select 'New' as status, 1 as sortkey from dual
union all
select 'Open' as status, 2 as sortkey from dual
union all
select 'Close' as status, 3 as sortkey from dual
)
select
d.day,
s.status,
count(case when (s.status = 'New' and d.day = o.open_time)
or (s.status = 'Open' and d.day = o.close_time)
or (s.status = 'Close' and d.day > cls.open_time and d.day < cls.close_time)
then 1 end) as cnt
from days d
cross join statuses s
join opentimes o on d.day between o.open_time and o.close_time
group by d.day, s.status
order by d.day, max(s.sortkey);
I have the following statement to extract the date, hour and number of users from a table in a Teradata DB . . .
SELECT
CAST(end_time AS DATE) AS end_date,
EXTRACT(HOUR FROM end_time) AS end_hour,
COUNT(users) AS total_users
FROM table
GROUP BY end_date, end_hour
When using the extract() function, my resultset contains missing hours where there is no activity by users over a 24 hour period... I'm wondering is there any technique to account for these missing hours in my resultset?
I can't creat a lookup table to reference as I don't have the necessary permissions to create a table on this DB.
Any help would be appreciated!
sys_calendar.calendar to generate the requested dates (change the range as needed)
WITH RECURSIVE to generate the hours
with recursive cte_hours (hr)
as
(
select 0 from (select 1) t(c)
union all select hr + 1 from cte_hours where hr < 23
)
select c.calendar_date as dt
,h.hr as hr
,zeroifnull(t.total_users) as total_users
from sys_calendar.calendar as c
cross join cte_hours as h
left join (select cast(end_time as date) as end_date
,extract(hour from end_time) as end_hour
,count(users) as total_users
from mytable t
group by end_date
,end_hour
) t
on t.end_date = c.calendar_date
and t.end_hour = h.hr
where c.calendar_date between current_date - 10 and current_date
order by dt,hr
;
For #GordonLinoff
select 0
0
select 1
1
select 0
union all
select 1
[3888] A SELECT for a UNION,INTERSECT or MINUS must reference a table.
select 0 from (select 1 as c) t
union all
select 1 from (select 1 as c) t
0
1
or
select 0 from (select 1) t(c)
union all
select 1 from (select 1) t(c)
0
1
If you want all hours from all days in the database, then you can generate the rows using cross join and then use left join to bring in results:
SELECT d.end_date,
EXTRACT(HOUR FROM end_time) AS end_hour,
COUNT(t.users) AS total_users
FROM (select distinct CAST(end_time AS DATE) AS end_date from table) d CROSS JOIN
(select distinct EXTRACT(HOUR FROM end_time) AS end_hour from table) h LEFT JOIN
table t
ON t.end_date = d.end_date and t.end_hour = d.end_hour
GROUP BY e.end_date, h.end_hour;
If all hours are not represented, you can use an explicit list:
SELECT d.end_date,
EXTRACT(HOUR FROM end_time) AS end_hour,
COUNT(t.users) AS total_users
FROM (select distinct CAST(end_time AS DATE) AS end_date from table) d CROSS JOIN
(select * from (select 0 as end_hour) t UNION ALL
select * from (select 1 as end_hour) t UNION ALL
. . .
) h LEFT JOIN
table t
ON t.end_date = d.end_date and t.end_hour = d.end_hour
GROUP BY e.end_date, h.end_hour;
I have an sql table like that:
Id Date Price
1 21.09.09 25
2 31.08.09 16
1 23.09.09 21
2 03.09.09 12
So what I need is to get min and max date for each id and dif in days between them. It is kind of easy. Using SQLlite syntax:
SELECT id,
min(date),
max(date),
julianday(max(date)) - julianday(min(date)) as dif
from table group by id
Then the tricky one: how can I receive the price per day during this difference period. I mean something like this:
ID Date PricePerDay
1 21.09.09 25
1 22.09.09 0
1 23.09.09 21
2 31.08.09 16
2 01.09.09 0
2 02.09.09 0
2 03.09.09 12
I create a cte as you mentioned with calendar but dont know how to get the desired result:
WITH RECURSIVE
cnt(x) AS (
SELECT 0
UNION ALL
SELECT x+1 FROM cnt
LIMIT (SELECT ((julianday('2015-12-31') - julianday('2015-01-01')) + 1)))
SELECT date(julianday('2015-01-01'), '+' || x || ' days') as date FROM cnt
p.s. If it will be in sqllite syntax-would be awesome!
You can use a recursive CTE to calculate all the days between the min date and max date. The rest is just a left join and some logic:
with recursive cte as (
select t.id, min(date) as thedate, max(date) as maxdate
from t
group by id
union all
select cte.id, date(thedate, '+1 day') as thedate, cte.maxdate
from cte
where cte.thedate < cte.maxdate
)
select cte.id, cte.date,
coalesce(t.price, 0) as PricePerDay
from cte left join
t
on cte.id = t.id and cte.thedate = t.date;
One method is using a tally table.
To build a list of dates and join that with the table.
The date stamps in the DD.MM.YY format are first changed to the YYYY-MM-DD date format.
To make it possible to actually use them as a date in the SQL.
At the final select they are formatted back to the DD.MM.YY format.
First some test data:
create table testtable (Id int, [Date] varchar(8), Price int);
insert into testtable (Id,[Date],Price) values (1,'21.09.09',25);
insert into testtable (Id,[Date],Price) values (1,'23.09.09',21);
insert into testtable (Id,[Date],Price) values (2,'31.08.09',16);
insert into testtable (Id,[Date],Price) values (2,'03.09.09',12);
The SQL:
with Digits as (
select 0 as n
union all select 1
union all select 2
union all select 3
union all select 4
union all select 5
union all select 6
union all select 7
union all select 8
union all select 9
),
t as (
select Id,
('20'||substr([Date],7,2)||'-'||substr([Date],4,2)||'-'||substr([Date],1,2)) as [Date],
Price
from testtable
),
Dates as (
select Id, date(MinDate,'+'||(d2.n*10+d1.n)||' days') as [Date]
from (
select Id, min([Date]) as MinDate, max([Date]) as MaxDate
from t
group by Id
) q
join Digits d1
join Digits d2
where date(MinDate,'+'||(d2.n*10+d1.n)||' days') <= MaxDate
)
select d.Id,
(substr(d.[Date],9,2)||'.'||substr(d.[Date],6,2)||'.'||substr(d.[Date],3,2)) as [Date],
coalesce(t.Price,0) as Price
from Dates d
left join t on (d.Id = t.Id and d.[Date] = t.[Date])
order by d.Id, d.[Date];
The recursive SQL below was totally inspired by the excellent answer from Gordon Linoff.
And a recursive SQL is probably more performant for this anyway.
(He should get the 15 points for the accepted answer).
The difference in this version is that the datestamps are first formatted to YYYY-MM-DD.
with t as (
select Id,
('20'||substr([Date],7,2)||'-'||substr([Date],4,2)||'-'||substr([Date],1,2)) as [Date],
Price
from testtable
),
cte as (
select Id, min([Date]) as [Date], max([Date]) as MaxDate from t
group by Id
union all
select Id, date([Date], '+1 day'), MaxDate from cte
where [Date] < MaxDate
)
select cte.Id,
(substr(cte.[Date],9,2)||'.'||substr(cte.[Date],6,2)||'.'||substr(cte.[Date],3,2)) as [Date],
coalesce(t.Price, 0) as PricePerDay
from cte
left join t
on (cte.Id = t.Id and cte.[Date] = t.[Date])
order by cte.Id, cte.[Date];
Suppose I have a table that indicates the number of items sold in a particular month for each sales rep. However, there will not be a row for a particular person in months where there were no sales. Example
rep_id month_yr num_sales
1 01/01/2012 3
1 05/01/2012 1
1 11/01/2012 1
2 02/01/2012 2
2 05/01/2012 1
I want to be able to create a query that shows for each rep_id and all possible months (01/01/2012, 02/01/2012, etc. through current) a rolling 12 month sales sum, like this:
rep_id month_yr R12_Sum
1 11/01/2012 5
1 12/01/2012 5
1 01/01/2013 5
1 02/01/2013 2
I have found some examples online, but the problem I'm running into is I'm missing some dates for each rep_id. Do I need to cross join or something?
To solve this problem, you need a driver table that has all year/month combinations. Then, you need to create this for each rep.
The solution is then to left join the actual data to this driver and aggregate the period that you want. Here is the query:
with months as (
select 1 as mon union all select 2 union all select 3 union all select 4 union all
select 5 as mon union all select 6 union all select 7 union all select 8 union all
select 9 as mon union all select 10 union all select 11 union all select 12
),
years as (select 2010 as yr union all select 2011 union all select 2012 union all select 2013
),
monthyears as (
select yr, mon, yr*12+mon as yrmon
from months cross join years
),
rmy as (
select *
from monthyears my cross join
(select distinct rep_id from t
) r
)
select rmy.rep_id, rmy.yr, rmy.mon, SUM(t.num_sales) as r12_sum
from rmy join
t
on rmy.rep_id = t.rep_id and
t.year(month_yr)*12 + month(month_yr) between rmy.yrmon - 11 and rmy.yrmon
group by rmy.rep_id, rmy.yr, rmy.mon
order by 1, 2, 3
This hasn't been tested, so it may have syntactic errors. Also, it doesn't convert the year/month combination back to a date, leaving the values in separate columns.
Here is one solution:
SELECT
a.rep_id
,a.month_yr
,SUM(b.R12_Sum) AS R12_TTM
FROM YourTable a
LEFT OUTER JOIN YourTable b
ON a.rep_id = b.rep_id
AND a.month_yr <= b.month_yr
AND a.month_yr >= DATEADD(MONTH, -11, b.month_yr)
GROUP BY
a.rep_id
,a.month_yr
It's certainly not pretty but is more simple than a CTE, numbers table or self join:
DECLARE #startdt DATETIME
SET #startdt = '2012-01-01'
SELECT rep_id, YEAR(month_yr), MONTH(month_yr), SUM(num_sales)
FROM MyTable WHERE month_yr >= #startdt AND month_yr < DATEADD(MONTH,1,#startdt)
UNION ALL
SELECT rep_id, YEAR(month_yr), MONTH(month_yr), SUM(num_sales)
FROM MyTable WHERE month_yr >= DATEADD(MONTH,1,#startdt) AND month_yr < DATEADD(MONTH,2,#startdt)
UNION ALL
SELECT rep_id, YEAR(month_yr), MONTH(month_yr), SUM(num_sales)
FROM MyTable WHERE month_yr >= DATEADD(MONTH,2,#startdt) AND month_yr < DATEADD(MONTH,3,#startdt)
UNION ALL
SELECT rep_id, YEAR(month_yr), MONTH(month_yr), SUM(num_sales)
FROM MyTable WHERE month_yr >= DATEADD(MONTH,3,#startdt) AND month_yr < DATEADD(MONTH,4,#startdt)
UNION ALL
etc etc
The following demonstrates using a CTE to generate a table of dates and generating a summary report using the CTE. Sales representatives are omitted from the results when they have had no applicable sales.
Try jiggling the reporting parameters, e.g. setting #RollingMonths to 1, for more entertainment.
-- Sample data.
declare #Sales as Table ( rep_id Int, month_yr Date, num_sales Int );
insert into #Sales ( rep_id, month_yr, num_sales ) values
( 1, '01/01/2012', 3 ),
( 1, '05/01/2012', 1 ),
( 1, '11/01/2012', 1 ),
( 2, '02/01/2012', 1 ),
( 2, '05/01/2012', 2 );
select * from #Sales;
-- Reporting parameters.
declare #ReportEnd as Date = DateAdd( day, 1 - Day( GetDate() ), GetDate() ); -- The first of the current month.
declare #ReportMonths as Int = 6; -- Number of months to report.
declare #RollingMonths as Int = 12; -- Number of months in rolling sums.
-- Report.
-- A CTE generates a table of month/year combinations covering the desired reporting time period.
with ReportingIntervals as (
select DateAdd( month, 1 - #ReportMonths, #ReportEnd ) as ReportingInterval,
DateAdd( month, 1 - #RollingMonths, DateAdd( month, 1 - #ReportMonths, #ReportEnd ) ) as FirstRollingMonth
union all
select DateAdd( month, 1, ReportingInterval ), DateAdd( month, 1, FirstRollingMonth )
from ReportingIntervals
where ReportingInterval < #ReportEnd )
-- Join the CTE with the sample data and summarize.
select RI.ReportingInterval, S.rep_id, Sum( S.num_sales ) as R12_Sum
from ReportingIntervals as RI left outer join
#Sales as S on RI.FirstRollingMonth <= S.month_yr and S.month_yr <= RI.ReportingInterval
group by RI.ReportingInterval, S.rep_id
order by RI.ReportingInterval, S.rep_id