I have this select statement
SELECT id, liked, markers, search_body, remote_bare_jid, direction
FROM mam_message where user_id='20' AND remote_bare_jid =
'5a95c47078f92c6337019521' ORDER BY id DESC;
that returns the following
I want to retrieve rows of the latest range direction 'I' -> 'I'
THIS:
SELECT id, liked, markers, search_body, remote_bare_jid, direction
FROM mam_message
where user_id ='20'
AND remote_bare_jid = '5a95c47078f92c6337019521'
ORDER BY id DESC
limit 4;
Even when the range is not on top
I am still able to get only the latest range of direction 'I'
THIS (the highligted):
You can find transition rows (where direction changes from O to I) using the window function lag(). Mark these rows as 1 (0 the others). Next, calculate cumulative sum of these marks. The group sought will have the sum = 1. Example:
with example(id, direction) as (
values
(1, 'O'),
(2, 'I'),
(3, 'I'),
(4, 'I'),
(5, 'O'),
(6, 'I')
)
select id, direction
from (
select id, direction, sum(mark) over w
from (
select
id, direction,
(lag(direction, 1, 'O') over w = 'O' and direction = 'I')::int mark
from example
window w as (order by id)
) s
window w as (order by id)
) s
where direction = 'I' and sum = 1
order by id
id | direction
----+-----------
2 | I
3 | I
4 | I
(3 rows)
Related
I'm trying to identify duplicate state_num that are failing validation. The R is causing issues with validation, but I want to just search the first 7 characters and find the duplicate values, so that it returns the row that has an R in the string and the row that doesn't. The column is a type: char(15) But when trying to run a query it is not finding the matching 7 characters. My table only showing how it should look, its not showing what is actually being returned. It basically is just finding the state and only finding non R state_num in results. It should be returning around 480 rows but is returning like 20k rows and not just showing the duplicates
I've tried querying a bunch of different ways but i've spen the last hour only being able to return the R row if i ad AND state_num[8] = 'R' to the end of the query. Which defeats what I'm trying to find the duplicate first 7 characters. This is an informix db.
My Query:
SELECT id_ref, cont_ref, formatted, state_num, type, state
FROM state_form sf1
WHERE EXISTS (select cont_ref, san
FROM state_form sf2
WHERE sf1.cont_ref = sf2.cont_ref and left(sf1.state_num,7) = LEFT(sf2.state_num,7)
GROUP BY cont_ref, state_num
HAVING COUNT(state_num) > 1)
AND state = 'MT';
This is what I'd like my results to return:
id_ref
cont_ref
formatted
state_num
type
state
658311
5237
71-75011R
7175011R
Y
MT
1459
5237
71-75011
7175011
I
MT
7501
555678
99-67894
9967894
I
MT
345443
555678
99-67894R
9967894R
Y
MT
Here are a couple options producing the same results. This may need to be changed if you need to identify the 8th character as something such as a Letter. That is, this will also catch 12345678 and 1234567.
create table my_data (
id_ref integer,
cont_ref integer,
state_num varchar(20),
type varchar(5),
state varchar(5)
);
insert into my_data values
(1, 5237, '7175011R', 'Y', 'MT'),
(2, 5237, '7175011', 'I', 'MT'),
(3, 6789, '7878787', 'Y', 'CA'),
(4, 6789, '7878787R', 'I', 'CA'),
(5, 555678, '9967894', 'I', 'MT'),
(6, 555678, '9967894R', 'Y', 'MT'),
(7, 98765, '123456', 'I', 'MT');
Query #1
with dupes as (
select cont_ref
from my_data
where state = 'MT'
group by cont_ref, left(state_num, 7)
having count(*) > 1
)
select m.id_ref, m.cont_ref, m.state_num, m.type, m.state
from my_data m
join dupes d
on m.cont_ref = d.cont_ref;
Query #2
select m.id_ref, m.cont_ref, m.state_num, m.type, m.state
from my_data m
where m.cont_ref in (
select cont_ref
from my_data
where state = 'MT'
group by cont_ref, left(state_num, 7)
having count(*) > 1
);
id_ref
cont_ref
state_num
type
state
1
5237
7175011R
Y
MT
2
5237
7175011
I
MT
5
555678
9967894
I
MT
6
555678
9967894R
Y
MT
View on DB Fiddle
UPDATE
If Informix does not want to group by left(column, 7), then you could get the target cont_ref values using this. Here's the CTE method, but you could also do with sub-query.
with dupes as (
select cont_ref
from (
select cont_ref, left(state_num, 7) as left_seven
from my_data
where state = 'MT'
)z
group by cont_ref
having count(*) > 1
)
select m.*
from my_data m
join dupes d
on m.cont_ref = d.cont_ref;
I have a table in Snowflake in following format:
create temp_test(name string, split string, value int)
insert into temp_test
values ('A','a', 100), ('A','b', 200), ('A','c',300), ('A', 'd', 400), ('A', 'e',500), ('B', 'a', 1000), ('B','b', 2000), ('B','c', 3000), ('B', 'd',4000), ('B','e', 5000)
First step, I needed only top 2 value per name (sorted on value), so I used following query to get that:
select name, split, value,
row_number() over (PARTITION BY (name) order by value desc) as row_num
from temp_test
qualify row_num <= 2
Which gives me following resultset:
NAME SPLIT VALUE ROW_NUM
A e 500 1
A d 400 2
B e 5000 1
B d 4000 2
Now, I need to sum values other than Top 2 and put it in a different Split named as "Others", like this:
NAME SPLIT VALUE
A e 500
A d 400
A Others 600
B e 5000
B d 4000
B Others 6000
How to do that in Snowflake query or SQL in general?
with data as (
select name, split, value,
row_number() over (partition by (name) order by value desc) as row_num
from temp_test
)
select
name,
case when row_num <= 2 then split else 'Others' end as split,
sum(value) as value
from data
group by name, case when row_num <= 2 then row_num else 3 end
Shawnt00's answer is good, but for the record in Snowflake this can be written simpler:
Firstly the group by at the end can refer to the results by index or name:
GROUP BY 1,2
or
GROUP BY name, split
also as the CASE only has too branches an IFF can be used and seems you are using a CTE to add the row_number you can push the IFF into the CTE also
WITH data AS (
SELECT name, value,
ROW_NUMBER() OVER (PARTITION BY name ORDER BY value DESC) AS row_num,
IFF(row_num < 3, split, 'Others') as n_split
FROM VALUES ('A','a', 100), ('A','b', 200), ('A','c',300), ('A', 'd', 400),
('A', 'e',500), ('B', 'a', 1000), ('B','b', 2000), ('B','c', 3000),
('B', 'd',4000), ('B','e', 5000)
v(name, split, value)
)
SELECT
name,
n_split,
SUM(value) AS value
FROM data
GROUP BY name, n_split;
and if super keen on small SQL push the ROW_NUMBER into the IFF:
WITH data AS (
SELECT name, value,
IFF(ROW_NUMBER() OVER (PARTITION BY name ORDER BY value DESC) < 3, split, 'Others') as n_split
FROM VALUES ('A','a', 100), ('A','b', 200), ('A','c',300), ('A', 'd', 400),
('A', 'e',500), ('B', 'a', 1000), ('B','b', 2000), ('B','c', 3000),
('B', 'd',4000), ('B','e', 5000)
v(name, split, value)
)
SELECT
name,
n_split AS split,
SUM(value) AS value
FROM data
GROUP BY name, n_split;
gives:
NAME SPLIT VALUE
A e 500
A d 400
A Others 600
B e 5000
B d 4000
B Others 6000
I want to get the price of an article for a specific customer.
There are several levels of prices which i ranked in my query.
So Article A has a price on rank 1, 4, 6. The result should always be the lowest ranked price.
Article B rank 3 ,5
So article A price is ranked 1 and Article b is price ranked 3.
My query is below .
SELECT p2.* FROM(
SElect ART_ID, MIN(RANG) RANG FROM (
Select p.ART_ID, p.betrag ,
CASE p.PREIS_EBENE WHEN 'KA' THEN 1 WHEN 'KW' THEN 2 WHEN 'W' THEN 7 WHEN 'A' THEN 6 ELSE 99 END RANG
FROM MDART a
INNER JOIN MDPRSVK p ON (a.KLIENT_ID = p.KLIENT_ID AND a.ART_ID = p.ART_ID)
WHERE ICP_KZ.IS_SET(KENNUNG_USER, 'P') = 1
ORDER BY RANG)
GROUP BY ART_ID) T
INNER JOIN MDPRSVK p2 ON (p2.ART_ID = T.ART_ID AND p2.PREIS_EBENE = p.PREIS_EBENE)
i want to have every article appearing only once in the result
You have tagged your request PL/SQL, so I guess your DBMS may be Oracle.
If I understand correctly, the table MDPRSVK contains several prices per ART_ID. And you want to select each ART_ID's best price (best to worst: 'KA' -> 'KW' -> 'A' -> 'W' -> any other PREIS_EBENE).
You can use a window function (ROW_NUMBER, RANK or DENSE_RANK) for this:
select *
from mdprsvk
order by row_number()
over (partition by art_id
order by decode(preis_ebene, 'KA', 1, 'KW', 2, 'A', 3, 'W', 4, 5))
fetch first row with ties;
This is standard SQL. In Oracle, FETCH FIRST is available as of version 12c. In earlier versions you'd use a subquery instead:
select *
from
(
select
mdprsvk.*,
row_number() over (partition by art_id
order by decode(preis_ebene, 'KA', 1, 'KW', 2, 'A', 3, 'W', 4, 5))
as rn
from mdprsvk
)
where rn = 1;
Or use OraclesKEEP FIRST`:
select art_id, max(betrag)
keep (dense_rank first
order by decode(preis_ebene, 'KA', 1, 'KW', 2, 'A', 3, 'W', 4, 5))
from mdprsvk
group by art_id;
It is not clear, how MDART comes into play. It looks like you want to restrict your results to articles for certain clients and KENNUNG_USER is the column in MDART to check. If so, add a WHERE clause:
where exists
(
select *
from mdart
where mdart.klient_id = mdprsvk.klient_id
and mdart.art_id = mdprsvk.art_id
and icp_kz.is_set(mdart.kennung_user, 'p') = 1
)
Or with IN instead of EXISTS:
where (klient_id, art_id) in
(
select klient_id, art_id
from mdart
where icp_kz.is_set(kennung_user, 'p') = 1
)
So in this case I want to display every ID where the corresponding value is 1. However, in the case below where the ID is 4, I don't want it to display the 4's where the value is 1, I just want it to not show 4 at all. If I do a WHERE value LIKE '1', it'll show me the two IDs of 4 where the value is 1. Is there a way to not show 4 at all? Thanks in advance.
ID:.......1...2...3...4...4...4...5
Value:....1...1...1...1...2...1...1
(This is on Microsoft SQL Server management studio by the way)
If you just want the ids, then use aggregation:
select id
from t
group by id
having min(value) = 1 and max(value) = 1;
To add on Gordon's answer
I would add a count since it seems your data has multiple 1s in that case if you have two 1s you'd have it as both min and max
select id
from t
group by id
having min(value) = 1 and max(value) = 1 and count(value) = 1;
You could also use
select id from t group by id having sum(value) = 1 and count(value) = 1;
with cte as (
select * from (values
(1, 1),
(2, 1),
(3, 1),
(4, 1),
(4, 2),
(4, 1),
(5, 1)
) as x(ID, Value)
)
select *
from cte
where ID not in (
select ID
from cte
where Value > 1
);
i have a table "mydata" with some data data :
id name position
===========================
4 foo -3
6 bar -2
1 baz -1
3 knork -1
5 lift 0
2 pitcher 0
i fetch the table ordered using order by position ASC;
the position column value may be non unique (for some reason not described here :-) and is used to provide a custom order during SELECT.
what i want to do :
i want to normalize the table column "position" by associating a unique position to each row which doesnt destroy the order. furthermore the highest position after normalising should be -1.
wished resulting table contents :
id name position
===========================
4 foo -6
6 bar -5
1 baz -4
3 knork -3
5 lift -2
2 pitcher -1
i tried several ways but failed to implement the correct update statement.
i guess that using
generate_series( -(select count(*) from mydata), -1)
is a good starting point to get the new values for the position column but i have no clue how to merge that generated column data into the update statement.
hope somebody can help me out :-)
Something like:
with renumber as (
select id,
-1 * row_number() over (order by position desc, id) as rn
from foo
)
update foo
set position = r.rn
from renumber r
where foo.id = r.id
and position <> r.rn;
SQLFiddle Demo
Try this one -
Query:
CREATE TABLE temp
(
id INT
, name VARCHAR(10)
, position INT
)
INSERT INTO temp (id, name, position)
VALUES
(4, 'foo', -3),
(6, 'bar', -2),
(1, 'baz', -1),
(3, 'knork', -1),
(5, 'lift', 0),
(2, 'pitcher', 0)
SELECT
id
, name
, position = -ROW_NUMBER() OVER (ORDER BY position DESC, id)
FROM temp
ORDER BY position
Update:
UPDATE temp
SET position = t.rn
FROM (
SELECT id, rn = - ROW_NUMBER() OVER (ORDER BY position DESC, id)
FROM temp
) t
WHERE temp.id = t.id
Output:
id name position
----------- ---------- --------------------
4 foo -6
6 bar -5
3 knork -4
1 baz -3
5 lift -2
2 pitcher -1
#a_horse_with_no_name is really near the truth - thank you !
UPDATE temp
SET position=t.rn
FROM (SELECT
id, name,
-((select count( *)
FROM temp)
+1-row_number() OVER (ORDER BY position ASC)) as rn
FROM temp) t
WHERE temp.id=t.id;
SELECT * FROM temp ORDER BY position ASC;
see http://sqlfiddle.com/#!1/d1770/6
update mydata temp1, (select a.*,#var:=#var-1 sno from mydata a, (select #var:=0) b
order by position desc, id asc) temp2
set temp1.position = temp2.sno
where temp1.id = temp2.id;