I need to find the latest price for some items
This is my query:
SELECT
MAX("POPORH1"."DATE") as "PO DATE",
"ICSHEH"."DOCNUM",
"ICSHEH"."TRANSDATE",
"ICSHEH"."FISCYEAR",
"ICSHEH"."FISCPERIOD",
"ICSHEH"."REFERENCE",
"ICSHED"."ITEMNO",
"ICSHED"."ITEMDESC",
"ICSHED"."LOCATION",
"ICSHED"."QUANTITY",
"ICSHED"."UNIT",
"POPORL"."UNITCOST"
FROM (("CABDAT"."dbo"."ICSHEH" "ICSHEH"
INNER JOIN
"CABDAT"."dbo"."ICSHED" "ICSHED" ON "ICSHEH"."SEQUENCENO"="ICSHED"."SEQUENCENO")
INNER JOIN "CABDAT"."dbo"."POPORL" "POPORL" ON "ICSHED"."ITEMNO"="POPORL"."ITEMNO")
INNER JOIN "CABDAT"."dbo"."POPORH1" "POPORH1" ON "POPORL"."PORHSEQ"="POPORH1"."PORHSEQ"
WHERE "ICSHED"."SEQUENCENO"=55873
group by
"ICSHEH"."DOCNUM",
"ICSHEH"."TRANSDATE",
"ICSHEH"."FISCYEAR",
"ICSHEH"."FISCPERIOD",
"ICSHEH"."REFERENCE",
"ICSHED"."ITEMNO",
"ICSHED"."ITEMDESC",
"ICSHED"."LOCATION",
"ICSHED"."QUANTITY",
"ICSHED"."UNIT",
"POPORL"."UNITCOST"
This query returns multiple results
These are the results:
"PODATE"='20180405' "ITEMNO"='2944' "UNITCOST"='0.266750'
"PODATE"='20180405' "ITEMNO"='2946' "UNITCOST"='0.266750'
"PODATE"='20170208' "ITEMNO"='2944' "UNITCOST"='0.250780'
"PODATE"='20170208' "ITEMNO"='2944' "UNITCOST"='0.250780'
"PODATE"='20170208' "ITEMNO"='2946' "UNITCOST"='0.250780'
"PODATE"='20170208' "ITEMNO"='2946' "UNITCOST"='0.250780'
I need to have only
"PODATE"='20180405' "ITEMNO"='2944' "UNITCOST"='0.266750'
"PODATE"='20180405' "ITEMNO"='2946' "UNITCOST"='0.266750'
I am learning SQL, so please be patient with my ignorance...
Thanks a lot!
You just need row_number().
WITH cte as (
SELECT *, ROW_NUMBER() OVER (PARTITION BY "ITEMNO" ORDER BY "PODATE" DESC) as rn
FROM "ICSHED" -- or join tables
WHERE "ICSHED"."SEQUENCENO"=55873
)
SELECT *
FROM cte where rn = 1
Or if you only need the highest value without any grouping can use TOP 1
SELECT TOP 1 *
FROM "ICSHED" -- or join tables
WHERE "ICSHED"."SEQUENCENO"=55873
ORDER "PODATE" DESC
By my understanding, you want top 2 rows with recent date. so I try this,
select top 2 * from yourtable order by dateCol desc
Related
I have written the query shown here that combines three tables and returns rows where the at_ticket_num from appeal_tickets is duplicated but against a different at_sys_ref value
select top 100
t.t_reference, at.at_system_ref, at_ticket_num, a.a_case_ref
from
tickets t, appeal_tickets at, appeals_2 a
where
t.t_reference in ('AB123','AB234') -- filtering on these values so that I can see that its working
and t.t_number = at.at_ticket_num
and at.at_system_ref = a.a_system_ref
and at.at_ticket_num IN (select at_ticket_num
from appeal_tickets
group by at_ticket_num
having count(distinct at_system_ref) > 1)
order by
t.t_reference desc
This is the output:
t_reference at_system_ref at_ticket_num a_case_ref
-------------------------------------------------------
AB123 30838974 23641583 1111979010
AB123 30838976 23641583 1111979010
AB234 30839149 23641520 1111977352
AB234 30839209 23641520 1111988003
I want to modify this so that it only returns records where t_reference is duplicated but against a different a_case_ref. So in above case only records for AB234 would be returned.
Any help would be much appreciated.
You want all ticket appeals that have more than one system reference and more than one case reference it seems. You can join the tables, count the occurrences per ticket and then only keep the tickets that match these criteria.
select *
from
(
select
t.t_reference, at.at_system_ref, at.at_ticket_num, a.a_case_ref,
count(distinct a.a_system_ref) over (partition by at.at_ticket_num) as sysrefs,
count(distinct a.a_case_ref) over (partition by at.at_ticket_num) as caserefs
from tickets t
join appeal_tickets at on at.at_ticket_num = t.t_number
join appeals_2 a on a.a_system_ref = at.at_system_ref
) counted
where sysrefs > 1 and caserefs > 1
order by t.t_reference, at.at_system_ref, at.at_ticket_num, a.a_case_ref;
Correction
It seems that SQL Server still doesn't support COUNT(DISTINCT ...) OVER (...). You can count distinct values in a subquery though. Replace
count(distinct a.a_system_ref) over (partition by at.at_ticket_num) as sysrefs,
by
(
select count(distinct a2.a_system_ref)
from appeal_tickets at2
join appeals_2 a2 on a2.a_system_ref = at2.at_system_ref
where at2.at_ticket_num = t.t_number
) as sysrefs,
An alternative workaround is to use DENSE_RANK in two directions (found here: https://stackoverflow.com/a/53518204/2270762):
dense_rank() over (partition by at.at_ticket_num order by a.a_system_ref) +
dense_rank() over (partition by at.at_ticket_num order by a.a_system_ref desc) -
1 as sysrefs,
with data as (
<your query plus one column>,
case when
min() over (partition by t.t_reference)
<>
max() over (partition by t.t_reference)
then 1 end as dup
)
select * from data where dup = 1
Im trying to create ie query to show itens with MAX DATE, but I don´t know how !
Follow the script and result:
Select
results.severity As "Count_severity",
tasks.name As task,
results.host,
to_timestamp(results.date)::date
From
tasks Inner Join
results On results.task = tasks.id
Where
tasks.name Like '%CORP 0%' And
results.severity >= 7 And
results.qod > 70
I need to show only tasks with the last date of each one.
Can you help me ?
You seem to be using Postgres (as suggested by the use of casting operator ::). If so - and I follow you correctly - you can use distinct on:
select distinct on(t.name)
r.severity, t.name as task, r.host, to_timestamp(r.date::bigint)::date
from tasks t
inner join results r on r.task = t.id
where t.name like '%corp 0%' and r.severity >= 7 and r.qod > 70
order by t.name, to_timestamp(r.date::bigint)::date desc
This guarantees one row per task only; which row is picked is controlled by the order by clause, so the above gets the row with the greatest date (time portion left apart). If there are ties, it is undefined which row is returned. You might want to adapt the order by clause to your exact requirement, if it is different than what I understood.
On the other hand, if you want top ties, then use window functions:
select *
from (
select r.severity, t.name as task, r.host, to_timestamp(r.date::bigint)::date,
rank() over(partition by t.name order by to_timestamp(r.date::bigint)::date desc) rn
from tasks t
inner join results r on r.task = t.id
where t.name like '%corp 0%' and r.severity >= 7 and r.qod > 70
) t
where rn = 1
I have 2 table and I m fetching record as below
The query is as
Select BMC.JCRS_Mem_crs_Code,
BMC.JCRS_Mem_Description,
BMC.JCRS_Mem_Date,
BJCM.JCRS_Mast_Title
From Bus_MemberCourse BMC
Inner Join Bus_JourneymanCourseMaster BJCM
On BMC.JCRS_Mem_crs_Code = BJCM.JCRS_Mast_Code
Where BMC.JCRS_Mem_Completed = 1
And BMC.JCRS_Mem_mem_ID = 5010
Group By BMC.JCRS_Mem_crs_Code,
BMC.JCRS_Mem_Description,
BMC.JCRS_Mem_Date,
BJCM.JCRS_Mast_Title
But what I want is I need to make group by on Jcrs_mem_crs_code and Jcrs_mem_description and if this 2 column data are common then I want to took the latest date only from this multiple dates. i.e. I want to pick only that row and ignore the other rows.
You just want MAX(date):
Select BMC.JCRS_Mem_crs_Code,
BMC.JCRS_Mem_Description,
MAX(BMC.JCRS_Mem_Date) as JCRS_Mem_Date,
BJCM.JCRS_Mast_Title
From Bus_MemberCourse BMC
Inner Join Bus_JourneymanCourseMaster BJCM
On BMC.JCRS_Mem_crs_Code = BJCM.JCRS_Mast_Code
Where BMC.JCRS_Mem_Completed = 1
And BMC.JCRS_Mem_mem_ID = 5010
Group By BMC.JCRS_Mem_crs_Code,
BMC.JCRS_Mem_Description,
BJCM.JCRS_Mast_Title
You don't need a Group by at all (you aren't doing any aggregation in your query).
This can easily be done with a Row_Number() windowed function with a Partition on those two columns whilst ordering by the date:
;With Cte As
(
Select BMC.JCRS_Mem_crs_Code,
BMC.JCRS_Mem_Description,
BMC.JCRS_Mem_Date,
BJCM.JCRS_Mast_Title,
Row_Number() Over (Partition By BMC.JCRS_Mem_crs_Code,
BMC.JCRS_Mem_Description
Order By BMC.JCRS_Mem_Date Desc) As RN
From Bus_MemberCourse BMC
Inner Join Bus_JourneymanCourseMaster BJCM
On BMC.JCRS_Mem_crs_Code = BJCM.JCRS_Mast_Code
Where BMC.JCRS_Mem_Completed = 1
And BMC.JCRS_Mem_mem_ID = 5010
)
Select JCRS_Mem_crs_Code,
JCRS_Mem_Description,
JCRS_Mem_Date,
JCRS_Mast_Title
From Cte
Where RN = 1
select client#,
SUM(ticketpurchase.totalamount) value
from ops$yyang00.ticketpurchase,
ops$yyang00.performance,
ops$yyang00.production
where ticketpurchase.per# = performance.per# and
performance.P#=production.P# and
season#=1
group by client#
order by value desc;
How to select top 5 client in this for each season by ticket sale value one value can include multiple client..
Please try this code for sql server.
Select * from (
select client#,SUM(ticketpurchase.totalamount) value,
row_number() over(order by SUM(ticketpurchase.totalamount)) rowNo
from ops$yyang00.ticketpurchase,
ops$yyang00.performance,
ops$yyang00.production
where ticketpurchase.per# = performance.per# and
performance.P#=production.P# and
season#=1
group by client#
) as t
where rowNo <=5
Try this: (If you are using SQL Server)
select top 5 from (
select client#,
SUM(ticketpurchase.totalamount) value
from ops$yyang00.ticketpurchase,
ops$yyang00.performance,
ops$yyang00.production
where ticketpurchase.per# = performance.per# and
performance.P#=production.P# and
season#=1
group by client# )
order by value desc
Note: If you want the least 5 records, remove the desc from order by
I have a table named PublishedData, see image below
I'm trying to get the output like, below image
I think you can use a query like this:
SELECT dt.DistrictName, ISNULL(dt.Content, 'N/A') Content, dt.UpdatedDate, mt.LastPublished, mt.Unpublished
FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY DistrictName ORDER BY UpdatedDate DESC, ISNULL(Content, 'zzzzz')) seq
FROM PublishedData) dt
INNER JOIN (
SELECT DistrictName, MAX(LastPublished) LastPublished, COUNT(CASE WHEN IsPublished = 0 THEN 1 END) Unpublished
FROM PublishedData
GROUP BY DistrictName) mt
ON dt.DistrictName = mt.DistrictName
WHERE
dt.seq = 1;
Because I think you use an order over UpdatedDate, Content to gain you two first columns.
Check out something like this (I don't have your tables, but you will get the idea where to follow with your query):
SELECT DirectName,
MAX(UpdatedDate),
MAX(LastPublished),
(
SELECT COUNT(*)
FROM PublishedData inr
WHERE inr.DirectName = outr.DirectName
AND inr.IsPublished = 0
) AS Unpublished
FROM PublishedData outr
GROUP BY DirectName
We should required a unique identity for that required output in PublishedData Table,Because We can't get the Latest content from given Schema.
If you want data apart from content like DistictName,updatedDate,LastPublishedDate and count of Unpublished records ,Please use Query given below :
select T1.DistrictName,T1.UpdatedDate,T1.LastPublished,T2.Unpublished from
(select DistrictName,Max(UpdateDate) as UpdatedDate,Max(LastPublished) as LastPublished from PublishedData group by DistrictName) T1
inner join
(select DistrictName,count(IsPublished) as Unpublished from PublishedData where isPublished=0 group by DistrictName) T2 ON T1.DistrictName=T2.DistrictName ORDER BY T2.Unpublished DESC