I'm setting up a new SQL query to summarize records from a table of employee attendance. These records are downloaded from a fingerprint or RFID sensor and recorded on the same table. I want to get the amount of hours on the workplace.
Everything works fine if the employee comes in and leaves the workplace once at day. The device generates 2 records on the table and that's are not a problem. It's easy identify entrance and exit time.
But I don't realize how to solve if the person comes in, take a break (leaves workplace) and after that he comes in again until the exit time.
Assume that they are always even records (arrival and exit timestamps) on each interval. Also, an employee never checks in one day and leaves on the next day.
I have the following query. Remember: this only gets the minimum timestamp (arrival time) and the max timestamp (leave time).
SELECT Userid, Name, Date, Entrance, Exit, Hours FROM
(SELECT Userid AS user,
CONVERT(VARCHAR, CONVERT(TIME, min(Checktime))) AS Entrance,
CONVERT(VARCHAR, CONVERT(TIME, max(Checktime))) AS Exit,
CONVERT(VARCHAR, CONVERT(TIME, max(Checktime)-min(CheckTime))) AS Hours,
CONVERT(VARCHAR, CONVERT(DATE, CheckTime)) AS Fecha,
COUNT(*) AS Regs,
SUM(edited) AS edited FROM attendance
WHERE CONVERT(DATE, CheckTime) < CONVERT(DATE, GETDATE())
GROUP BY Userid, CONVERT(DATE, CheckTime)) AS Hs
INNER JOIN Userinfo
ON Userinfo.Userid = Hs.user
ORDER BY Date DESC, Name ASC;
For example, if the table has the following records:
id | Logid | Userid | CheckTime | edited
1 | 10 | 1 | 2019-06-18 8:00:00 | 0
2 | 11 | 1 | 2019-06-18 12:00:00 | 0
3 | 12 | 1 | 2019-06-18 15:00:00 | 0
4 | 13 | 1 | 2019-06-18 17:00:00 | 0
5 | 14 | 2 | 2019-06-18 8:00:00 | 0
6 | 15 | 2 | 2019-06-18 17:00:00 | 0
What I get:
Userid | Name | Date | Entrance | Exit | Hours | edited
1 | Gandalf | 2019-06-18 | 8:00:00 | 17:00:00 | 9:00:00 | 0
2 | Frodo | 2019-06-18 | 8:00:00 | 17:00:00 | 9:00:00 | 0
What I need:
Userid | Name | Date | Entrance | Exit | Hours | edited
1 | Gandalf | 2019-06-18 | 8:00:00 | 17:00:00 | 6:00:00 | 0
2 | Frodo | 2019-06-18 | 8:00:00 | 17:00:00 | 9:00:00 | 0
The total time was calculated from (12:00:00 - 8:00:00) + (17:00:00 - 15:00:00).
The columns "Entrance" and "Exit" on this case are not necessary at all.
Have you an idea how I can solve this? Thank you very much!
This assume you have pair enter/exit and handle multiple breaks.
SQL DEMO
with cte as (
SELECT *, ROW_NUMBER() OVER (PARTITION BY [Userid], cast ([CheckTime] as Date)
ORDER BY [CheckTime]) as rn
FROM Table1 t1
)
SELECT c1.[Userid],
cast (c1.[CheckTime] as Date) as the_day,
SUM (DATEDIFF (hh, c1.[CheckTime], c2.[CheckTime])) as total_hours
FROM cte c1
JOIN cte c2
ON c1.rn = c2.rn -1
AND c1.[Userid] = c2.[Userid]
AND c1.rn % 2 = 1
GROUP BY c1.[Userid],
cast (c1.[CheckTime] as Date) ;
OUTPUT
| Userid | the_day | total_hours |
|--------|------------|-------------|
| 1 | 2019-06-18 | 6 |
| 2 | 2019-06-18 | 9 |
NOTE:
General syntax for DATEDIFF:
DATEDIFF(datepart, start_date, end_date)
Just realize the function DATEDIFF is used to calculate the time interval between two date values and return it as an integer.
So if you have 08:00 and 09:30 using hh as datepart you still get 1h. Maybe is better use mi and divide by 60
Perfect! Juan Carlos's solution works great!
I'm posting this because I've edited some of his code to match the original post requirements.
The code is exactly the same. Only I've changed/added a few lines
with cte as (
SELECT *, ROW_NUMBER() OVER (PARTITION BY [Userid], cast ([CheckTime] as Date)
ORDER BY [CheckTime]) as rn
FROM Table1 t1
WHERE CAST(CheckTime AS DATE) = '2019-06-17' -- Filter by specific date
)
SELECT c1.[Userid],
cast (c1.[CheckTime] as Date) as the_day,
-- Return time as HH:MM
CONVERT(VARCHAR, SUM (DATEDIFF (SECOND , c1.[CheckTime], c2.[CheckTime]))/3600) + ':' + right('00' + CONVERT(VARCHAR, CONVERT(FLOAT, (SUM (DATEDIFF (SECOND , c1.[CheckTime], c2.[CheckTime]))/60) - ((SUM (DATEDIFF (SECOND , c1.[CheckTime], c2.[CheckTime]))/3600)*60))),2) as total_time
FROM cte c1
JOIN cte c2
ON c1.rn = c2.rn -1
AND c1.[Userid] = c2.[Userid]
AND c1.rn % 2 = 1
GROUP BY c1.[Userid],
cast (c1.[CheckTime] as Date);
This query returns:
| Userid | the_day | total_time |
|--------|------------|-------------|
| 1 | 2019-06-18 | 6:00 |
| 2 | 2019-06-18 | 9:00 |
I have pretty simple table which has 2 column. First one show time (timestamp), the second one show speed of car at that time (float8).
| DATE_TIME | SPEED |
|---------------------|-------|
| 2018-11-09 00:00:00 | 256 |
| 2018-11-09 01:00:00 | 659 |
| 2018-11-09 02:00:00 | 256 |
| other dates | xxx |
| 2018-11-21 21:00:00 | 651 |
| 2018-11-21 22:00:00 | 515 |
| 2018-11-21 23:00:00 | 849 |
Lets say we have period from 9 november to 21 november. How to group that period by week. In fact I want such result:
| DATE_TIME | AVG_SPEED |
|---------------------|-----------|
| 9-11 November | XXX |
| 12-18 November | YYY |
| 19-21 November | ZZZ |
I use PostgreSQL 10.4.
I use such SQL Statement to know the number of the week of the certain date:
SELECT EXTRACT(WEEK FROM TIMESTAMP '2018-11-09 00:00:00');
EDIT:
#tim-biegeleisen when I set period from '2018-11-01' to '2018-11-13' your sql statement return 2 result:
In fact I need such result:
2018-11-01 00:00:00 | 2018-11-04 23:00:00
2018-11-05 00:00:00 | 2018-11-11 23:00:00
2018-11-12 00:00:00 | 2018-11-13 05:00:00
As you can see in the calendar there are 3 week in that period.
We can do this using a calendar table. This answer assumes that a week begins with the first date in your data set. You could also do this assuming something else, e.g. a standard week according to something else.
WITH dates AS (
SELECT date_trunc('day', dd)::date AS dt
FROM generate_series
( '2018-11-09'::timestamp
, '2018-11-21'::timestamp
, '1 day'::interval) dd
),
cte AS (
SELECT t1.dt, t2.DATE_TIME, t2.SPEED,
EXTRACT(week from t1.dt) week
FROM dates t1
LEFT JOIN yourTable t2
ON t1.dt = t2.DATE_TIME::date
)
SELECT
MIN(dt)::text || '-' || MAX(dt) AS DATE_TIME,
AVG(SPEED) AS AVG_SPEED
FROM cte
GROUP BY
week
ORDER BY
MIN(dt);
Demo
I have a structure like this
+-----+-----+------------+----------+------+----------------------+---+
| Row | id | date | time | hour | description | |
+-----+-----+------------+----------+------+----------------------+---+
| 1 | foo | 2018-03-02 | 19:00:00 | 8 | across single day | |
| 2 | bar | 2018-03-02 | 23:00:00 | 1 | end at midnight | |
| 3 | qux | 2018-03-02 | 10:00:00 | 3 | inside single day | |
| 4 | quz | 2018-03-02 | 23:15:00 | 2 | with minutes | |
+-----+-----+------------+----------+------+----------------------+---+
(I added the description column only to understand the context, for analysis purpose is useless)
Here is the statement to generate table
WITH table AS (
SELECT "foo" as id, CURRENT_dATE() AS date, TIME(19,0,0) AS time,8 AS hour
UNION ALL
SELECT "bar", CURRENT_dATE(), TIME(23,0,0), 1
UNION ALL
SELECT "qux", CURRENT_dATE(), TIME(10,0,0), 3
UNION ALL
SELECT "quz", CURRENT_dATE(), TIME(23,15,0), 2
)
SELECT * FROM table
Adding the hour value to the given time, I need to split the row on multiple ones, if the sum goes on the next day.
Jumps on multiple days are NOT to be considered, like +27 hours (this should simplify the scenario)
My initial idea was starting from adding the hours value in a date field, in order to obtain start and end limits of the interval
SELECT
id,
DATETIME(date, time) AS date_start,
DATETIME_ADD(DATETIME(date, time), INTERVAL hour HOUR) AS date_end
FROM table
here is the result
+-----+-----+---------------------+---------------------+---+
| Row | id | date_start | date_end | |
+-----+-----+---------------------+---------------------+---+
| 1 | foo | 2018-03-02T19:00:00 | 2018-03-03T03:00:00 | |
| 2 | bar | 2018-03-02T23:00:00 | 2018-03-03T00:00:00 | |
| 3 | qux | 2018-03-02T10:00:00 | 2018-03-02T13:00:00 | |
| 4 | quz | 2018-03-02T23:15:00 | 2018-03-03T01:15:00 | |
+-----+-----+---------------------+---------------------+---+
but now I'm stuck on how to proceed considering the existing interval.
Starting from this table, the rows should be splitted if the day change, like
+-----+-----+------------+-------------+----------+-------+--+
| Row | id | date | hourt_start | hour_end | hours | |
+-----+-----+------------+-------------+----------+-------+--+
| 1 | foo | 2018-03-02 | 19:00:00 | 00:00:00 | 5 | |
| 2 | foo | 2018-03-03 | 00:00:00 | 03:00:00 | 3 | |
| 3 | bar | 2018-03-02 | 23:00:00 | 00:00:00 | 1 | |
| 4 | qux | 2018-03-02 | 10:00:00 | 13:00:00 | 3 | |
| 5 | quz | 2018-03-02 | 23:15:00 | 00:00:00 | 0.75 | |
| 6 | quz | 2018-03-03 | 00:00:00 | 01:15:00 | 1.25 | |
+-----+-----+------------+-------------+----------+-------+--+
I tried to study a similar scenario from an already analyzed scenario, but I was unable to adapt it for handling the day component as well.
My whole final scenario will include both this approach and the other one analyzed in the other question (split on single days and then split on given breaks of hours), but I can approach these 2 themes separately, first query split with day (this question) and then split on time breaks (other question)
Interesting problem ... I tried the following:
Create a second table creating all the new rows starting at midnight
UNION ALL it with source table while correcting hours of old rows accordingly
Commented Result:
WITH table AS (
SELECT "foo" as id, CURRENT_dATE() AS date, TIME(19,0,0) AS time,8 AS hour
UNION ALL
SELECT "bar", CURRENT_dATE(), TIME(23,0,0), 1
UNION ALL
SELECT "qux", CURRENT_dATE(), TIME(10,0,0), 3
)
,table2 AS (
SELECT
id,
-- create datetime, add hours, then cast as date again
CAST( datetime_add( datetime(date, time), INTERVAL hour HOUR) AS date) date,
time(0,0,0) AS time -- losing minutes and seconds
-- substract hours to midnight
,hour - (24-EXTRACT(HOUR FROM time)) hour
FROM
table
WHERE
date != CAST( datetime_add( datetime(date,time), INTERVAL hour HOUR) AS date) )
SELECT
id
,date
,time
-- correct hour if midnight split
,IF(EXTRACT(hour from time)+hour > 24,24-EXTRACT(hour from time),hour) hour
FROM
table
UNION ALL
SELECT
*
FROM
table2
Hope, it makes sense.
Of course, if you need to consider jumps over multiple days, the correction fails :)
Here a possibile solution I came up starting from #Martin Weitzmann approach.
I used 2 different ways:
ids where there is a "jump" on the day
ids which are in the same day
and a final UNION ALL of the two data
I forgot to mention the first time that the hours value of the input value can be float (portion of hours) so I added that too.
#standardSQL
WITH
input AS (
-- change of day
SELECT "bap" as id, CURRENT_dATE() AS date, TIME(19,0,0) AS time, 8.0 AS hour UNION ALL
-- end at midnight
SELECT "bar", CURRENT_dATE(), TIME(23,0,0), 1.0 UNION ALL
-- inside single day
SELECT "foo", CURRENT_dATE(), TIME(10,0,0), 3.0 UNION ALL
-- change of day with minutes and float hours
SELECT "qux", CURRENT_dATE(), TIME(23,15,0), 2.5 UNION ALL
-- start from midnight
SELECT "quz",CURRENT_dATE(), TIME(0,0,0), 4.5
),
-- Calculate end_date and end_time summing hours value
table AS (
SELECT
id,
date AS start_date,
time AS start_time,
EXTRACT(DATE FROM DATETIME_ADD(DATETIME(date,time), INTERVAL CAST(hour*3600 AS INT64) SECOND)) AS end_date,
EXTRACT(TIME FROM DATETIME_ADD(DATETIME(date,time), INTERVAL CAST(hour*3600 AS INT64) SECOND)) AS end_time
FROM input
),
-- portion that start from start_time and end at midnight
start_to_midnight AS (
SELECT
id,
start_time,
start_date,
TIME(23,59,59) as end_time,
start_date as end_date
FROM
table
WHERE end_date > start_date
),
-- portion that start from midnightand end at end_time
midnight_to_end AS (
SELECT
id,
TIME(0,0,0) as start_time,
end_date as start_date,
end_time,
end_date
FROM
table
WHERE
end_date > start_date
-- Avoid rows that starts from 0:0:0 and ends to 0:0:0 (original row ends at 0:0:0)
AND end_time != TIME(0,0,0)
)
-- Union of the 3 tables
SELECT
id,
start_date,
start_time,
end_time
FROM (
SELECT id, start_time, end_time, start_date FROM table WHERE start_date = end_date
UNION ALL
SELECT id, start_time, end_time, start_date FROM start_to_midnight
UNION ALL
SELECT id, start_time, end_time, start_date FROM midnight_to_end
)
ORDER BY id,start_date,start_time
Here is the provided output
+-----+-----+------------+------------+----------+---+
| Row | id | start_date | start_time | end_time | |
+-----+-----+------------+------------+----------+---+
| 1 | bap | 2018-03-03 | 19:00:00 | 23:59:59 | |
| 2 | bap | 2018-03-04 | 00:00:00 | 03:00:00 | |
| 3 | bar | 2018-03-03 | 23:00:00 | 23:59:59 | |
| 4 | foo | 2018-03-03 | 10:00:00 | 13:00:00 | |
| 5 | qux | 2018-03-03 | 23:15:00 | 23:59:59 | |
| 6 | qux | 2018-03-04 | 00:00:00 | 01:45:00 | |
| 7 | quz | 2018-03-03 | 00:00:00 | 04:30:00 | |
+-----+-----+------------+------------+----------+---+
Have a table scheme that look as :
events{id int, date date, begin time, end time, title varchar)
and want to retrieve rows from a web user form, by example : 11:00 (i'm french so use 24h format)
So, if i have in the table the following rows :
1 | 2016-03-29 | 11:15 | 12:00
2 | 2016-03-29 | 09:45 | 11:15
3 | 2016-03-29 | 10:45 | 13:00
4 | 2016-03-29 | 12:45 | 14:45
I would like to be able to count, or retrieve rows have events that have 11:00 in the range :
2 | 2016-03-29 | 09:45 | 11:15
3 | 2016-03-29 | 10:45 | 13:00
Note : i use PostgreSQL but want to respect SQL normalization to achieve...
Thanks
Use Between operator
Try this
select *
from yourtable
where '11:00' between "begin" and "end"
Any hints to get the minimum difference between start time and end time per guid with the following data in Microsoft SQL 2014:
id| start time | guid | end time
1 | 2015-04-05 12:00 | a | 2015-04-05 12:30
2 | 2015-04-05 12:10 | a | 2015-04-05 12:15
3 | 2015-04-05 12:20 | a | 2015-04-05 12:30
4 | 2015-04-05 12:30 | b | 2015-04-05 12:35
5 | 2015-04-05 12:40 | b | 2015-04-05 12:55
6 | 2015-04-05 12:50 | c | 2015-04-05 12:55
7 | 2015-04-05 13:00 | c | 2015-04-05 13:25
the output I am looking for is:
id | start time | guid | end time
2 | 2015-04-05 12:10 | a | 2015-04-05 12:15
4 | 2015-04-05 12:30 | b | 2015-04-05 12:35
6 | 2015-04-05 12:50 | c | 2015-04-05 12:55
I have tried grouping by guid and using the DateDiff function, but it didn't work.
try with below query
;with CTE as(
select id, sttime,guid,endtime
row_number() over (partition by guid order by datediff(ss,endtime,sttime))
from tablename
) select * from CTE where rowid =1
This answer looks a bit like Indra's answer, however there is a significant difference. Not using datediff, which will fail if any dates are more than approximate 168 years(or 2147483647 seconds) apart. Also fixed some issues.
;WITH CTE as
(
SELECT
id, start_time, guid, end_time,
row_number() over (partition by guid order by end_time - start_time) rn
FROM
table
)
SELECT
id, start_time, guid, end_time
FROM CTE
WHERE rn = 1
WITH CTE
(
SELECT *,ROW_NUMBER() OVER(PARTITION BY GUID ORDER BY DATEDIFF(SS,STARTTIME,ENDTIME) ASC) AS RN
FROM YOURTABLE
)
SELECT * FROM CTE WHERE RN=1
Use NOT EXIST to return a row if no other row with same guid has less datediff:
select id, start_time, guid, end_time
from tablename t1
where not exists
(select 1 from tablename t2
where t2.guid = t1.guid
and datediff(t2.end_time - t2.start_time) < datediff(t1.end_time - t1.start_time))
Note, I don't know SQL Server, so you'll have to adjust the datediff code above.