I want to know how to round up and down between in a range example:
57272.726 ---> 57272.730
57272.724--> 57272.720
select round(57272.726);
Output : 57273
Syntax:
Select round(X,D);
X: The argument or the number you want to round
D: The no.of Decimal places you want to round(If you have not specified it, it is taken as zero)
Hope this Helps
Use this code:
Round Up:-
declare #value decimal(10,2)
set #value=57272.726
SELECT CAST(ROUND(#value, 2) AS NUMERIC(12,3)) As RoundUpValues
Round Down:-
declare #value decimal(10,2)
set #value=57272.724
SELECT CAST(ROUND(#value, 2) AS NUMERIC(12,3)) As RoundDownValues
Try this :
SELECT ROUND(57272.726 , 2);
Return : 57272.730.
SELECT ROUND(57272.724 , 2);
return : 57272.720.
The following query may help you getting the desirable result.
Select ROUND( number, decimal_places [, operation ] )
SELECT round(57272.724, 2);
It gives 57272.72 as answer.
It gets round down because last decimal digit is 4 which is in the range 0.1 to 0.4
SELECT round(57272.726, 2);
It gives 57272.73 as answer.
It gets round up because last decimal digit is 6 which is in the range 0.5 to 0.9
I have a table software and columns in it as dev_cost, sell_cost. If dev_cost is 16000 and sell_cost is 7500, how do I find the quantity of software to be sold in order to recover the dev_cost?
I have queried as below:
select dev_cost / sell_cost from software ;
It is returning 2 as the answer. But we need to get 3, right?
What would be the query for that?
Your columns have integer types, and integer division truncates the result towards zero. To get an accurate result, you'll need to cast at least one of the values to float or decimal:
select cast(dev_cost as decimal) / sell_cost from software ;
or just:
select dev_cost::decimal / sell_cost from software ;
You can then round the result up to the nearest integer using the ceil() function:
select ceil(dev_cost::decimal / sell_cost) from software ;
(See demo on SQLFiddle.)
You can cast integer type to numeric and use ceil() function to get the desired output
The PostgreSQL ceil function returns the smallest integer value that
is greater than or equal to a number.
SELECT 16000::NUMERIC / 7500 col
,ceil(16000::NUMERIC / 7500)
Result:
col ceil
------------------ ----
2.1333333333333333 3
So your query should be
select ceil(dev_cost::numeric/sell_cost)
from software
You can also cast your variable to the desired type, then apply division:
SELECT (dev_cost::numeric/sell_cost::numeric);
You can round your value , and specify the number of digits after point:
SELECT TRUNC((dev_cost::numeric/sell_cost::numeric),2);
This query will round result to next integer
select round(dev_cost ::decimal / sell_cost + 0.5)
CEILING in T-SQL does not return correct values in SQL Server 2012. Please see below details.
select CEILING(0.3333333333333333)
Result: 1
But I want to do a calculation of based on count of columns. Internal calculation is given below.
select CEILING((17 - 2) / 45)
Result: 0
(17 - 2) / 45 = 0.33333
But
select CEILING((17 - 2) / 45)
returns zero
I want to get one as result. What should I do?
It ended with a integer division. So
15/45 = 0
Try CASTing atleast one of the operand into decimal ,
SELECT CEILING((17-2)/CAST(45 AS DECIMAL (4,2))
OR like,
SELECT CEILING(15,45.0)
I have the following query that gives a rounded result. How can I modify this to
Stop rounding
Display to 2 decimal places. E.g 3.456 -> 3.45
SELECT SUM(Invoice_Details.Amount) AS TotalNet_C FROM Invoice_Details WHERE Invoice_Details.Invoice_Number = ||InvNo||
To format it to 2 digits you can e.g. convert it to currency.
SELECT CAST(SUM(Invoice_Details.Amount) AS money) AS TotalNet_C
FROM Invoice_Details
WHERE Invoice_Details.Invoice_Number = ||InvNo||
For be more specific you can use CONVERT.
Check this for details: http://msdn.microsoft.com/de-de/library/ms187928.aspx
About rounding: You want to crop the digits, not round them:
SELECT CAST(CAST(3.456 * 100 AS int) as float)/100
This will do it. Your case then
SELECT CAST(CAST(CAST(SUM(Invoice_Details.Amount) * 100 AS int) as float)/100 AS money) AS TotalNet_C
FROM Invoice_Details
WHERE Invoice_Details.Invoice_Number = ||InvNo||
you can simply do this for rounding your value
Str(ColumnName, 10, 2)
10-- this is for total length of your value.
2-- this is for how many decimal you want
declare #Num decimal(6,3)
set #Num = 3.456
select LEFT(round(#Num, 2, 1),4)
OR
select CAST(round(#Num, 2, 1)AS MONEY)
I think u should to convert value before sum_function and u can use parameters of the numeric/decimal, just like this:
select SUM(TRY_CONVERT(decimal(18,2), value) from TestTable ...
I'm trying to determine the best way to truncate or drop extra decimal places in SQL without rounding. For example:
declare #value decimal(18,2)
set #value = 123.456
This will automatically round #value to be 123.46, which is good in most cases. However, for this project, I don't need that. Is there a simple way to truncate the decimals I don't need? I know I can use the left() function and convert back to a decimal. Are there any other ways?
ROUND ( 123.456 , 2 , 1 )
When the third parameter != 0 it truncates rather than rounds.
Syntax
ROUND ( numeric_expression , length [ ,function ] )
Arguments
numeric_expression
Is an expression of the exact numeric or approximate numeric data
type category, except for the bit data type.
length
Is the precision to which numeric_expression is to be rounded. length must be an expression of type tinyint, smallint, or int. When length is a positive number, numeric_expression is rounded to the number of decimal positions specified by length. When length is a negative number, numeric_expression is rounded on the left side of the decimal point, as specified by length.
function
Is the type of operation to perform. function must be tinyint, smallint, or int. When function is omitted or has a value of 0 (default), numeric_expression is rounded. When a value other than 0 is specified, numeric_expression is truncated.
select round(123.456, 2, 1)
SELECT Cast(Round(123.456,2,1) as decimal(18,2))
Here's the way I was able to truncate and not round:
select 100.0019-(100.0019%.001)
returns 100.0010
And your example:
select 123.456-(123.456%.001)
returns 123.450
Now if you want to get rid of the ending zero, simply cast it:
select cast((123.456-(123.456%.001)) as decimal (18,2))
returns 123.45
Actually whatever the third parameter is, 0 or 1 or 2, it will not round your value.
CAST(ROUND(10.0055,2,0) AS NUMERIC(10,2))
Do you want the decimal or not?
If not, use
select ceiling(#value),floor(#value)
If you do it with 0 then do a round:
select round(#value,2)
Another truncate with no rounding solution and example.
Convert 71.950005666 to a single decimal place number (71.9)
1) 71.950005666 * 10.0 = 719.50005666
2) Floor(719.50005666) = 719.0
3) 719.0 / 10.0 = 71.9
select Floor(71.950005666 * 10.0) / 10.0
Round has an optional parameter
Select round(123.456, 2, 1) will = 123.45
Select round(123.456, 2, 0) will = 123.46
ROUND(number, decimals, operation)
number => Required. The number to be rounded
decimals => Required. The number of decimal places to round number to
operation => Optional. If 0, it rounds the result to the number of decimal. If another value than 0, it truncates the result to the number of decimals. Default value is 0
SELECT ROUND(235.415, 2, 1)
will give you 235.410
SELECT ROUND(235.415, 0, 1)
will give you 235.000
But now trimming0 you can use cast
SELECT CAST(ROUND(235.415, 0, 1) AS INT)
will give you 235
This will remove the decimal part of any number
SELECT ROUND(#val,0,1)
SELECT CAST(Value as Decimal(10,2)) FROM TABLE_NAME;
Would give you 2 values after the decimal point. (MS SQL SERVER)
Another way is ODBC TRUNCATE function:
DECLARE #value DECIMAL(18,3) =123.456;
SELECT #value AS val, {fn TRUNCATE(#value, 2)} AS result
LiveDemo
Output:
╔═════════╦═════════╗
║ val ║ result ║
╠═════════╬═════════╣
║ 123,456 ║ 123,450 ║
╚═════════╩═════════╝
Remark:
I recommend using built-in ROUND function with 3rd parameter set to 1.
I know this is pretty late but I don't see it as an answer and have been using this trick for years.
Simply subtract .005 from your value and use Round(#num,2).
Your example:
declare #num decimal(9,5) = 123.456
select round(#num-.005,2)
returns 123.45
It will automatically adjust the rounding to the correct value you are looking for.
By the way, are you recreating the program from the movie Office Space?
Try like this:
SELECT cast(round(123.456,2,1) as decimal(18,2))
If you desire to take some number like 89.0904987 and turn it into 89.09 by simply omitting the undesired decimal places, simply use the following:
select cast(yourColumnName as decimal(18,2))
The following screenshot is from W3Schools SQL Data Types section, which describes what decimal(18,2) is doing:
Therefore,
select cast(89.0904987 as decimal(18,2))
gives you: 89.09
Please try to use this code for converting 3 decimal values after a point into 2 decimal places:
declare #val decimal (8, 2)
select #val = 123.456
select #val = #val
select #val
The output is 123.46
I think you want only the decimal value,
in this case you can use the following:
declare #val decimal (8, 3)
SET #val = 123.456
SELECT #val - ROUND(#val,0,1)
I know this question is really old but nobody used sub-strings to round. This as advantage the ability to round really long numbers (limit of your string in SQL server which is usually 8000 characters):
SUBSTRING('123.456', 1, CHARINDEX('.', '123.456') + 2)
I think we can go much easier with simpler example solution found in Hackerrank:
Problem statement: Query the greatest value of the Northern Latitudes
(LAT_N) from STATION that is less than 137.2345. Truncate your answer
to 4 decimal places.
SELECT TRUNCATE(MAX(LAT_N),4)
FROM STATION
WHERE LAT_N < 137.23453;
Solution Above gives you idea how to simply make value limited to 4 decimal points. If you want to lower or upper the numbers after decimal, just change 4 to whatever you want.
Mod(x,1) is the easiest way I think.
select convert(int,#value)