sql pulling data in in certain rows but not others - sql

Question

table 1 looks like this:
filekey hourstype hours
123 1 40
123 2 5
123 3 6
123 4 7
123 5 8
needed output should look like this:
filekey hours1 hours2 otherhourstype otherhourstotal
123 40 5 '' ''
123 '' '' 3 6
123 '' '' 4 7
123 '' '' 5 8
hours1 and hours2 occupy the same row, all other hours occupy their own row
there is one other possible format that can work:
filekey hours1 hours2 difhrstype difhrstotal difhourstype difhrstotal
123 40 5 3 6 4 7
in this scenario start with lowest hours type, then total extended through columns instead of rows with one row per filekey. I'm not sure how to make this one happen either. especially because there can be up to 8 hourstypes each of which may or may not exist for a given filekey

Answer 1

Try this for scenario 1:
CREATE TABLE #TMP(filekey INT, hourstype INT, [hours] INT)
INSERT INTO #TMP VALUES
(123,1,40)
,(123,2,5)
,(123,3,6)
,(123,4,7)
,(123,5,8)
SELECT
T.filekey
,SUM(CASE WHEN hourstype = 1 THEN [hours] ELSE 0 END) AS hours1
,SUM(CASE WHEN hourstype = 2 THEN [hours] ELSE 0 END) AS hours2
,CASE WHEN hourstype > 2 THEN [hourstype] ELSE 0 END AS otherhourstype
,CASE WHEN hourstype > 2 THEN [hours] ELSE 0 END AS otherhourstotal
FROM
#TMP T
GROUP BY
T.filekey
,CASE WHEN hourstype > 2 THEN [hourstype] ELSE 0 END
,CASE WHEN hourstype > 2 THEN [hours] ELSE 0 END

Answer 2

UNION a query that will produce the first row over a query that will produce the other three rows.
Hard-code the NULLs (or blanks or whatever you want) for the unused columns in each query.

Answer 3

Try the following:
select
pivottable.filekey,
[1] as hours1,
[2] as hours2,
[3] as hours3,
[4] as hours4,
[5] as hours5,
[6] as hours6,
[7] as hours7,
[8] as hours8
from table1
PIVOT (
sum(hours)
FOR hourstype IN ([1],[2],[3],[4],[5],[6],[7],[8])
) as pivottable