Are next two queries going to return same result set?
SELECT * FROM tableA a
JOIN tableB b
ON a.id = b.id
WHERE a.id = '5'
--------------------------------
SELECT * FROM tableA a
JOIN tableb b
ON a.id = b.id
WHERE b.id = '5'
Also, will answer be different if LEFT JOIN is used instead of JOIN?
As written, they will return the same result.
The two will not necessarily return the same result with a left join.
Yes the result will be the same.
With a left join you will get every dataset of both table who got a ID.
With a join (Inner Join) you will get only the dataset's who a.id = b.id.
This site will explain you how to join https://www.w3schools.com/sql/sql_join.asp
Yes they will. A simple join works like an inner join by default. It checks for instances where the item you're joining on exist on both tables. Since you're joining on where a.id=b.id the results will be the same.
If you change the type of join to a left, the results will include all a.id's regardless of whether they are equal to 5.
Related
This is a conceptual question. So I dont have any actual code. But it is simple to follow.
Lets stay we have two tables (Join_1 and Join_2) from joining A and B:
Join_1:
Select *
From A join B on A.id = B.id
Join_2
Select *
From A left join B on A.id = B.id
where B.id is not null
Question: Does Join_1 always equal to Join_2? You can think of any conditions such as null values, duplicates and so on.
For all practical purposes, "yes".
The only exception would be if a.id could be NULL. In that case, the first version would filter out those rows. The second would include them.
I have the following scenario on a SQL Server 2008 R2:
The following queries returns :
select * from TableA where ID = '123'; -- 1 rows
select * from TableB where ID = '123'; -- 5 rows
select * from TableC where ID = '123'; -- 0 rows
When joining these tables the following way, it returns 1 row
SELECT A.ID
FROM TableA A
INNER JOIN ( SELECT DISTINCT ID
FROM TableB ) AS D
ON D.ID = A.ID
INNER JOIN TableC C
ON A.ID = C.ID
ORDER BY A.ID
But, when switching the inner joins order it does not returns any row
SELECT A.ID
FROM TableA A
INNER JOIN TableC C
ON A.ID = C.ID
INNER JOIN ( SELECT DISTINCT ID
FROM TableB ) AS D
ON D.ID = A.ID
ORDER BY A.ID
Can this be possible?
Print Screen:
For inner joins, the order of the join operations does not affect the query (it can affect the ordering of the rows and columns, but the same data is returned).
In this case, the result set is a subset of the Cartesian product of all the tables. The ordering doesn't matter.
The order can and does matter for outer joins.
In your case, one of the tables is empty. So, the Cartesian product is empty and the result set is empty. It is that simple.
As Gordon mentioned, for inner joins the order of joins doesn't matter, whereas it does matter when there's at least one outer join involved; however, in your case, none of this is pertinent as you are inner joining 3 tables, one of which will return zero rows - hence all combinations will result in zero rows.
You cannot reproduce the erratic behavior with the queries as they are shown in this question since they will always return zero records. You can try it again on your end to see what you come up with, and if you do find a difference, please share it with us then.
For the future, whenever you have something like this, creating some dummy data either in the form of insert statements or in rextester or the like, you make it that much easier for someone to help you.
Best of luck.
Will there be any difference if I change the order from this to the next one in the last line ESPECIALLY when I use left join or left outer join? SOme people confuse me that it might have differnet value when we change order, I reckon they themselves aren't sure about this.
Or, if we change the order, under what situations such as right outer, right, left, left outer joins the query result differs?
It makes no difference which side you put criteria on when an = is being used.
Table order matters in the case of LEFT JOIN and RIGHT JOIN, but criteria order does not.
For example:
SELECT *
FROM Table1 a
LEFT JOIN Table2 b
ON a.ID = b.ID
Is equivalent to:
SELECT *
FROM Table2 a
RIGHT JOIN Table1 b
ON a.ID = b.ID
But not equivalent to:
SELECT *
FROM Table2 a
LEFT JOIN Table1 b
ON a.ID = b.ID
Demo: SQL Fiddle
I'm a complete novice teaching myself SQL by writing and modifying a few queries and reports at work.
I've got something of a handle on the various types of JOINs and I've used INNER JOIN a few times with decent success.
What I'm stuck on should be a simple task, but my Google-Fu must be weak. Here's what I'm trying to do.
Say I have 3 tables, Table_A, Table_B, and Table_C, and each table has a column called [Serial_Number].
What I'm wanting to select is 3 of the other columns if A.Serial_Number = B.Serial_Number OR C.Serial_Number.
I've tried doing:
SELECT
*
FROM
Table_A AS A
INNER JOIN Table_B AS B ON A.Serial_Number = B.Serial_Number
INNER JOIN Table_C AS C ON A.Serial_Number = C.Serial_Number
But this always yields 0 results as the nature of the data dictates that if A matches B, it will never match C and vice versa. I also tried a LEFT OUTER JOIN as the second clause, but this just includes NULLs from Table_C that have already matched on Table_B.
All the searches I have done relating to JOINs on multiple tables seem to be about using JOINS to further exclude records, where I'm actually wanting to INCLUDE more records.
Like I said, I'm sure this is really simple, just needing a nudge in right direction.
Thanks!
The use of two inner joins here is akin to saying
If A.Serial_Number = B.Serial_Number AND
A.Serial_Number = C.Serial_Number
Using left outer join on the second clause - by which i presume you mean second join - would perform a left join on a result set already filtered by A.Serial_Number = B.Serial_Number by the first inner join. Given that B.Serial_Number doesn't relate to C.Serial_Number you wouldn't expect the an equijoin to return any result from tablec.
What you want is a left outer join like you tried but for both tableb and tablec.
Select *
From tablea
Left join tableb on tableb.Serial_Number = tablea.Serial_Number
Left join tablec on tablec.Serial_Number = tablea.Serial_Number
This way regardless of whether tablea.Serial_Number is in tableb it will still be returned and thus available to be joined to tablec
Agreed. Your output for your inner joins is producing NULLs which is why it is resulting in 0. I would suggest modifying your INNER JOIN.
SELECT * FROM Table A LEFT JOIN TABLE B LEFT JOIN TABLE C
From the snippet above, TABLE C will left join into (TABLE B) or (data from TABLE A LEFT JOIN TABLE B) or (TABLE A)?
TABLE C will left join into 1. (TABLE B) or 2. (data from TABLE A LEFT JOIN
TABLE B) or 3. (TABLE A)?
The second. But The join condition will help you to understand more.
You can write:
SELECT *
FROM Table A
LEFT JOIN TABLE B ON (A.id = B.id)
LEFT JOIN TABLE C ON (A.ID = C.ID)
But you are able to:
SELECT *
FROM Table A
LEFT JOIN TABLE B ON (A.id = B.id)
LEFT JOIN TABLE C ON (A.id = C.id and B.code = C.code)
So, you can join on every field from previous tables and you join on "the result" (though the engine may choose its way to get the result) of the previous joins.
Think at left join as non-commutative operation (A left join B is not the same as B left join A) So, the order is important and C will be left joined at the previous joined tables.
The Oracle documentation is quite specific about how the joins are processed:
To execute a join of three or more tables, Oracle first joins two of
the tables based on the join conditions comparing their columns and
then joins the result to another table based on join conditions
containing columns of the joined tables and the new table. Oracle
continues this process until all tables are joined into the result.
This is the logic approach to handling the joins and is consistent with the ANSI standard (in other words, all database engines process the joins in order).
However, when the query is actually executed, the optimizer may choose to run the joins in a different order. The result needs to be logically the same as processing the joins in the order given in the query.
Also, the join conditions may cause some unexpected conditions to arise. So if you have:
from A left outer join
B
on A.id = B.id left outer join
C
on B.id = C.id
Then, you might have the condition where A and C each have a row with a particular id, but B does not. With this formulation, you will not see the row in C because it is joining to NULL. So, be careful with join conditions on left outer join, particularly when joining to a table other than the first table in the chain.
You need to mentioned the column name properly in order to run the query. Let´s say if you are using:
SELECT *
FROM Table A
LEFT JOIN TABLE B ON (A.id = B.id)
LEFT JOIN TABLE C ON (A.id = C.id and B.code = C.code)
Then you may get the following error:
ORA-00933:SQL command not properly ended.
So to avoid it you can try:
SELECT A.id as "Id_from_A", B.code as "Code_from_B"
FROM Table A
LEFT JOIN TABLE B ON (A.id = B.id)
LEFT JOIN TABLE C ON (A.id = C.id and B.code = C.code)
Thanks