SQL report - Matching percent value with a number - sql

Question

I have a small issue with my report and I need to know if its even possible to do it?
Im using Oracle12c and the tool OBIEE, im trying to create a custom column with numbers values (1 and 2) that are matching my results from my "Percent" column in a way I described below.
Here is my results in table:
I will give u an example of how it should work:
Emilian is an owner of few customers, the customers have their annual revenue listed and the column next to it its the Percent value of the total customer revenue for Emilian. Now, in my custom column I need to show "1" for customers that contribute more than (or exact) 80% of his total and "2" for the rest. So in Emilian Case, his first two customers will be "1" since 78% + 14% is already above 80% and the rest will be "2". For other Owners that only have one customer, all of them logically would be matched with "1" since their contribution is 100%
Hope I made this clear, will be veery grateful for the help with coding it :)
Alex

Answer 1

There's probably a much more efficient way to do this. I built up what you need to get at with a series of sub-selects. This still doesn't handle the equal percents, but you said that isn't an expected problem. I'd still watch out for it.
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE t1 ( ownerId int, customerId int, revenue int ) ;
INSERT INTO t1 ( ownerid, customerid, revenue )
SELECT 1, 1, 99 FROM dual UNION ALL
SELECT 1, 2, 200 FROM dual UNION ALL
SELECT 1, 3, 300 FROM dual UNION ALL
SELECT 1, 4, 400 FROM dual UNION ALL
SELECT 2, 5, 100 FROM dual UNION ALL
SELECT 2, 6, 100 FROM dual UNION ALL
SELECT 2, 7, 200 FROM dual UNION ALL
SELECT 2, 8, 600 FROM dual UNION ALL
SELECT 3, 9, 100 FROM dual UNION ALL
SELECT 3, 10, 900 FROM dual UNION ALL
SELECT 4, 11, 1000 FROM dual UNION ALL
SELECT 5, 12, 1000 FROM dual UNION ALL
SELECT 6, 13, 200 FROM dual UNION ALL
SELECT 6, 14, 200 FROM dual UNION ALL
SELECT 6, 15, 200 FROM dual UNION ALL
SELECT 6, 16, 200 FROM dual UNION ALL
SELECT 6, 17, 200 FROM dual UNION ALL
SELECT 42, 736784, 1480000 FROM dual UNION ALL
SELECT 42, 736580, 280160 FROM dual UNION ALL
SELECT 42, 1040137, 112486 FROM dual UNION ALL
SELECT 42, 738685, 22903 FROM dual UNION ALL
SELECT 42, 736781, 56 FROM dual
;
Query 1:
SELECT s3.ownerID, s3.customerID, s3.revenue, s3.OwnerRevenue
, CAST(s3.customerRevPct AS decimal(5,2)) AS customerRevPct
, CASE WHEN s3.PctRT < 80 OR s3.custCount = 1 THEN 1 ELSE 2 END AS customCol
/* Do the running pcts add up to 80+? 1 customer = 100% == 1. What if all are pcts are equal? */
FROM (
SELECT s2.*
, 100-SUM(nvl(s2.customerRevPct,0)) OVER (PARTITION BY s2.ownerID ORDER BY s2.customerRevPct, s2.customerID RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS pctRT
, COUNT(*) OVER (PARTITION BY s2.ownerID ORDER BY (s2.ownerID) ) AS custCount /* Is there only 1 customer? */
FROM (
SELECT s1.*
, ( ( ( s1.revenue * 1.0 ) / s1.ownerRevenue ) * 100 ) AS customerRevPct
FROM (
SELECT t1.ownerID, t1.customerID, t1.revenue
, SUM(t1.revenue) OVER ( PARTITION BY t1.ownerID ) AS ownerRevenue
FROM t1
) s1
) s2
) s3
WHERE ownerID = 42 /* REMOVE THIS LINE - TESTING ONLY */
ORDER BY s3.ownerID, s3.customerRevPct DESC
Results:
| OWNERID | CUSTOMERID | REVENUE | OWNERREVENUE | CUSTOMERREVPCT | CUSTOMCOL |
|---------|------------|---------|--------------|----------------|-----------|
| 42 | 736784 | 1480000 | 1895605 | 78.08 | 1 |
| 42 | 736580 | 280160 | 1895605 | 14.78 | 1 |
| 42 | 1040137 | 112486 | 1895605 | 5.93 | 2 |
| 42 | 738685 | 22903 | 1895605 | 1.21 | 2 |
| 42 | 736781 | 56 | 1895605 | 0 | 2 |
EDIT: I changed the Fiddle to illustrate your data example.

Answer 2

create table custrev(owner varchar2(100), cust_id number, revenue number);
insert into custrev values('Emilian',1,1480000);
insert into custrev values('Emilian',2,280160);
insert into custrev values('Emilian',3,112486);
insert into custrev values('Emilian',4,22903);
insert into custrev values('Emilian',5,56);
insert into custrev values('Andy',6,1378);
insert into custrev values('Sandy',7,560000);
commit;
Below is the SQL for your requirement.
select owner, cust_id, revenue, pct,
case when pct = 100 then 1
when flg is null or flg < 80 then 1
else 2 end flag_col
from (select owner, cust_id, revenue, pct,--cumulative_sum,
lag(cumulative_sum) over(partition by owner
order by revenue desc) flg
from (select owner, cust_id, revenue, pct,
sum(pct) over(partition by owner
order by revenue desc
rows between unbounded preceding
and current row) cumulative_sum
from (select owner, cust_id, revenue,
round(ratio_to_report(revenue) over(partition by owner)*100,2) pct
from custrev)
)
)
order by owner, revenue desc;
Output:
OWNER CUST_ID REVENUE PCT FLAG_COL
Andy 6 1378 100 1
Emilian 1 1480000 78.08 1
Emilian 2 280160 14.78 1
Emilian 3 112486 5.93 2
Emilian 4 22903 1.21 2
Emilian 5 56 0 2
Sandy 7 560000 100 1

Answer 3

Alex,
OBIEE is based on models. Not on SQL.
So sorry to say this but the SQL code will help you exactly zero...