I've been trying to find a way to count days difference between two dates from previous and current rows which counting only business days.
Example data and criteria here.
ID StartDate EndDate NewDate DaysDifference
========================================================================
0 04/05/2017 null
1 12/06/2017 16/06/2017 12/06/2017 29
2 03/07/2017 04/07/2017 16/06/2017 13
3 07/07/2017 10/07/2017 04/07/2017 5
4 12/07/2017 26/07/2017 10/07/2017 13
My end goal is
I want two new columns; NewDate and DayDifference.
NewDate column is from EndDate from previous row. As you can see that for example, NewDate of ID 2 is 16/06/2017 which come from EndDate of ID 1. But if value in EndDate of previous row is null, use its StartDate instead(ID 1 case).
DaysDifference column is from counting only business days between EndDate and NewDate columns.
Here is script that I am using atm.
select distinct
c.ID
,c.EndDate
,isnull(p.EndDate,c.StartDate) as NewDate
,count(distinct cast(l.CalendarDate as date)) as DaysDifference
from
(select *
from table) c
full join
(select *
from table) p
on c.level = p.level
and c.id-1 = p.id
left join Calendar l
on (cast(l.CalendarDate as date) between cast(p.EndDate as date) and cast(c.EndDate as date)
or
cast(l.CalendarDate as date) between cast(p.EndDate as date) and cast(c.StartDate as date))
and l.Day not in ('Sat','Sun') and l.Holiday <> 'Y'
where c.ID <> 0
group by
c.ID
,c.EndDate
,isnull(p.EndDate,c.StartDate)
And this's the current result :
ID EndDate NewDate DaysDifference
=========================================================
1 16/06/2017 12/06/2017 0
2 04/07/2017 16/06/2017 13
3 10/07/2017 04/07/2017 5
4 26/07/2017 10/07/2017 13
Seems like in the real data, I've got correct DaysDifference for ID 2,3,4 except ID 1 because of the null value from its previous row(ID 0) that printing StartDate instead of null EndDate, so it counts incorrectly.
Hope I've provided enough info. :)
Could you please guide me a way to count DaysDifference correctly.
Thanks in advance!
I think you can use this logic to get the previous date:
select t.*,
lag(coalesce(enddate, startdate), 1) over (order by 1) as newdate
from t;
Then for the difference:
select id, enddate, newdate,
sum(case when c.day not in ('Sat', 'Sun') and c.holiday <> 'Y' then 1 else 0 end) as diff
from (select t.*,
lag(coalesce(enddate, startdate), 1) over (order by 1) as newdate
from t
) t join
calendar c
on c.calendardate >= newdate and c.calendardate <= startdate
group by select id, enddate, newdate;
Related
Here are two tables.
ItemInfo
Id Description
1 First Item
2 Second Item
ItemInfoHistory
Id ItemInfoId Price StartDate EndDate
1 1 45 2020-09-01 2020-09-15
2 2 55 2020-09-26 null
3 1 50 2020-09-16 null
Here is SQL query.
SELECT i.Id, Price, StartDate, EndDate
FROM Itemsinfo i
LEFT JOIN ItemInfoHistory ih ON i.id= ih.ItemsMasterId AND CONVERT(DATE, GETDATE()) >= StartDate AND ( CONVERT(DATE, GETDATE()) <= EndDate OR EndDate IS NULL)
Which gives following results, when runs the query on 9/20
Id Price StartDate EndDate
1 50 2020-09-16 NULL
2 NULL NULL NULL
For the second item, I want to get latest record from history table, as shown below.
Id Price StartDate EndDate
1 50 2020-09-16 NULL
2 55 2020-09-26 NULL
Thanks in advance.
Probably the most efficient method is two joins. Assuming the "latest" record has a NULL values for EndDate, then:
SELECT i.Id,
COALESCE(ih.Price, ih_last.Price) as Price,
COALESCE(ih.StartDate, ih_last.StartDate) as StartDate,
COALESCE(ih.EndDate, ih_last.EndDate) as EndDate
FROM Itemsinfo i LEFT JOIN
ItemInfoHistory ih
ON i.id = ih.ItemsMasterId AND
CONVERT(DATE, GETDATE()) >= StartDate AND
(CONVERT(DATE, GETDATE()) <= EndDate OR EndDate IS NULL) LEFT JOIN
ItemInfoHistory ih_last
ON i.id = ih_last.ItemsMasterId AND
ih_last.EndDate IS NULL;
Actually, the middle join doesn't need to check for NULL, so that could be removed.
I'm trying to come up with the correct query to calculate the employment experience time but, I can't get it right. Here's the data I have:
Case 1:
EmployeeID PoisitionID StartDate EndDate
1 15 5/22/2017 5/22/2018
1 17 7/14/2018 8/10/2019
Case 2:
EmployeeID PositonID StartDate EndDate
1 15 5/22/2017 8/10/2019
1 17 3/8/2019 8/10/2019
Case 3:
EmployeeID PositonID StartDate EndDate
1 15 5/22/2017 NULL
1 17 3/8/2019 NULL
In the first case, my expected result in months would be: 27 months for both positions.
In the second case, my expected result in months would be:27 months for positonid 15 and 0 months for positionid 17 because positionid 17 falls during the date range of the first position and therefore, the employee will not be awarded with any years of experience.
In the third case, my expected result in months would be:30 months using today's date as an enddate for positonid 15 and 0 months for positionid 17 because positionid 17 falls during the date range of the first position and therefore, the employee will not be awarded with any years of experience.
You don't have any gaps, so I think this does what you want:
select employeeid,
datediff(month, min(startdate), coalesce(max(enddate), getdate())) as months
from t
group by employeeid;
This is what I have:
Your table 1:
select 1 as EmployeeID , 15 as PositonID , cast('5/22/2017' as date) as StartDate, cast('5/22/2018' as date) as EndDate into t2
union select 1, 17, '7/14/2018', '8/10/2019'
And the query to get the result
with a as
(
select EmployeeID, isnull(StartDate, cast(getdate() as date)) as sedate from t2
union
select EmployeeID, isnull(EndDate, cast(getdate() as date)) from t2
)
select a1.*, a2.sedate, case when datediff(month,a1.sedate, a2.sedate)< 0 then 0 else isnull(datediff(month,a1.sedate, a2.sedate), 0) end as months from a a1 left join a a2 on a1.EmployeeID = a2.EmployeeID and a1.sedate < a2.sedate
and not exists(select 1 from a a3 where a3.EmployeeID = a2.EmployeeID and a3.sedate > a1.sedate and a3.sedate < a2.sedate )
I changed the table to the values of Case2 and Case 3 and it seemed to work.
Let us know if that helps
I have two dates start date and end date .
How can I know if between these two dates , I got 01/01 meaning new year .
For example :
Table test
id start date End date
1 02/03/2013 19/09/2016
2 15/02/2015 30/06/2015
Output
id start date End date
1 02/03/2013 31/12/2013
1 01/01/2014 31/12/2014
1 01/01/2015 31/12/2015
1 01/01/2016 19/09/2016
2 15/02/2015 30/06/2015
How to do something like that ?
You would know if the year component is different:
select t.*,
(case when year(startdate) < year(enddate) then 1
else 0
end) as HasNewYear
from table t;
You can use a recursive CTE to find all years between the two dates, then cast out the dates to DATETIME objects to get the desired output:
;WITH CTE AS (
SELECT ID, DATEPART(YEAR, STARTDATE) AS YR, ENDDATE
FROM TABLE1
UNION ALL
SELECT ID, YR+1, ENDDATE
FROM CTE
WHERE YR < DATEPART(YEAR,ENDDATE))
SELECT A.ID, CASE WHEN CAST(A.YR AS VARCHAR)+'-01-01' > B.STARTDATE THEN CAST(A.YR AS VARCHAR)+'-01-01' ELSE B.STARTDATE END AS STARTDATE, CASE WHEN CAST(A.YR AS VARCHAR)+'-12-31' < B.ENDDATE THEN CAST(A.YR AS VARCHAR)+'-12-31' ELSE B.ENDDATE END AS ENDDATE
FROM CTE AS A
JOIN TABLE1 AS B
ON A.ID=B.ID
ORDER BY A.ID
Im using SQL Server 2005. From the tbl_temp table below, I would like to add an EndDate column based on the next row's StartDate minus 1 day until there's a change in AID and UID combination. This calculated EndDate will go to the row above it as the EndDate. The last row of the group of AID and UID will get the system date as its EndDate. The table has to be ordered by AID, UID, StartDate sequence. Thanks for the help.
-- tbl_temp
AID UID StartDate
1 1 2013-02-20
2 1 2013-02-06
1 1 2013-02-21
1 1 2013-02-27
1 2 2013-02-02
1 2 2013-02-04
-- Result needed
AID UID StartDate EndDate
1 1 2013-02-20 2013-02-20
1 1 2013-02-21 2013-02-26
1 1 2013-02-27 sysdate
1 2 2013-02-02 2013-02-03
1 2 2013-02-04 sysdate
2 1 2013-02-06 sysdate
The easiest way to do this is with a correlated subquery:
select t.*,
(select top 1 dateadd(day, -1, startDate )
from tbl_temp t2
where t2.aid = t.aid and
t2.uid = t.uid and
t2.startdate > t.startdate
) as endDate
from tbl_temp t
To get the current date, use isnull():
select t.*,
isnull((select top 1 dateadd(day, -1, startDate )
from tbl_temp t2
where t2.aid = t.aid and
t2.uid = t.uid and
t2.startdate > t.startdate
), getdate()
) as endDate
from tbl_temp t
Normally, I would recommend coalesce() over isnull(). However, there is a bug in some versions of SQL Server where it evaluates the first argument twice. Normally, this doesn't make a difference, but with a subquery it does.
And finally, the use of sysdate makes me think of Oracle. The same approach will work there too.
;WITH x AS
(
SELECT AID, UID, StartDate,
ROW_NUMBER() OVER(PARTITION BY AID, UID ORDER BY StartDate) AS rn
FROM tbl_temp
)
SELECT x1.AID, x1.UID, x1.StartDate,
COALESCE(DATEADD(day,-1,x2.StartDate), CAST(getdate() AS date)) AS EndDate
FROM x x1
LEFT OUTER JOIN x x2 ON x2.AID = x1.AID AND x2.UID = x1.UID
AND x2.rn = x1.rn + 1
ORDER BY x1.AID, x1.UID, x1.StartDate
SQL Fiddle example
Given three tables Dates(date aDate, doUse boolean), Days(rangeId int, day int, qty int) and Range(rangeId int, startDate date) in Oracle
I want to join these so that Range is joined with Dates from aDate = startDate where doUse = 1 whith each day in Days.
Given a single range it might be done something like this
SELECT rangeId, aDate, CASE WHEN doUse = 1 THEN qty ELSE 0 END AS qty
FROM (
SELECT aDate, doUse, SUM(doUse) OVER (ORDER BY aDate) day
FROM Dates
WHERE aDate >= :startDAte
) INNER JOIN (
SELECT rangeId, day,qty
FROM Days
WHERE rangeId = :rangeId
) USING (day)
ORDER BY day ASC
What I want to do is make query for all ranges in Range, not just one.
The problem is that the join value "day" is dependent on the range startDate to be calculated, wich gives me some trouble in formulating a query.
Keep in mind that the Dates table is pretty huge so I would like to avoid calculating the day value from the first date in the table, while each Range Days shouldn't be more than a 100 days or so.
Edit: Sample data
Dates Days
aDate doUse rangeId day qty
2008-01-01 1 1 1 1
2008-01-02 1 1 2 10
2008-01-03 0 1 3 8
2008-01-04 1 2 1 2
2008-01-05 1 2 2 5
Ranges
rangeId startDate
1 2008-01-02
2 2008-01-03
Result
rangeId aDate qty
1 2008-01-02 1
1 2008-01-03 0
1 2008-01-04 10
1 2008-01-05 8
2 2008-01-03 0
2 2008-01-04 2
2 2008-01-05 5
Try this:
SELECT rt.rangeId, aDate, CASE WHEN doUse = 1 THEN qty ELSE 0 END AS qty
FROM (
SELECT *
FROM (
SELECT r.*, t.*, SUM(doUse) OVER (PARTITION BY rangeId ORDER BY aDate) AS span
FROM (
SELECT r.rangeId, startDate, MAX(day) AS dm
FROM Range r, Days d
WHERE d.rangeid = r.rangeid
GROUP BY
r.rangeId, startDate
) r, Dates t
WHERE t.adate >= startDate
ORDER BY
rangeId, t.adate
)
WHERE
span <= dm
) rt, Days d
WHERE d.rangeId = rt.rangeID
AND d.day = GREATEST(rt.span, 1)
P. S. It seems to me that the only point to keep all these Dates in the database is to get a continuous calendar with holidays marked.
You may generate a calendar of arbitrary length in Oracle using following construction:
SELECT :startDate + ROWNUM
FROM dual
CONNECT BY
1 = 1
WHERE rownum < :length
and keep only holidays in Dates. A simple join will show you which Dates are holidays and which are not.
Ok, so maybe I've found a way. Someting like this:
SELECT irangeId, aDate + sum(case when doUse = 1 then 0 else 1) over (partionBy rangeId order by aDate) as aDate, qty
FROM Days INNER JOIN (
select irangeId, startDate + day - 1 as aDate, qty
from Range inner join Days using (irangeid)
) USING (aDate)
Now I just need a way to fill in the missing dates...
Edit: Nah, this way means that I'll miss the doUse vaue of the last dates...