This is my table:
Using this query, I am getting most sold items:
SELECT [Purchased Item], SUM([Overall Quantity purchased] )
FROM ReportDraft
GROUP BY [Purchased Item]
ORDER BY SUM([Overall Quantity purchased] )
This returns items and total quantity purchased by customer.
how I can create a table like this
ItemName | Total quantity purchased | Customer who purchased most | Customer quantity bought
Pie--------|---------6------------|---------------Tonya----------|--------4------------|
Big Burger-|---------3------------|---------------Tonya----------|--------3------------| and etc
Thank you
Why do you post a new question instead of nodifying/extending the previous one?
WITH cte AS
(
SELECT [Purchased Item],
-- quantity per item
SUM(SUM([Overall Quantity purchased]))
OVER (PARTITION BY [Purchased Item]) AS "Total quantity purchased",
[Customer name],
-- quantity per item/customer
SUM([Overall Quantity purchased]) AS customer_qantity,
-- rank the customer quantity per item
ROW_NUMBER()
OVER (PARTITION BY [Purchased Item]
ORDER BY SUM([Overall Quantity purchased]) DESC) AS rn
FROM ReportDraft
GROUP BY [Purchased Item], [Customer name]
)
SELECT *
FROM cte
WHERE rn = 1
ORDER BY "Total quantity purchased" DESC
Related
I am trying to produce an analysis which shows 2 things.
Deciles (or percentiles) of customers and their revenue so I can see what 10% of customer count produce the the most revenue.
Deciles of Revenue : how many customers produce 10% of revenue.
select yeardate, decile, sum(revenue) as revenue, count(distinct(customername)) as cust_count
from
(
select yeardate,
customername,
ntile(10) over (order by sum(revenue) ) as decile,
sum(revenue) as revenue
from
(select
year(DateStamp) as yeardate ,
customername,
sum(Sell) as revenue
from MarginListView
where reporttype = 'Invoice' and sell >0 and year(datestamp) = 2018
group by year(DateStamp), customername) d
group by yeardate, CustomerName) c
group by yeardate, decile
order by 1,2
I can get the customer count deciles but not the revenue deciles....
using MS SQL server - Any help appreciated.
To get the number of customers that produce 10% of revenue, start with the cumulative revenue:
select customername, sum(sell) as revenue,
sum(sum(sell)) over (order by sum(sell) desc) as running_revenue
from MarginListView
where reporttype = 'Invoice' and sell > 0 and
year(datestamp) = 2018
group by customername;
To get the number that account for 10%:
select count(*)
from (select customername, sum(sell) as revenue,
sum(sum(sell)) over (order by sum(sell) desc) as running_revenue,
sum(sum(sell)) over () as total_revenue
from MarginListView
where reporttype = 'Invoice' and sell > 0 and
year(datestamp) = 2018
group by customername
) c
where running_revenue - revenue >= 0.1 * total_revenue;
Gordon - thanks for your help.... it really did get me towards where I needed to be.
I ended with this...
select
yeardate, customername,
sell,
cast((round(sum(sum(revenue_sub_tot)) over (order by sum(revenue_sub_tot) asc),2,2)) as decimal (2,2)) as revenue_percentiles,
cast((round(sum(sum(revenue_sub_tot)) over (order by sum(revenue_sub_tot) asc),1,1)) as decimal (2,2)) as revenue_deciles
from (select year(datestamp) as yeardate,
customername,
sum(sell) as sell,
sum(sell)/sum(sum(sell)) over () as revenue_sub_tot
from MarginListView
where reporttype = 'Invoice' and sell > 0
group by year(datestamp), customername
) c
group by yeardate, customername, sell
order by 1,3
This is my table:
Using this query, I am getting most sold items:
SELECT [Purchased Item], SUM([Overall Quantity purchased] )
FROM ReportDraft
GROUP BY [Purchased Item]
ORDER BY SUM([Overall Quantity purchased] )
This returns items and total quantity purchased by customer.
Can I somehow create a table like
ItemName | Total quantity purchased | Customer who purchased most | Customer quantity bought
Pie--------|---------11------------|---------------ALEX----------|--------3------------|
Thank you
I would use window functions and conditional aggregation:
SELECT [Purchased Item], sum(total) as total,
MAX(CASE WHEN seqnum = 1 THEN Customer END) as customer,
MAX(Total) as max_quantity
FROM (SELECT [Purchased Item], Customer, SUM([Overall Quantity purchased] ) as total,
ROW_NUMBER() OVER (PARTITION BY Customer ORDER BY SUM([Overall Quantity purchased]) DESC) as seqnum
FROM ReportDraft
GROUP BY [Purchased Item], Customer
) rd
GROUP BY [Purchased Item]
ORDER BY SUM([Overall Quantity purchased] );
I'm Trying to Get the date , Discount , Total , Net Total ... ordered by date , the discount is showing the real amount but when I select multiple dates the total will be summed in those dates I've selected and it will be ordered by date
DECLARE #pR FLOAT = (SELECT SUM(CAST(Price AS FLOAT)) AS Price
FROM Orders WHERE isPaid = 1
AND PaidDate BETWEEN '8/17/2015' AND '8/18/2015' ) ;
SELECT Orders.PaidDate
, #pR AS Total
,sum(theorderids.Discount) As Discount
,(#pR - sum(theorderids.Discount)) AS [Net Total]
From
(SELECT OrderId, PaidDate
FROM Orders
WHERE Orders.PaidDate BETWEEN '8/17/2015' AND'8/18/2015'
GROUP BY Orders.OrderId, Orders.PaidDate) AS Orders
INNER JOIN theorderids ON Orders.OrderId = theorderids.ID
GROUP BY Orders.PaidDate ;
Example Data :
Row 1
"PaidDate": "17-08-2015",
"Total": 7388.0,
"Discount": 38.0,
"NetTotal": 7363.0
Row 2
"PaidDate": "18-08-2015",
"Total": 7388.0,
"Discount": 2.0,
"NetTotal": 7363.0
This will work.
SELECT TheOrderids.PaidDate, MAX(Price) AS Total
,sum(theorderids.Discount) As Discount
,(MAX(Price) - sum(theorderids.Discount)) AS [Net Total]
From
(SELECT PaidDate ,SUM(Price ) AS Price
FROM Orders
WHERE Orders.PaidDate BETWEEN '8/17/2015' AND'8/19/2015'
GROUP BY Orders.PaidDate
) AS Orders
INNER JOIN theorderids ON Orders.PaidDate = theorderids.PaidDate
GROUP BY theorderids.PaidDate
ORDER BY theorderids.PaidDate ;
Try this way
SELECT Orders.PaidDate
, #pR AS Total
,sum(theorderids.Discount) As Discount
,(#pR - sum(theorderids.Discount)) AS [Net Total]
From
(SELECT ROW_NUMBER() OVER(ORDER BY Orders.PaidDate ) AS Row, OrderId, PaidDate
FROM Orders
WHERE Orders.PaidDate BETWEEN '8/17/2015' AND'8/18/2015'
GROUP BY Orders.OrderId, Orders.PaidDate) AS Orders
INNER JOIN theorderids ON Orders.OrderId = theorderids.ID
GROUP BY Orders.PaidDate ;
I have a view which ultimately I want to return 1 row per customer.
Currently its a Select as follows;
SELECT
Customerid,
MAX(purchasedate) AS purchasedate,
paymenttype,
delivery,
amount,
discountrate
FROM
Customer
GROUP BY
Customerid,
paymenttype,
delivery,
amount,
discountrate
I was hoping the MAX(purchasedate) would work but when I do my groupings it breaks as sometimes there could be a discountrate, sometimes its NULL, paymenttype can differ for each customer also, is there anyway just to show the last purchase a customer makes?
since SQL Server 2008 r2 supports windows function,
SELECT Customerid,
purchasedate,
paymenttype,
delivery,
amount,
discountrate
FROM
(
SELECT Customerid,
purchasedate,
paymenttype,
delivery,
amount,
discountrate,
ROW_NUMBER() OVER (Partition By CustomerID
ORDER BY purchasedate DESC) rn
FROM Customer
) derivedTable
WHERE derivedTable.rn = 1
or by using Common Table Expression
WITH derivedTable
AS
(
SELECT Customerid,
purchasedate,
paymenttype,
delivery,
amount,
discountrate,
ROW_NUMBER() OVER (Partition By CustomerID
ORDER BY purchasedate DESC) rn
FROM Customer
)
SELECT Customerid,
purchasedate,
paymenttype,
delivery,
amount,
discountrate
FROM derivedTable
WHERE derivedTable.rn = 1
or by using join with subquery which works in other DBMS
SELECT a.*
FROM Customer a
INNER JOIN
(
SELECT CustomerID, MAX(purchasedate) maxDate
FROM Customer
GROUP BY CustomerID
) b ON a.CustomerID = b.CustomerID AND
a.purchasedate = b.maxDate
I have a table with purchased orders data.
Each row contails the amount of certain item purchased, cost per item and the order number group. Each different item purchased is a new row with same order number.
I basically want to return the total cost for that order. I have tried the following but am getting nowhere:
SELECT order_number, SUM( sub_total ) AS `total`
FROM
SELECT order_number, SUM( SUM( amount ) * SUM( cost_per_item ) ) AS `sub_total`
FROM `ecom_orders`
WHERE member_id = '4'
GROUP BY order_number
ORDER BY purchase_date DESC
Pretty much any SQL-92 compliant RDBMS will take this:
SELECT
order_number
,SUM(amount * cost_per_item) AS total
,purchase_date
FROM
ecom_orders
WHERE member_id = '4'
GROUP BY order_number,purchase_date
ORDER BY purchase_date DESC