I am working on an image retrieval task. I have a dataset of wikipedia images with their textual description in xml files (1 xml file per image). I have indexed those xmls in Solr. Now while retrieving those, I want to maintain some threshold for Score values, so that docs with less score will not come in the result (because they are not of much importance). For example I want to retrieve all documents having similarity score greater than or equal to 2.0. I have already tried range queries like score:[2.0 TO *] but can't get it working. Does anyone have any idea how can I do that?
What's the motivation for wanting to do this? The reason I ask, is
score is a relative thing determined by Lucene based on your index
statistics. It is only meaningful for comparing the results of a
specific query with a specific instance of the index. In other words,
it isn't useful to filter on b/c there is no way of knowing what a
good cutoff value would be.
http://lucene.472066.n3.nabble.com/score-filter-td493438.html
Also, take a look here - http://wiki.apache.org/lucene-java/ScoresAsPercentages
So, in general it's bad to cut off by some value, because you'll never know which threshold value is best. In good query it could be score=2, in bad query score=0.5, etc.
These two links should explain you why you DONT want to do it.
P.S. If you still want to do it take a look here - https://stackoverflow.com/a/15765203/2663985
P.P.S. I recommend you to fix your search queries, so they will search better with high precision (http://en.wikipedia.org/wiki/Precision_and_recall)
I'd like your advices regarding optimalization of this:
Data:
I have SQLite database with +- 3000 cities, all of which have name and some lattitude and longitude. All cities have also relevance (based on how often user visits them). Relevance is classic integer. Then, I have user location, again, as lat/lon coordinates.
Request:
I need to create autocomplete editBox. Suggestions must satisfy these conditions:
1) Phrase in editBox must be a substring of suggested city name.
2) Suggestions must by ordered first by relevance. (Classic integer ordering, no problem)
3) If relevance is the same, then suggestions are ordered by distance to user.
4) Display max. 10 suggestions.
Since there are usually a lot of cities with equal relevance, biggest problem is the distance ordering.
My current approach:
A) Get IDs and coordinates of cities that satisfy condition (1) and (2) using classic: name LIKE '% phrase%' ordered by relevance.
B) Split result to groups by relevance. Order these relevance groups by distance using sorting in Java.
C) When there are 10 suggestions that are fixed, (f.e. 11 relevance groups, all containing one city, so no location ordering is needed) stop ordering.
This works well. But, there is a problem. Usually, very few cities have different relevance.
So when user starts typing and there is just one or two letters in the search phrase, I end up sorting 500 cities by distance, just to get to my 10 suggestions, what I find highly inefficient.
Is there any better way to handle such situations using SQLite?
P.S. It is running on Android, if that helps :)
I have 2 documents, and am searching for the keyword "Twitter". Suppose both documents are blog posts with a "tags" field.
Document A has ONLY 1 term in the "tags" field, and it's "Twitter".
Document B has 100 terms in the "tags" field, but 3 of them is "Twitter".
Elastic Search gives the higher score to Document A even though Document B has a higher frequency. But the score is "diluted" because it has more terms. How do I give Document B a higher score, since it has a higher frequency of the search term?
I know ElasticSearch/Lucene performs some normalization based on the number of terms in the document. How can I disable this normalization, so that Document B gets a higher score above?
As the other answer says it would be interesting to see whether you have the same result on a single shard. I think you would and that depends on the norms for the tags field, which is taken into account when computing the score using the tf/idf similarity (default).
In fact, lucene does take into account the term frequency, in other words the number of times the term appears within the field (1 or 3 in your case), and the inverted document frequency, in other words how the term is frequent in the index, in order to compare it with other terms in the query (in your case it doesn't make any difference if you are searching for a single term).
But there's another factor called norms, that rewards shorter fields and take into account eventual index time boosting, which can be per field (in the mapping) or even per document. You can verify that norms are the reason of your result enabling the explain option in your search request and looking at the explain output.
I guess the fact that the first document contains only that tag makes it more important that the other ones that contains that tag multiple times but a lot of ther tags as well. If you don't like this behaviour you can just disable norms in your mapping for the tags field. It should be enabled by default if the field is "index":"analyzed" (default). You can either switch to "index":"not_analyzed" if you don't want your tags field to be analyzed (it usually makes sense but depends on your data and domain) or add the "omit_norms": true option in the mapping for your tags field.
Are the documents found on different shards? From Elastic search documentation:
"When a query is executed on a specific shard, it does not take into account term frequencies and other search engine information from the other shards. If we want to support accurate ranking, we would need to first execute the query against all shards and gather the relevant term frequencies, and then, based on it, execute the query."
The solution is to specify the search type. Use dfs_query_and_fetch search type to execute an initial scatter phase which goes and computes the distributed term frequencies for more accurate scoring.
You can read more here.
I need to normalize the Lucene scores between 0 and 1.
For example, a random query returns the following scores...
8.864665
2.792687
2.792687
2.792687
2.792687
0.49009037
0.33730242
0.33730242
0.33730242
0.33730242
What's the biggest score ? 10.0 ?
thanks
You can divide all scores with the maximum score to get scores between 0 and 1.
However, please note that the normalised scores should be used to compare the results of a single query only. It is not correct to compare the scores (normalised or not) of results from 2 different queries.
There is no good standard way to normalize scores with lucene. Read this: ScoresAsPercentages and this explanation
In your case the highest score is the score of the first result, if the results are sorted by score. But this score will be different for every other query.
See also how-do-i-normalise-a-solr-lucene-score
There is no maximum score in Solr, it depends on too many variables, so it can't be predicted.
But you can implement something called normalized score (Scores As Percentages) which is not recommended.
See related links for more details:
Is it possible to set a Solr Score threshold 'reasonably', independent of results returned? (i.e. Is Solr Scoring standardized in any way)
how do I normalise a solr/lucene score?
Remove results below a certain score threshold in Solr/Lucene?
A regular normalization will only help you to compare the scoring distribution among queries (and theirs retrieved lists).
You cannot simply normalize the score to compare the performance between queries.
Think of a query which all retrieved documents are highly relevant and received the same (high score), and on another query that the retrieved list comprise barley relevant document (again, with the same score) - now, no matter the per-query normalization you make - the normalized score will be the same.
You need to think on a cross-query factor that can bring all the scores to the same level.
For example - maybe computing similarity between the query and the whole index, and use that score somehow along with the document-score
If you want to compare two or more queries, i found an workaround.
You can compare your highest scored document with your queryterm using the LevenstheinDistance or LuceneLevenstheinDistance(Damerau) class to get the distance between your queryterm and your result. The result is the similiarity between them. Do this for each query you want to compare against. Now you have a tool to compare your queries using the similiarity of your querytherm and your highest result. You can now choose the query with the highest score of similiarity and use this for next proper actions.
//Damerau LevenstheinDistance
LuceneLevenshteinDistance d = new LuceneLevenshteinDistance();
similiarity = d.getDistance(queryterm, yourResult );
I applied a non-linearity function in order to compress every queries.
I have Persons table in SQL Server 2008.
My goal is to find Persons who have almost similar addresses.
The address is described with columns state, town, street, house, apartment, postcode and phone.
Due to some specific differences in some states (not US) and human factor (mistakes in addresses etc.), address is not filled in the same pattern.
Most common mistakes in addresses
Case sensitivity
Someone wrote "apt.", another one "apartment" or "ap." (although addresses aren't written in English)
Spaces, dots, commas
Differences in writing street names, like 'Dr. Jones str." or "Doctor Jones street" or "D. Jon. st." or "Dr Jones st" etc.
The main problem is that data isn't in the same pattern, so it's really difficult to find similar addresses.
Is there any algorithm for this kind of issue?
Thanks in advance.
UPDATE
As I mentioned address is separated into different columns. Should I generate a string concatenating columns or do your steps for each column?
I assume I shouldn't concatenate columns, but if I'll compare columns separately how should I organize it? Should I find similarities for each column an union them or intersect or anything else?
Should I have some statistics collecting or some kind of educating algorithm?
Suggest approaching it thus:
Create word-level n-grams (a trigram/4-gram might do it) from the various entries
Do a many x many comparison for string comparison and cluster them by string distance. Someone suggested Levenshtein; there are better ones for this kind of task, Jaro-Winkler Distance and Smith-Waterman work better. A libraryt such as SimMetrics would make life a lot easier
Once you have clusters of n-grams, you can resolve the whole string using the constituent subgrams i.e. D.Jones St => Davy Jones St. => DJones St.
Should not be too hard, this is an all-too-common problem.
Update: Based on your update above, here are the suggested steps
Catenate your columns into a single string, perhaps create a db "view" . For example,
create view vwAddress
as
select top 10000
state town, street, house, apartment, postcode,
state+ town+ street+ house+ apartment+ postcode as Address
from ...
Write a separate application (say in Java or C#/VB.NET) and Use an algorithm like JaroWinkler to estimate the string distance for the combined address, to create a many x many comparison. and write into a separate table
address1 | address n | similarity
You can use Simmetrics to get the similarity thus:
JaroWinnkler objJw = new JaroWinkler()
double sim = objJw.GetSimilarity (address1, addres n);
You could also trigram it so that an address such as "1 Jones Street, Sometown, SomeCountry" becomes "1 Jones Street", "Jones Street Sometown", and so on....
and compare the trigrams. (or even 4-grams) for higher accuracy.
Finally you can order by similarity to get a cluster of most similar addresses and decide an approprite threshold. Not sure why you are stuck
I would try to do the following:
split up the address in multiple words, get rid of punctuation at the same time
check all the words for patterns that are typically written differently and replace them with a common name (e.g. replace apartment, ap., ... by apt, replace Doctor by Dr., ...)
put all the words back in one string alphabetically sorted
compare all the addresses using a fuzzy string comparison algorithm, e.g. Levenshtein
tweak the parameters of the Levenshtein algorithm (e.g. you want to allow more differences on longer strings)
finally do a manual check of the strings
Of course, the solution to keep your data 'in shape' is to have explicit fields for each of your characteristics in your database. Otherwise, you will end up doing this exercise every few months.
The main problem I see here is to exactly define equality.
Even if someone writes Jon. and another Jone. - you will never be able to say if they are the same. (Jon-Jonethan,Joneson,Jonedoe whatever ;)
I work in a firm where we have to handle exact this problem - I'm afraid I have to tell you this kind of checking the adress lists for navigation systems is done "by hand" most of the time. Abbrevations are sometimes context dependend, and there are other things that make this difficult. Ofc replacing string etc is done with python - but telling you the MEANING of such an abbr. can only done by script in a few cases. ("St." -> Can be "Saint" and "Street". How to decide? impossible...this is human work.).
Another big problem is as you said "Is there a street "DJones" or a person? Or both? Which one is ment here? Is this DJones the same as Dr Jones or the same as Don Jones? Its impossible to decide!
You can do some work with lists as presented by another answer here - but it will give you enough "false positives" or so.
You have a postcode field!!!
So, why don't you just buy a postcode table for your country
and use that to clean up your street/town/region/province information?
I did a project like this in the last centuary. Basicly it was a consolidation of two customer files after a merger, and, involved names and addresses from three different sources.
Firstly as many posters have suggested, convert all the common words and abbreveations and spelling mistakes to a common form "Apt." "Apatment" etc. to "Apt".
Then look through the name and identifiy the first letter of the first name, plus the first surname. (Not that easy consider "Dr. Med. Sir Henry de Baskerville Smythe") but dont worry where there are amiguities just take both! So if you lucky you get HBASKERVILLE and HSMYTHE. Now get rid of all the vowels as thats where most spelling variations occur so now you have HBSKRVLL HSMTH.
You would also get these strings from "H. Baskerville","Sir Henry Baskerville Smith" and unfortunately "Harold Smith" but we are talking fuzzy matching here!
Perform a similar exercise on the street, and apartment and postcode fields. But do not throw away the original data!
You now come to the interesting bit first you compare each of the original strings and give say 50 points for each string that matches exactly. Then go through you "normalised" strings and give say 20 points for each one that matches exactly. Then go through all the strings and give say 5 points for each four character or more substring they have in common. For each pair compared you will end up with some with scores > 150 which you can consider as a certain match, some with scores less than 50 which you can consider not matched and some inbetween which have some probability of matching.
You need some more tweaking to improve this by adding various rules like "subtract 20 points for a surname of 'smith'". You really have to keep running and tweaking until you get happy with the resulting matches, but, once you look at the results you get a pretty good feel which score to consider a "match" and which are the false positives you need to get rid of.
I think the amount of data could affect what approach works best for you.
I had a similar problem when indexing music from compilation albums with various artists. Sometimes the artist came first, sometimes the song name, with various separator styles.
What I did was to count the number of occurrences on other entries with the same value to make an educated guess wether it was the song name or an artist.
Perhaps you can use soundex or similar algorithm to find stuff that are similar.
EDIT: (maybe I should clarify that I assumed that artist names were more likely to be more frequently reoccurring than song names.)
One important thing that you mention in the comments is that you are going to do this interactively.
This allows to parse user input and also at the same time validate guesses on any abbreviations and to correct a lot of mistakes (the way for example phone number entry works some contact management systems - the system does the best effort to parse and correct the country code, area code and the number, but ultimately the user is presented with the guess and has the chance to correct the input)
If you want to do it really good then keeping database/dictionaries of postcodes, towns, streets, abbreviations and their variations can improve data validation and pre-processing.
So, at least you would have fully qualified address. If you can do this for all the input you will have all the data categorized and matches can then be strict on certain field and less strict on others, with matching score calculated according weights you assign.
After you have consistently pre-processed the input then n-grams should be able to find similar addresses.
Have you looked at SQL Server Integration Services for this? The Fuzzy Lookup component allows you to find 'Near matches': http://msdn.microsoft.com/en-us/library/ms137786.aspx
For new input, you could call the package from .Net code, passing the value row to be checked as a set of parameters, you'd probably need to persist the token index for this to be fast enough for user interaction though.
There's an example of address matching here: http://msdn.microsoft.com/en-us/magazine/cc163731.aspx
I'm assuming that response time is not critical and that the problem is finding an existing address in a database, not merging duplicates. I'm also assuming the database contains a large number of addresses (say 3 million), rather than a number that could be cleaned up economically by hand or by Amazon's Mechanical Turk.
Pre-computation - Identify address fragments with high information content.
Identify all the unique words used in each database field and count their occurrences.
Eliminate very common words and abbreviations. (Street, st., appt, apt, etc.)
When presented with an input address,
Identify the most unique word and search (Street LIKE '%Jones%') for existing addresses containing those words.
Use the pre-computed statistics to estimate how many addresses will be in the results set
If the estimated results set is too large, select the second-most unique word and combine it in the search (Street LIKE '%Jones%' AND Town LIKE '%Anytown%')
If the estimated results set is too small, select the second-most unique word and combine it in the search (Street LIKE '%Aardvark%' OR Town LIKE '%Anytown')
if the actual results set is too large/small, repeat the query adding further terms as before.
The idea is to find enough fragments with high information content in the address which can be searched for to give a reasonable number of alternatives, rather than to find the most optimal match. For more tolerance to misspelling, trigrams, tetra-grams or soundex codes could be used instead of words.
Obviously if you have lists of actual states / towns / streets then some data clean-up could take place both in the database and in the search address. (I'm very surprised the Armenian postal service does not make such a list available, but I know that some postal services charge excessive amounts for this information. )
As a practical matter, most systems I see in use try to look up people's accounts by their phone number if possible: obviously whether that is a practical solution depends upon the nature of the data and its accuracy.
(Also consider the lateral-thinking approach: could you find a mail-order mail-list broker company which will clean up your database for you? They might even be willing to pay you for use of the addresses.)
I've found a great article.
Adding some dlls as sql user-defined functions we can use string comparison algorithms using SimMetrics library.
Check it
http://anastasiosyal.com/archive/2009/01/11/18.aspx
the possibilities of such variations are countless and even if such an algorithm exists, it can never be fool-proof. u can't have a spell checker for nouns after all.
what you can do is provide a drop-down list of previously entered field values, so that they can select one, if a particular name already exists.
its better to have separate fields for each value like apartments and so on.
You could throw all addresses at a web service like Google Maps (I don't know whether this one is suitable, though) and see whether they come up with identical GPS coordinates.
One method could be to apply the Levenshtein distance algorithm to the address fields. This will allow you to compare the strings for similarity.
Edit
After looking at the kinds of address differences you are dealing with, this may not be helpful after all.
Another idea is to use learning. For example you could learn, for each abbreviation and its place in the sentence, what the abbreviation means.
3 Jane Dr. -> Dr (in 3rd position (or last)) means Drive
Dr. Jones St -> Dr (in 1st position) means Doctor
You could, for example, use decision trees and have a user train the system. Probably few examples of each use would be enough. You wouldn't classify single-letter abbreviations like D.Jones that could be David Jones, or Dr. Jones as likely. But after a first level of translation you could look up a street index of the town and see if you can expand the D. into a street name.
Again, you would run each address through the decision tree before storing it.
It feels like there should be some commercial products doing this out there.
A possibility is to have a dictionary table in the database that maps all the variants to the 'proper' version of the word:
*Value* | *Meaning*
Apt. | Apartment
Ap. | Apartment
St. | Street
Then you run each word through the dictionary before you compare.
Edit: this alone is too naive to be practical (see comment).