Suppose I have the following tables
Owner Table
item_id owner_id
A 1
A 2
B 1
B 2
B 3
I want to find items owned by owner 1 & 2 only i.e. item A, not Item C
What could be a query for this ?
Edit:
If its not obvious, the owner list will be given by user, hence the query should be able to find items of given owner list maintaining the above criteria (i.e. not hardcoded).
At present I am doing it with a query like this
SELECT * FROM items WHERE id = (
SELECT item_id FROM item_owners WHERE owner_id in (:ownerIds)
GROUP BY item_id HAVING COUNT(distinct owner_id) = :ownerCount LIMIT 1
)
Where :ownerIds and :ownerCount are user inputs from ORM, and items is my original table of item to hold other details of item
The question is: is it a correct query ? Will it fail in any scenario ? And is it efficient ?
THIS ANSWERS THE ORIGINAL VERSION OF THE QUESTION.
You can do this with group by and having:
select item_id
from owner_item
group by item_id
having sum(case when owner_id = 1 then 1 else 0 end) > 0 and
sum(case when owner_id = 2 then 1 else 0 end) > 0 and
sum(case when owner_id not in (1, 2) then 1 else 0 end) = 0;
Related
The table 1 is as follows,
ID
FK1_ID
FK2_ID
1
1
1
2
1
2
3
1
3
The table with FK2 is as follows,
ID
Type
Status
1
Type1
True
2
Type2
True
3
Type1
False
The FK2_ID column is the ID column of table 2.
The expected result is, for any FK1_ID(which I have as a list of IDs), need to check all its FK2 entries in the 2nd table of Type1 and status True.
For example:
Here, I want to return YES, if all the Type1 entries are True for the specific FK1_ID. Else NO.
So, for FK1_ID with 1, the FK2 table has 3 records. Of which Type1 has 2 records. I should return YES, if both Type1 records are True, else NO.
I want accomplish this using SQL.
Any help is appreciated?
Looks like you just need to compare a conditional count of Status to the full count, with a CASE for the final result.
SELECT
t1.FK1_ID,
Result = CASE WHEN COUNT(*) = COUNT(CASE WHEN FK2.Status = 'True' THEN 1 END)
THEN 'Yes'
ELSE 'No' END
FROM table1 t1
JOIN FK2 ON FK2.ID = t1.FK2_ID
AND FK2.Type = 'Type1'
GROUP BY
t1.FK1_ID;
A slightly shorter but less understandable version
CASE WHEN COUNT(*) = COUNT(NULLIF(FK2.Status, 'False'))
Alternatively
CASE WHEN COUNT(NULLIF(FK2.Status, 'True')) = 0
I'm not totally following your logic (how these two tables are joined) but sounds like you want to compare a total count with a conditional count so maybe something like
with t as (select type, count(status) as cnt,
sum(case when status ='True' then 1 else 0 end) as truecnt
from FK2
group by type)
select type, case when truecnt > 0 and cnt = truecnt then 'Yes' else 'No' end as MyResult
from t
My requirement is to get id for missing status from SQL table. I will get a list of status for each id, say A,B,C,D. In a scenario, I have to check status B exists or not. Table gets updated everyday and each time new Id will be created
Conditions,
If status A exists and other statuses such as C and D does not
exists, then don't need to get id.
If status A and B exists and other statuses such as C or D does not exists, then don't need to get id .
If status A exists and B not exists, other
statuses such as C or D exists, then I should get the id of that
record
If status A and B exists, other
statuses such as C or D exists (all status exists), then I don't need to get the id of that
record
Table1:
Id StatusCode
1 A
1 C
2 A
2 B
2 C
3 A
3 C
3 D
How do I get Id 1 and 3 using SQL query?, Seems simple but as I am new to SQL I could not able to get it in SQL.
select statement in this screenshot works fine when there is only one id, it fails on multiple id. I tried many other way, but no use
Try this
SELECT DISTINCT ID
FROM T1
WHERE Statuscode = 'A' AND ID NOT IN (SELECT ID FROM T1 WHERE Statuscode = 'B' )
AND (ID IN (SELECT ID FROM T1 WHERE Statuscode = 'C' ) OR ID IN (SELECT ID FROM T1 WHERE Statuscode = 'D' ))
FIDDLE DEMO
Also, To correct Gordon Linoff's answer, we need to add one more where criteria there
SELECT Id
FROM T1
GROUP BY Id
HAVING SUM(CASE WHEN Statuscode = 'A' THEN 1 ELSE 0 END) > 0 AND
SUM(CASE WHEN Statuscode = 'B' THEN 1 ELSE 0 END) = 0 AND
SUM(CASE WHEN Statuscode IN ('C', 'D') THEN 1 ELSE 0 END) > 0;
FIDDLE DEMO
This answers the original version of the question.
I think you can use aggregation:
select id
from t
group by id
having sum(case when status = 'A' then 1 else 0 end) > 0 and
sum(case when status in ('C', 'D') then 1 else 0 end) > 0;
SELECT id
FROM t
GROUP BY
Id
HAVING MAX(status) = CHAR(64 + COUNT(*))
--char(64+1) = A, char(64+2) = B etc
The logic behind this is that it will take all count the same types of id. So if you have 3 rows you will need abc. If you have an id with 4 rows you will have ABCD. Generally the max status should always be the same as the number of rows.
This is true of course if you have no duplicate between id and status code.
select distinct id from t where t.statuscode = 'C' or t.statuscode = 'D' group by t.id
I want to write an SQL query to find records which contain a particular column and from that subset want to find records which doesn't contain a some other value. How do you write a query for that?
cid id2 attribute
--------------------------------
1 100 delete
1 100 payment
1 100 void
2 100 delete
2 102 payment
2 102 void
3 102 delete
3 103 payment
In above example, I want to list cid for which payment and delete attributes exist but void attribute doesn't exist. So it should list out 3 from above example because it doesn't have void attribute.
Forgot to mention that there could be more attributes. However, I need to list out records for which delete and payment exist regardless of other attributes but void doesn’t.
I call this a "set-within-sets" query, because you are looking for particular sets of attributes within each cid.
I would express this with group by and conditions in the having:
select cid
from t
group by cid
having sum(case when attribute = 'payment' then 1 else 0 end) > 0 and
sum(case when attribute = 'delete' then 1 else 0 end) > 0 and
sum(case when attribute = 'void' then 1 else 0 end) = 0 ;
In some databases, you can simplify this with string aggregation -- assuming there are no duplicate attributes for cids. For instance, using the MySQL function:
select cid
from t
where attribute in ('payment', 'delete' 'void')
group by cid
having group_concat(attribute order by attribute) = 'delete,payment';
You can use conditional aggregation:
select cid
from tablename
where attribute in ('delete', 'payment', 'void')
group by cid
having
count(distinct attribute) = 2
and
sum(
case attribute
when 'void' then 1
else 0
end
) = 0
If there are not more attributes than these 3, then you can omit the WHERE clause.
See the demo.
Results:
| cid |
| --- |
| 3 |
I'm assuming that there are only three attributes, so the logic behind this query is:
First COUNT the number of attributes GROUP BY cid, and then LEFT JOIN the original table ON attribute is void. You should grab cid that has exactly 2 attributes and no void.
The original table is named as temp:
SELECT
subq2.result_cid
FROM (
SELECT
*
FROM (
SELECT
T.cid AS result_cid,
COUNT(T.attribute) AS count
FROM
temp AS T
GROUP BY
T.cid
) AS subq
LEFT OUTER JOIN temp AS T2 ON subq.result_cid = T2.cid AND T2.attribute = 'void'
) AS subq2
WHERE subq2.count = 2 AND subq2.id2 IS NULL
use corelated subquery by using not exists
select t1.* from tablename t1
where not exists( select 1 from tablename t2
where t1.cid=t2.cid and attribute='void'
)
and exists ( select 1 from tablename t2
where t1.cid=t2.cid
having count(distinct attribute)=2
)
and attribute in ('payment','delete')
demo online
I have a product table and every product might be delivered, idle, shipping, preparing.
I want to show a list with the counts of products for each state, and I can see how to query for that here:
How to get multiple counts with one SQL query?
However, what does this query return, and how do I assign the return value to lets say, 4 integers, called deliveredCount, idleCount, shippingCount, preparingCount?
PS: For the record, I am using SQLite with OrmLite in Android with JAVA
EDIT: In this SO question people explain what Query to do when you want to get multiple counts, but they don't tell us what does that query return and in what format. For example:
SELECT a.distributor_id,
(SELECT COUNT(*) FROM myTable WHERE level='personal' and distributor_id = a.distributor_id) as PersonalCount,
(SELECT COUNT(*) FROM myTable WHERE level='exec' and distributor_id = a.distributor_id) as ExecCount,
(SELECT COUNT(*) FROM myTable WHERE distributor_id = a.distributor_id) as TotalCount
FROM myTable a ;
What is the return type of this and what is the format?
PS2: Someone was really quick to downvote my question because it lacked sufficient information. Then I edited it, but the downvote still remains :(
Hard to say for sure but sounds like you need to use a version of the top answer in the link you have provided.
Something like;
SELECT ProductID,
COUNT(*) AS Total,
SUM(CASE WHEN pStatus = 'delivered' THEN 1 ELSE 0 END) DeliveredCount,
SUM(CASE WHEN pStatus = 'idle' THEN 1 ELSE 0 END) IdleCount,
SUM(CASE WHEN pStatus = 'shipping' THEN 1 ELSE 0 END) ShippingCount,
SUM(CASE WHEN pStatus = 'preparing' THEN 1 ELSE 0 END) PreparingCount
FROM ProductTable
GROUP BY ProductID
This will return something like;
ProductID | DeliveredCount | IdleCount | ...
1 | 250 | 3250 | ...
You might want to try this.
SELECT
SUM(CASE WHEN Prod = 'delivered' THEN 1 ELSE 0 END) as deliveredCount,
SUM(CASE WHEN Prod = 'idle' THEN 1 ELSE 0 END) as idleCount,
SUM(CASE WHEN Prod = 'shipping' THEN 1 ELSE 0 END) as shippingCount,
SUM(CASE WHEN Prod = 'preparing' THEN 1 ELSE 0 END) as preparingCount
FROM Product
select
concat(state, "Count"),
count(*)
from product
group by state
Which would return 4 rows (assuming four unique values of state):
fooCount | 15
etc
Quick one,
I have a table, with the following structure
id lid taken
1 1 0
1 1 0
1 1 1
1 1 1
1 2 1
Pretty simply so far right?
I need to query the taken/available from the lid of 1, which should return
taken available
2 2
I know I can simply do two counts and join them, but is there a more proficient way of doing this rather than two separate queries?
I was looking at the following type of format, but I can not for the life of me get it executed in SQL...
SELECT
COUNT(case taken=1) AS taken,
COUNT(case taken=0) AS available FROM table
WHERE
lid=1
Thank you SO much.
You can do this:
SELECT taken, COUNT(*) AS count
FROM table
WHERE lid = 1
GROUP BY taken
This will return two rows:
taken count
0 2
1 2
Each count corresponds to how many times that particular taken value was seen.
Your query is correct just needs juggling a bit:
SELECT
SUM(case taken WHEN 1 THEN 1 ELSE 0 END) AS taken,
SUM(case taken WHEN 1 THEN 0 ELSE 1 END) AS available FROM table
WHERE
lid=1
Alternatively you could do:
SELECT
SUM(taken) AS taken,
COUNT(id) - SUM(taken) AS available
FROM table
WHERE
lid=1
SELECT
SUM(case WHEN taken=1 THEN 1 ELSE 0 END) AS taken,
SUM(case WHEN taken=0 THEN 1 ELSE 0 END) AS available
FROM table
WHERE lid=1
Weird application of CTE's:
WITH lid AS (
SELECT DISTINCT lid FROM taken
)
, tak AS (
SELECT lid,taken , COUNT(*) AS cnt
FROM taken t0
GROUP BY lid,taken
)
SELECT l.lid
, COALESCE(a0.cnt, 0) AS available
, COALESCE(a1.cnt, 0) AS taken
FROM lid l
LEFT JOIN tak a0 ON a0.lid=l.lid AND a0.taken = 0
LEFT JOIN tak a1 ON a1.lid=l.lid AND a1.taken = 1
WHERE l.lid=1
;