I have two tables Tbl_Event (primary key:-EventID) and tbl_items.
tbl_items table contains multiple items for same EventID with status 0 or 1.
Sample Data:
Tbl_event:
EventId Name
5 Test
6 Seminar
7 Meet
tbl_items
ItemId EventId status
1 5 0
2 6 1
2 6 0
3 7 1
3 7 1
I just need to get Event "Meet" having both status value 1.
This is what I tried:
SELECT *
FROM Tbl_items L
INNER JOIN Tbl_Events E ON L.EventId = E.EventId
WHERE L.Eventid NOT IN (SELECT Eventid FROM TBL_VMS_LENT_ITEMS WHERE Status = 0)
One approach is to use a subquery which aggregates over events and checks that all statuses are 1:
WITH cte AS (
SELECT EventId
FROM tbl_items
GROUP BY EventId
HAVING SUM(CASE WHEN status <> 1 THEN 1 ELSE 0 END) = 0
)
SELECT t1.*
FROM Tbl_event t1
INNER JOIN cte t2
ON t1.EventId = t2.EventId;
If you just want the event IDs, use SELECT * FROM cte, otherwise use the full query I gave immediately above. This approach will generalize to more complex logic, should you need it later.
This will give you all events that have all items with status 1.
SELECT
E.EventID
FROM
Tbl_event AS E
INNER JOIN tbl_items AS I ON E.EventID = I.EventID
GROUP BY
E.EventID
HAVING
MIN(I.status) = 1
If you want the full Event record:
;WITH EventsWithItemsStatus1 AS
(
SELECT
E.EventID
FROM
Tbl_event AS E
INNER JOIN tbl_items AS I ON E.EventID = I.EventID
GROUP BY
E.EventID
HAVING
MIN(I.status) = 1
)
SELECT
E.*
FROM
Tbl_event AS E
INNER JOIN EventsWithItemsStatus1 AS N ON E.EventID = N.EventID
Use group by clause with subquery
select * from Tbl_event e
inner join (
select EventId
from tbl_items
where status = 1
group by EventId
having count(*) > 1
) i on i.EventId = e.EventId
Question is not very clear
SELECT min(L.ItemId), L.EventId
FROM Tbl_items L
where L.Status = 1
group by L.EventId
having count(*) > 1
Related
Hi I tried to build sql query to find id when is in 2 records (can be more). Let me explained by example
I have 2 tables
C
id
type_id
1
499
1
599
D
type_id
type_name
499
AN
599
DE
And I want to get id which has AN and DE
SELECT *
FROM C
INNER JOIN D
ON D.type_id = C.type_id
WHERE
EXISTS (SELECT 1 FROM D D1 WHERE D1.type_id = C.type_id AND D1.type_name = 'AN') AND
EXISTS (SELECT 1 FROM D D2 WHERE D2.type_id = C.type_id AND D2.type_name = 'DE');
But did not work .Than you for help
If you want all the data from the join then you can use analytic functions:
SELECT id,
type_id,
type_name
FROM (
SELECT c.id,
c.type_id,
d.type_name,
COUNT(CASE d.type_name WHEN 'AN' THEN 1 END) OVER (PARTITION BY c.id)
AS num_an,
COUNT(CASE d.type_name WHEN 'DE' THEN 1 END) OVER (PARTITION BY c.id)
AS num_de
FROM C
INNER JOIN D
ON D.type_id = C.type_id
WHERE d.type_name IN ('AN', 'DE')
)
WHERE num_an > 0
AND num_de > 0;
Which outputs:
ID
TYPE_ID
TYPE_NAME
1
599
DE
1
499
AN
If you just want the id then you can aggregate and use a HAVING clause:
SELECT c.id
FROM C
INNER JOIN D
ON D.type_id = C.type_id
WHERE d.type_name IN ('AN', 'DE')
GROUP BY c.id
HAVING COUNT(CASE d.type_name WHEN 'AN' THEN 1 END) > 0
AND COUNT(CASE d.type_name WHEN 'DE' THEN 1 END) > 0
Which outputs:
ID
1
fiddle
Get the distinct counts of type_name for each ID ensure count = two and limit type_name to 'AN' or 'DE'
SELECT C.ID
FROM C
INNER JOIN D
on C.type_id=D.type_id -- standard join on Type_ID
WHERE D.Type_name in ('AN','DE') -- limit records to only AN/DE since we need both.
GROUP BY C.ID -- group so we get just 1 ID
HAVING Count(Distinct Type_name) = 2 -- ensure distinct count is 2 for each C.ID.
We join the two tables
We limit to ID having either an 'AN' or DE type name
We group by ID's
We count the distinct types for each ID and if it's 2, we know we have an AN and DE type for that ID.
Count distinct is used since I'm unsure if a type_name could be duplicated for a C.ID. It looks possible given table structure. but unsure without known Pk/FK relations. distinct "Might" be able to be removed if we KNOW it's not possible.
I have two tables and I wanna join them (outer).
day description
-----
1 mo
2 tu
...
5 fr
order day code
----
1 1 0
2 2 0
3 1 2
4 3 0
5 4 0
I wanna this table as a result:
description order code
------
mo 1 0
th 2 0
we 4 0
tu 5 0
fr null null
When I use a left join like this, the code does not work right and does not show me friday:
select *
from days d left join order o on d.id= o.day
where o.code = 0
But when I write the code like this, the code works right:
select *
from
(select * from day) d
left join
(select * from order when code = 0) o
on d.id = o.day
Does anyone know why?
Just put the condition on the left joined table in the on clause of the left join rather than in the where clause:
select d.description, o.order, o.code
from days d
left join order o on d.id= o.day and o.code = 0
Conditions in the where clause are mandatory - so the where clause eliminates rows where the left join came back empty, since o.code is null, which is not equal to 0.
on condition is used to join the table.
where condition is to filter the records from the join result.
Below will join the table on the condition of d.id = o.day
and then select records only with o.code=0
select *
from days d left join order o on d.id= o.day
where o.code = 0
In order to join on both d.id = o.day and o.code=0
you need below
select *
from days d left join order o on d.id= o.day
and o.code = 0
I have this query that generates about 40,000 records and the execution time of this query is about 1 minute 30 seconds.
SELECT DISTINCT
a.ID,
a.NAME,
a.DIV,
a.UID,
(select NAME from EMPLOYEE where UID= a.UID and UID<>'') as boss_id,
(select DATE(MAX(create_time)) from XYZ where XYZ_ID= 1 and id = a.ID) as TERM1,
(select DATE(MAX(create_time)) from XYZ where XYZ_ID= 2 and id = a.ID) as TERM2,
(select DATE(MAX(create_time)) from XYZ where XYZ_ID= 3 and id = a.ID) as TERM3,
(select DATE(MAX(create_time)) from XYZ where XYZ_ID= 4 and id = a.ID) as TERM4,
(select DATE(MAX(create_time)) from XYZ where XYZ_ID= 5 and id = a.ID) as TERM5,
(select DATE(MAX(create_time)) from XYZ where XYZ_ID= 6 and id = a.ID) as TERM6,
(select DATE(MAX(create_time)) from XYZ where XYZ_ID= 7 and id = a.ID) as TERM7,
(select DATE(MAX(create_time)) from XYZ where XYZ_ID= 8 and id = a.ID) as TERM8
FROM EMPLOYEE a
WHERE ID LIKE 'D%'
I tried using group by, different kinds of join to improve the execution time but couldn't succeed.Both the tables ABC and XYZ are indexed.
Also, I think that the root cause of this problem is either the DISTINCT keyword or the MAX function.
How can I optimize the above query to bring down the execution time to at least less than a minute?
Any help is appreciated.
Query is not tested, this is just an idea on how you could get this done in two different ways.
(SQL Server solutions here)
Using LEFT JOIN for each ID should look something like this:
SELECT a.ID,
a.NAME,
a.DIV,
a.UID,
b.Name as boss_id,
MAX(xyz1.create_time) as TERM1,
MAX(xyz2.create_time) as TERM2,
MAX(xyz3.create_time) as TERM3,
MAX(xyz4.create_time) as TERM4,
MAX(xyz5.create_time) as TERM5,
MAX(xyz6.create_time) as TERM6,
MAX(xyz7.create_time) as TERM7,
MAX(xyz8.create_time) as TERM8
FROM EMPLOYEE a
JOIN EMPLOYEE b on a.UID = b.UID and b.UID <> ''
LEFT JOIN XYZ xyz1 on a.ID = xyz1.ID and xyz1.XYZ_ID = 1
LEFT JOIN XYZ xyz2 on a.ID = xyz2.ID and xyz1.XYZ_ID = 2
LEFT JOIN XYZ xyz3 on a.ID = xyz3.ID and xyz1.XYZ_ID = 3
LEFT JOIN XYZ xyz4 on a.ID = xyz4.ID and xyz1.XYZ_ID = 4
LEFT JOIN XYZ xyz5 on a.ID = xyz5.ID and xyz1.XYZ_ID = 5
LEFT JOIN XYZ xyz6 on a.ID = xyz6.ID and xyz1.XYZ_ID = 6
LEFT JOIN XYZ xyz7 on a.ID = xyz7.ID and xyz1.XYZ_ID = 7
LEFT JOIN XYZ xyz8 on a.ID = xyz8.ID and xyz1.XYZ_ID = 8
WHERE a.ID LIKE 'D%'
GROUP BY a.ID, a.NAME, a.DIV, a.UID, b.Name
Using PIVOT would look something like this:
select * from (
SELECT DISTINCT
a.ID,
a.NAME,
a.DIV,
a.UID,
b.NAME as boss_id,
xyz.xyz_id,
xyz.create_time
FROM EMPLOYEE a
JOIN EMPLOYEE b on a.UID = b.UID and b.UID <> ''
LEFT JOIN (SELECT DATE(MAX(create_time)) create_time, XYZ_ID, ID
from XYZ
where XYZ_ID between 1 and 8
group by XYZ_ID, ID) xyz on a.ID = xyz1.ID
WHERE a.ID LIKE 'D%') src
PIVOT (
max(create_time) for xyz_id IN (['1'], ['2'], ['3'], ['4'],
['5'], ['6'], ['7'], ['8'])
) PIV
Give it a shot
I would recommend group by and conditional aggregation:
SELECT e.ID, e.NAME, e.DIV, e.UID,
DATE(MAX(CASE WHEN XYZ_ID = 1 THEN create_time END)) as term1,
DATE(MAX(CASE WHEN XYZ_ID = 2 THEN create_time END)) as term2,
DATE(MAX(CASE WHEN XYZ_ID = 3 THEN create_time END)) as term3,
DATE(MAX(CASE WHEN XYZ_ID = 4 THEN create_time END)) as term4,
DATE(MAX(CASE WHEN XYZ_ID = 5 THEN create_time END)) as term5,
DATE(MAX(CASE WHEN XYZ_ID = 6 THEN create_time END)) as term6,
DATE(MAX(CASE WHEN XYZ_ID = 7 THEN create_time END)) as term7,
DATE(MAX(CASE WHEN XYZ_ID = 8 THEN create_time END)) as term8
FROM EMPLOYEE e LEFT JOIN
XYZ
ON xyz.ID = e.id
WHERE e.ID LIKE 'D%'
GROUP BY e.ID, e.NAME, e.DIV, e.UID;
I don't understand the logic for boss_id, so I left that out. This should improve the performance significantly.
I have 3 tables:
Emp (Id(PK), Name)
Address (AddressId(PK), AddressType)
EmpAddress (EmpId(FK), AddresId(FK))
One employee may have multiple address.
Sample data:
Emp
1 abc
2 pqr
Address
1 a
2 b
3 c
EmpAddress
1 1
1 2
1 3
Here empid 1 has all 3 addresses.
I want the only one address at a time based on availability.
If adresstype a is available then display only a
If adresstype c is available then display only c
If adresstype b is available then display only b
Priority is a->c->b
If only one available then display that without any Priority .
I wrote this query, but it is not working:
select *
from Emp
inner join EmpAddress on Emp.Id = .EmpAddress .Emp
inner join Address on Address.Id = EmpAddress.Address_Id
where AddressType is NOT NULL
and AddressType = case
when AddressType = 'a' then 'a'
when AddressType = 'c' then 'c'
when AddressType = 'b' then 'b'
end
One approach would be to use ROW_NUMBER() to assign a numerical priority to each address type based on the ordering a > c > b. Then, subquery to retain only the highest ranking address for each employee.
SELECT Id, Emp, AddressType
FROM
(
SELECT e.Id, ea.Emp, a.AddressType,
ROW_NUMBER() OVER (PARTITION BY e.Id
ORDER BY CASE WHEN a.AddressType = 'a' THEN 1
WHEN a.AddressType = 'b' THEN 2
WHEN a.AddressType = 'c' THEN 3 END) rn
FROM Emp e
INNER JOIN EmpAddress ea
ON e.Id = ea.Emp
INNER JOIN Address a
ON a.Id = ea.Address_Id
) t
WHERE t.rn = 1;
select *
from Emp e
cross apply
(
select top 1 ea.AddresId, a.AddressType
from EmpAddress ea
inner join Address a on ea.AddresId = a.AddresId
where ea.EmpId = e.Id
order by case a.AddressType
when 'a' then 1
when 'c' then 2
when 'b' then 3
end
) a
You could also retrieve the records based on Priority via TOP(1) with TIES
SELECT
TOP(1) with TIES e.Id, *
FROM Emp e
INNER JOIN EmpAddress ea ON e.Id = ea.Emp
INNER JOIN Address a ON a.Id = ea.Address_Id
ORDER BY ROW_NUMBER() OVER (PARTITION BY e.Id ORDER BY
CASE (a.AddressType) WHEN 'a' THEN 1
WHEN 'c' THEN 2 WHEN 'b' THEN 3 END)
When trying to get a count of IDs I get a different answer when grouping by day vs when I am not.
select cv.CONV_DAY, count(distinct cv.CLICK_ID)
from
clickcache.click cc
right join(
select distinct cv.CLICK_ID, cv.CONV_DAY, cv.PIXEL_ID
from clickcache.CONVERSION cv
where cv.CLICK_ID IS NOT NULL) cv ON cv.CLICK_ID = cc.ID
where cc.ADV_ACCOUNT_ID = 25176
and cv.CONV_DAY between '2016-8-01' AND '2016-08-07'
and AMP_CLICK_STATUS_ID = 1
AND pixel_id IN
(SELECT DISTINCT conversion_pixel_id
FROM
ampx.campaign_event_funnel ef
JOIN ampx.campaign cp ON
cp.id = ef.campaign_id
AND cp.campaign_status_id = 1
WHERE
ef.account_id IN(25176)
AND include_optimization = 1 )
group by 1
order by 1 asc
This yields 170 which is the correct answer and the I want. This, on the other hand, displays 157.
select count(distinct cv.CLICK_ID)
from
clickcache.click cc
right join(
select distinct cv.CLICK_ID, cv.CONV_DAY, cv.PIXEL_ID
from clickcache.CONVERSION cv
where cv.CLICK_ID IS NOT NULL) cv ON cv.CLICK_ID = cc.ID
where cc.ADV_ACCOUNT_ID = 25176
and cv.CONV_DAY between '2016-8-01' AND '2016-08-07'
and AMP_CLICK_STATUS_ID = 1
AND pixel_id IN
(SELECT DISTINCT conversion_pixel_id
FROM
ampx.campaign_event_funnel ef
JOIN ampx.campaign cp ON
cp.id = ef.campaign_id
AND cp.campaign_status_id = 1
WHERE
ef.account_id IN(25176)
AND include_optimization = 1 )
My question is why do I get this discrepancy and how to fix it to get a proper count?
Thank you!
Your count dependents from right query, maybe you have duplicate row?
example
table1
id name value
1 2 3
table2
id name value
1 4 5
2 6 3
1 6 3
right join tables on value get result
select * from table1 a right join table2 b on a.value = b.value
1 2 3 2 6 3
1 2 3 1 6 3
select count(distinct a.value)
from (select a.id, a.name, a.value, b.id, b.name, b.value
from table1 a right join table2 b on a.value = b.value)
result is 1
select b.id, count(distinct a.value)
from (select a.id, a.name, a.value, b.id, b.name, b.value
from table1 a right join table2 b on a.value = b.value group)
group by b.id
result is two rows
2 1
1 1
My guess is that, you have a problem for this reason.