I have table like this called, table test:
+------------------------+--------+
| id_laporan_rekomendasi | status |
+------------------------+--------+
| 1 | 2 |
| 1 | 2 |
| 1 | 2 |
| 1 | 3 |
| 2 | 2 |
| 2 | 2 |
| 2 | 2 |
| 2 | 3 |
| 3 | 2 |
| 3 | 3 |
| 4 | 2 |
| 5 | 2 |
| 5 | 3 |
| 6 | 2 |
+------------------------+--------+
I want to group by id_laporan_rekomendasi and make a new column when in column status there is value 3. so if there is no value 3 in column status, then the value would be 0, but if there is value 3 than 1.
I expect the result would be like this
+------------------------+------+
| id_laporan_rekomendasi | test |
+------------------------+------+
| 1 | 1 |
| 2 | 1 |
| 3 | 1 |
| 4 | 0 |
| 5 | 1 |
| 6 | 0 |
+------------------------+------+
I have tried this query
SELECT t1.id_laporan_rekomendasi,
COUNT(distinct case when t1.status = 3 then 1 else 0 end) as test
FROM test t1
GROUP BY t1.id_laporan_rekomendasi
But i got the result like below
+------------------------+------+
| id_laporan_rekomendasi | test |
+------------------------+------+
| 1 | 2 |
| 2 | 2 |
| 3 | 2 |
| 4 | 1 |
| 5 | 2 |
| 6 | 1 |
+------------------------+------+
Does anyone could help me with this table ?
You are close. In MariaDB, you can simplify this to:
SELECT t1.id_laporan_rekomendasi,
MAX( t1.status = 3 ) as test
FROM test t1
GROUP BY t1.id_laporan_rekomendasi;
MariaDB (and MySQL) treat boolean expressions as numbers, with "1" for true and "0" for false. So this does what you want.
Related
While going through SQL columns, if we find text match "NEW" in Calc column, update the incrementing a count starting with 1 in Results column.
It should look like this on the output:
The following uses an id column to resolve the order issue. Replace that with your corresponding expression. This also addresses the requirement to start the display sequence with 1 and also show 0 for the 'NEW' rows.
The SQL (updated):
SELECT logs.*
, CASE WHEN text = 'NEW' THEN 0
ELSE
COALESCE(SUM(CASE WHEN text = 'NEW' THEN 1 END) OVER (PARTITION BY xrank ORDER BY id)+1, 1)
END AS display
FROM logs
ORDER BY id
The result:
+----+-------+------+---------+
| id | xrank | text | display |
+----+-------+------+---------+
| 1 | 1 | A | 1 |
| 2 | 1 | B | 1 |
| 3 | 1 | C | 1 |
| 4 | 1 | NEW | 0 |
| 5 | 1 | D | 2 |
| 6 | 1 | Q | 2 |
| 7 | 1 | B | 2 |
| 8 | 1 | NEW | 0 |
| 9 | 1 | D | 3 |
| 10 | 1 | Z | 3 |
| 11 | 2 | A | 1 |
| 12 | 2 | B | 1 |
| 13 | 2 | C | 1 |
| 14 | 2 | NEW | 0 |
| 15 | 2 | D | 2 |
| 16 | 2 | Q | 2 |
| 17 | 2 | B | 2 |
| 18 | 2 | NEW | 0 |
| 19 | 2 | D | 3 |
| 20 | 2 | Z | 3 |
+----+-------+------+---------+
You need a column that specifies the ordering for the table. With that, just use a cumulative sum:
select t.*,
1 + sum(case when Calc = 'NEW' then 1 else 0 end) over (partition by Rank_Id order by Seq) as display
from t;
I need to create a new column that restarts at every 0 value of Column Repeated Call of each Customer_ID:
+-------------+---------+----------------------+---------------+
| Customer_ID | Call_ID | Days Since Last Call | Repeated Call |
+-------------+---------+----------------------+---------------+
| 1 | 1 | Null | 0 |
| 1 | 2 | 45 | 0 |
| 1 | 3 | 0 | 1 |
| 1 | 4 | 0 | 1 |
| 1 | 5 | 0 | 1 |
| 1 | 6 | 48 | 0 |
| 1 | 7 | 1 | 1 |
| 2 | 8 | Null | 0 |
| 2 | 9 | 1 | 1 |
+-------------+---------+----------------------+---------------+
In to something like this:
+-------------+---------+----------------------+---------------+-------------+
| Customer_ID | Call_ID | Days Since Last Call | Repeated Call | Order_Group |
+-------------+---------+----------------------+---------------+-------------+
| 1 | 1 | Null | 0 | 1 |
| 1 | 2 | 45 | 0 | 2 |
| 1 | 3 | 0 | 1 | 2 |
| 1 | 4 | 0 | 1 | 2 |
| 1 | 5 | 0 | 1 | 2 |
| 1 | 6 | 48 | 0 | 3 |
| 1 | 7 | 1 | 1 | 3 |
| 2 | 8 | Null | 0 | 1 |
| 2 | 9 | 1 | 1 | 1 |
+-------------+---------+----------------------+---------------+-------------+
Appreciate your suggestion, thanks!
You can use SUM() window function:
select t.*,
sum(case when Repeated_Call = 0 then 1 else 0 end)
over (partition by Customer_ID order by Call_Id) Order_Group
from tablename t
See the demo (for MySql but it is standard SQL).
Results:
| Customer_ID | Call_ID | Days Since Last Call | Repeated_Call | Order_Group |
| ----------- | ------- | -------------------- | ------------- | ----------- |
| 1 | 1 | | 0 | 1 |
| 1 | 2 | 45 | 0 | 2 |
| 1 | 3 | 0 | 1 | 2 |
| 1 | 4 | 0 | 1 | 2 |
| 1 | 5 | 0 | 1 | 2 |
| 1 | 6 | 48 | 0 | 3 |
| 1 | 7 | 1 | 1 | 3 |
| 2 | 8 | | 0 | 1 |
| 2 | 9 | 1 | 1 | 1 |
You can calculation every 0 value in column Repeated Call (for each customer) using window analytic function COUNT with ROWS UNBOUNDED PRECEDING:
SELECT *,
COUNT(CASE WHEN Repeated Call=0 THEN 1 ELSE NULL END )OVER(PARTITION BY Customer_ID
ORDER BY Call_ID ROWS UNBOUNDED PRECEDING)Order_Gr FROM Table
So I have an accounts table in witch row may or may not have a parent account (0 means it doesn't have a parent):
+----+-----------+
| id | parent_id |
+----+-----------+
| 1 | 2 |
| 2 | 0 |
| 3 | 1 |
| 4 | 3 |
| 5 | 4 |
+----+-----------+
I was trying to add the top 3 parents for each row, so I would get something like this:
+----+-----------+----------+----------+----------+
| id | parent_id | parent_1 | parent_2 | parent_3 |
+----+-----------+----------+----------+----------+
| 1 | 2 | 2 | null | null |
| 2 | 0 | null | null | null |
| 3 | 1 | 2 | 1 | null |
| 4 | 3 | 2 | 1 | 3 |
| 5 | 4 | 2 | 1 | 3 |
+----+-----------+----------+----------+----------+
I figured I can do it with recursive queries, but I haven't managed to build a working query.
Any help would be appreciated.
I want to select from a table if row counts of similar filed is maximum depends on other columns.
As example
| user_id | team_id | isOk |
| 1 | 1 | 1 |
| 2 | 1 | 1 |
| 3 | 1 | 1 |
| 4 | 1 | 1 |
| 5 | 2 | 1 |
| 6 | 2 | 1 |
| 7 | 2 | 1 |
| 8 | 3 | 1 |
| 9 | 3 | 1 |
| 10 | 3 | 1 |
| 11 | 3 | 0 |
So i want to select team 1 and 2 because they all have 1 value at isOk Column,
i tried to use this query
SELECT Team
FROM _Table1
WHERE isOk= 1
GROUP BY Team
HAVING COUNT(*) > 3
But still i have to define a row count which can be maximum or not.
Thanks in advance.
Is this what you are looking for?
select team
from _table1
group by team
having min(isOk) = 1;
i have table like this:
| ID | id_number | a | b |
| 1 | 1 | 0 | 215 |
| 2 | 2 | 28 | 8952 |
| 3 | 3 | 10 | 2000 |
| 4 | 1 | 0 | 215 |
| 5 | 1 | 0 |10000 |
| 6 | 3 | 10 | 5000 |
| 7 | 2 | 3 |90933 |
I want to sum a*b where id_number is same, what the query to get all value for every id_number? for example the result is like this :
| ID | id_number | result |
| 1 | 1 | 0 |
| 2 | 2 | 523455 |
| 3 | 3 | 70000 |
This is a simple aggregation query:
select id_number, sum(a*b)
from t
group by id_number
I'm not sure what the first column is for.