Simple question. Say I have a table with two columns, PersonID and CardID and 10 rows. I have another Table that contains 1 column, Code and 10 rows. I simply want to stack the codes to the other table. Note that is does not matter which person gets which code, they should all just get one.
At the moment I find myself adding rownumbers in both tables and updating were TableA.ID = TableB.ID. But this seems overly complex for such a simple taks.
Any suggestions?
TableA
PersonID CardID
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
10 10
Table B
Code
Random1
Random2
Random3
Random4
Random5
Random6
Random7
Random8
Random9
Random10
Desired Result:
PersonID CardID Code
1 1 Random1
2 2 Random2
3 3 Random3
4 4 Random4
5 5 Random5
6 6 Random6
7 7 Random7
8 8 Random8
9 9 Random9
10 10 Random10
Again, code order does not matter. Each person, one code. That's it.
You need not to append 1 extra column to each row, You can use CTE with RowNum like :
;WITH CTE_Results
AS (
SELECT ROW_NUMBER() OVER (ORDER BY Code) as ID, Code
from TableB B
)
select A.PersonId, A.CardID, CTE_Results.Code from CTE_Results
INNER JOIN TableA A ON A.PersonId= CTE_Results.ID
Working SQL Fiddle is : http://sqlfiddle.com/#!18/f8f86/9
Result will be like :
PersonId CardID Code
1 1 Random1
2 2 Random10
3 3 Random2
4 4 Random3
5 5 Random4
6 6 Random5
7 7 Random6
8 8 Random7
9 9 Random8
10 10 Random9
Related
I'm trying to prepare my data to create a burndown visual. As you can see the Rate column isn't simply A - B, as it carries forward the previous value if B is null.
I've tried some case statements using lag and sums but no avail.
Some direction on the case statement or an optimal solution would be ideal.
For example, this is how my data looks:
ID
A
B
1
20
NULL
2
20
3
3
20
NULL
4
20
7
5
20
NULL
6
20
NULL
7
20
NULL
8
20
5
9
20
7
And I want a rate column that looks like this.
ID
A
B
Rate
1
20
NULL
20
2
20
3
17
3
20
NULL
17
4
20
7
10
5
20
NULL
10
6
20
NULL
10
7
20
NULL
10
8
20
5
5
9
20
7
-2
Thanks to #Larnu for the guidance.
Here is the solution when you have your data partitioned by some group ID and ordered by some data or row ID.
SELECT
GROUP_ID,
ROW_ID,
COL_A,
COL_B,
COL_A - (SUM(ISNULL(COL_B,0)) OVER (PARTITION BY GROUP_ID ORDER BY ROW_ID ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW))
FROM table
I'm studying SQL and somehow I'm stuck with a question. I have 2 tables ('users' and 'follows').
Follows Table
user_id
follows
date
1
2
1993-09-01
2
1
1989-01-01
3
1
1993-07-01
2
3
1994-10-10
3
2
1995-03-01
4
2
1988-08-08
4
1
1988-08-08
1
4
1994-04-02
1
5
2000-01-01
5
1
2000-01-02
5
6
1986-01-10
7
1
1990-02-02
1
7
1996-10-01
1
8
1993-09-03
8
1
1995-09-01
8
9
1995-09-01
9
8
1996-01-10
7
8
1993-09-01
3
9
1996-05-30
4
9
1996-05-30
Users Table
user_id
first_name
last_name
school
1
Harry
Potter
Gryffindor
2
Ron
Wesley
Gryffindor
3
Hermonie
Granger
Gryffindor
4
Ginny
Weasley
Gryffindor
5
Draco
Malfoy
Slytherin
6
Tom
Riddle
Slytherin
7
Luna
Lovegood
Ravenclaw
8
Cho
Chang
Ravenclaw
9
Cedric
Diggory
Hufflepuff
I need to list all rows from follows where someone from one house follows someone from a different house. I tried to make 2 queries, one to get all houses related to follows.user_id and another one with all houses related to follows.follows and "merge" then:
select a.nome_id, a.user_id_house, b.follows_id, b.follows_house
from ( select follows.user_id as nome_id
, users.house as user_id_house
from follows inner join users
ON users.user_id = follows.user_id
) as a,
( select follows.follows as follows_id
, users.house as follows_house
from follows inner join users
ON follows.user_id = users.user_id
) as b
where a.user_id_house <> b.follows_house;
The problem is that the result is like 400 rows, its not right. I have no idea how I could solve this.
Try this
SELECT follows.user_id, users.school, followers.user_id, followers.school FROM follows
JOIN users ON follows.user_id=users.user_id
JOIN users as followers ON follows.follows=followers.user_id
WHERE users.school <> followers.school
Note: Pay attention to naming in my answer
Thanks for correcting to Thorsten Kettner
I have this table:
id sort_ord
0 6
1 7
2 2
3 3
4 4
5 5
6 8
Why does this query:
UPDATE table
SET sort_ord=(
SELECT count(*)
FROM table AS pq
WHERE sort_ord<table.sort_ord
ORDER BY sort_ord
)
WHERE(sort_ord>=0)
Produce:
id sort_ord
0 4
1 5
2 0
3 1
4 2
5 4
6 6
I was expecting all sort_ord fields to subtract by 2.
Here is defined: https://www.sqlite.org/isolation.html
About this link i can interpret, you has several instances for one query (update table and select count table) and independent of each other.
When you are in update sort_data(5) id 5, you have new data for read on every "SET sot_ord" (understanding what say about isolation), and now the result is 4.
Every select is a new instance and a new data reading
id sort_ord
0 4
1 5
2 0
3 1
4 2
5 5**
6 8**
From a given table I want to be able to sum values having the same number (should be easy, right?)
Problem: A given value can be assigned from 2 to n consecutive numbers.
For some reasons this information is stored in a single row describing the value, the starting number and the ending number as below.
TABLE A
id | starting_number | ending_number | value
----+-----------------+---------------+-------
1 2 5 8
2 0 3 5
3 4 6 6
4 7 8 10
For instance the first row means:
value '8' is assigned to numbers: 2, 3 and 4 (5 is excluded)
So, I would like the following intermediairy result table
TABLE B
id | number | value
----+--------+-------
1 2 8
1 3 8
1 4 8
2 0 5
2 1 5
2 2 5
3 4 6
3 5 6
4 7 10
So I can sum 'value' for elements having identical 'number'
SELECT number, sum(value)
FROM B
GROUP BY number
TABLE C
number | sum(value)
--------+------------
2 13
3 8
4 14
0 5
1 5
5 6
7 10
I don't know how to do this and didn't find any answer on the web (maybe not looking with appropriate key words...)
Any idea?
You can do what you want with generate_series(). So, TableB is basically:
select id, generate_series(starting_number, ending_number - 1, 1) as n, value
from tableA;
Your aggregation is then:
select n, sum(value)
from (select id, generate_series(starting_number, ending_number - 1, 1) as n, value
from tableA
) a
group by n;
I've got a bit of a complicated query that I'm struggling with. You will notice that the schema isn't the easiest thing to work with but it's what I've been given and there isn't time to re-design (common story!).
I have rows like the ones below. Note: The 3 digit value numbers are just random numbers I made up.
id field_id value
1 5 999
1 6 888
1 7 777
1 8 foo <--- foo so we want the 3 values above
1 9 don't care
2 5 123
2 6 456
2 7 789
2 8 bar <--- bar so we DON'T want the 3 values above
2 9 don't care
3 5 623
3 6 971
3 7 481
3 8 foo <--- foo so we want the 3 values above
3 9 don't care
...
...
n 5 987
n 6 654
n 7 321
n 8 foo <--- foo so we want the 3 values above
n 9 don't care
I want this result:
id result
1 999*888*777
3 623*971*481
...
n 987*654*321
Is this clear? So we have a table with n*5 rows. For each of the sets of 5 rows: 3 of them have values we might want to multiply together, 1 of them tells us if we want to multiply and 1 of them we don't care about so we don't want the row in the query result.
Can we do this in Oracle? Preferably one query.. I guess you need to use a multiplication operator (somehow), and a grouping.
Any help would be great. Thank you.
something like this:
select m.id, exp(sum(ln(m.value)))
from mytab m
where m.field_id in (5, 6, 7)
and m.id in (select m2.id
from mytab m2
where m2.field_id = 8
and m2.value = 'foo')
group by m.id;
eg:
SQL> select * from mytab;
ID FIELD_ID VAL
---------- ---------- ---
1 5 999
1 6 888
1 7 777
1 8 foo
1 9 x
2 5 123
2 6 456
2 7 789
2 8 bar
2 9 x
3 5 623
3 6 971
3 7 481
3 8 foo
3 9 x
15 rows selected.
SQL> select m.id, exp(sum(ln(m.value))) result
2 from mytab m
3 where m.field_id in (5, 6, 7)
4 and m.id in (select m2.id
5 from mytab m2
6 where m2.field_id = 8
7 and m2.value = 'foo')
8 group by m.id;
ID RESULT
---------- ----------
1 689286024
3 290972773
Same logic; just removed the hard-coded values. posting this answer thinking might be helpful to some others.
SELECT a.id,
exp(sum(ln(a.val)))
FROM mytab a,
(SELECT DISTINCT id,
field_id
FROM mytab
WHERE val = 'foo') b
WHERE a.id = b.id
AND a.field_id < b.field_id
GROUP BY a.id;