String_agg for SQL Server before 2017 - sql

Question

Can anyone help me make this query work for SQL Server 2014?
This is working on Postgresql and probably on SQL Server 2017. On Oracle it is listagg instead of string_agg.
Here is the SQL:
select
string_agg(t.id,',') AS id
from
Table t
I checked on the site some xml option should be used but I could not understand it.

Answer 1

In SQL Server pre-2017, you can do:
select stuff( (select ',' + cast(t.id as varchar(max))
from tabel t
for xml path ('')
), 1, 1, ''
);
The only purpose of stuff() is to remove the initial comma. The work is being done by for xml path.

Answer 2

Note that for some characters, the values will be escaped when using FOR XML PATH, for example:
SELECT STUFF((SELECT ',' + V.String
FROM (VALUES('7 > 5'),('Salt & pepper'),('2
lines'))V(String)
FOR XML PATH('')),1,1,'');
This returns the string below:
7 > 5,Salt & pepper,2
lines'
This is unlikely desired. You can get around this using TYPE and then getting the value of the XML:
SELECT STUFF((SELECT ',' + V.String
FROM (VALUES('7 > 5'),('Salt & pepper'),('2
lines'))V(String)
FOR XML PATH(''),TYPE).value('(./text())[1]','varchar(MAX)'),1,1,'');
This returns the string below:
7 > 5,Salt & pepper,2
lines
This would replicate the behaviour of the following:
SELECT STRING_AGG(V.String,',')
FROM VALUES('7 > 5'),('Salt & pepper'),('2
lines'))V(String);
Of course, there might be times where you want to group the data, which the above doesn't demonstrate. To achieve this you would need to use a correlated subquery. Take the following sample data:
CREATE TABLE dbo.MyTable (ID int IDENTITY(1,1),
GroupID int,
SomeCharacter char(1));
INSERT INTO dbo.MyTable (GroupID, SomeCharacter)
VALUES (1,'A'), (1,'B'), (1,'D'),
(2,'C'), (2,NULL), (2,'Z');
From this wanted the below results:
GroupID
Characters
1
A,B,D
2
C,Z
To achieve this you would need to do something like this:
SELECT MT.GroupID,
STUFF((SELECT ',' + sq.SomeCharacter
FROM dbo.MyTable sq
WHERE sq.GroupID = MT.GroupID --This is your correlated join and should be on the same columns as your GROUP BY
--You "JOIN" on the columns that would have been in the PARTITION BY
FOR XML PATH(''),TYPE).value('(./text())[1]','varchar(MAX)'),1,1,'')
FROM dbo.MyTable MT
GROUP BY MT.GroupID; --I use GROUP BY rather than DISTINCT as we are technically aggregating here
So, if you were grouping on 2 columns, then you would have 2 clauses your sub query's WHERE: WHERE MT.SomeColumn = sq.SomeColumn AND MT.AnotherColumn = sq.AnotherColumn, and your outer GROUP BY would be GROUP BY MT.SomeColumn, MT.AnotherColumn.
Finally, let's add an ORDER BY into this, which you also define in the subquery. Let's, for example, assume you wanted to sort the data by the value of the ID descending in the string aggregation:
SELECT MT.GroupID,
STUFF((SELECT ',' + sq.SomeCharacter
FROM dbo.MyTable sq
WHERE sq.GroupID = MT.GroupID
ORDER BY sq.ID DESC --This is identical to the ORDER BY you would have in your OVER clause
FOR XML PATH(''),TYPE).value('(./text())[1]','varchar(MAX)'),1,1,'')
FROM dbo.MyTable MT
GROUP BY MT.GroupID;
For would produce the following results:
GroupID
Characters
1
D,B,A
2
Z,C
Unsurprisingly, this will never be as efficient as a STRING_AGG, due to having the reference the table multiple times (if you need to perform multiple aggregations, then you need multiple sub queries), but a well indexed table will greatly help the RDBMS. If performance really is a problem, because you're doing multiple string aggregations in a single query, then I would either suggest you need to reconsider if you need the aggregation, or it's about time you conisidered upgrading.