I have db with names etc with date of birth. How can I get count of columns for all 12 months of the dates?
Exact code depends on the database you use; you should, somehow, "extract" month from date of birth in order to GROUP BY it.
In Oracle, you might have done it as
select to_char(date_of_birth), 'mon') dob_month,
count(*)
from your_table
group by to_char(date_of_birth, 'mon');
or
select extract(month from date_of_birth) dob_month,
count(*)
from your_table
group by extract(month from date_of_birth);
Related
I'm trying to get DISTINCT IDs for DISTINCT dates in BigQuery to build a report.
The date field is the kay partition field.
I tried to start with something looking like
SELECT DISTINCT(Id) FROM `project.dataset.table`
WHERE DATE(KeyPartitionDate)
BETWEEN '2017-01-01' AND '2020-06-01'
But this only gives me the different Ids between those 2 dates.
Now when it comes to query and check for every month of the year the DISTINCT(Ids), I have no clue how to do it.
I tried using DISTINCT and GROUP By for the Date but that doesn't seem to be the right path...
Any idea ?
If you are looking for number of distinct IDs for each month then this might help you.
SELECT DATE_TRUNC(DATE(KeyPartitionDate), MONTH) as month,COUNT(DISTINCT Id) as num_of_Ids
FROM `project.dataset.table`
WHERE DATE(KeyPartitionDate) BETWEEN '2017-01-01' AND '2020-06-01'
GROUP BY DATE_TRUNC(DATE(KeyPartitionDate), MONTH)
#standardSQL
SELECT DISTINCT
DATE_TRUNC(DATE(KeyPartitionDate), MONTH) year_month,
id
FROM `project.dataset.table`
WHERE DATE(KeyPartitionDate)
BETWEEN '2017-01-01' AND '2020-06-01'
I have a table with the following columns:
Date
Skills,
Customer ID
I want to find out Date(x), Customers, Count of Customers in between Date(x) and Date(x)+6
Can somebody guide me how to make this query, or can I create this function in SQL Server?
If I understand you correctly, you want something like this:
(take care, can be bad syntax, because i "work" only with oracle. But I think that it should work)
select date, customer_id, COUNT(*)
from your_table --add your table
where date between getdate() and DATEADD(day, 6, getdate())
-- between current database system date and +6 day
group by date, customer id
order by COUNT (*) desc -- if you want, you can order your result - ASC||DESC
If you have data on each date, then perhaps this is what you want:
select date, count(*),
sum(count(*)) over (order by date rows between 6 preceding and current row) as week_count
from t
group by date;
customer Date location
1 25Jan2018 texas
2 15Jan2018 texas
3 12Feb2018 Boston
4 19Mar2017 Boston.
I am trying to find out count of customers group by yearmon of Date column.Date column is of text data type
eg: In jan2018 ,the count is 2
I would do something like the following:
SELECT
date_part('year', formattedDate) as Year
,date_part('month', formattedDate) as Month
,count(*) as CustomerCountByYearMonth
FROM
(SELECT to_date(Date,'DDMonYYYY') as formattedDate from <table>) as tbl1
GROUP BY
date_part('year', formattedDate)
,date_part('month', formattedDate)
Any additional formatting for dates could be done on the inner query that will allow for adjustments in case some single digit days need to be padded or a month has four letters instead of three etc.
By converting to date type, you can properly order by date type and not alphabetical etc.
Optionally:
SELECT
Year
,Month
,count(*) as CustomerCountByYearMonth
FROM
(SELECT
date_part('year', to_date(Date,'DDMonYYYY')) as Year
,date_part('month', to_date(Date,'DDMonYYYY')) as Month
FROM <table>) as tbl1
GROUP BY
Year
,Month
You shouldn't store dates in a text column...
select substring(Date, length(Date)-6), count(*)
from tablename
group by substring(Date, length(Date)-6)
I thought #Jarlh asked a good question -- what about dates like January 1? Is it 01Jan2019 or 1Jan2019? If it can be either, perhaps a regex would work.
select
substring (date from '\d+(\D{3}\d{4})') as month,
count (distinct customer)
from t
group by month
The 'distinct customer' also presupposes you may have the same customer listed in the same month, but you only want to count it once. If that's not the case, just remove 'distinct.'
And, if you wanted the output in date format:
select
to_date (substring (date from '\d+(\D{3}\d{4})'), 'monyyyy') as month,
count (distinct customer)
from t
group by month
If it is a date column, you can truncate the date:
select date_trunc('month', date) as yyyymm, count(*)
from t
group by yyyymm
order by yyyymm;
I really read that the type was date. For a string, just use string functions:
select substr(date, 3, 7) as mmmyyyy, count(*)
from t
group by mmmyyyy;
Unfortunately, ordering doesn't work in this case. You should really be storing dates using the proper type.
SELECT EVENT_DT - ((EVENT_DT -DATE'1900-01-07') MOD 7) AS dates,
CLSFD_USER_ID AS user_id,
COUNT(DISTINCT CLSFD_USER_ID) AS number_of_user_ids,
COUNT(DISTINCT CLSFD_CAS_AD_ID) AS number_of_ads,
SUM(IMPRSN_CNT) AS number_of_impressions
FROM clsfd_access_views.CLSFD_CAS_AD_HST
WHERE CLSFD_SITE_ID = 3001
AND datum >= '2017-01-01'
GROUP BY 1,2
I want to have the total number of unique users during each month of the year 2017. I tried:
GROUP BY EXTRACT(MONTH FROM datum), 2
But this returns an error. What would be the most efficient code to retrieve the total number of user ids, ads, and impressions, per month.
It doesn't make sense to me to be aggregating by users, since they are what you are trying to count. Try grouping by the month and year alone:
SELECT
EXTRACT(YEAR FROM EVENT_DT) || '-' || EXTRACT(MONTH FROM EVENT_DT) AS month,
COUNT(DISTINCT CLSFD_USER_ID) AS number_of_user_ids,
COUNT(DISTINCT CLSFD_CAS_AD_ID) AS number_of_ads,
SUM(IMPRSN_CNT) AS number_of_impressions
FROM clsfd_access_views.CLSFD_CAS_AD_HST
WHERE
CLSFD_SITE_ID = 3001 AND
datum >= '2017-01-01' AND datum < '2018-01-01'
GROUP BY
EXTRACT(YEAR FROM EVENT_DT) || '-' || EXTRACT(MONTH FROM EVENT_DT);
Note that I changed your restriction on datum to also exclude any year greater than 2017.
If you want this values to be included in current query, then you should use analytical functions. For example "total number of unique users during each month" would be something like:
select count(distinct user_id) over(partition by EXTRACT(MONTH FROM datum))
Be aware that those values will be repeated for each user.
having table
id|date|somefield
I need to get count of entries for each day of the year
select EXTRACT (DAY_OF_YEAR FROM date) as day, id from table
works fine
but when I try
select EXTRACT (DAY_OF_YEAR FROM date) as day, count(*) from table
fails
select count(*) from table group by EXTRACT (DAY_OF_YEAR FROM date)
fails as well
You need to add a group by expression. Here is some pseudo code, I will work up a SqlFiddle in a moment.
select EXTRACT (DAY_OF_YEAR FROM date) as day,
count(*)
from table
group by EXTRACT (DAY_OF_YEAR FROM date)
SQLFIDDLE (Using MYSQL) http://sqlfiddle.com/#!2/42c9e/10