I have a string Organization, INC..Truck/Equipment Failure |C. I want to fetch the sub-string after organization name (after two '..' characters) and before pipe character. So the output string should be - Truck/Equipment Failure.
Can you please help.
I have been trying forming regexp like this but doesn't seem working.
select regexp_substr('Organization, INC..Truck/Equipment Failure |C', '[^.]+',1,2) from dual;
You may use this.
SELECT REGEXP_SUBSTR ('Organization, INC..Truck/Equipment Failure |C',
'([^.]+)\|',
1,
1,
NULL,
1)
FROM DUAL;
EDIT: This will match exactly two dots followed by one or more characters other than a | till the end of string.
SELECT REGEXP_SUBSTR ('Organization, INC..Truck/Equipment Failure',
'\.{2}([^|]+)',
1,
1,
NULL,
1)
FROM DUAL;
DEMO
Classic SUBSTR + INSTR option:
SQL> with test as (select 'Organization, INC..Truck/Equipment Failure |C' col from dual)
2 select substr(col, instr(col, '..') + 2,
3 instr(col, '|') - instr(col, '..') - 2
4 ) result
5 from test;
RESULT
------------------------
Truck/Equipment Failure
SQL>
Related
I'm using Oracle database 18 c and Oracle Apex 22.
I have a string like this one:
'Hello this Marc ||www.stackoverflow.com|| welcome to our family'
I want to remove any character within this delimiter ||
So the output should be:
'Hello this Marc welcome to our family'
Can anyone help with a regexp query that does that?
The way you put it, combination of substr and instr functions returns that result:
Sample data:
SQL> with test (col) as
2 (select 'Hello this Marc ||www.stackoverflow.com|| welcome to our family' from dual)
Query:
3 select substr(col, 1, instr(col, '|') - 2) ||
4 substr(col, instr(col, '|', 1, 4) + 1) as result
5 from test;
RESULT
-------------------------------------
Hello this Marc welcome to our family
SQL>
Or, if you prefer regular expressions, remove everything between outmost pipe signs:
3 select regexp_replace(col, ' \|.+\|') result
4 from test;
RESULT
-------------------------------------
Hello this Marc welcome to our family
SQL>
I have a table with a "Link" attribute. It has the following meaning:
INC102
INC1020
INC10200
I want to get the following result:
INC102
INC1020
INC10200
I need to leave the INC and the numbers after it without .
Tell me which command will help here? Since I understand that "Substr" will not work here.
I am use SQL Developer - Oracle
If you just want to extract "INC" with the following digits, use regexp_substr():
select regexp_substr(link, 'INC[0-9]+')
Here is a db<>fiddle.
Since I understand that "Substr" will not work here.
Says who?
SQL> with test (col) as
2 (select 'INC102' from dual union all
3 select 'INC1020' from dual union all
4 select 'INC10200' from dual
5 )
6 select
7 substr(col,
8 instr(col, '>') + 1,
9 instr(col, '<', instr(col, '>')) - instr(col, '>') - 1
10 ) result
11 from test;
RESULT
------------------------------------------------------------------------------------------------------------------------
INC102
INC1020
INC10200
SQL>
What does it do?
lines #1 - 5: sample data
line #8: starting point of the SUBSTR function is one character after the first > sign
line #9: length (used as the 3rd parameter of the SUBSTR) is position of the first < that follows the first > minus position of the first >
And that's it ... why wouldn't it work?
You could treat [<>] as the word delimiter and take the second word:
with test (col) as
( select 'INC102' from dual union all
select 'INC1020' from dual union all
select 'INC10200' from dual
)
select regexp_substr(col,'[^<>]+', 1, 2)
from test;
REGEXP_SUBSTR(COL,'[^<>]+',1,2)
-------------------------------
INC102
INC1020
INC10200
I need to remove all the characters after a particular string (-->).
select
REGEXP_SUBSTR('-->Team Name - Red-->blue', '[^(-->)]+')
from dual;
expected result from the above query is "Team Name - Red". But its returning "Team Name".
Its filtering out everything whenever it matches any of one character.
You can still use Regexp_Substr() analytic function :
Select Regexp_Substr('-->Team Name - Red-->blue',
'-{2}>(.*?)-{2}>',1,1,null,1) as "Result"
From dual;
Result
---------------
Team Name - Red
-{2}> ~ exactly twice occurence of - and single occurence of > e.g. ( --> )
(.*?) ~ matches anything delimited by the pattern above
Demo
You could try using REGEXP_REPLACE here with a capture group:
SELECT
REGEXP_REPLACE('-->Team Name - Red-->blue', '.*-->(.*?)-->.*', '\1')
FROM dual;
The output from this is Team Name - Red
Demo
It seems that you, actually, want to return string between two --> marks. A good, old substr + instr option would be
SQL> with test (col) as
2 (select '-->Team Name - Red-->blue' from dual)
3 select substr(col,
4 instr(col, '-->', 1, 1) + 3,
5 instr(col, '-->', 1, 2) - instr(col, '-->', 1, 1) - 3
6 ) result
7 from test;
RESULT
---------------
Team Name - Red
SQL>
I'm struggling with a query in Oracle SQL, wanting to get some timings out of some text stored in an Oracle db.
Table :
kde_test (myString varchar(50))
Table contents (3 records):
'task1 - 6m'
'task2 - 66m'
'task3 - 666m'
I would like to get only the interesting part of the string, being the timings, so I would like to get only '6', '66' & '666' as results.
Searched this forum a bit, and got up with this query eventually, but it seems I do not completely get it, as the results it returns are :
6m
66m
666m
select
CASE
WHEN myString like 'task1%' THEN substr(myString,9,INSTR(myString,'m',1,1)-1)
WHEN myString like 'task2%' THEN substr(myString,9,INSTR(myString,'m',1,1)-1)
WHEN myString like 'task3%' THEN substr(myString,9,INSTR(myString,'m',1,1)-1)
END
from kde_test
where myString like 'task%'
EDIT :
Since some solutions (thanks already for quick response) take into account the specific values (eg. all 3 records ending on '6m'), maybe it best to take into account the values could be :
Table contents (3 records):
'task1 - 6m'
'task2 - 58m'
'task3 - 123m'
you can use this way too
select regexp_replace(SUBSTR('task3 - 666m' ,
INSTR('task3 - 666m', '-',1, 1)+1, length('task3 - 666m')), '[A-Za-z]')
from dual
result :666
Use SUBSTR and INSTR and make it dynamic.
SUBSTR(str,
instr(str, ' - ', 1, 1) +3,
instr(str, 'm', 1, 1) -
instr(str, ' - ', 1, 1) -3
)
For example,
SQL> WITH DATA AS(
2 SELECT 'task1 - 6m' str FROM dual UNION ALL
3 SELECT 'task2 - 66m' str FROM dual UNION ALL
4 SELECT 'task3 - 666m' str FROM dual UNION ALL
5 SELECT 'task4 - 58m' str FROM dual UNION ALL
6 SELECT 'task5 - 123m' str FROM dual
7 )
8 SELECT str,
9 SUBSTR(str, instr(str, ' - ', 1, 1) +3,
10 instr(str, 'm', 1, 1) - instr(str, ' - ', 1, 1) -3) new_st
11 FROM DATA;
STR NEW_STR
------------ ------------
task1 - 6m 6
task2 - 66m 66
task3 - 666m 666
task4 - 58m 58
task5 - 123m 123
SQL>
You can use the regex_substr function. \d+ means one or more digits, and $ anchors the end of the string.
select regexp_substr(str, '\d+m$')
from mytable
Example at SQL Fiddle.
In order to correct your current query, you should change the following string - "INSTR(myString,'m',1,1)-1" to "INSTR(myString,'m',1,1)-9".
However, the other answers provided above seem like a more elegant solution to your problem.
I did feel the need to publish this just to clarify what wasn't working well in current query - in INSTR function returns the position of the m letter, and then used as the length of the string to print. What my fix does is telling the query to print everything from the 9th character until the position of the m letter, which results in the task time required.
I have tried to divide this into two parts
First pick the string after -
regexp_substr ('task1 - 1234m', '[^ _ ]+',1, 3) --results 1234m
Fetch the number part of the string fetched from output of first
regexp_substr(regexp_substr ('task1 - 1234m', '[^ _ ]+',1, 3),'[[:digit:]]*')
--output 1234
So,the final query is
SELECT regexp_substr(regexp_substr (mystring, '[^ _ ]+',1, 3),'[[:digit:]]*')
FROM kde_test;
Use This:-
select substr(replace(myString,'m',''),9) output
from kde_test
where myString like 'task%'
in my table one column contains data as below
BMS/430301420-XN/0
I need to use substr function in oracle and output to be taken as
430301420-XN
the one I used is as below
substr(buy_id,5),substr(substr(buy_id,5),instr(buy_id,'/',2))
but it is not working please help me
If you know the format of the string and you always want to start on the fifth character and remove the last two, then:
select substr(str, 5, -2)
If you just want the part between the slashes, then use regexp_substr():
select replace(regexp_substr(str, '/.*/'), '/', '')
Easiest way is a Regular Expression, find the string between the slashes but don't include them in the result:
regexp_substr(buy_id, '(?<=/).*(?=/)')
With a combination of SUBSTR and INSTR:
SQL> WITH DATA AS(
2 SELECT 'BMS/430301420-XN/0' str FROM dual UNION ALL
3 SELECT 'BMSABC/430301420-XN/0' str FROM dual UNION ALL
4 SELECT 'BMS/430301420-XN/012345' str FROM dual
5 )
6 SELECT str,
7 SUBSTR(str, instr(str, '/', 1, 1)+1, instr(str, '/', 1, 2)
8 -instr(str, '/', 1, 1)-1) new_str
9 FROM DATA;
STR NEW_STR
----------------------- -----------------------
BMS/430301420-XN/0 430301420-XN
BMSABC/430301420-XN/0 430301420-XN
BMS/430301420-XN/012345 430301420-XN
SQL>
The above uses the logic to find the substring between the first and second occurrence of the /.
This will also Work :D
select Column_Name as OLD , substr(''||to_char(Column_Name)||'',instr
(''||to_char(Column_Name)||'','/',1)+1,(instr(''||to_char(Column_Name)
||'','/',1,2)-instr(''||to_char(Column_Name)||'','/',1,1)-1)) as NEW from Table_Name;
Same Use Of substr and instr
my answer is :
select
substr('BMS/430301420-XN/0',
(instr('BMS/430301420-XN/0','/') +1),
(instr('BMS/430301420-XN/0','/',(instr('BMS/430301420-XN/0','/')+1))-instr('BMS/430301420-XN/0','/')-1 ))
from dual
you can see this sample :
http://www.sqlfiddle.com/#!4/9eecb7/863/0