TSQL syntax to feed results into subquery - sql

I'm after some help on how best to write a query that does the following. I think I need a subquery but I don't know how to use the data returned in the row to feed back into the subquery without hardcoding values? A subquery may not be the right thing here?
Ideally I only want 1 variable ...WHERE t_Date = '2018-01-01'
Desired Output:
The COUNT Criteria column has the following rules
Date < current row
Area = current row
Name = current row
Value = 1
For example, the first row indicates there are 2 records with Date < '2018-01-01' AND Area = 'Area6' AND Name = 'Name1' AND Value = 1
Example Data:
SQLFiddle: http://sqlfiddle.com/#!18/92ba3/4
Effectively I only want to return the first 2 rows but summarise the historic data into a column based on the output in that column.

The right way to do this is to use the cumulative sum functionality in ANSI SQL and SQL Server since 2012:
select t.*,
sum(case when t.value = 1 then 1 else 0 end) over (partition by t_area, t_name order by t_date)
from t;
This actually includes the current row. If you have only one row per date (for the area/name combo), then you can just subtract it or use a windowing clause:
select t.*,
sum(case when t.value = 1 then 1 else 0 end) over
(partition by t_area, t_name
order by t_date
rows between unbounded preceding and 1 preceding
)
from t;

Use a self join to find records in the same table that are related to a particular record:
SELECT t1.t_Date, t1.t_Area, t1.t_Name, t1.t_Value,
COUNT(t2.t_Name) AS COUNTCriteria
FROM Table1 as t1
LEFT OUTER JOIN Table1 as t2
ON t1.t_Area=t2.t_Area
AND t1.t_Name=t2.T_Name
AND t2.t_Date<t1.t_Date
AND t2.t_Value=1
GROUP BY t1.t_Date, t1.t_Area, t1.t_Name, t1.t_Value

Related

SQL - Count new entries based on last date

I have a table with the follow structure
ID ReportDate Object_id
What I need to know, is the count of new and count of old (Object id's)
For example: If I have the data below:
I want the following output grouped by ReportDate:
I thought a way doing it using a Where clause based on date, however i need the data for all the dates I have in the table. To see the count of what already existed in the previous report and what is new at that report. Any Ideas?
Edit: New/Old definition- New would be the records that never appeared before that report run date and appeared on this one, whereas old is the number of records that had at least one match in previous dates. I'll edit the post to include this info.
managed to do it using a left join. Below is my solution in case it helps anyone in the future :)
SELECT table.ReportRunDate,
-1*sum(table.ReportRunDate = new_table.init_date) as count_new,
-1*sum(table.ReportRunDate <> new_table.init_date) as count_old,
count(*) as count_total
FROM table LEFT JOIN
((SELECT Object_ID, min(ReportRunDate) as init_date
FROM table
GROUP By OBJECT_ID) as new_table)
ON table.Object_ID = new_table.Object_ID
GROUP BY ReportRunDate
This would work in Oracle, not sure about ms-access:
SELECT ReportDate
,COUNT(CASE WHEN rnk = 1 THEN 1 ELSE NULL END) count_of_new
,COUNT(CASE WHEN rnk <> 1 THEN 1 ELSE NULL END)count_of_old
FROM (SELECT ID
,ReportDate
,Object_id
,RANK() OVER (PARTITION BY Object_id ORDER BY ReportDate) rnk
FROM table_name)
GROUP BY ReportDate
Inner query should rank each occurence of object_id based on the ReportDate so the 1st occurrence of certain object_id will have rank = 1, the next one rank = 2 etc.
Then the outer query counts how many records with rank equal/not equal 1 are the within each group.
I assumed that 1 object_id can appear only once within each reportDate.

SQL Server - How to fill in missing column values

I have set of records at day level with 2 columns:
Invoice_date
Invoice_amount
For few records, value of invoice_amount is missing.
I need to fill invoice_amount values where it is NULL using this logic:
Look for next available invoice_amount (in dates later than the blank value record date)
For records with invoice_amount still blank (invoice_amount not present for future dates), look for most previous invoice_amount (in dates before the blank value date)
Note: We have consecutive multiple days where invoice_amount is blank in the dataset:
use CROSS APPLY to find next and previous not null Invoice Amount
update p
set Invoice_Amount = coalesce(nx.Invoice_Amount, pr.Invoice_Amount)
from Problem p
outer apply -- Next non null value
(
select top 1 *
from Problem x
where x.Invoice_Amount is not null
and x.Invoice_Date > p.Invoice_Date
order by Invoice_Date
) nx
outer apply -- Prev non null value
(
select top 1 *
from Problem x
where x.Invoice_Amount is not null
and x.Invoice_Date < p.Invoice_Date
order by Invoice_Date desc
) pr
where p.Invoice_Amount is null
this updates back your table. If you need a select query, it can be modify to it easily
Not efficient but seems to work. Try:
update test set invoice_amount =
coalesce ((select top 1 next.invoice_amount from test next
where next.invoiceDate > test.invoiceDate and next.invoice_amount is not null
order by next.invoiceDate),
(select top 1 prev.invoice_amount from test prev
where prev.invoiceDate < test.invoiceDate and prev.invoice_amount is not null
order by prev.invoiceDate desc))
where invoice_amount is null;
As per given example you could use window function with self join
update t set t.amount = tt.NewAmount
from table t
inner join (
select Dates, coalesce(min(amount) over (order by dates desc ROWS BETWEEN 1 PRECEDING AND CURRENT ROW),
min(amount) over (order by dates asc ROWS BETWEEN 1 PRECEDING AND CURRENT ROW)) NewAmount
from table t
) tt on tt.dates = t.dates
where t.amount is null

ORACLE: How to get earliest record of certain value when value alternates?

I'll simplify what I'm looking for here.
I have a table that stores an asset name, the date (job runs daily), and a value that is either 1 or 0 that indicates whether the asset is out of compliance.
I need to get the earliest date where the value is 0.
The issue I run into is that the issue can be intermittent, such that the same asset may show as in compliance, then out, and then in again. I want to retrieve the earliest date it was out of compliance this time.
Asset Date Compliant
NAME 2-FEB-18 0
NAME 1-FEB-18 0
NAME 31-JAN-18 1
NAME 30-JAN-18 0
In this example, I want to retrieve 1-FEB-18, and not 30-JAN-18.
I'm using a subquery into a temp table that retrieves the MIN(date) which would return 30-JAN-18. Thoughts?
Anonymized current subquery:
least_recent_created AS
(
SELECT t.date,t.ASSET, t.DATABASE_NAME FROM table t
WHERE t.date =
(
SELECT MIN(date)
FROM table2 t2
WHERE t.ASSET_ID = t2.ASSET_ID
AND t.DATABASE_NAME = t2.DATABASE_NAME
AND t2.compliant = 0
)
)
You want the earliest out-of-compliance date since the last in compliance. If the asset was never in compliance, I assume you want the earliest date.
select t.asset, min(date)
from (select t.*,
max(case when t.complaint = 1 then date end) over (partition by asset) as max_compliant1_date
from t
) t
where complaint = 0 and
(date > max_complaint1_date or max_complaint1_date is null)
group by t.asset;
You can use the following query:
SELECT "Asset", MAX("Date")
FROM (
SELECT "Asset", "Date", "Compliant",
CASE
WHEN "Compliant" = 0 AND
LAG("Compliant") OVER (PARTITION BY "Asset"
ORDER BY "Date") = 1 THEN "Date"
END AS OutOfComplianceDate
FROM mytable) t
WHERE OutOfComplianceDate IS NOT NULL
GROUP BY "Asset"
The inner query identifies 'Out-of-Compliance' dates, that is dates where the current record has "Compliant" = 0 whereas the immediately preceding record has "Compliant" = 1.
The outer query returns the latest 'Out-of-Compliance' date per "Asset".
Demo here

Select records where the only exist 1 in a joined table

I have the following query:
SELECT
A.POSTCARD_ID, A.STAMP_ID, B.END_DT
FROM
PST_VS_STAMP A
JOIN
STAMP B ON A.POSTCARD_ID = B.POSTCARD_ID
WHERE
B.ACCOUNT LIKE 'AA%'
AND B.END_DT = '9999-12-31'
GROUP BY
A.POSTCARD_ID, A.STAMP_ID, B.END_DT
HAVING
COUNT(A.POSTCARD_ID) < 2
But I get the wrong results.
I want only the postcards ID's where there is 1 record (HAVING < 2) in the PST_VS_STAMP table. How can I query this?
Do the aggregation in the subquery, only on the table where you want one row. Because there is one row, you can use an aggregation function to pull out the value of any column (for one row min(col) is the column's value):
select s.postcard_id, vs.stamp_id, s.end_dt
from stamp s join
(select vs.postcard_id, min(stamp_id) as stamp_id
from pst_vs_stamp vs
group by vs.postcard_id
having count(*) = 1
) s
on vs.POSTCARD_ID = s.POSTCARD_ID
where s.ACCOUNT like 'AA%' and s.END_DT = '9999-12-31';

SQL Server 2012 - updating a column based on row to row comparison

I have a table that contains dates and times. For example columns are Date, ExTime, NewTime, Status. I am ordering them based on a expkey column that makes them show in the right order.
I want to do a row by row comparison and compare the second row column of extime to the first row column NewTime. If extime < Newtime then I want to update status with a "1". And then traverse through the table row by row where second row in the above example becomes the first and a new second is pull and used. Here is a sample of what I have now - but it is not hitting and working all all of the rows for some reason.
UPDATE t
SET t.Status = 1
FROM MyTable t
CROSS APPLY (SELECT TOP 1 NewTime
FROM MyTable
WHERE ID = t.ID AND [Date] = t.[Date]
ORDER BY ExpKey) t1
WHERE t.Extime < t1.NewTime
This is not hitting all the rows like I want it to. I have the where clause comparing fields ID and Date to insure that the rows are attached to the same person. If the ID or Dates are not the same it is not attached to the same person so I would not want to update the status. So basically if the ID of Row 2 = ID of Row 1 and Date of Row 2 = Date of Row 1 I want to compare extime of row 2 and see if it is less than newtime of Row 1 - if so then update the status field of row 2.
Any help in figuring out why this sort of works but not on all would be appreciated.
Ad.
On SQL Server 2012 you can easily update status with window function lag():
with cte as (
select
extime,
lag(newtime) over(partition by id, date order by expKey) as newtime,
status
from table1
)
update cte set status = 1 where extime < newtime;
sql fiddle demo
I haven't tested this, but I've dealt with similar issues of comparing adjacent rows. I put this together off-the-cuff, so it may need tweaking, but give it a try.
;WITH CTE AS
( SELECT ID,[Date],ExpKey,ExTime,NewTime,
ROW_NUMBER()OVER(PARTITION BY ID,[Date] ORDER BY ExpKey) AS Sort
FROM MyTable
)
UPDATE row2
SET row2.[Status] = 2
WHERE row2.ExTime < row1.NewTime
FROM CTE row2
CROSS JOIN CTE row1
ON row1.ID = row2.ID
AND row1.[Date] = row2.[Date]
AND row1.Sort = row2.Sort-1 --Join to prior row