In an MS-Access database I'm working with, one of the tables has a field called "Name". The format of this field will generally be along the lines of "firstname surname integer", but sometimes may just be "firstname surname".
I need to select just the first name and the surname from the name field.
I've looked at using the Left function
SELECT DISTINCT LEFT([Name], x)
However since names are different lengths, this isn't going to work since there is no constant integer to use as the second parameter. Nor can it be used with
SELECT DISTINCT LEFT(InStr([Name], " "), x)
for the above reason, but also because because that would split the field at the first space.
Is there a way using LEFT, TRIM, SPLIT or any other string manipulation that I can create a query to select just the first two parts of the name? I need the space included.
You can try this.
SELECT DISTINCT IIf( ( InStr( InStr([Name],' ') + 1 , [Name], ' ') > 0 ), Left( [Name], InStr(InStr([Name],' ') + 1 , [Name], ' ') ), [Name])
FROM MyTable;
Related
I am working with a field called codes that is a delimited list of values, separated by commas. Within each item there is a title ending in a colon and then a code number following the colon. I want a list of only the code numbers after each colon.
Example Value:
name-form-na-stage0:3278648990379886572,rules-na-unwanted-sdfle2:6886328308933282817,us-disdg-order-stage1:1273671130817907765
Desired Output:
3278648990379886572,6886328308933282817,1273671130817907765
The title does always start with a letter and the end with a colon so I can see how REGEXP_REPLACE might work to replace any string between starting with a letter and ending with a colon with '' might work but I am not good at REGEXP_REPLACE patterns. Chat GPT is down fml.
Side note, if anyone knows of a good guide for understanding pattern notation for regular expressions it would be much appreciated!
I tried this and it is not working REGEXP_REPLACE(REPLACE(REPLACE(codes,':', ' '), ',', ' ') ,' [^0-9]+ ', ' ')
This solution assumes a few things:
No colons anywhere else except immediately before the numbers
No number at the very start
At a high level, this query finds how many colons there are, splits the entire string into that many parts, and then only keeps the number up to the comma immediately after the number, and then aggregates the numbers into a comma-delimited list.
Assuming a table like this:
create temp table tbl_string (id int, strval varchar(1000));
insert into tbl_string
values
(1, 'name-form-na-stage0:3278648990379886572,rules-na-unwanted-sdfle2:6886328308933282817,us-disdg-order-stage1:1273671130817907765');
with recursive cte_num_of_delims AS (
select max(regexp_count(strval, ':')) AS num_of_delims
from tbl_string
), cte_nums(nums) AS (
select 1 as nums
union all
select nums + 1
from cte_nums
where nums <= (select num_of_delims from cte_num_of_delims)
), cte_strings_nums_combined as (
select id,
strval,
nums as index
from cte_nums
cross join tbl_string
), prefinal as (
select *,
split_part(strval, ':', index) as parsed_vals
from cte_strings_nums_combined
where parsed_vals != ''
and index != 1
), final as (
select *,
case
when charindex(',', parsed_vals) = 0
then parsed_vals
else left(parsed_vals, charindex(',', parsed_vals) - 1)
end as final_vals
from prefinal
)
select listagg(final_vals, ',')
from final
I have a column desc_txt in my table and its contents are quite similar to that of xml like shown below-
desc_txt
-----------
<td><strong>Criticality</strong></td><td>High</td></tr><td><strong>Country</strong></td><td>India</td></tr><tr><td><strong>City</strong></td><td>Indore</td>
Requirement is to have a new table/view created from this table having additional columns like Criticality, Country, City along with the column values like High, India, Indore, respectively.
How can this be achieved in Hive/Impala?
This can be done in two steps. I assumed you have only four columns to pull.
Load the data as is in a table. Put everything in a column.
Then use this below SQL to split the data multiple columns. I assumed 4 columns, you can increase as per your requirement.
with t as (
SELECT rtrim(ltrim(
regexp_replace( replace( trim(
regexp_replace(
regexp_replace("<td><strong>Criticality</strong></td><td>High</td></tr><td><strong>Country</strong></td><td>India</td></tr><tr><td><strong>City</strong></td><td>Indore</td>","</?[^>]*>",",")
,',,',',') ), ' ,', ',' ), '(,){2,}', ','),','),',')
str)
select split_part(str, ',', 1) as first_col,
split_part(str, ',', 2) as second_col,
split_part(str, ',', 3) as third_col,
split_part(str, ',', 4) as fourth_col
from t
The query is tricky - first it replaces all tags with comma in them, then it replaces multiple commas with single comma, then it removes comma from start and end of the string. split function then splits whole string based on comma and create individual columns.
HTH...
I am looking for some help in separating scientific names in my data. I want to take only the genus names and group them, but they are both connected in the same column. I saw the SQL Sever had a CHARINDEX command, but PostgreSQL does not. Does there need to be a function created for this? If so, how would it look?
I want to change 'Mallotus philippensis' to just 'Mallotus' or to just 'philippensis'
I am currently using Postgres 11, 12.
Use SPLIT_PART:
WITH yourTable AS (
SELECT 'Mallotus philippensis'::text AS genus
)
SELECT
SPLIT_PART(genus, ' ', 1) AS genus,
SPLIT_PART(genus, ' ', 2) AS species
FROM yourTable;
Demo
Probably string_to_array will be slightly more efficient than split_part here because string splitting will be done only once for each row.
SELECT
val_arr[1] AS genus,
val_arr[2] AS species
FROM (
SELECT string_to_array(val, ' ') as val_arr
FROM (
VALUES
('aaa bbb'),
('cc dddd'),
('e fffff')
) t (val)
) tt;
I am doing some data clean-up and need to Capitalize the first letter of City names. How do I capitalize the second word in a City Like Terra Bella.
SELECT UPPER(LEFT([MAIL CITY],1))+
LOWER(SUBSTRING([MAIL CITY],2,LEN([MAILCITY])))
FROM masterfeelisting
My results is this 'Terra bella' and I need 'Terra Bella'. Thanks in advance.
Ok, I know I answered this before, but it bugged me that we couldn't write something efficient to handle an unknown amount of 'text segments'.
So re-thinking it and researching, I discovered a way to change the [MAILCITY] field into XML nodes where each 'text segment' is assigned it's own Node within the xml field. Then those xml fields can be processed node by node, concatenated together, and then changed back to a SQL varchar. It's convoluted, but it works. :)
Here's the code:
CREATE TABLE
#masterfeelisting (
[MAILCITY] varchar(max) not null
);
INSERT INTO #masterfeelisting VALUES
('terra bellA')
,(' terrA novA ')
,('chicagO ')
,('bostoN')
,('porT dE sanTo')
,(' porT dE sanTo pallo ');
SELECT
RTRIM
(
(SELECT
UPPER([xmlField].[xmlNode].value('.', 'char(1)')) +
LOWER(STUFF([xmlField].[xmlNode].value('.', 'varchar(max)'), 1, 1, '')) + ' '
FROM [xmlNodeRecordSet].[nodeField].nodes('/N') as [xmlField]([xmlNode]) FOR
xml path(''), type
).value('.', 'varchar(max)')
) as [MAILCITY]
FROM
(SELECT
CAST('<N>' + REPLACE([MAILCITY],' ','</N><N>')+'</N>' as xml) as [nodeField]
FROM #masterfeelisting
) as [xmlNodeRecordSet];
Drop table #masterfeelisting;
First I create a table and fill it with dummy values.
Now here is the beauty of the code:
For each record in #masterfeelisting, we are going to create an xml field with a node for each 'text segment'.
ie. '<N></N><N>terrA</N><N>novA</N><N></N>'
(This is built from the varchar ' terrA novA ')
1) The way this is done is by using the REPLACE function.
The string starts with a '<N>' to designate the beginning of the node. Then:
REPLACE([MAILCITY],' ','</N><N>')
This effectively goes through the whole [MAILCITY] string and replaces each
' ' with '</N><N>'
and then the string ends with a '</N>'. Where '</N>' designates the end of each node.
So now we have a beautiful XML string with a couple of empty nodes and the 'text segments' nicely nestled in their own node. All the 'spaces' have been removed.
2) Then we have to CAST the string into xml. And we will name that field [nodeField]. Now we can use xml functions on our newly created record set. (Conveniently named [xmlNodeRecordSet].)
3) Now we can read the [xmlNodeRecordSet] into the main sub-Select by stating:
FROM [xmlNodeRecordSet].[nodeField].nodes('/N')
This tells us we are reading the [nodeField] as nodes with a '/N' delimiter.
This table of node fields is then parsed by stating:
as [xmlField]([xmlNode]) FOR xml path(''), type
This means each [xmlField] will be parsed for each [xmlNode] in the xml string.
4) So in the main sub-select:
Each blank node '<N></N>' is discarded. (Or not processed.)
Each node with a 'text segment' in it will be parsed. ie <N>terrA</N>
UPPER([xmlField].[xmlNode].value('.', 'char(1)')) +
This code will grab each node out of the field and take its contents '.' and only grab the first character 'char(1)'. Then it will Upper case that character. (the plus sign at the end means it will concatenate this letter with the next bit of code:
LOWER(STUFF([xmlField].[xmlNode].value('.', 'varchar(max)'), 1, 1, ''))
Now here is the beauty... STUFF is a function that will take a string, from a position, for a length, and substitute another string.
STUFF(string, start position, length, replacement string)
So our string is:
[xmlField].[xmlNode].value('.', 'varchar(max)')
Which grabs the whole string inside the current node since it is 'varchar(max)'.
The start position is 1. The length is 1. And the replacement string is ''. This effectively strips off the first character by replacing it with nothing. So the remaining string is all the other characters that we want to have lower case. So that's what we do... we use LOWER to make them all lower case. And this result is concatenated to our first letter that we already upper cased.
But wait... we are not done yet... we still have to append a + ' '. Which adds a blank space after our nicely capitalized 'text segment'. Just in case there is another 'text segment' after this node is done.
This main sub-Select will now parse each node in our [xmlField] and concatenate them all nicely together.
5) But now that we have one big happy concatenation, we still have to change it back from an xml field to a SQL varchar field. So after the main sub-select we need:
.value('.', 'varchar(max)')
This changes our [MAILCITY] back to a SQL varchar.
6) But hold on... we still are not done. Remember we put an extra space at the end of each 'text segment'??? Well the last 'text segment still has that extra space after it. So we need to Right Trim that space off by using RTRIM.
7) And dont forget to rename the final field back to as [MAILCITY]
8) And that's it. This code will take an unknown amount of 'text segments' and format each one of them. All using the fun of XML and it's node parsers.
Hope that helps :)
Here's one way to handle this using APPLY. Note that this solution supports up to 3 substrings (e.g. "Phoenix", "New York", "New York City") but can easily be updated to handle more.
DECLARE #string varchar(100) = 'nEW yoRk ciTY';
WITH DELIMCOUNT(String, DC) AS
(
SELECT #string, LEN(RTRIM(LTRIM(#string)))-LEN(REPLACE(RTRIM(LTRIM(#string)),' ',''))
),
CIPOS AS
(
SELECT *
FROM DELIMCOUNT
CROSS APPLY (SELECT CHARINDEX(char(32), string, 1)) CI1(CI1)
CROSS APPLY (SELECT CHARINDEX(char(32), string, CI1.CI1+1)) CI2(CI2)
)
SELECT
OldString = #string,
NewString =
CASE DC
WHEN 0 THEN UPPER(SUBSTRING(string,1,1))+LOWER(SUBSTRING(string,2,8000))
WHEN 1 THEN UPPER(SUBSTRING(string,1,1))+LOWER(SUBSTRING(string,2,CI1-1)) +
UPPER(SUBSTRING(string,CI1+1,1))+LOWER(SUBSTRING(string,CI1+2,100))
WHEN 2 THEN UPPER(SUBSTRING(string,1,1))+LOWER(SUBSTRING(string,2,CI1-1)) +
UPPER(SUBSTRING(string,CI1+1,1))+LOWER(SUBSTRING(string,CI1+2,CI2-(CI1+1))) +
UPPER(SUBSTRING(string,CI2+1,1))+LOWER(SUBSTRING(string,CI2+2,100))
END
FROM CIPOS;
Results:
OldString NewString
--------------- --------------
nEW yoRk ciTY New York City
This will only capitalize the first letter of the second word. A shorter but less flexible approach. Replace #str with [Mail City].
DECLARE #str AS VARCHAR(50) = 'Los angelas'
SELECT STUFF(#str, CHARINDEX(' ', #str) + 1, 1, UPPER(SUBSTRING(#str, CHARINDEX(' ', #str) + 1, 1)));
This is a way to use imbedded Selects for three City name parts.
It uses CHARINDEX to find the location of your separator character. (ie a space)
I put an 'if' structure around the Select to test if you have any records with more than 3 parts to the city name. If you ever get the warning message, you could add another sub-Select to handle another city part.
Although... just to be clear... SQL is not the best language to do complicated formatting. It was written as a data retrieval engine with the idea that another program will take that data and massage it into a friendlier look and feel. It may be easier to handle the formatting in another program. But if you insist on using SQL and you need to account for city names with 5 or more parts... you may want to consider using Cursors so you can loop through the variable possibilities. (But Cursors are not a good habit to get into. So don't do that unless you've exhausted all other options.)
Anyway, the following code creates and populates a table so you can test the code and see how it works. Enjoy!
CREATE TABLE
#masterfeelisting (
[MAILCITY] varchar(30) not null
);
Insert into #masterfeelisting select 'terra bella';
Insert into #masterfeelisting select ' terrA novA ';
Insert into #masterfeelisting select 'chicagO ';
Insert into #masterfeelisting select 'bostoN';
Insert into #masterfeelisting select 'porT dE sanTo';
--Insert into #masterfeelisting select ' porT dE sanTo pallo ';
Declare #intSpaceCount as integer;
SELECT #intSpaceCount = max (len(RTRIM(LTRIM([MAILCITY]))) - len(replace([MAILCITY],' ',''))) FROM #masterfeelisting;
if #intSpaceCount > 2
SELECT 'You need to account for more than 3 city name parts ' as Warning, #intSpaceCount as SpacesFound;
else
SELECT
cThird.[MAILCITY1] + cThird.[MAILCITY2] + cThird.[MAILCITY3] as [MAILCITY]
FROM
(SELECT
bSecond.[MAILCITY1] as [MAILCITY1]
,SUBSTRING(bSecond.[MAILCITY2],1,bSecond.[intCol2]) as [MAILCITY2]
,UPPER(SUBSTRING(bSecond.[MAILCITY2],bSecond.[intCol2] + 1, 1)) +
SUBSTRING(bSecond.[MAILCITY2],bSecond.[intCol2] + 2,LEN(bSecond.[MAILCITY2]) - bSecond.[intCol2]) as [MAILCITY3]
FROM
(SELECT
SUBSTRING(aFirst.[MAILCITY],1,aFirst.[intCol1]) as [MAILCITY1]
,UPPER(SUBSTRING(aFirst.[MAILCITY],aFirst.[intCol1] + 1, 1)) +
SUBSTRING(aFirst.[MAILCITY],aFirst.[intCol1] + 2,LEN(aFirst.[MAILCITY]) - aFirst.[intCol1]) as [MAILCITY2]
,CHARINDEX ( ' ', SUBSTRING(aFirst.[MAILCITY],aFirst.[intCol1] + 1, LEN(aFirst.[MAILCITY]) - aFirst.[intCol1]) ) as intCol2
FROM
(SELECT
UPPER (LEFT(RTRIM(LTRIM(mstr.[MAILCITY])),1)) +
LOWER(SUBSTRING(RTRIM(LTRIM(mstr.[MAILCITY])),2,LEN(RTRIM(LTRIM(mstr.[MAILCITY])))-1)) as [MAILCITY]
,CHARINDEX ( ' ', RTRIM(LTRIM(mstr.[MAILCITY]))) as intCol1
FROM
#masterfeelisting as mstr -- Initial Master Table
) as aFirst -- First Select Shell
) as bSecond -- Second Select Shell
) as cThird; -- Third Select Shell
Drop table #masterfeelisting;
I need to do a select in a column that contains a query string like:
user_id=300&company_id=201503&status=WAITING OPERATION&count=1
I want to perform a select and break each value in a new column, something like:
user_id | company_id | status | count
300 | 201503 | WAITING OPERATION | 1
How can i do it in SQL Server without use procs?
I've tried a function:
CREATE FUNCTION [xpto].[SplitGriswold]
(
#List NVARCHAR(MAX),
#Delim1 NCHAR(1),
#Delim2 NCHAR(1)
)
RETURNS TABLE
AS
RETURN
(
SELECT
Val1 = PARSENAME(Value,2),
Val2 = PARSENAME(Value,1)
FROM
(
SELECT REPLACE(Value, #Delim2, '&') FROM
(
SELECT LTRIM(RTRIM(SUBSTRING(#List, [Number],
CHARINDEX(#Delim1, #List + #Delim1, [Number]) - [Number])))
FROM (SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
FROM sys.all_objects) AS x
WHERE Number <= LEN(#List)
AND SUBSTRING(#Delim1 + #List, [Number], LEN(#Delim1)) = #Delim1
) AS y(Value)
) AS z(Value)
);
GO
Execution:
select QueryString
from User.Log
CROSS APPLY notifier.SplitGriswold(REPLACE(QueryString, ' ', N'ŏ'), N'ŏ', '&') AS t;
But it returns me only one column with all inside:
QueryString
user_id=300&company_id=201503&status=WAITING OPERATION&count=1
Thanks in advance.
I've had to do this many times before, and you're in luck! Since you only have 3 delimiters per string, and that number is fixed, you can use SQL Server's PARSENAME function to do it. That's far less ugly than the best alternative (using the XML parsing stuff). Try this (untested) query (replace TABLE_NAME and COLUMN_NAME with the appropriate names):
SELECT
PARSENAME(REPLACE(COLUMN_NAME,'&','.'),1) AS 'User',
PARSENAME(REPLACE(COLUMN_NAME,'&','.'),2) AS 'Company_ID',
PARSENAME(REPLACE(COLUMN_NAME,'&','.'),3) AS 'Status',
PARSENAME(REPLACE(COLUMN_NAME,'&','.'),4) AS 'Count',
FROM TABLE_NAME
That'll get you the results in the form "user_id=300", which is far and away the hard part of what you want. I'll leave it to you to do the easy part (drop the stuff before the "=" sign).
NOTE: I can't remember if PARSENAME will freak out over the illegal name character (the "=" sign). If it does, simply nest another REPLACE in there to turn it into something else, like an underscore.
You need to use SQL SUBSTRING as part of your select statement. You would first need to build the first row, then use a UNION to return the second row.