I appologize for this simple question but cannot find a straight and simple answer and am going crazy.
I am running on DB2 and I want to
Select date_column from my_table
but I want to select date_column as number the way Excel does it. So for example: 2017-02-26 would show up as 43157.
date_column is a DATE type in my table.
Assuming you are using the Excel 1900 date system, where the number of days is measured since January 1, 1900, you may try the following query which uses the DAYS function to find a date difference:
SELECT
DAYS(date_column) - DAYS('1900-01-01') AS excel_date
FROM my_table;
Related
I have a table with column DATE. Date is 'dd/mm/yyyy' and I want only days. So I try with extract and return what I need, but I what using transpose for column to row.
The select statement is:
select EXTRACT (DAY FROM "DATE") DAY
from people;
Is this thing possible?
Thank you!
If you have a string, then just use the leftmost two characters:
select substr("DATE", 1, 2) as day
That said, you should not be storing dates as strings. It is wrong, wrong, wrong. You cannot use the built-in date/time functions. You cannot use inequality comparisons either. Fix your data model.
The date format doesn't matter. It is linked to your NLS local settings and this is how you see this.
To have it generic and extract DAY from the date do this:
select to_char(sysdate, 'DD') from dual;
Would return 07 since it's September 7th 2020.
I have a problem with converting a varchar2 fields into a date format.
I got 2 columns with the datatyp varchar2, one is called qtime the other is called ztime. Both fields contain strings in this format (f.e. 152015 -> would be a timestamp 15:20:15).
For reporting reasons I need to convert this fields into a date format, afterwards I want to substract (qtime-ztime) the fields an convert them into the format [hh] (f.e. after the operation 01:20:00 would be -> 01). Is it possible to to this within Oracle SQL 12c? The biggest problem for me right now is that I don't get those Strings converted into a date format.
select TO_DATE(qtime,'MM/DD/YYYY hh24:mi:ss') just gives me
ORA-01861:"literal does not match format string"
select TO_DATE(qtime,'hh24mmss') gives me a wrong Date
01.03.2018
select TO_TIMESTAMP(qtime,'hh24mmss') gives me a wrong Date
01.03.2018 BUT the correct time with f.e. 15:20:15,0000000
Thank you in advance, any help is appreciated
Note: I only have reading rights on the database Oracle 12c, so I need to to this within Statements
"The Database contains another column with the correct date for each time"
The missing piece of the puzzle! Concatenate the two columns to get something which can be converted to an Oracle DATE:
select to_date(qdate||qtime, 'yyyymmddhh24miss') as qdatetime
, to_date(zdate||ztime, 'yyyymmddhh24miss') as zdatetime
from your_table
Once you have done that you can perform arithmetic of the dates e.g.
select id
, zdatetime - qdatetime as time_diff
from ( select id
, to_date(qdate||qtime, 'yyyymmddhh24miss') as qdatetime
, to_date(zdate||ztime, 'yyyymmddhh24miss') as zdatetime
from your_table
)
If you want the number of hours in the difference you can include this expression in the projection of the outer query:
, extract( hour from (zdatetime - qdatetime) day to second) as hrs_ela
First off, if you are trying to convert a varchar2 into a date without specifying neither day nor month, it will default to the first day of the current month:
If you specify a date value without a date, then the default date is the first day of the current month.
You can read up more here
Also in 2nd and 3rd your example, you are using 'hh24mmss' for specifying hour, minute and second components, but do note that correct format for minutes is 'mi' and not 'mm', which is used for months.
So the solution is to concatenate both date and time component when creating the date as the other answer suggested, tho I would recommend using a single date field as it can store the information you need.
I am importing records from a DB2 data source into a MS SQL Server destination.
The records are coming in with the date format of 20150302/YYYYMMDD, but I only want the last 14 days based on current server date.
Can some advise on how to select based on this date format against DATEADD(d, - 1, { fn CURDATE() }) please.
Thanks!
It would be better to do this on the DB2 side, to reduce the number of records brought over.
Additionally, it's better from a performance standpoint to convert the static date into a numeric date and compare to the column in your table. Rather than convert the numeric date in your table to a actual date type for comparison.
where numdate >= int(replace(char(current_date - 14 days,iso),'-',''))
Doing it this way will allow you to take advantage of an index over numdate. In addition, DB2 will only need to perform this conversion once.
Depending on your platform & version, you may have an easier way to convert from a date data type to a numeric date. But the above works on DB2 for i and should work on most (all?) DB2 versions and platforms.
You may find it worthwhile to create a UDF to do this conversion for you.
If you want logic in SQL Server, then you are in luck, because you can just convert the YYYYMMDD format to a date:
where cast(datecol as date) >= cast(getdate() - 14 as date)
(This assumes no future dates.)
If you want to do this on the DB2 side, you can use to_date():
where to_date(datecol, 'YYYYMMDD') >= current date - 14 days
I have a table with a LOAD_STRT_DTM colum. This is a date column and values are like this - 18-JUL-14 08.20.34.000000000 AM.
I want to find the data which came before 5 days.
My logic is -
Select * from Table where 24 *(To_DATE(Sysdate,'DD-MM-YY') - To_DATE(LOAD_STRT_DTM,'DD-MM-YY')) >120
The issue is -
Select (To_DATE(Sysdate,'DD-MM-YY') - To_DATE(LOAD_STRT_DTM,'DD-MM-YY')) from table
This query should give the NumberOfDays between two dates. But this is not working, I Doubt, the issue is because of the format of the LOAD_STRT_DTM colum.
Please let me know where i am doint it wrong.
If your column is DATE datatype everything is ok, just shoot an:
select * from table where LOAD_STRT_DTM > sysdate - 5;
No need to convert dates to DATE datatype.
(To_DATE(Sysdate,'DD-MM-YY') - To_DATE(LOAD_STRT_DTM,'DD-MM-YY'))
You don't have to convert a DATE into a DATE again. IT is already a DATE. You just need to use it for date calculations. You use TO_DATE to convert a STRING into a DATE.
For example, if you have a string value like '18-JUL-14', then you would need to convert it into date using TO_DATE. Since your column is DATE data type, you just need to use as it is.
This is a date column
I want to find the data which came before 5 days.
Simply use the filter predicate as:
WHERE load_strt_dtm > SYSDATE - 5;
NOTE : SYSDATE has both date and time elements, so it will filter based on the time too. If you want to use only the date part in the filter criteria, then you could use TRUNC. IT would truncate the time element.
I have answered a similar question, have a look at this https://stackoverflow.com/a/29005418/3989608
It looks like LOAD_STRT_DTM is a TIMESTAMP rather than a DATE, given the number of decimal points following the seconds. The only thing you have to be cautious about is that Oracle will convert a DATE to a TIMESTAMP implicitly where one of the operands is a TIMESTAMP. So the solution
WHERE load_strt_dtm > SYSDATE - 5
will work; as will
WHERE load_strt_dtm + 5 > SYSDATE
but the following will not:
WHERE SYSDATE - load_start_dtm < 5
the reason being that TIMESTAMP arithmetic produces an INTERVAL rather than a NUMBER.
first convert two dates to same format select datediff(dd,convert(varchar(20),'2015-01-01',112),convert(varchar(20),'01-10-2015',112))
I am trying to check for dates but after running the query below, it displays no result. Could someone recommend me the correct syntax?
SELECT TOP 10 * FROM MY_DATABASE.AGREEMENT
WHERE end_dt=12/31/9999
12/31/9999 might look like a date for you but for the database it's a calculation:
12 divided by 31 divided by 9999 and because this involves INTEGER division this results in an INTEGER 0
So finally you compare a DATE to an INT and this results in typecasting the DATE to a INT.
The only reliable way to write a date literal in Teradata is DATE followed by a string with a YYYY-MM-DD format:
DATE '9999-12-31'
Similar for TIME '12:34:56.1' and TIMESTAMP '2014-08-20 12:34:56.1'
Is it a date column? Then try where end_dt = '9999-12-31'.
The question you ask is not very clear. The date you specify is language dependent.
Try
SELECT TOP 10 * FROM MY_DATABASE.AGREEMENT WHERE end_dt='99991231'