I have a DB with three tables.
"Campaign" table has a column "Campaign number" (e.g. value = 1)
"Payment" table has a column "user_id" (e.g. value = 134356)
"User_Source" table has a column "dump" which contains both the user id and campaign number: info_u134356_cpn_1 OR info_cpn_1_u134356
I need to divide the data from the combined values in user_source, so that I would be able to see user_id and their linked campaign number in one table, and then count how many users are attributed to each campaign.
I can't get my head around the way to split ths column, and whether there is a way to do s without spitting (e.g. somehow filtering).
I'm currently using DataGrip for this.
You can use regexp_match() in Postgres:
with sample (dump) as (
values
('info_cpn_1_u134356'),
('info_u456789_cpn_5')
)
select (regexp_match(dump, 'u([0-9]+)'))[1] as user_id,
(regexp_match(dump, 'cpn_([0-9]+)'))[1] as campaign
from sample;
returns:
user_id | campaign
--------+---------
134356 | 1
456789 | 5
Related
I am trying to create a table that has columns called user_id and top5_foods (binary column). I currently have two tables, one has all of the user_ids and the foods associated with those user_ids and one table that only contains the top5 foods according to a type of calculation to select the top5 foods.
The table that I am trying to create if to have the column of the user_id and if at least one of their favorite foods is in the top_5_food table, put the value of the top5_foods as 1 and if not, 0.
Something like the following:
user_id top5_foods
----------------------
34223 1
43225 0
34323 1
I have tried to use the CASE command but it just duplicated the user_ids and mark 1 or 0 whenever it finds a food that is in the top_5_foods table. But I don't want it to duplicate. Could you please help ?
Thank you very much
If I understand correctly, a left join and aggregation:
select uf.user_id,
(count(t.food_id) > 0) as top5_foods
from user_foods uf left join
top5_foods t
on uf.food_id = t.food_id
group by uf.user_id;
I am currently rebuilding a messy Access Database and I entcountered the following problem:
I've got a Table of facilities which contain a row called district. Those Rows contain a number linked to another table which just contains the numbers and names of districts. I added a lookup Column with the Name of the district displayed.
I now want to change the new column for every row depending on the data in the old row.
Facilities
NAME|..|DISTRICT_OLD
A |..| 1
B |..| 2
C |..| 1
...
DISTRICTS
ID|NAME
1 |EAST
2 |WEST
...
I would like something like the following:
Facilities
NAME|..|DISTRICT_OLD|DISTRICT
A |..| 1|EAST
B |..| 2|WEST
C |..| 1|EAST
...
The District Field (lookup) gets its Data like follows SELECT [DISTRICTS].ID, [DISTRICTS].NAME FROM DISTRICTS ORDER BY [NAME];
(Thanks to Gordon Linoff) I could get the query but I do now struggle with the insert. I can get the Data I want:
SELECT [DISTRICTS].NAME FROM Facilities INNER JOIN DISTRICTS ON Facilities.DISTRICT_OLD = [DISTRICTS].ID;
If I try to INSERT INTO Facilities(DISTRICT) It says Typerror.
How can I modify the data to be compatible with a lookup column?
I guess I need to select the ID as well which isnt't a problem but then the error says to many columns.
I hope I haven't mistaken any names, my Access isn't running the english language.
Can you help me?
Fabian
Lookup columns are number (long integer)
with a relational database, you only need the single column containing the ID (as you always lookup the district.name with a query) so:
INSERT INTO Facilities(DISTRICT) SELECT 4
where 4 is the ID of the record in the lookup table that you want, or better still:
INSERT INTO Facilities(DISTRICT)
SELECT ID FROM DISTRICTS
where District.Name = "Name you want the ID for"
I have an SQL Server 2012 table with ID, First Name and Last name. The ID is unique per person but due to an error in the historical feed, different people were assigned the same id.
------------------------------
ID FirstName LastName
------------------------------
1 ABC M
1 ABC M
1 ABC M
1 ABC N
2 BCD S
3 CDE T
4 DEF T
4 DEG T
In this case, the people with ID’s 1 are different (their last name is clearly different) but they have the same ID. How do I query and get the result? The table in this case has millions of rows. If it was a smaller table, I would probably have queried all ID’s with a count > 1 and filtered them in an excel.
What I am trying to do is, get a list of all such ID's which have been assigned to two different users.
Any ideas or help would be very appreciated.
Edit: I dont think I framed the question very well.
There are two ID's which are present multiple time. 1 and 4. The rows with id 4 are identical. I dont want this in my result. The rows with ID 1, although the first name is same, the last name is different for 1 row. I want only those ID's whose ID is same but one of the first or last names is different.
I tried loading ID's which have multiple occurrences into a temp table and tried to compare it against the parent table albeit unsuccessfully. Any other ideas that I can try and implement?
SELECT
ID
FROM
<<Table>>
GROUP BY
ID
HAVING
COUNT(*) > 1;
SELECT *
FROM myTable
WHERE ID IN (
SELECT ID
FROM myTable
GROUP BY ID
HAVING MAX(LastName) <> MIN(LastName) OR MAX(FirstName) <> MIN(FirstName)
)
ORDER BY ID, LASTNAME
I want to fetch the a field say excep_point from a transparent table z_accounts for the combination of company_code and account_number. How can I do this in ABAP SQL?
Assume that table structure is
|company_code | account_number | excep_point |
Assuming you have the full primary key...
data: gv_excep_point type zaccounts-excep_point.
select single excep_point
into gv_excep_point
from zaccounts
where company_code = some_company_code
and account_number = some_account_number.
if you don't have the full PK and there could be multiple values for excep_point
data: gt_excep_points type table of zaccounts-excep_point.
select excep_point
into table gt_excep_points
from zaccounts
where company_code = some_company_code
and account_number = some_account_number.
There is at least another variation, but those are 2 I use most often.
For information only. When you selects data into table you can write complex expressions to combine different fields. For example, you have internal table (itab) with two fields "A" and "B". And you are going to select data from DB table (dbtab) wich have 6 columns - "z","x","y","u","v","w". And for example each field is type char2 You aim to cimbine "z","x","y","u" in "A" field of internal table and "v","w" in "B" field. You can write simple code:
select z as A+0(2)
x as A+2(2)
y as A+4(2)
u as A+6(2)
v as B+0(2)
w as B+2(2) FROM dbtab
INTO CORRESPONDING FIELDS OF TABLE itab
WHERE <where condition>.
This simple code makes you job done very simple
In addition to Bryans answer, here is the official online documentation about Open SQL.
Here is the SQL table:
KEY | NAME | VALUE
---------------------
13b | Jeffrey | 23.5
F48 | Jonas | 18.2
2G8 | Debby | 21.1
Now, if I type:
SELECT *
FROM table
WHERE VALUE = 23.5
I will get the first row.
What I need to accomplish is to get the first and the next two rows below. Is there a way to do it?
Columns are not sorted and WHERE condition doesn't participate in the selection of the rows, except for the first one. I just need the two additional rows below the returned one - the ones that were entered after the one which has been returned by the SELECT query.
Without a date column or an auto-increment column, you can't reliably determine the order the records were entered.
The physical order with which rows are stored in the table is non-deterministic.
You need to define an order to the results to do this. There is no guaranteed order to the data otherwise.
If by "the next 2 rows after" you mean "the next 2 records that were inserted into the table AFTER that particular row", you will need to use an auto incrementing field or a "date create" timestamp field to do this.
If each row has an ID column that is unique and auto incrementing, you could do something like:
SELECT * FROM table WHERE id > (SELECT id FROM table WHERE value = 23.5)
If I understand correctly, you're looking for something like:
SELECT * FROM table WHERE value <> 23.5
You can obviously write a program to do that but i am assuming you want a query. What about using a Union. You would also have to create a new column called value_id or something in those lines which is incremented sequentially (probably use a sequence). The idea is that value_id will be incremented for every insert and using that you can write a where clause to return the remaining two values you want.
For example:
Select * from table where value = 23.5
Union
Select * from table where value_id > 2 limit 2;
Limit 2 because you already got the first value in the first query
You need an order if you want to be able to think in terms of "before" and "after".
Assuming you have one you can use ROW_NUMBER() (see more here http://msdn.microsoft.com/en-us/library/ms186734.aspx) and do something like:
With MyTable
(select row_number() over (order by key) as n, key, name, value
from table)
select key, name, value
from MyTable
where n >= (select n from MyTable where value = 23.5)