select query to identify numeric or alphanumeric values - sql

Question

I have a table like below:
TN Tier
90 1
90 N3
30 2
40 3
50 A
"Tier" column may contain numeric as well as alpha-numeric values for any TN. I want to run a select query on above table so that if for any TN, there are both(numeric and alpha-numeric) values present in Tier column then it should be called as "Mix" otherwise "Numeric" or "Non-Numeric".
Desired Output :
TN Result
90 Mix
30 Numeric
40 Numeric
50 Non-Numeric
I am able to achieve it by using multiple temp tables but i want to avoid using temp tables. Any help would be appreciated!!!

Answer 1

You can take use advantage of ISNUMERIC() function in SQL Server.
SELECT [TN],
CASE MAX(ISNUMERIC(Tier)) + MIN(ISNUMERIC(Tier))
WHEN 2 THEN 'Numeric'
WHEN 1 THEN 'Mix'
ELSE 'Non-Numeric'
End As Result
FROM TableName
GROUP BY TN
Here's a Demo.

Answer 2

For MySQL, use REGEXP with a CASE expression:
SELECT
TN,
CASE WHEN SUM(CASE WHEN Tier REGEXP '[A-Z]' AND Tier REGEXP '[0-9]'
THEN 1 ELSE 0 END) > 0 THEN 'Mix'
WHEN SUM(CASE WHEN Tier REGEXP '[A-Z]'
THEN 1 ELSE 0 END) > 0 THEN 'Non-Numeric'
WHEN SUM(CASE WHEN Tier REGEXP '[0-9]'
THEN 1 ELSE 0 END) > 0 THEN 'Numeric'
ELSE 'Other' END AS Result
FROM yourTable
GROUP BY
TN;
For SQL Server, you may slightly alter the above query by using LIKE with an appropriate pattern:
SELECT
TN,
CASE WHEN SUM(CASE WHEN Tier LIKE '%[A-Z]%' AND Tier LIKE '%[0-9]%'
THEN 1 ELSE 0 END) > 0 THEN 'Mix'
WHEN SUM(CASE WHEN Tier LIKE '%[A-Z]%'
THEN 1 ELSE 0 END) > 0 THEN 'Non-Numeric'
WHEN SUM(CASE WHEN Tier LIKE '%[0-9]%'
THEN 1 ELSE 0 END) > 0 THEN 'Numeric'
ELSE 'Other' END AS Result
FROM yourTable
GROUP BY
TN;
The SQL Server answer given by #JohnWoo is tighter than this, but as you tagged with MySQL I initially answered for this database.

Answer 3

You dont need any big query it can be make with simple,
try this:
Select * from table
then you can check value of you column in while loop, each time you can search string having number or not number in you record.
$string = $row['Tier'];
if (preg_match('/[A-Za-z]/', $myString) )
{
echo 'String contains letters';
}
else if(preg_match('/[0-9]/', $myString))
{
echo 'String contains numbers';
}else if($string == '')
{
echo 'String contains no letter and no number';
}

Answer 4

I hope, you are using mysql. It is better if you can write a custom function as follows.
delimiter //
CREATE FUNCTION is_numeric(inputValue VARCHAR(50))
RETURNS INT
BEGIN
IF (inputValue REGEXP ('^[0-9]+$'))
THEN
RETURN 1;
ELSE
RETURN 0;
END IF;
END;
Example - select is_numeric(id),is_numeric(full_name) FROM tbl_user;