how to select multiple max values from column in sql server? - sql

Question

I have following two tables TBLSession and TBLStudentFeeRecord having following sample datasets
TBLSession:
SessionId SessionName SessionStartMonth SessionEndMonth
1 2018-2019 2018-03-24 2019-02-24
2 2019-2020 2019-01-30 2019-12-30
3 2020-2021 2020-01-30 2021-12-30
TBLStudentFeeRecord:
StudentId SessionId TutionFee BranchId ClassId SectionId
1001 1 1000 1 1 1
1001 2 2000 1 3 1
1001 3 1000 2 2 1
Now,what i am trying to achieve is to select two maximum sessions TutionFee of selected StudentId. I can use max(columnName) to get one maximum value from that particular column. Now how can i get two maximum sessions?
Following dataset is required after querying these table
ResultDataSet:
StudentId SessionId TutionFee SessionName
1001 2 2000 2019-2020
1001 3 1000 2020-2021
What will be the query to achieve above dataset?

Answer 1

You can use SQL Row_Number function with Partition By clause if you want to get the 2 session info per student
Otherwise, use Row_number() function without Partition By clause
You can find explanations for two alternatives in the following SQL CTE statements
;with cte as (
select *,
-- top 2 session per student
-- rn = ROW_NUMBER() over (partition by studentid order by sessionid desc)
-- top 2 sessions
rn = ROW_NUMBER() over (order by sessionid desc)
from TBLStudentFeeRecord
)
select
*
from cte
inner join TBLSession on TBLSession.sessionid = cte.sessionid
where rn <= 2
The output is as follows
You can modify the select list according to your requirements

Answer 2

Since you haven't posted your tries, so try something like this:
Pseudo query:
select top 2 from (select TutionFee from TBLStudentFeeRecord
where StudentId = 1001
order by TutionFee desc )

Answer 3

You could use a subselect Top 2 on the max TutionFee and SessionId
select a.* , t.TutionFee
from TBLSession a
inner JOIN (
select TOP 2 studentID, TutionFee, SessionId
from TBLStudentFeeRecord
where StudentId = 1001
order TutionFee desc, SessionID desc
) t on t.SessionId = a.SessionId

Answer 4

Try this:
SELECT StudentId ,SessionId,TutionFee,SessionName
FROM(
SELECT TSF.StudentId ,TSF.SessionId,TSF.TutionFee,TS.SessionName
,ROW_NUMBER() OVER(PARTITION BY TSF.TutionFee ORDER BY SessionId DESC)RN
FROM TBLStudentFeeRecord TSF
INNER JOIN TBLSession TS ON TS.SessionId=TSF.SessionId
)D
WHERE RN=1

Answer 5

this should work
select TBLStudentFeeRecord.StudentId, TBLStudentFeeRecord.SessionId, TBLStudentFeeRecord.TutionFee, TBLStudentFeeRecord.SessionName
from TBLStudentFeeRecord
inner join TBLSession on TBLSession.SessionId = TBLStudentFeeRecord.SessionId
where TBLStudentFeeRecord.StudentId = 1000
ORDER BY TBLStudentFeeRecord.TutionFee DESC
LIMIT 2

Answer 6

In general query languages are powerful if you face any difficult or any complex scenario just use stored procedure
Two max..........................................
CREATE PROCEDURE twoMaxFrom()
BEGIN
DECLARE max1 DOUBLE;
DECLARE max2 DOUBLE;
DECLARE emp_cursor CURSOR FOR SELECT
TutionFee
FROM TBLStudentFeeRecord;
-- 2. Declare NOT FOUND handler
DECLARE CONTINUE HANDLER FOR NOT FOUND SET finished = 1;
-- 3. Open the cursor
OPEN emp_cursor;
L: LOOP
-- 4. Fetch next element
FETCH emp_cursor
INTO TutionFee;
-- Handler will set finished = 1 if cursor is empty
IF finished = 1
THEN
LEAVE L;
END IF;
SET max1 = 0;
SET max2 = 0;
IF max1 > max2
THEN
SET max1 = TutionFee;
SET max2 = max1;
END IF;
END LOOP;
-- 5. Close cursor when done
CLOSE emp_cursor;
SELECT max1;
SELECT max2;
END;

Answer 7

You can get it by using join and TOP
SELECT TOP 2 StudentId
,t1.SessionId
,TutionFee
,SessionName
FROM TBLSession AS t1
INNER JOIN TBLStudentFeeRecord AS t2 ON t1.SessionId = t2.SessionId
WHERE t2.StudentId = 1001
ORDER BY t1.SessionId DESC