I have data in database an example of data below
folder/subfolder/file/doc
folder/subfolder/doc
how do I get the 1st instance of characters from between the '/'
I want to extract 'folder/subfolder'
I have tried the following but not what I need. this gets 'folder/'
LEFT([Cat], CHARINDEX('/', [Cat]) ) as 'doc_cat',
and the below gets the last part
RIGHT([Cat], CHARINDEX('/', [Cat]) ) as 'doc_cat2',
I want to get the 1st part of and second part of string
Here is one method:
select left(doc_cat_1, charindex('/', doc_cat_1) - 1)
from t cross apply
(select stuff(cat, 1, charindex('/', cat), '') as doc_cat_1
) v1;
The string handling capabilities of SQL Server are pretty lousy. Apply at least makes it easier to handle intermediate results.
You can use LEFT and CHARINDEX
LEFT([Cat],charindex('/',[Cat],charindex('/',[Cat])+1)-1) AS 'doc_cat'
One more way to accomplish using XML -
declare #s table(patterns nvarchar(100))
insert into #s
values ('folder/subfolder/file/doc'), ('folder/subfolder/doc'),('folder/subfolder')
select cast(concat('<x>', REPLACE(patterns, '/', '</x><x>'), '</x>') as xml).value('/x[1]','varchar(100)') + '/'
+ cast(concat('<x>', REPLACE(patterns, '/', '</x><x>'), '</x>') as xml).value('/x[2]','varchar(100)')
from #s
If you're on SQL 2016 or newer, you could use STRING_SPLIT()
WITH cte AS (
SELECT cat, value, ROW_NUMBER() OVER (PARTITION BY cat ORDER BY cat) rn
FROM someTable CROSS APPLY
STRING_SPLIT(cat,'/')
)
SELECT cat, value FROM cte WHERE rn = 2;
The advantage here is that rn could be any number you need.
Fiddle here.
Related
I am trying to extract the data between two underscore characters. In some situations, the 2nd underscore may not exist.
MyFld
P_36840
U_216137
C_203134_H
C_203134_W
I tried this:
substring(i.[MyFld],
CHARINDEX ('_',i.[MyFld])+1,len(i.[MyFld])
-CHARINDEX ('_',i.[MyFld])
) [DerivedPrimaryKey]
And I get this:
DerivedPrimaryKey
36840
216137
203134_H
203134_W
https://dbfiddle.uk/uPKC6oX4
I want to remove the second underscore and data that follows it. I'm trying to combine it with a trim right, but I'm unsure where to start.
How can I do this?
We can start by simplifying what you have so far. I will also add enough to make this a complete query, so we can see it in context for later steps:
SELECT
right(i.MyFld, len(i.MyFld) - charindex('_', i.MyFld)) [DerivedPrimaryKey]
FROM I
With this much done, we can now use it as the source for removing the trailing portion of the field:
SELECT
reverse(substring(reverse(step1)
, charindex('_', reverse(step1))+1
, len(step1)
)) [DerivedPrimaryKey]
FROM (
SELECT right(i.MyFld, len(i.MyFld) - charindex('_', i.MyFld)) [step1]
FROM I
) T
Notice the layer of nesting. You can, of course, remove the nesting, but it means replicating the entire inner expression every time you see step1 (good thing I took the time to simplify it):
SELECT
reverse(substring(reverse(right(i.MyFld, len(i.MyFld) - charindex('_', i.MyFld)))
, charindex('_', reverse(right(i.MyFld, len(i.MyFld) - charindex('_', i.MyFld))))+1
, len(right(i.MyFld, len(i.MyFld) - charindex('_', i.MyFld)))
))
FROM I
And now back to just the expression:
reverse(substring(reverse(right(i.MyFld, len(i.MyFld) - charindex('_', i.MyFld)))
, charindex('_', reverse(right(i.MyFld, len(i.MyFld) - charindex('_', i.MyFld))))+1
, len(right(i.MyFld, len(i.MyFld) - charindex('_', i.MyFld)))
))
See it work here:
https://dbfiddle.uk/nFO4Vwhm
There is also this alternate expression that saves one function call:
left( right(i.MyFld,len(i.MyFld)-charindex('_',i.MyFld)),
coalesce(
nullif(
charindex('_',
right(i.MyFld,len(i.MyFld)-charindex('_',i.MyFld))
) -1, -1,
),
len( right(i.MyFld,len(i.MyFld)-charindex('_',i.MyFld)) )
)
)
Just a two more options. One using parsename() provided your data does not have more than 4 segments. The second using a JSON array
Example
Declare #YourTable Table ([MyFld] varchar(50)) Insert Into #YourTable Values
('P_36840')
,('U_216137')
,('C_203134_H')
,('C_203134_W')
Select *
,UsingParseName = reverse(parsename(reverse(replace(MyFld,'_','.')),2))
,UsingJSONValue = json_value('["'+replace(MyFld,'_','","')+'"]','$[1]')
From #You
Results
MyFld UsingParseName UsingJSONValue
P_36840 36840 36840
U_216137 216137 216137
C_203134_H 203134 203134
C_203134_W 203134 203134
We can do this:
Declare #testData Table ([MyFld] varchar(50));
Insert Into #testData (MyFld)
Values ('P_36840')
, ('U_216137')
, ('C_203134_H')
, ('C_203134_W');
Select *
, second_element = substring(v.MyFld, p1.pos, p2.pos - p1.pos - 1)
From #testData As td
Cross Apply (Values (concat(td.MyFld, '__'))) As v(MyFld) -- Make sure we have at least 2 delimiters
Cross Apply (Values (charindex('_', v.MyFld, 1) + 1)) As p1(pos) -- First Position
Cross Apply (Values (charindex('_', v.MyFld, p1.pos) + 1)) As p2(pos) -- Second Position
If you actually have a fixed number of characters in the first element, then it could be simplified to:
Select *
, second_element = substring(v.MyFld, 3, charindex('_', v.MyFld, 4) - 3)
From #testData td
Cross Apply (Values (concat(td.MyFld, '_'))) As v(MyFld)
Often I try to fake out SQL if an expected character isn't always present and I don't need the resulting value:
SELECT SUBSTRING(field_Calculated, 1, CHARINDEX('_', field_Calculated) - 1)
FROM (SELECT SUBSTRING(MyFld, CHARINDEX('_', MyFld) + 1, LEN(MyFld)) + '_' As field_Calculated
FROM MyTable) T
I think this is clear, but I really like the ParseName solution #JohnCappalletti suggests.
If it's only ever one numeric value you can use string_split:
SELECT * FROM MyTable
CROSS APPLY string_split(MyFld, '_')
WHERE ISNUMERIC(value) = 1
Either way you have to be careful of the data before deciding the best approach.
your data
Declare #Table Table ([MyFld] varchar(100))
Insert Into #Table
([MyFld] ) Values
('P_36840')
,('U_216137')
,('C_203134_H')
,('C_203134_W')
use SubString,Left and PatIndex
select
Left(
SubString(
[MyFld],
PatIndex('%[0-9.-]%', [MyFld]),
8000
),
PatIndex(
'%[^0-9.-]%',
SubString(
[MyFld],
PatIndex('%[0-9.-]%', [MyFld]),
8000
) + 'X'
)-1
) as DerivedPrimaryKey
from
#Table
I have this data point:
455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215
Column: ,[t810str]
How would I be able to modify column [t810str] in order to pull out the last comma set before 857?
Desired Result = 422-L-202008011052
First you need to implement some kind of splitter that respects ordinal position (STRING_SPLIT does not). I'm therefore going to make use of DelimitedSplit8k_LEAD. Then you can split the value, and use LAG to get the prior value. Finally you can filter on where the item has a value LIKE '857%' but the previous does not:
WITH CTE AS(
SELECT DS.Item,
LAG(DS.Item) OVER (PARTITION BY YourColumn ORDER BY DS.itemNumber) AS PrevItem
FROM (VALUES('455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215'))V(YourColumn)
CROSS APPLY dbo.DelimitedSplit8K_LEAD(V.YourColumn,',') DS)
SELECT C.PrevItem
FROM CTE C
WHERE C.Item LIKE '857%'
AND C.PrevItem NOT LIKE '857%';
Based on your data and the assumption that items are 18 characters (your data do not indicate otherwise):
DECLARE #t AS NVARCHAR(255) = '455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215';
SELECT RIGHT(LEFT(#t,CHARINDEX(',857',#t)-1),18)
Using cross apply (which you can also rewrite using a CTE or a subquery for readability). This removes everything after first occurrence of 857 and then grabs the last set that's left. So even if you have multiple 857 and varying length of delimited strings, this should work
select *, right(remind , charindex (',' ,reverse(remind))-1)
from t t1
cross apply (select stuff(col, charindex(',857',col), len(col),'') as remind) t2
DEMO
Another solution use a recursive CTE
DECLARE #Var VARCHAR(200) = '455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215';
WITH CTE AS
(
SELECT 0 N, LEFT(#Var, CHARINDEX(',', #Var)-1) Part,
RIGHT(#Var, LEN(#Var) - CHARINDEX(',', #Var)) Remind
UNION ALL
SELECT N + 1,
LEFT(Remind, CHARINDEX(',', Remind) - 1),
RIGHT(Remind, LEN(Remind) - CHARINDEX(',', Remind))
FROM CTE
WHERE CHARINDEX(',', Remind) <> 0
)
SELECT TOP 1 Part
FROM CTE
WHERE LEFT(Remind, 3) = '857'
ORDER BY N;
Demo
Implemented with string functions (and assuming your data items can have variable length :-) it might look a bit confusing (therefore I'd prefer #Larnu's answer):
DECLARE #string VARCHAR(2000) = '455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215'
SELECT SUBSTRING(#string, CHARINDEX(',857',#string) - CHARINDEX(',', REVERSE( LEFT(#string, PATINDEX('%,857%',#string) - 1)) ) + 1, CHARINDEX(',', REVERSE( LEFT(#string, PATINDEX('%,857%',#string) - 1)))-1 )
Parts of the latter separated:
DECLARE #string VARCHAR(2000) = '455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215'SELECT CHARINDEX(',857',#string)
SELECT LEFT(#string, PATINDEX('%,857%',#string) - 1)
SELECT REVERSE( LEFT(#string, PATINDEX('%,857%',#string) - 1) )
SELECT CHARINDEX(',', REVERSE( LEFT(#string, PATINDEX('%,857%',#string) - 1)) )
I have many different types of string, but they all follow the two same patterns:
ABC123-S-XYZ789
ABC123-P-XYZ789
QUESTION 1:
I know how I can extract the first part: ABC123
But how do I extract the second part??? XYZ789
QUESTION 2:
I can't tell beforehand if the string follows the -S- pattern or the -P- pattern, it can be different each time. Anyone who know how I can solve this?
Thanks! / Sophie
You can try following code:
SELECT CASE WHEN #a LIKE '%-S-%' THEN right(#a, CHARINDEX('-S-', #a)-1)
WHEN #a LIKE '%-P-%' THEN right(#a, CHARINDEX('-P-', #a)-1)
ELSE NULL END AS 'ColName'
FROM tablename
Is this what you need?
DECLARE #Input VARCHAR(100) = 'ABC123-S-XYZ789'
SELECT
FirstPart = SUBSTRING(
#Input,
1,
CHARINDEX('-', #Input) - 1),
SecondPart = SUBSTRING(
#Input,
LEN(#Input) - CHARINDEX('-', REVERSE(#Input)) + 2,
100),
Pattern = CASE
WHEN #Input LIKE '%-S-%' THEN 'S'
WHEN #Input LIKE '%-P-%' THEN 'P' END
You can use parsename() if the string has always this kind of parts such as ABC123-S-XYZ789
select col, parsename(replace(col, '-', '.'), 1)
However, the parsename() requires the SQL Server+12 if not then you can use reverse()
select col, reverse(left(reverse(col), charindex('-', reverse(col))-1))
If you're using SQL Server 2016 or newer, you can use STRING_SPLIT
CREATE TABLE #temp (string VARCHAR(100));
INSERT #temp VALUES ('ABC123-S-XYZ789'),('ABC123-P-XYZ789');
SELECT *, ROW_NUMBER() OVER (PARTITION BY string ORDER BY string)
FROM #temp t
CROSS APPLY STRING_SPLIT(t.string, '-');
I can't tell beforehand if the string folllows the -S- pattern or the -P- pattern
You can then use a CTE to get a specific part of the string:
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY string ORDER BY string) rn
FROM #temp t
CROSS APPLY STRING_SPLIT(t.string, '-')
)
SELECT * FROM cte WHERE rn = 2
I have a table with this values:
Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx
OurStory/MeettheFoodieandtheMD.aspx
TheFood/OurMenu.aspx
I want to get this
Diet.aspx
MeettheFoodieandtheMD.aspx
OurMenu.aspx
How can i do this?
The way to do it in SQL :
SELECT SUBSTRING( string , LEN(string) - CHARINDEX('/',REVERSE(string)) + 2 , LEN(string) ) FROM SAMPLE;
JSFiddle here http://sqlfiddle.com/#!3/41ead/11
SELECT REVERSE(LEFT(REVERSE(columnName), CHARINDEX('/', REVERSE(columnName)) - 1))
FROM tableName
SQLFiddle Demo
ORHER SOURCE(s)
REVERSE
LEFT
CHARINDEX
Please try:
select url,(CASE WHEN CHARINDEX('/', url, 1)=0 THEN url ELSE RIGHT(url, CHARINDEX('/', REVERSE(url)) - 1) END)
from(
select 'Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx' as url union
select 'OurStory/MeettheFoodieandtheMD.aspx' as url union
select 'MeettheFoodieandtheMD.aspx' as url
)xx
Try this. It's easier.
SELECT RIGHT(string, CHARINDEX('/', REVERSE(string)) -1) FROM TableName
SELECT REVERSE ((
SELECT TOP 1 value FROM STRING_SPLIT(REVERSE('Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx'), '/')
)) AS fName
Result: Diet.aspx
Standard STRING_SPLIT does not allow to take last value.
The trick is to reverse the string (REVERSE) before splitting with STRING_SPLIT, get the first value from the end (TOP 1 value) and then the result needs to be reversed again (REVERSE) to restore the original chars sequence.
Here is the common approach, when working with SQL table:
SELECT REVERSE ((
SELECT TOP 1 VALUE FROM STRING_SPLIT(REVERSE(mySearchString), '/')
)) AS myLastValue
FROM myTable
A slightly more compact way of doing this (similar to ktaria's answer but in SQL Server) would be
SELECT TOP 1 REVERSE(value) FROM STRING_SPLIT(REVERSE(fullPath), '/') AS fileName
The equivalent for PostgreSQL:
SELECT reverse(split_part(reverse(column_name), '/', 1));
Please try the code below:
SELECT SUBSTRING( attachment, LEN(attachment)
- CHARINDEX('/', REVERSE(attachment)) + 2, LEN(attachment) ) AS filename
FROM filestable;
more simple and elegant :
select reverse(SPLIT_PART(reverse('Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx'), '/',1))
You can try this too
( SELECT TOP(1) value
FROM STRING_SPLIT(#string, '/')
ORDER BY CHARINDEX('/' + value + '/', '/' + #string+ '-') DESC)
I corrected jazzytomato's solution for single character tokens (D) and for single tokens (Diet.aspx)
SELECT SUBSTRING( string , LEN(string) - CHARINDEX('/','/'+REVERSE(string)) + 2 , LEN(string) ) FROM SAMPLE;
The easiest way in MySQL:
SELECT SUBSTRING_INDEX(string, '/', -1) FROM SAMPLE;
I have more simple solve
SELECT SUBSTRING_INDEX(string, 'SUBSTRING_INDEX(string, '/', -1)', 1) FROM SAMPLE;
reverse(SUBSTRING(reverse(yourString),0,CHARINDEX('/',reverse(yourString)))) as stringLastPart
Create Table #temp
(
ID int identity(1,1) not null,
value varchar(100) not null
)
DECLARE #fileName VARCHAR(100);
INSERT INTO #temp(value) SELECT value from STRING_SPLIT('C:\Users\Documents\Datavalidation\Input.csv','\')
SET #fileName=(SELECT TOP 1 value from #temp ORDER BY ID DESC);
SELECT #fileName AS File_Name;
DROP TABLE #temp
How can I get the value from the sixth field in the following column? I am trying to get the 333 field:
ORGPATHTXT
2123/2322/12323/111/222/333/3822
I believe I have to use select substring, but am unsure how to format the query
Assuming SQL Server
The easiest way I can think of is create a Split function that splits based on '/' and you extract the sixth item like below
declare #text varchar(50) = '2123/2322/12323/111/222/333/3822'
select txt_value from fn_ParseText2Table(#text, '/') t where t.Position = 6
I used the function in this url. See it worked at SQLFiddle
Try this - for a string variable or wrap into a function to use with a select query (Sql-Demo)
Declare #s varchar(50)='2123/2322/12323/111/222/333/3822'
Select #s = right(#s,len(#s)- case charindex('/',#s,1) when 0 then len(#s)
else charindex('/',#s,1) end)
From ( values (1),(2),(3),(4),(5)) As t(num)
Select case when charindex('/',#s,1)>0 then left(#s,charindex('/',#s,1)-1)
else #s end
--Results
333
I'd like to offer a solution that uses CROSS APPLY to split up any delimited string in MSSQL and ROW_NUMBER() to return the 6th element. This assumes you have a table with ORGPATHTXT as a field (it can easily be converted to work without the table though):
SELECT ORGPATHTXT
FROM (
SELECT
Split.a.value('.', 'VARCHAR(100)') AS ORGPATHTXT,
ROW_NUMBER() OVER (PARTITION BY ID ORDER BY (SELECT 1)) RN
FROM
(SELECT ID, CAST ('<M>' + REPLACE(ORGPATHTXT, '/', '</M><M>') + '</M>' AS XML) AS String
FROM MyTable
) AS A
CROSS APPLY String.nodes ('/M') AS Split(a)
) t
WHERE t.RN = 6;
Here is some sample Fiddle to go along with it.
Good luck.
For sql, you can use
declare #string varchar(65) = '2123/2322/12323/111/222/333/3822'
select substring(string,25,27) from table_name
If you are using MySQL, then you can use:
select substring_index(orgpathtxt, '/', 6)
Let me just say that it is less convenient in most other databases.
Also you can use option with dynamic management function sys.dm_fts_parser
DECLARE #s nvarchar(50) = '2123/2322/12323/111/222/333/3822'
SELECT display_term
FROM sys.dm_fts_parser('"'+ #s + '"', 1033, NULL, 0)
WHERE display_term NOT LIKE 'nn%' AND occurrence = 6