How to split a column into two columns based on the value in the another column - sql

Question

I have below data in the Ms SQL server table.
I would like to get the output like below.
I have tried two sets of queries but it didn't helped me.
1st set query gives me the null values
Query
SELECT
[id]
, [sav]
, [cat]
, [tech]
, [asset]
, CASE
WHEN [objname] = 'FieldName'
THEN [stringvalue]
END AS [fieldname]
, CASE
WHEN [objname] = 'FieldValue'
THEN [stringvalue]
END AS [fieldvalue]
FROM [test].[dbo].[sample];
Output
2nd set query gives me 0 as field value, because i have hard coded it.
Query
SELECT
ROW_NUMBER() OVER(ORDER BY [fieldname]) AS 'id'
, [sav]
, [cat]
, [tech]
, [asset]
, [fieldname]
, 0 AS [fieldvalue]
FROM [test].[dbo].[sample] PIVOT(MAX([stringvalue]) FOR [objname] IN(
[fieldname])) [p]
WHERE [fieldname] IS NOT NULL;
Output
How to achieve it ?

Answer 1

You have a very arcane data structure. SQL tables are inherently unordered. From what I can tell, the SQL value is in the "next" row based on the id.
If so, you can use lead():
select . . .,
stringvalue as fieldname, next_string_value as stringvalue
from (select t.*, lead(t.stringvalue) over (order by id) as next_string_value
from t
) t
where t.objname = 'objname';
If you are really using SQL Server 2008, you can use a self-join. This does assume that the ids have no gaps in them.